give an example of a primary income from the rest of the world​

Answers

Answer 1

Answer:

(1) Income Associated with the Production Process

(a) Compensation of employees

(b) Taxes and subsidies on products and

production .

(2) Property Income

(a) Investment income:

• Dividends and withdrawals from income of

quasi-corporations

• Reinvested earnings

• Interest

(b) Rent .

I hope this is correct :-)


Related Questions

when rolling a number cube 500 times, how many times you expect to get a 3?

Answers

Answer:

[tex]\frac{250}{3}[/tex]

Explanation:

you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.

Here's the equation:

[tex]\frac{1}{6} =\frac{x}{500}[/tex]

cross multiply (i think that's what it is called)

500=6x

divide by 6 on both sides:

x=[tex]\frac{250}{3}[/tex] or approx 83 times.

Hope this helps! Lmk if u have more questions <3

PLEASE HELP I HAVE 19 MINUTES LEFT I WILL MARK BRAINLIEST
How much more acidic is a pH of 4 as compared to a pH of 6.5?

Answers

Answer:

316.227766

Explanation:

Answer 3.16 hope it helps

A saturated solution of sucrose in 500.0 mL of boiling water is cooled to 20.0 0C. What mass of rock candy will be formed?

Answers

Answer:

1280.5g

Explanation:

What quality is attributed to water due to “capillary action”?
A. change of liquid water into gaseous phase
B. the ability of water molecules to adhere to the surfaces of objects
C. high volatility
D. vapor pressure

Answers

Answer:

I think it's B. The ability of water molecules to adhere to the surfaces of objects

What is the partial pressure (in atm) of CO₂ at 468.2 K in a 25.0 L fuel combustion vessel if it contains 60.0 grams CO₂, 82.1 g H₂O, and 7.30 mol vaporized, yet uncombusted fuel?

Answers

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

Mass of CO₂ (m): 60.0 gVolume of the vessel (V): 25.0 LTemperature (T): 468.2 K

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

From the ideal gas equation:

PV =nRT

P= partial pressure

V = volume = 25 L

n = moles of carbon dioxide

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{60}{44}[/tex] mol

Moles of [tex]\rm CO_2[/tex] = 1.36 mol

R = constant = 0.0821 atm.L/mol.K

T = temperature in Kelvin =  468.2 K

Partial pressure of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{1.36\;\times\0.0821\;\times\;468.2}{25}[/tex]

Partial pressure of [tex]\rm CO_2[/tex] = 2.09 atm.

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

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Why is the regression equation not exactly y = 100 • 0.5n?

Answers

Answer:

Radioactive decay is a random event.

Explanation:

on edge

Answer:

Radioactive decay is a random event.

Explanation:

Edge 2020

Can someone please solve this question?? Is an element in group 3 likely to bond with an element from group 2?? Explain using the number of balance electrons from each element and the tot number of balance electrons needed to fill an about shell

Answers

Answer:

An atom with one or two valence electrons more than a closed shell The number of valence electrons of an element can be determined Groups 3-12 (transition metals), 2* (The 4s shell is complete and cannot hold any more electrons)  in explaining the molecular structure of many organic compounds.

Explanation:

How many moles of aluminum oxide (Al2O3) will be produced if 1.5 mole of aluminum (AI) reacts with oxygen? Input a numerical answer only. 4Al + 302 ---> 2Al2O3

Answers

Explanation:

The number of moles of Al2O3 formed is approximately 4.25 moles. Second find the limiting reactant. Since O2 has less value that is 2.126 than Al that is 2.287, O2 is the limiting reactant in this reaction.

0.41g of neon is held in a 200. mL container at 11 °C. Calculate the pressure in atm.

Answers

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

how many molecules in 400g of acetic acid

Answers

Answer:chemical formula of acetic acid is  or

so, molecular mass of acetic acid = 2 × atomic mass of C + 4 × atomic mass of H + 2 × atomic mass of O

= 2 × 12 + 4 × 1 + 2 × 16

= 24 + 4 + 32

= 60g/mol

given mass of acetic acid = 22g

so, no of moles of acetic acid = given mass/molecular mass

= 22/60 ≈ 0.367

so, number of moles of acetic acid is 0.367mol

number of molecules in 0.367 mol of acetic acid = 6.022 × 10²³ × 0.367

= 2.21 × 10²³

Explanation:

What does the cell theory state? Answer F All organisms are composed of a nucleus G All prokaryotes are composed of multiple cells H All prokaryotes are single celled organisms J All organisms are composed of cells

Answers

Answer:

(J) All organisms are composed of cells

Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of 15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example

Answers

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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Calculate the volume of solvent present in a 55.5%
by volume of 10.5 mL alcohol solution.

Answers

Answer:

I dont know

Explanation:

good luck

is benzene saturated or unsaturated?​

Answers

Answer:

Benzene shows that it is actually unsaturated because it adds hydrogen or chlorine, although only when allowed to react under very vigorous conditions (higher temperature or pressure) compared to those required for alkenes and alkynes.

Explanation:

Which type of molecule is shown below?

O A. Alkene
O B. Cyclic alkane
O C. Alkane
O D. Alkyne

Answers

Answer:

A. Alkene

Explanation:

Alkenes are a class of hydrocarbons characterized by the possession of a carbon to carbon double bond (=) in their structure. This means that C=C is the functional group of alkenes. Alkenes have the general formula; CnH2n.

Based on the structure in the attached image, the structure can be identified to be an ALKENE because it possess a C=C functional group. Specifically, the IUPAC name of the structure is 1,2- dimethyl ethene.

1. In a chemical reaction
a. the mass of the reactants equals the mass of the products.
b. the mass of the products is greater than the mass of reactants.
c.the number of atoms in the reactants and products must change.
d. energy as heat must be added to the reactants.

Answers

Answer:

A

Explanation:

Law of conservation of matter

In the energy profile of a reaction, the species that exists at the maximum on the curve is called the ________. In the energy profile of a reaction, the species that exists at the maximum on the curve is called the ________. atomic state activated complex activation energy enthalpy of reaction product

Answers

Answer:

The activated complex

Explanation:

The activated complex are the species that exists maximum in every energy profile of a reaction.

Activated complex is nothing but an intermediate state of reactants formed during its conversion from a reactant to product state in coarse of reaction.

The activated complex is formed at the maximum energy level in the reaction path. And this difference between energy of the activated complex and the energy of the reactants is only known as activation energy

An experimental measurement was taken of 10.4mL and the actual measurement was 9.7mL. What is the percent error?

Answers

Answer:

13%

Explanation:

A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

Answers

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = [tex]5.48\times 10^{-7} \ M[/tex]

M2 = 484 nM

or,

      = [tex]4.84\times 10^{-7} \ M[/tex]  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ [tex]M1\times V1=M2\times V2[/tex]

or,

⇒            [tex]V2=\frac{M1\times V1}{M2}[/tex]

By substituting the values, we get

                    [tex]=\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}[/tex]

                    [tex]=\frac{339.212}{4.84}[/tex]

                    [tex]=70.08 \ mL[/tex]

14. The illustration below shows two atoms of a fictitious element (M) forming a diatomic
molecule. What type of bonding occurs between these two atoms?
A. Covalent
B. Hydrogen
C. lonic
D. Polar

Answers

The anwers will be c

Covalent bonding involving covalent bonds is depicted between these two atoms as they form diatomic molecule.

What is a covalent bond?

Covalent bond is defined as a type of bond which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.

Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.

Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.

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A common asteroid is in the first photograph. Haley's Comet is in the second photograph. What can be inferred about comets and asteroids? Answer A Both have orbits around the Earth that are ellipses B Both are miniature planets because they orbit the Sun C Both could be planetary fragments from the beginnings of solar system formation D Both are made of rock, ice, and solar dust from the beginning of the solar system

Answers

Answer:

D Both are made of rock ,ice and solar dust from the beginning of the solar system

Answer:

The answer is D

Explanation:

given mass of nitrogen is 0.12 dm^3 at 60°C and 1.01*10^5 Nm^2. Find its pressure at the same temperature if its volume is changed to 0.24 dm^3​

Answers

50500Nm^2 or 5.05Nm^2

Explanation:

so bring out the parameters

p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?

general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake

Question 1
What term is used to describe atoms of the same element that have different masses?
O A) radioactive
B) constituents
C) telomers
OD) isotopes
E) None of the above

Answers

Answer:

Isotopes

Explanation:

iso means the same like in triangles (isosceles) so the atoms are the same element but different in mass. Since the isotopes have the same number of protons and electrons the isotopes have much the same chemical behavior. Since the isotopes have different numbers of neutrons the nuclear behavior differs.

What are the missing coefficients for C3H8 + o2 = Co2 +H2O

Answers

Answer: C3H8 + 5O2 = 3Co2 +4H2O

Explanation: Equations must be balanced

You must have the same amount of C

H and O on both sides of the equation

write half-reactions that show how H2O2 can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing.

Answers

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

How many grams of oxygen are required to burn 3.01 x 10^23 propane molecules?

Answers

That’s some hard stuff what grade are you in im going to find the answer really fast hold on

A balloon is inflated to a volume of 8.0 L on a day when the atmospheric pressure is 1.013 bar . The next day, a storm front arrives, and the atmospheric pressure drops to 0.968 bar . Assuming the temperature remains constant, what is the new volume of the balloon, in liters

Answers

Answer:

[tex]V_2=8.4L[/tex]

Explanation:

Hello there!

In this case, according to the definition of the Boyle's law, which describes de pressure-volume behavior as an inversely proportional relationship, it is possible for us to write:

[tex]P_1V_1=P_2V_2[/tex]

Thus, since we are given the initial pressure and temperature, and the final pressure, we are able to calculate the final volume as shown below:

[tex]baV_2=\frac{P_1V_1}{P_2}\\\\V_2=\frac{8.0L*1.013bar}{ 0.968bar}\\\\V_2=8.4L[/tex]

Regards!

A balloon is filled with 3.50 L of water at 24.0°C. What is the volume of the water at 307 K?

Answers

Answer:

what is the volume of the water at 307 k?

Which organic compound listed below does not have a carbonyl group ?

A. Aldehyde
B. Ketone
C. Ethers
D. Protein
E. Ester
F. Amides

Answers

I believe the answer is F

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.

Answers

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

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