Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 65
and DC = 6, what is the length of BC in simplest radical form?
Answer: =
B
65
6
C
Submit Answer

Answer:

v = 8.6

Step-by-step explanation:

The first step to solve for x in the equation v + 1.26 = 9.86​  is to isolate the variable (v) on one side of the equation.

Looking at the equation, this can be done by subtracting 1.26 from both sides of the equation.

Shown below:

v + 1.26 - 1.26 = 9.86​ - 1.26      

v  = 8.6

As a result, v = 8.6

xKavinsky

Answer:

Step-by-step explanation:

[tex]\mathrm{v + 1.26 = 9.86}[/tex]

Subtract -1.26 to both sides:-

[tex]\mathrm{v + 1.26-1.26 = 9.86-1.26}[/tex]

Simplify :-

[tex]\mathrm{v=8.6}[/tex]

_____________________

Hope this helps!

The recursive formula is 5/6

You should know that a recursive formula is an equation used to describe a sequence in which terms are defined using one or more previous terms along with an initial condition.

The given parameters are

aₓ = a(n-1) + 2

Where aₓ = 2aₓ₋1

= 2*5(₃₋₁) = 5(3-1) + 2

= 10₂ = 10 + 2

Taking the log of both sides

Log₂10 - Log12 = 0

Dividing by 10 we have

10/12 = 5/6

therefore the recursive formula is  5/6

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Answer:

Step-by-step explanation:

It is

4

√

12

=

4

√

3

⋅

4

=

4

⋅

2

⋅

√

3

=

8

√

3

The equation of the line in point-slope form that passes through (1, -7) and has a slope of -2/3 is y + 7 = -2/3(x-1). Correct option is B.

The point-slope form of a linear equation is given by:

y - y₁ = m(x - x₁)

where m is the slope of the line and (x₁, y₁) is a point on the line.

We are given a point (1, -7) that the line passes through and a slope of -2/3. Therefore, we can substitute these values into the point-slope form equation to obtain:

y - (-7) = (-2/3)(x - 1)

Simplifying this equation, we get:

y + 7 = (-2/3)x + (2/3)

Taking 2/3 common from right sides, we get:

y + 7 = -2/3(x-1)

Therefore, Correct option is B.

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The formula for the variable r is r = √A/π

The subject of formula can be defined as the variable that is allowed to alone in an equation.

The variables is made to be written on one end of the equality sign.

It is also described as the variable that is worked out in an equation.

From the information given, we have that;

the formula for the area of the circular pool is;

A = πr²

Such that;

We then have;

r = √A/π

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Answer:

Step-by-step explanation:

picture?

a) An equation representing Christina's investment's value, y, after x years is y = 10,000(1.05)^x.

b) Using the above equation, Christina's investment will be worth a future value of $26,532.98 after 20 years.

The principal = $10,000

Annual compound interest rate = 5%

The investment period = 20 years

Let the value of the investment after x years = y

Let the number of investment periods = x

y = 10,000(1.05)^20

= $26,532.98

Online finance calculator, the future value is determined as follows:

N (# of periods) = 20 years

I/Y (Interest per year) = 5%

PV (Present Value) = $10,000

PMT (Periodic Payment) = $0

Results:

FV = $26,532.98

Total Interest = $16,532.98

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The investment compounds at a 5% interest rate yearly.

The value of the expression 5z - 3z, when z is equal to 3, is 6.

Given the expression in the question:

Evaluating an expression simply means substituting the given value of a variable into the expression and simplifying the result.

Given the expression 5z - 3z, we are given the value of z as 3.

Hence, we substitute z with 3 in the expression:

5z - 3z

Plug in z = 3

5(3) - 3(3)

Simplifying further using the order of operations (multiplication before subtraction), we get:

15 - 9

= 6

Therefore, the value of the expression is 6.

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The quadratic regression equation that best fits the data-set is given as follows:

y = 32.86x² - 379.14x + 1229.14.

To find the quadratic regression equation, we need to insert the points (x,y) into a quadratic regression calculator.

Considering the table in this problem, the points on the data-set are given as follows:

(3, 330), (4, 276), (5, 263), (6, 86), (7, 174), (8, 198), (9, 553).

Inserting these points into a calculator, the quadratic regression equation is given as follows:

y = 32.86x² - 379.14x + 1229.14.

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The experimental design that will not result in a randomized sample is C.Using all students from sections 1 and 2 of a statistics course to constitute two samples

Random sampling  can be regarded as the part of the sampling technique whereby each of the sample that is been involved in the population will have an equal probability of being chosen.

It should be noted that in this , the sample is chosen randomly  which is  unbiased representation , and in the third option, we can see that all the population was using.

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There are numerous concepts in algebra 2 that can be applied in real life scenarios. Some of which are linear equations and quadratic functions. The linear equation, for instance, helps to estimate that the cost i.e. of gas for a trip.

Linear equations can be used in real-life for calculating distances, rates and costs. For instance, during plan for a road trip, it can be used to estimate distance, time it takes to travel, estimated cost of gas etc.

An illustration is when one is planning a road trip from New York to Los Angeles. We can estimate that the distance between the two cities is 2,800 miles and car has average fuel efficiency of 25 miles per gallon.

If gas costs $3.50 per gallon, We can use the linear equation to get the cost of trip which is:

= Distance / Miles per gallon * Price per gallon

= 2,800 / 25 * 3.50

= $392.

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$48.07 would be the monthly payments on the loan.

We must first determine the total amount of interest charged over the course of the 4-year term in order to determine the monthly payments on a basic interest add-on loan.

The formula for simple interest is:

I = P * r * t

where I is the interest charged, P is the principal (the amount borrowed), r is the annual interest rate as a decimal, and t is the time period in years.

In this case, P = $1,426.25, r = 0.1545 (15.45% expressed as a decimal), and t = 4 years. So, the total amount of interest charged is:

I = $1,426.25 * 0.1545 * 4

I = $881.25

Adding the interest to the principal, we get the total amount paid over the 4-year term:

Total amount = $1,426.25 + $881.25

Total amount = $2,307.50

We must divide the sum by the number of months left in the loan term in order to get the monthly installments. As the loan period is 4 years long, there are 48 months:

Monthly payment = Total amount / Number of months

Monthly payment = $2,307.50 / 48

Monthly payment = $48.07

Therefore, the monthly payments on the loan would be $48.07.

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Answer:g=g(9)

Step-by-step explanation:

The solution to the equation as it is given in (8) above is -21.

According to the subtraction property of equality, If you subtract the same number from both sides of an equation, the equation remains true.

Also by the multiplication  property of equality,  If you multiply both sides of an equation by the same number (except zero), the equation remains true.  These can be used to solve the question in (7) above

Given;

280 = -8(-14 + x)

280 = 112 - 8x

280 - 112 = -8x

x = -21

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The wingspan (in feet) of the actual airplane is equal to 87.5 feet.

A property of equality which you would use to solve the equation -15 = x/3 + 18 is: D. Subtraction property of equality and multiplication of equality.

The solution of the equation 280 = -8(-14 + x) is: B. x = -21.

Based on the scale model, we can logically deduce that the airplane has a length of 12.2 inches and a wingspan of 12.5 inches. This ultimately implies that, we would convert from inches to feet as follows;

1 inch = 1/12 feet

12.2 inches = 12.2 × 1/12 = 12.2/12 feet.

Therefore, the scaled factor is given by;

Scale factor = (85.4 × 12/12.2)

For the actual length of the wingspan with a scaled length of 12.5 inches, we have:

12.5 inches = 12.5/12 feet

Actual length of wingspan = 12.5/12 × (85.4 × 12/12.2)

Actual length of wingspan = 87.5 feet.

-15 = x/3 + 18

x/3 = -15 - 18 ⇒ (Subtraction property of equality)

x/3 = -33

x = 3(-33) ⇒ (Multiplication property of equality)

x = -99

280 = -8(-14 + x)

280 = 112 - 8x

8x = 112 - 280

x = -168/8

x = -21

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Answer:

10miles I think

Step-by-step explanation:

The required distance between, Nate's house and the restaurant is 7.5 miles.

From the graph,

Consider point C on the graph, which is 6  and 8 units apart from A and B respectively.

The distance between, Nate's house and the restaurant is given as,
AB = √[AC² + BC²]
AB = √[6² + 8²]
AB = 10 units

Now 1 unit = 3/4 miles
AB = 10 * 3/4
AB = 7.5 miles

Thus, the required distance between, Nate's house and the restaurant is 7.5 miles.

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The checkbook balance is $5703.25.

To find the checkbook balance, we need to start with the original balance and then subtract the amounts of the checks written and add the amount of the deposit.

Original balance: $7349.44

Checks written: $1349.67 + $344.12 = $1693.79

Deposit: $956.60

To find the checkbook balance, we can subtract the total amount of the checks written from the original balance and then add the deposit:

Checkbook balance = Original balance - Checks written + Deposit

Checkbook balance = $7349.44 - $1693.79 + $956.60

Checkbook balance = $5703.25

Therefore, the checkbook balance after store manager deposited $956.60 is $5703.25.

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The total cost of SE Company's advertising campaign will be $14,436.23.

The first step is to calculate the cost of the half-page ad for one week:

65.5 column inches × $24.55 per column inch = $1604.025

Since the ad will run for nine weeks, the total cost of the campaign is:

$1604.025 × 9 = $14,436.225

Therefore, the total cost of SE Company's advertising campaign will be $14,436.23.

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Answer:

A) 2,500 square yards

Step-by-step explanation:

Hope this helps! Pls give brainliest!

The correct box plot is

A box plot uses a number line from 7 to 46 with tick marks every one unit. The box extends from 22.5 to 33.5 on the number line. A line in the box is at 30. The lines outside the box end at 10 and 40.

We have the data:

10, 14, 20, 25, 29, 30, 30, 31, 32, 35, 39, 40 .

So, First Quartile(Q1) = ((n + 1)/4)th Term.

= (12+1)/4

= 13/4

= 3.25 th term

=  (20+25)/2

= 22.5

and, Second Quartile or median (Q2) = ((n + 1)/2)th Term.

Q₂ = ((12 + 1)/2)th term

   = 6.5th term

   = 30

and, Third Quartile(Q3) = (3(n + 1)/4)th Term.

Q₃ =3 (3.25)

    = 9.75

   = 33.5

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Answer:

We can use the transformations of the graph of y=1/x to graph the rational function r(x) = 2x-9/x-4.

First, we will shift the graph of y=1/x to the right by 4 units to get the graph of y=1/(x-4). Next, we will stretch the graph vertically by a factor of 2 to get the graph of y=2/(x-4). Finally, we will shift the graph down by 9 units to get the graph of r(x) = 2x-9/x-4.

The domain of r(x) is all real numbers except x=4, since that would make the denominator zero. The range of r(x) is also all real numbers except y=2, since that would make the numerator zero.

Here is a rough sketch of the graph of r(x), using the transformations:

| ----------

| / \

| / \

| -- --

| | |

-- -- -- -- -- -- -- -- -- -- -

| | |

| | |

| | |

| | |

| | |

| | |

x=4 y=2

Note: This graph is not to scale and is intended to show the general shape of the graph.

The requried probability that Luc gets both questions correct is 1/16 or approximately 0.0625.

The probability of guessing a single question correctly is 1/4, since there are 4 answer choices and only 1 is correct. Since the questions are independent, the probability of guessing both questions correctly is the product of the probability of guessing each question correctly.

Therefore, the probability that Luc gets both questions correct is:

P(both correct) = P(first correct) * P(second correct)

P(both correct) = (1/4) * (1/4)

P(both correct) = 1/16

Thus, the probability that Luc gets both questions correct is 1/16 or approximately 0.0625.

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In the words that your describing it, I supposed we are talking about the pythagorean theorem

What is the formula for the theorem?

a^2+b^2= C^2

A being the height

B being the Bottom

C being the slant or hypotenuse

How to Solve?

Well supposed 9 is a and 6 is b

[tex]9^{2}[/tex]+[tex]6^{2}[/tex]=[tex]c^{2}[/tex]

9 squared is 81 and 6 squared is 36

81+36= 117

So, 117=[tex]c^{2}[/tex]

Which means [tex]\sqrt{117}[/tex] is the answer or 10.8

Hope this helped!

The total at 0 id 100 hours and rate if increasing is 50 per hour.

From the given graph;

Let x represents the total hours

And y represents total pay

Then,

(a) When x = 0

Then from graph we have y = 100

So total pay is 100 dollars.

(b) When x = 1 then y = 150

Therefore,

Rate of increasing = (150-100)/(1-0) = 50

So it is increasing 50 per hour.

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The student is correct because we can factorize x² - x - 56 to get (x - 8)(x + 7).

How to Factorize an Expression?

In order to determine if -56 is the integer that can replace the box in the expression, we can try to factorize the expression and see if it works.

Factorize x² - x - 56 using the sum-product pattern:

x² - x - 56

Take out the common factors from each pair:

(x² + 7x) - (8x - 56)

x(x + 7) -8(x + 7)

Rewrite in factored form:

(x - 8)(x + 7)

Thus, this shows that the student is correct.

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Answer: 4:42

Step-by-step explanation:

4:30 + 0:12 = 4:42

ΔPQR and ΔMNR are similar  and if  MN = 15 ft then the side length of QP is 52.

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

ΔPQR and ΔMNR are similar are similar because both have the corresponding angles are congruent and the corresponding sides are in proportion .

If MN=15 feet we have to find QP

As sides are proportional

45/13=QP/15

Apply cross multiplication

45×15=13QP

675=13QP

Divide both sides by 13

QP=52

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The statements of description are true about function h as:

The horizontally compressed by a factor of 1/2.

The vertically shifted up 4 units.

The period of function h is half the period of the parent function.

The given function h(x) = -3cos(2x-π)+4 and compare it with the parent cosine function f(x) = cos(x).

First, let's look at the expression: -3cos(2x-π).

The factor of -3 represents a vertical compression by a factor of 3 from the parent function, which means the amplitude is three times smaller.

The argument 2x-π represents a horizontal compression by a factor of 2 and a phase shift to the right by π/2 units.

The period of the cosine function is 2π, but the period of -3cos(2x-pi) is π. Therefore, the period of h(x) = -3cos(2x-π)+4 is half that of the parent function.

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