Answer:
Hey there!
Sine is equal to opposite/hypotenuse
Tangent is equal to opposite/adjacent
opposite=a
hypotenuse=b
adjacent=c
Thus, tangent x= a/c.
Hope this helps :)
Answer:
tan x = a/sqrt(b^2 - a^2)
Step-by-step explanation:
sin x = a/b = opp/hyp
tan x = opp/adj
adj^2 + opp^2 = hyp^2
adj^2 + a^2 = b^2
adj = sqrt(b^2 - a^2)
tan x = a/sqrt(b^2 - a^2)
In triangle $ABC$, $AB = BC = 25$ and $AC = 40$. What is $\sin \angle ACB$?
Answer:
Sine angle of <ACB = 38.68°
Step-by-step explanation:
Hello,
To solve this problem, we need a good representation of the sides and the angle.
See attached document for better illustration.
Assuming it's a right angled triangle,
AC = hypothenus
AB = opposite
BC = adjacent
AC = 40
BC = 25
AB = 25
From trigonometric ratios
Sinθ = opposite/ hypothenus
Sinθ = AB / AC
Sinθ = 25 / 40
Sinθ = 0.625
θ = sin⁻¹0.625
θ = 38.68°
Sine angle of <ACB = 38.68°
Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair at which the maximum value occurs.
Incomplete question. However, let's assume this are feasible regions to consider:
Points:
- (0, 100)
- (0, 125)
- (0, 325)
- (1, 200)
Answer:
Maximum value occurs at 325 at the point (0, 325)
Step-by-step explanation:
Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.
- For point (0, 100): P= 2(0) + 1.5 (100) =150
- For point (0, 125): P= 2(0) + 1.5 (125) =187.5
For point (0, 325): P= 2(0) + 1.5 (325) = 487.5
For point (1, 200): P= 2(1) + 1.5 (200) = 302
Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.
What number :Increased by 130% is 69 i rlly need help!!!
Answer:
53.076923
Step-by-step explanation:
130% as a decimal is 1.3
Divide 69 by 1.3:
69 /1.3 = 53.076923
Answer:
30
Step-by-step explanation:
The unknown number is x.
Start with x.
To increase x by 130%, you need to add 130%of x to x.
x + 130% of x
The sum equals 69.
x + 130% of x = 69
x + 130% * x = 69
1x + 1.3x = 69
2.3x = 69
x = 30
Answer: The number is 30.
sin theta = x , sec theta =y . find cot theta pls answer fast i need to verify my answer . you can directly write the answer no issues
Answer:
[tex]\huge\boxed{\cot\theta=\dfrac{1}{xy}}[/tex]
Step-by-step explanation:
[tex]\bold{METHOD\ 1}[/tex]
[tex]\sin\theta=x\\\\\sec\theta=y\\\\\cot\theta=?\\\\\text{We know:}\\\\\sec x=\dfrac{1}{\cos x};\ \cot x=\dfrac{\cos x}{\sin x}\\\\\sec\theta=y\to\dfrac{1}{\cos \theta}=y\to\dfrac{\cos\theta}{1}=\dfrac{1}{y}\to\cos\theta=\dfrac{1}{y}\\\\\cot \theta=\dfrac{\frac{1}{y}}{x}=\dfrac{1}{xy}[/tex]
[tex]\bold{METHOD\ 2}[/tex]
[tex]\text{We know}\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}=\dfrac{1}{\tan x}\\\\\sec x=\dfrac{1}{\cos x}\\\\\text{therefore}\\\\(sin x)(\sec x)=(\sin x)\left(\dfrac{1}{\cos x}\right)=\dfrac{\sin x}{\cos x}=\tan x\\\\\dfrac{1}{(\sin x)(\sec x)}=\dfrac{1}{\tan x}=\cot x[/tex]
[tex]\\\sin \theta=x;\ \sec\theta=y\\\\\text{substitute}\\\\\cot\theta=\dfrac{1}{xy}[/tex]
100 points timed Which is the correct way to model the equation 5 x + 6 = 4 x + (negative 3) using algebra tiles? 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side 6 positive x-tiles and 5 positive unit tiles on the left side; 3 negative x-tiles and 4 positive unit tiles on the right side 5 positive x-tiles and 6 negative unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 positive unit tiles on the right side
Answer: A
Step-by-step explanation:
The answer is A. It accurately describes the equation shown. Negative values are represented by negative tiles and positive values are represented by positive tiles.
Hope it helps <3
How to do this question plz
Answer: x=10
Step-by-step explanation:
We can use the pythagorean theorem here: a^2 + b^2 = c^2, where c is the hypotenuse.
The values for c and one of the legs are already given, so we can plug them into the equation to find the length of the other leg x:
(square root of 200)^2 + x^2 = (square root of 300)^2
200 + x^2 = 300
x^2 = 100
x = 10
Answer:
Step-by-step explanation
square root 300 square - square root 200 square = x square
300 - 200 = x square
100 = x square
square root 100 = x
10= x
Algebra 2 help needed!
Answer:
(g + f) (x) = (2^x + x – 3)^1/2
Step-by-step explanation:
The following data were obtained from the question:
f(x) = 2^x/2
g(x) = √(x – 3)
(g + f) (x) =..?
(g + f) (x) can be obtained as follow:
(g + f) (x) = √(x – 3) + 2^x/2
(g + f) (x) = (x – 3)^1/2 + 2^x/2
(g + f) (x) = (x – 3)^1/2 + (2^x)^1/2
(g + f) (x) = (x – 3 + 2^x)^1/2
Rearrange
(g + f) (x) = (2^x + x – 3)^1/2
NEED HELP ASAP!!!! RIGHT NOW
Answer:
120 degrees
Step-by-step explanation:
Answer:
120
Step-by-step explanation:
Add all the number then subtract it with 360.
Consider the two functions. Which statement is true?
A)Function 1 has a greater rate of change by 13/4
B)Function 2 has a greater rate of change by 13/4
C)Function 1 has a greater rate of change by 13/2
D)Function 2 has a greater rate of change by 13/2
Answer: Function 2 has a greater rate of change by 13/4
Step-by-step explanation:
We must work with linear equations, remember that the general shape is:
y = a*x + b
where a is the slope and b is the y-intercept.
Ok, first we want to find the rate of change (or the slope) of the graphed line:
We know that for a line that passes through the points (x1, y1) and (x2, y2)
The slope is:
a = (y2 - y1)/(x2 - x1)
Then for the graphed function, we can see that it passes through the points:
(0, -2) and (4, 0)
Then the slope is:
a = (0 -(-2))/(4 - 0) = 2/4 = 1/2
Now, the slope of the second line is 15/4.
Let's calculate the difference between the slopes:
15/4 - 1/2 = 15/4 - 2/4 = 13/4
(notice that we are calculating slope2 - slope1)
Then the correct option is:
Function 2 has a greater rate of change by 13/4
Answer:
B) Function 2 has a greater rate of change by 13/4
Step-by-step explanation:
Is (0, 3) a solution to the following system?
Y=-x+3
Y=2x-3
A No, because it does not check in either equation.
B. No, because it does not check in the first equation.
C. No, because it does not check in the second equation.
D. Yes, because it checks in both equations.
Solve each equation with (0, 3)
y = -x + 3
3 = -0 + 3
y = 3 (correct since y = 3 in (0, 3))
y = 2x - 3
3 = 2(0) - 3
3 = 0 - 3
3 = -3 (incorrect since it isn't equal)
So... No, because it does not check in the second equation.
Best of Luck!
Can someone please help me with this and show work
Answer:
29/6-16/2549/30Rationalize(1.63333333333)1*(19/30)please solve this using quadratic formula :")
Answer:
Step-by-step explanation:
The given equation is expressed as
(x + 1)/(x - 1) - (x - 1)/(x + 1) = 7/12
Simplifying the right hand side of the equation, it becomes
[(x + 1)(x + 1) - (x - 1)(x - 1)]/(x - 1)(x + 1)
x² + x + x + 1 - (x² - 2x + 1)/(x - 1)(x + 1)
(x² + 2x + 1 - x² + 2x - 1)/(x - 1)(x + 1)
4x/(x - 1)(x + 1)
Therefore,
4x/(x - 1)(x + 1) = 7/12
Cross multiplying, it becomes
4x × 12 = 7(x - 1)(x + 1)
48x = 7(x² + x - x - 1)
48x = 7x² - 7
7x² - 48x - 7 = 0
Applying the quadratic formula,
x = - b ± √(b² - 4ac)]/2a
from our equation,
b = - 48
a = 7
c = - 7
Therefore
x = [- - 48 ± √(- 48² - 4(7 × - 7)]/2 × 7)
x = [48 ± √(2304 + 196]/14
x = (48 ± √2500)/14
x = (48 ± 50)/14
x = (48 + 50)/14 or x = (48 - 50)/14
x = 98/14 or x = - 2/14
x = 7 or x = - 1/7
Answer: The given equation is expressed as (x + 1)/(x - 1) - (x - 1)/(x + 1) = 7/12Simplifying the right hand side of the equation, it becomes[(x + 1)(x + 1) - (x - 1)(x - 1)]/(x - 1)(x + 1)x² + x + x + 1 - (x² - 2x + 1)/(x - 1)(x + 1)(x² + 2x + 1 - x² + 2x - 1)/(x - 1)(x + 1)4x/(x - 1)(x + 1)Therefore, 4x/(x - 1)(x + 1) = 7/12Cross multiplying, it becomes4x × 12 = 7(x - 1)(x + 1)48x = 7(x² + x - x - 1)48x = 7x² - 77x² - 48x - 7 = 0Applying the quadratic formula,x = - b ± √(b² - 4ac)]/2a from our equation, b = - 48a = 7c = - 7Thereforex = [- - 48 ± √(- 48² - 4(7 × - 7)]/2 × 7)x = [48 ± √(2304 + 196]/14x = (48 ± √2500)/14x = (48 ± 50)/14x = (48 + 50)/14 or x = (48 - 50)/14x = 98/14 or x = - 2/14x = 7 or x = - 1/7
Step-by-step explanation:
Can anyone please help me with this?
Answer: 4
Step-by-step explanation:
Because there are two equal angles, this is an isoceles triangle. Line JP and HP are equal. To find the variable, write the equation which would be 3x-6=x+2. X is 4.
hope this helped:)
Answer: 4 AKA D
Step-by-step explanation:
Well to start off, we must first establish that line JP and line HP are equal because of the red ticks in the corner. So once we figured that out, then 3x-6 = x+2
»Next we add 6 to both side to make 3x = x+8
»Then we subtract x from both sides to equal 2x = 8
»Then we divide both sides by 2 which equals x=4
»So the final answer would be D. 4
Hope i helped
-lvr
Please help me with this problem! If anybody answers first in this, i will give brainliest to you! Be the first one to answer this then i will give out a brainliest award to you!
Are you sure your that person?
Answer:
32 remainder 2
Step-by-step explanation:
To divide 162 by 5, we simply do the following:
5 goes into 16 => 3
Multiply 5 by 3 => 3 × 5 = 15
Subtract 15 from 16 => 16 – 15 = 1
Put the 1 before 2 => 12
5 goes into 12 => 2
Multiply 5 by 2 => 5 × 2 = 10
Subtract 10 from 12 => 12 – 10 => 2
In summary,
162 divided by 5 => 32 remainder 2
Please see attached photo for further details.
Use the distributive property to remove the parentheses -5(2x-3w-6)
Answer:
15w - 10x + 30.
Step-by-step explanation:
-5(2x - 3w - 6)
= (-5 * 2x) + (-5 * -3w) + (-5 * -6)
= -10x + 15w + 30
= 15w - 10x + 30.
Hope this helps!
Answer:
[tex] - 10x + 15w + 30[/tex]Step-by-step explanation:
[tex] - 5(2x - 3w - 6)[/tex]
Multiply each term in the parentheses by -5
[tex] - 5 \times 2x - 5 \times ( - 3w) - 5 \times ( - 6)[/tex]
Calculate the product
[tex] - 10x - 5 \times ( - 3x) - 5 \times ( - 6)[/tex]
Multiplying two negatives equals a positive [tex]( - ) \times ( - ) = ( + )[/tex]
[tex] - 10x + 5 \times 3w - 5 \times ( - 6)[/tex]
Calculate the product
[tex] - 10x + 15w - 5 \times ( - 6)[/tex]
Multiply the numbers
[tex] - 10x + 15w + 30[/tex]
Hope this helps..
Best regards!!
Bella is going back to school shopping and her favorite store is having a sale. She sees there are 4 packages of 15 tops for $18 and 5 packages of 10 tops for $16 which is the better deal? How do you know
Answer:
The 4 packages of 15 tops for $18 is a better deal
Step-by-step explanation:
We can see which set of tops have the lowest unit price.
4 packages of 15 tops for $18:
4*15=60
There is a total of 60 tops for $18, which means each top costs 18/60 dollars, or $0.30.
5 packages of 10 tops for $16
5*10=50
There is a total of 50 tops for $16, which means that each top costs 16/50 dollars, or $0.32.
0.32>0.3
The 4 packages of 15 tops for $18 is a better deal :)
Have a great day
For a chemical reaction to occur, at least one-third of the solution must be an acid. If there are five liters of acid, in interval form, how much solution is present?
A. [5,8)
B. (3/5,5]
C. (5/3,5]
D. [5,15]
Answer:
Amount of solution = 15 liter
Step-by-step explanation:
Given:
One third of solution is acid
Amount of acid = 5 Liter
Find:
Amount of solution
Computation:
Amount of solution = Amount of acid (1 / One third of solution is acid)
Amount of solution = Amount of acid (3)
Amount of solution = (5)(3)
Amount of solution = 15 liter
Please answer this in two minutes
Answer:
u = [tex]\sqrt{6}[/tex].
Step-by-step explanation:
This is a 45-45-90 triangle.
That means that there are two side lengths with lengths of x, and a hypotenuse with a length of xsqrt(2). We can then set up a proportion.
[tex]\frac{1}{\sqrt{3} } =\frac{\sqrt{2} }{u}[/tex]
1 * u = [tex]\sqrt{3} * \sqrt{2}[/tex]
u = [tex]\sqrt{6}[/tex].
Hope this helps!
The Department of Education would like to test the hypothesis that the average debt load of graduating students with a bachelor's degree is equal to $17,600. A random sample of 28 students had an average debt load of $18,800. It is believed that the population standard deviation for student debt load is $4800. The α is set to 0.05. The confidence interval for this hypothesis test would be ________.
Answer:
A 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$17,022.05, $20,577.94].
Step-by-step explanation:
We are given that a random sample of 28 students had an average debt load of $18,800. It is believed that the population standard deviation for student debt load is $4800. The α is set to 0.05.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample average debt load = $18,800
[tex]\sigma[/tex] = population standard deviation = $4,800
n = sample of students = 28
[tex]\mu[/tex] = population average debt load
Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 5% level of
significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]
= [ [tex]\$18,800-1.96 \times {\frac{\$4,800}{\sqrt{28} } }[/tex] , [tex]\$18,800+1.96 \times {\frac{\$4,800}{\sqrt{28} } }[/tex] ]
= [$17,022.05, $20,577.94]
Therefore, a 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$17,022.05, $20,577.94].
There were some pieces of candy in a bowl. Shirley took half of them. Then Rose took half of the pieces left in the bowl. After that, Susan took half of the remaining pieces of candy. In the end there were 8 pieces of candy left in the bowl. How many candies were there in the bowl at the beginning?
Answer:
Number of pieces of candy in the bowl=64
Step-by-step explanation:
Let
x=number of pieces of candy in a bowl
Shirley took=1/2 of x
=1/2x
Remaining
x-1/2x
= 2x-x/2
=1/2x
Rose took half of the pieces left in the bowl=1/2 of 1/2x
=1/2*1/2x
=1/4x
Remaining
1/2x-1/4x
=2x-x/4
=1/4x
Susan took 1/2 of the remaining pieces of candy=1/2 of 1/4x
=1/2*1/4x
=1/8x
Remaining 8
1/8x=8
x=8÷1/8
=8*8/1
=64
x=64
Name an inscribed angle
Answer:
BHF
Step-by-step explanation:
Definition of inscribed
Please answer this in two minutes
Answer:
R = 21.8° to the nearest tenth
Step-by-step explanation:
To find Angle R we use tan
tan ∅ = opposite / adjacent
From the question
The opposite is 2
The adjacent is 5
So we have
tan R = 2/5
R = tan-¹ 2/5
R = 21.8° to the nearest tenthHope this helps you
1. Which financial statement reports the amount of cash paid for acquisitions of property, plant, and equipment? In which section (operating, investing, or financing) of this statement is the information reported? 2. Indicate the amount of cash paid for acquisitions of property and equipment in the year ended September 30, 2017.
Answer:
1. Cash flow statements; the investing section
Step-by-step explanation:
The cash flow statements is a useful document that shows where the company receives funds and uses it. Thus, it shows both incoming and outgoing cash flow.
The investment section of the cash flow statement is where all the amount of cash paid for acquisitions of property and equipment is imputed. Usually the transactions are written as capital expenditure.
Find: ∠a ∠b ∠c Plaese help
Answer:
i believe a=105, b=29, and c=45
John wants to nail a thumbtack on his circular board, pictured below. If the thumbtack is equally likely to be placed anywhere on the board, what is the probability that the thumbtack will be placed on the inner circle? Use 3.14 for , and round your answer to the nearest whole percent. A. 51% B. 55% C. 57% D. 60%
Answer:
[tex]Probability = 51\%[/tex]
Step-by-step explanation:
Given
Radius of inner circle = 5ft
Radius of outer circle = 7ft
Required
Determine the probability that the thumbtack will be placed on the inner circle
We start by calculating the area of both circles;
Inner Circle
[tex]Area = \pi r^2[/tex]
[tex]Area = 3.14 * 5^2[/tex]
[tex]Area = 3.14 * 25[/tex]
[tex]Area = 78.5[/tex]
Outer Circle
[tex]Area = \pi R^2[/tex]
[tex]Area = 3.14 * 7^2[/tex]
[tex]Area = 3.14 * 49[/tex]
[tex]Area = 153.86[/tex]
At this point, the probability can be calculated;
The probability = Area of Inner Circle / Area of Outer Circle
[tex]Probability = \frac{78.5}{153.86}[/tex]
[tex]Probability = 0.51020408163[/tex]
Convert to percentage
[tex]Probability = 0.51020408163 * 100\%[/tex]
[tex]Probability = 51.020408163\%[/tex]
Approximate
[tex]Probability = 51\%[/tex]
A circle has a radius of 21 inches. What is the length of the arc intercepted by a central angle that measures 4π/7 radians? Express the answer in terms of π .
Answer:
12π inches
Step-by-step explanation:
s = rθ
s = (21) (4π/7)
s = 12π
The length of the arc will be;
⇒ Arc = 37.68 inches
What is Circle?
The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.
Given that;
The central angle = 4π/7
And, A circle has a radius of 21 inches.
Now,
We know that in circle;
⇒ Arc = Radius × Angle
Substitute all the values, we get;
⇒ Arc = 21 × 4π/7
⇒ Arc = 3 × 4 × 3.14
⇒ Arc = 37.68 inches
Thus, The length of the arc will be;
⇒ Arc = 37.68 inches
Learn more about the circle visit:
https://brainly.com/question/1294687
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the sum of the first term of an ap is 240 and the sum of the next 4 term is 220 find the first term of the ap
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
find the rules for these sequence
Answer:
start with -29, multiply each term by 4
start with 60, multiply each term by 0.1
start with 97 and multiply each term by 0.5
3.03 cells
Step-by-step explanation:
1. The first sequence begins with -29. -116 ÷ -29 = 4, -464 ÷ -116 = 4, etc. Each value is multiplied by 4 to get the next value.
2. The second sequence begins with 60. 6 ÷ 60 = 0.1, 0.6 ÷ 6 = 0.1, etc. Each value is multiplied by 0.1 to get the next value.
3. The colony starts with 97 cells. Splitting into two is the same as multiplying by 0.5.
4. Multiply 97 by 0.5, 5 times for 5 minutes.
97 · 0.5 · 0.5 · 0.5 · 0.5 · 0.5 = 3.03
Find the sum of two consecutive odd numbers is 56 find the numbers
Answer:
[tex]\boxed{\sf 27 \ and \ 29}[/tex]
Step-by-step explanation:
Let the first consecutive odd integer be [tex]\sf x[/tex].
Let the second consecutive odd integer be [tex]\sf x+2[/tex].
The sum of the two numbers is 56.
[tex]\sf x+x+2=56[/tex]
[tex]\sf 2x+2=56[/tex]
[tex]\sf 2x=54[/tex]
[tex]\sf x=27[/tex]
Put x as 27 for the second consecutive odd integer.
[tex]\sf 27+2=29[/tex]
The two numbers are 27 and 29.
Which situation can be represented by 80x > 150 + 50x?
Answer:
All numbers greater than 5, i.e., [tex]x>5[/tex] .
Step-by-step explanation:
The given inequality is
[tex]80x>150+50x[/tex]
Isolate variable terms on one side to find the solution.
Subtract 50x from both sides.
[tex]80x-50x>150+50x-50x[/tex]
[tex]30x>150[/tex]
Divide both sides by 30.
[tex]\dfrac{30x}{30}>\dfrac{150}{30}[/tex]
[tex]x>5[/tex]
It means, all the numbers which are greater than 5, are the solutions of the given inequality and 5 is not included in the solution set.