w is 1.07 × 10^4, expressed in scientific notation with the correct number of significant figures.
How do we calculate the value of w?The equation given is:
Ψ = w/(yz^2)
We Substitute the given values, we get:
Ψ = w/(y × z^2) = 1.1 × 10^3 × 2.48 × 10^-2 × 6.000 = 1.6464
solving for w and rearranging the equation as:
w = Ψ × y × z^2
We Substitute the given values, we get:
w = 1.6464 × 37 × (14)^2 = 10,722.7584
we round the value of w to three significant figures, since the values of y, z, and Ψ are given with three significant figures, in order to express the result in scientific notation with the correct number of significant figures,
Rounding 10,722.7584 to three significant figures gives 10,700. Therefore, the value of w is:
w = 1.07 × 10^4
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HELP ME!!!!If a researcher is designing an electromagnet for a life-saving medical application, which properties of the magnet will she need to take into account?
Select two answers!!
Wether or not magnetic field is constant.
Number of could of conducting wire.
Wether or not domains are present in iron core.
Metal composition of conducting wire.
Answer:
Number of coils of conducting wire and whether or not domains are present in iron core are the two properties of the electromagnet that the researcher will need to take into account.
Explanation:
The number of coils of conducting wire affects the strength of the magnetic field produced by the electromagnet. More coils will produce a stronger magnetic field, while fewer coils will produce a weaker magnetic field. The researcher will need to determine the appropriate number of coils to produce the desired strength of the magnetic field for the medical application.
The presence of domains in the iron core is also an important consideration. The iron core of the electromagnet helps to concentrate the magnetic field and increase its strength. The domains in the iron core align with the magnetic field produced by the current flowing through the wire, and this alignment reinforces the magnetic field. If the iron core does not have domains, the magnetic field produced by the electromagnet will be weaker. Therefore, the researcher will need to ensure that the iron core has domains to maximize the strength of the magnetic field for the medical application.
What are some examples of conservation of energy?
Answer:
power plant
collision
Battery
Burning wood
speaker
Beating drum
An athlete whirls a 7.66 kg hammer tied to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 0.372 rev/s. What is the tension in the chain? Answer in units of N.
The hammer's centripetal acceleration is therefore 100.59 m/s².
Using an example, what is acceleration?An object has positive acceleration when it is going faster than it was previously. Positive acceleration was demonstrated by the moving car in the first scenario. Positive forward motion is being made by the car.
Hammer mass, m, is 6.55 kg. chain length, including the length of the arms, r = 1.3 m, Hammer's angular velocity is given by the formula: = 1.4 rev/s = 8.79646 rad/s (1 rev = 6.28 rad).
The formula a = V2/r, where V is the transverse velocity of the hammer, yields the centripetal acceleration.
V = r, hence
As a result, a = r²
A = 1.3 x 8.796462, or 100.59 m/s², is obtained by substituting the supplied numbers in the equation above.
The hammer's centripetal acceleration is therefore 100.59 m/s².
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Two asteroids are suspended in space 50 meters apart. The masses of the asteroids are 2000000 kg and
3000000 kg.
Answer:
Explanation:
What is the gravitational force between them?
To calculate the gravitational force between two objects, we can use the formula:
F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.
Plugging in the given values, we get:
F = (6.6743 x 10^-11 N * m^2 / kg^2) * (2000000 kg) * (3000000 kg) / (50 m)^2
F = 0.8046 N
Therefore, the gravitational force between the two asteroids is approximately 0.8046 N.
A porter can climb 10 staircase of 30cm each in 10 sec by carrying a 50kg bag. Calculate the power of the porter
Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.
What is work done?The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.
The force applied is the weight of the bag, which is given by:
F = m * g
where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:
F = 50 kg * 9.81 m/s²
F = 490.5 N
The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:
v = (10 * 30 cm) / 10 s
v = 30 cm/s
The power of the porter is the rate at which work is done, which can be calculated as:
P = W / t
where W is the work done and t is the time taken. Substituting the values, we get:
P = F * d * v / t
P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s
P = 441,450 J/s
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If 10 A of current flows through a 2 ohm resistor, what is the voltage of the battery?
20 V
0.2 V
OS V
12 V
The voltage of the battery would be 20 volts. Option I.
Voltage calculationAccording to Ohm's law, the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Mathematically,
V = I × R
In this case, the current (I) flowing through the resistor is given as 10 A and the resistance (R) of the resistor is given as 2 ohms. Substituting these values into the above formula, we get:
V = 10 A × 2 ohms = 20 volts
Therefore, the voltage of the battery is 20 volts.
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Is this statement is correct ?? According to Newton's 4rd law, Action and reaction never start from the same point.
help me...
Explanation:
I'm sorry, but the statement you provided is incorrect. There is no such thing as Newton's 4th law. Newton's laws of motion consist of three laws, which are:
An object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.
For every action, there is an equal and opposite reaction.
None of these laws state that action and reaction never start from the same point. However, it is true that the action and reaction forces act on different objects, not necessarily at the same point. This is because Newton's third law states that every action has an equal and opposite reaction, which means that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.
Why do you think the pylon in Figure 24 is designed the way it is, and not in the way shown in Figure 25?
They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.
What kinds οf patterns are used tο create electrical pylοns?Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.
Whο was the electrical pylοn's designer?This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.
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Complete question:
6. An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and how much momentum does it have after it has reached this final velocity?
The truck's acceleration is 3.0m/s² and the momentum of the truck is 144000 kg m/s.
What is acceleration?It is the rate at which the speed and direction of a moving object vary over time.
We can use the following equation to calculate the acceleration of the truck:
a = (v - u) / t
where
a = acceleration
v = final velocity = 18.0 m/s
u = initial velocity = 0 m/s (the truck starts from rest)
t = time taken = 6.00 s
Substituting the values, we get:
a = (18.0 m/s - 0 m/s) / 6.00 s
a = 3.00 m/s²
Therefore, the acceleration of the truck is 3.00 m/s².
We can use the following equation to calculate the momentum of the truck:
p = m * v
where
p = momentum
m = mass of the truck = 8000.0 kg
v = final velocity = 18.0 m/s
Substituting the values, we get:
p = 8000.0 kg * 18.0 m/s
p = 144000 kg m/s
Therefore, the momentum of the truck after it has reached its final velocity is 144000 kg m/s.
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The bigger the spring constant, the more__________the spring is.
The bigger the spring constant, the more stiff or rigid the spring is.
What does it signify when a spring's spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
What does it signify when the spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.
Answer:
Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.
One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.
Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.
Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.
A student uses 800 W microwave for 30 seconds how much energy does a student use
Answer:
The student used 24000 Joules of energy.
Explanation:
We can use the Energy Power equation to solve this example.
[tex]\sf E=Pt[/tex]
Where
[tex]\sf E[/tex] is the energy in Joules (J)
[tex]\sf P[/tex] is the power in Watts (W)
[tex]\sf t[/tex] is the time in seconds (s)
Numerical Evaluation
In this example we are given
[tex]\sf P=800\\t=30[/tex]
Substituting our given values into the equation yields
[tex]\sf E=800 \cdot 30[/tex]
[tex]\sf E=24000[/tex]
24000 Joules
[tex]\Large\bold{SOLUTION}[/tex]
To calculate the energy used by the student in this scenario, we can use the formula:
[tex]\sf{Energy\: (in\: Joules) = Power\: (in\: Watts) \times Time\: (in\: seconds)}[/tex]
Given that the student uses an 800 W microwave for 30 seconds, we can plug in these values to the formula:
[tex]\sf Energy = 800\: W \times 30\: s = 24,000\: J[/tex]
Therefore, the student uses 24,000 Joules of energy in this scenario.
[tex]\rule{200pt}{5pt}[/tex]