Given the following equation: 3C12 (g) + 8NH3 (g) → N2(g) +
ONH4Cl (S)
How many moles of NH3 are required to produce 12 moles of
NH4Cl?

Answer:

See explanation and image attached

Explanation:

Hydrogen peroxide is made up of two atoms of hydrogen and two atoms of oxygen as shown in the image attached.

The two oxygen atoms are joined together by a single covalent bond and each of the oxygen atoms are bonded to one hydrogen atom each.

There are two lone pairs on each of the oxygen atoms.

The Lewis(dot) structure for hydrogen peroxide is shown in the image attached to this answer.

Answer:

[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Explanation:

Hello there!

In this case, according to the given information, we can set up the appropriate chemical equation when ammonium phosphate reacts with sodium chloride in aqueous solution:

[tex](NH_4)_3PO_4(aq)+NaCl(aq)\rightarrow NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Which stands for a double replacement reaction, whereby ammonium changes phosphate to chloride and sodium changes chloride to phosphate on the products side. In addition, we can balance the aforementioned equation as shown below:

[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Regards!

Explanation:

i think the answer is A ........ hope this helps

Answer:

The explanation according to the given question is summarized below.

Explanation:

Given:

Tris,

= 250 mM

Glycine,

= 1.92 M

According to the solution,

For the dilution pf 10X to 1X buffer, we get

= [tex]1 \ ml \ of \ 10X \ buffer +9 \ ml \ of \ distilled \ water[/tex]

= [tex]10[/tex]

i.e.,

⇒ [tex]10X \ to \ 1X=1:10 \ dilution[/tex]

Now,

⇒ [tex]10X (250 \ mM\ Tris \ HCl, 1.92M\ Glycine, and\ 1 \ percent (\frac{w}{v} ) SDS) ---->1X(25 \ mM \ Tris \ HCl,0.193 M\ Glycine, and \ 0.1 \ percent(\frac{w}{v} )SDS)[/tex]

Answer:

1. Ions are either negatively or positively charged species in which the number of electrons and protons are not equal.

2. The chemical bond that arises due to the sharing of electrons is termed a covalent bond.

3. The positively charged ions are called cations, which comprise more protons than electrons.

4. An example of a polyatomic anion is the hydroxide anion.

5. The system of assigning an unambiguous name to a compound is called nomenclature.

Answer:

9.0mm x 2.0mm x 2.0mm

= 18mm3

Answer:

36mm^3

Explanation:

This is easy

Answer:

How to Formulate an Effective Research Hypothesis

State the problem that you are trying to solve. Make sure that the hypothesis clearly defines the topic and the focus of the experiment.

Try to write the hypothesis as an if-then statement. ...

Define the variables.

Explanation:

Answer:

Three isomers

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

Explanation:

Complete question

How many isomers are there with the following descriptions?

a) Alcohol with formula C3H8O

Solution

There are total 3 carbon atoms in this alcohol. Hence, there will be three isomers of Alcohol with formula C3H8O .

The three isomers will comprise of alcohol group (OH) attached to the three carbon atoms one by one.

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

Answer:

2Mg(s) + O2(g) ----->2MgO(s)

Explanation:

In writing a balanced chemical reaction equation, the rule of thumb is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same elements on the products side.

Hence for the reaction of magnesium and oxygen shown below;

2Mg(s) + O2(g) ----->2MgO(s)

We notice that there are two atoms each of magnesium and oxygen on both sides of the reaction equation hence the equation is balanced.

Answer:

0.144 M

Explanation:

First we convert 0.307 g of KHP (potassium hydrogen phthalate, KHC₈H₄O₄) into moles, using its molar mass:

1 mol of KHP reacts with 1 mol of NaOH, that means that in 10.40 mL of the NaOH solution there were 0.0015 moles of NaOH.

Now we calculate the molarity of the NaOH solution:

Answer:

That should be Hydrogen.

So The second option Is legit!

Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

Answer:

NCl₃

Explanation:

From the question given above, the following data were obtained:

Mass of nitrogen (N) = 0.77 mg

Mass of chlorine (Cl) = 6.61 mg

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

N = 0.77 mg

Cl = 6.61 mg

Divide by their molar mass

N = 0.77 / 14 = 0.055

Cl = 6.61 / 35.5 = 0.186

Divide by the smallest

N = 0.055 / 0.055 = 1

Cl = 0.186 /0.055 = 3

Therefore, the empirical formula of the compound is NCl₃

Answer:

just look at what row the element is in. The lower the row, the bigger the radius

Explanation:

The question is incomplete. The complete question is :

C. Balance these fossil-fuel combustion reactions. (1 point)

C8H18(g) + 12.5O2(g) →    ____CO2(g) + 9H2O(g) + heat

CH4(g) + ____O2(g) →     ____CO2(g) + ____H2O(g) + heat

C3H8(g) + ____O2(g) →    ____CO2(g) + ____H2O(g) + heat

C6H6(g) + ____O2(g)  →   ____CO2(g) + ____H2O(g) + heat

Solution :

C8H18(g) + 12.5O2(g) →    __8__CO2(g) + 9H2O(g) + heat

When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.

CH4(g) + __2__O2(g) →     __1__CO2(g) + __2__H2O(g) + heat

When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.

C3H8(g) + __5__O2(g) →    __3__CO2(g) + __4__H2O(g) + heat

When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.

C6H6(g) + __1/2__O2(g)  →   __6__CO2(g) + __3__H2O(g) + heat

When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.

Light energy travels in the form of waves.

Answer:

106.180

Explanation:

maybe this is the correct answer

I SAID MAYBE

Answer:

Explanation:

Short answer: Yes.

The coefficients may not be conserved, but mass always has to be. Take this equation as an example

2 Mg3P2 ===>   6Mg + P4

There is a 2 on the left side and 6 and 1 on the right. I hope you mean that the coefficient 2 is not equal to 7.

But let's look a little closer. You have to look at the molecular structure of the left and right side.

2Mg3P2 has 6 Mgs and 4 Ps on the left side.

6Mg is on the right. They are free standing.

P4    has 1 molecule consisting of 4 Ps.

Everything balances.

This is a terrific question to be asking. You need to understand the internal balance numbers vs the molecular ones on the out side.

That sounds like a bit of gobbledygook and it takes a bit of study.

2 Mg3P2 means that Mg3P2 is written twice.

Mg3P2 ==> "3 Mg2+   +  2P3+   and there is another one written the same way.

Mg3P2 ==> "3 Mg2+   +  2P3+  

I believe the answer for this is:

C. Visible Light Rays

I hope this helps! :D

Answer:

C, visible light rays :)

Explanation:

Hope i could help

We are given:

Initial concentration of HA: 0.200 Molar

The acid is 9.4% ionized

Dissociation constant (α) = (Percent Ionized) / 100 = 0.094

Molar concentration of H+ = 0.0188

Let's Chill! (making the ICE box):

Reaction:       HA         ⇄       H⁺      +      A⁻

Initial:           0.200M               -                -

Equilibrium: 0.200(1-α)      0.200α       0.200α

while we're here, let's confirm the given equilibrium concentration of H⁺ ions

from the table here, we can see that the equilibrium concentration of H⁺ ions is 0.200α, we know that α = 0.094

[H⁺] = 0.200α = 0.200 * 0.094 = 0.0188 M

which means that we're on the right track

We're basically scientists at this point (finding the dissociation constant):

Acid dissociation is nothing but the equilibrium constant, but for the dissociation of Acids

From the reaction above, we can write the equation of the acid dissociation constant:

Ka = [H⁺][A⁻] / [HA]

now, let's take the values from the 'equilibrium' row of the ice box the plug those in this equation

Ka = (0.200α)(0.200α) / [0.200(1-α)]

Ka = (0.200α)²/[0.200(1-α)]

plugging the value of α

Ka = (0.200*0.094)² / [0.200(0.906)]

Ka = (0.0188)² / 0.1812

Ka = 1.95 * 10⁻³

Answer:

5 Acids

Chemical

- Hydrochloric acid in gastric juice

- Sulphuric acid

- Nitric acid

- Uric acid

- Acetic acid

Household

- Vinegar

- Lemon

- Milk

- Batteries

- Soft drinks

5 Alkali

Household

- Dishwashwer soaps

- Detergents

- Toothpaste

- Oven cleaner

- Alkaline batteries

- Sodium bicarbonate

Chemicals

- Sodium hydroxide or lye

- Calcium carbonate (limestone)

- Ammonium hydroxide

- Calcium hydroxide

Answer:  the area of the telescope lens is \textit{0,08507 ft}

Explanation: Happy I could help!

Answer:

silicon

Explanation:

because silicon has 14 electrons and protons

Answer:

non polar. polar ionic substance

Answer:

Explanation:

Given the data in the question;

wavelength λ₁ = 853 nm = 853 × 10⁻⁹ m

wavelength λ₂ = 865 nm = 865 × 10⁻⁹ m

we determine the energy of each photons using the following expression;

[tex]E_{photon[/tex] = hc / λ

where h is Planck's constant ( 6.626 × 10⁻³⁴ J.s )

c is speed of light ( 3 × 10⁸ m/s )

For Photon with wavelength λ₁ = 853 × 10⁻⁹ m

[tex]E_{photon1[/tex] = hc / λ

we substitute

= ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / (853 × 10⁻⁹ m)

= 1.9878 × 10⁻²⁵ / 853 × 10⁻⁹

= 2.33 × 10⁻¹⁹ J

For Photon with wavelength  λ₂ = 865 × 10⁻⁹ m

[tex]E_{photon2[/tex] = ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / (865 × 10⁻⁹ m)

= 1.9878 × 10⁻²⁵ / 865 × 10⁻⁹

= 2.298 × 10⁻¹⁹ J

We know that; energy of the combined photon will be equal to the sum of energies of the two photons.

so

Energy of the combined photon = [tex]E_{photon1[/tex] + [tex]E_{photon2[/tex]

[tex]E_{combined[/tex] = 2.33 × 10⁻¹⁹ J + 2.298 × 10⁻¹⁹ J

[tex]E_{combined[/tex]  = 4.628 × 10⁻¹⁹ J

so wavelength of the new combined photon will be;

[tex]E_{combined[/tex] = hc / λ[tex]_{combined[/tex]

[tex]E_{combined[/tex]λ[tex]_{combined[/tex] = hc

λ[tex]_{combined[/tex] = hc / [tex]E_{combined[/tex]

we substitute

λ[tex]_{combined[/tex] = ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / 4.628 × 10⁻¹⁹ J

= 1.9878 × 10⁻²⁵ / 4.628 × 10⁻¹⁹

= 4.2952 × 10⁻⁷ m

= ( 4.2952 × 10⁻⁷ × 10⁹ )nm

= 429.5 nm

Therefore, Wavelength of the new 'combined' photon is 429.5 nm