Given trapezoid PQRS, find the length of midsegment TU.

Given Trapezoid PQRS, Find The Length Of Midsegment TU.

Answers

Answer 1

Answer:

Option (4)

Step-by-step explanation:

In the given picture,

Trapezoid PQRS has two points T and U as the midpoints of sides PS and RQ.

Segment TU joins the midpoints of the sides PS and RQ.

Mid-segment theorem states that "If a line joining midpoints of a trapezoid is parallel to the bases, length of this segment is half the sum of lengths of the bases."

Therefore, m(TU) = [tex]\frac{1}{2}(m\text{PQ}+m\text{SR})[/tex]

7x - 26 = [tex]\frac{1}{2}[(3x+23)+(9x-3)][/tex]

7x - 26 = 6x + 10

7x - 6x = 26 + 10

x = 36

m(TU) = 7x - 26

          = 7(36) - 26

          = 252 - 26

          = 226

Therefore, Option (4) will be the answer.


Related Questions

What is the following product?

Answers

Answer:

[tex]\boxed{6\sqrt{6} }[/tex]

Step-by-step explanation:

[tex]\sqrt{12} \sqrt{18}[/tex]

Multiply square roots.

[tex]\sqrt{12 \times 18}[/tex]

[tex]\sqrt{216}[/tex]

Simplify square root.

[tex]\sqrt{36} \sqrt{6}[/tex]

[tex]6\sqrt{6}[/tex]

Bao can eat 12 chicken wings in 3 minutes.She eats the chicken wings at a constant rate how many chicken wings can bao eat in 12 minutes

Answers

Answer:

48 wings

Step-by-step explanation:

12:3 is the ratio. So multiply both of it by 4. Then it would be 48:12

Answer:

48 chicken wings

Step-by-step explanation:

If Bao can eat 12 chicken wings in 3 minutes and 12 minutes is 3 minutes times 4, then the answer would be 12 chicken wings times 4, so 12 times 4, which is 48, so the answer would be 48 chicken wings.

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.

Answers

Answer:

The function has two real roots and crosses the x-axis in two places.

The solutions of the given function are

x = (-0.4495, 4.4495)

Step-by-step explanation:

The given quadratic equation is

[tex]G(x) = -x^2 + 4x + 2[/tex]

A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.

Recall that the general form of a quadratic equation is given by

[tex]a^2 + bx + c[/tex]

Comparing the general form with the given quadratic equation, we get

[tex]a = -1 \\\\b = 4\\\\c = 2[/tex]

The nature of the solutions can be found using

If [tex]b^2- 4ac = 0[/tex] then we get two real and equal solutions

If [tex]b^2- 4ac > 0[/tex] then we get two real and different solutions

If [tex]b^2- 4ac < 0[/tex] then we get two imaginary solutions

For the given case,

[tex]b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\[/tex]

Since 24 > 0

we got two real and different solutions which means that the function crosses the x-axis at two different places.

Therefore, the correct option is the last one.

The function has two real roots and crosses the x-axis in two places.

The solutions (roots) of the equation may be found by using the quadratic formula

[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]

[tex]x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\[/tex]

Therefore, the solutions of the given function are

x = (-0.4495, 4.4495)

A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.

The following box plot shows the number of years during which 40 schools have participated in an interschool swimming meet: A box and whisker plot is drawn using a number line from 0 to 10 with primary markings and labels at 0, 5, 10. In between two primary markings are 4 secondary markings. The box extends from 1 to 6 on the number line. There is a vertical line at 3.5. The whiskers end at 0 and 8. Above the plot is written Duration of Participation. Below the plot is written Years. At least how many schools have participated for more than 1 year and less than 6 years?

Answers

Answer:

Step-by-step explanation:

The box encloses data between the two quartiles, namely at least half of the data.  If there are 40 schools, then half of them would be in the box, between 1 and 6.

see attached plot.

Answer:

really hard to tell what the box plot is like without an attachment so im gonna help u find it out anyway

Step-by-step explanation:

basically when u look at a  box plot and the range the line in the middle is the median  and then the max the lowest range the lower quartile and then the higher quartile you can find ur anser, simply find the median first, find where the lower quartile is and then the lowest number in the group thats in betweeen 1 and 6

compare two spheres. first has a diameter of 8 yards. The second sphere has a diameter of 1064 yards. Determine the ratio of the volume of the larger sphere to the volume of the smaller sphere

Answers

Answer:

The ratio of the volume of the larger sphere to the volume of the smaller sphere is

2352637 : 1

Step-by-step explanation:

Volume of a sphere is

[tex] \frac{4}{3} \pi {r}^{3} [/tex]

Where r is the radius

radius = diameter / 2

For First sphere

diameter = 8yards

radius = 8 / 2 = 4 yards

Volume of first sphere is

[tex] \frac{4}{3} \pi( {4})^{3} \\ \\ = \frac{256}{3} \pi \: {yd}^{3} [/tex]

For second sphere

diameter = 1064 yards

radius = 1064 / 2 = 532 yards

Volume of second sphere is

[tex] \frac{4}{3} \pi( {532})^{3} \\ \\ = \frac{602275072}{3} \pi \: {yd}^{3} [/tex]

Since the volume of the second sphere is the largest

Ratio of the second sphere to the first one is

[tex] \frac{602275072}{3} \pi \div \frac{256}{3} \pi \\ \\ = \frac{602275072}{3} \pi \times \frac{3}{256} \pi \\ \\ = \frac{602275072}{256} \\ \\ = \frac{ 2352637}{1} \\ \\ = 2352637: 1[/tex]

Hope this helps you

An angle measuring 5.25 radians is equal to which of the measures given below? Check all that apply. - 300 degrees 48’ - 16.49 degrees - 16degree 24’ -300.8 degree

Answers

Answer:

300.8 degrees

Step-by-step explanation:

in a circle full angle is [tex]2\pi[/tex] radian

In degrees the value of angle is 360.

Thus

[tex]2\pi[/tex] radian is same as  360 degrees

thus

[tex]2\pi[/tex] radian= 360 degrees

dviding both side by  [tex]2\pi[/tex]

[tex]2\pi[/tex] / [tex]2\pi[/tex] radian= 360/[tex]2\pi[/tex] degrees

1 radian= 360/[tex]2\pi[/tex] degrees

multiply both side by 5.25

1*5.25 radian= (360/[tex]2\pi[/tex])  * 5.25 degrees

using value of  [tex]\pi[/tex] as 3.14 we have

5.25 radian= (360/2*3.14)  * 5.25 degrees  = 300.8 degrees

Helppppppppppppppppp

Answers

Answer/Step-by-step explanation:

Surface area of cylinder = 2πrh + 2πr²

Surface area of the cylinder with,

height (h) = 4 ft

radius (r) = 5 ft

Surface area = 2*3.14*5*4 + 2*3.14*5²

= 125.6 + 157

= 282.6 ft²

Surface area of the cylinder with,

height (h) = 12 yd

radius (r) = 3 yd

Surface area = 2*3.14*3*12 + 2*3.14*3²

= 282.74 yd²

In this figure, and are parallel. is perpendicular to line segment . If the length of is a units, then the length of is units.

Answers

Answer:

is perpendicular to line segment  

GH

. If the length of  is a units, then the length of  is  

a

units.

Step-by-step explanation:

had to do it myself.

Answer:

Blank 1-
GH


Blank 2-
a

AB is perpendicular to line segment GH. If the length of EF is a units, then the length of GH is a units.

Step-by-step explanation:

I got it correct

Someone please help! Thank you

Answers

Answer:

110

Step-by-step explanation:

the sum of straight angle is 180

the sum of angle of triangle=180

angle E=180-120=60

triangle BDE: <B=180-60-90=30

<B in triangle ACB=180-(130+30)=20)

in traingle ACB: <A = 180-(90+20)=70

angle x=180-70=110 degrees

the diagram above shows a rectangle inscribed in a circle AB=10 and AC =12 caculate the total surface area of the shaded part

Answers

Answer:

[tex]71.63 \: \: \mathrm{cm^2 }[/tex]

Step-by-step explanation:

Once we know the diameter of the circle, we can figure out the problem.

The diameter of the circle = The diagonal of the rectangle inscribed in the circle

To find the diagonal of the rectangle, we can use a formula.

[tex]d=\sqrt{w^2 + l^2}[/tex]

The width is 10 cm and the length is 12 cm.

[tex]d=\sqrt{10^2 + 12^2}[/tex]

[tex]d \approx 15.62[/tex]

The diagonal of the rectangle inscribed in the circle is 15.62 cm.

The diameter of the circle is 15.62 cm.

Find the area of the whole circle.

[tex]A=\pi r^2[/tex]

The [tex]r[/tex] is the radius of the circle, to find radius from diameter we can divide the value by 2.

[tex]r = \frac{d}{2}[/tex]

[tex]r=\frac{15.62}{2}[/tex]

[tex]r=7.81[/tex]

Let’s find the area now.

[tex]A=\pi (7.81)^2[/tex]

[tex]A \approx 191.625[/tex]

Find the area of rectangle.

[tex]A=lw[/tex]

Length × Width.

[tex]A = 12 \times 10[/tex]

[tex]A=120[/tex]

Subtract the area of the whole circle with the area of rectangle to find area of shaded part.

[tex]191.625-120[/tex]

[tex]71.625 \approx 71.63[/tex]

Can someone help me with these two questions I don’t know how to do it and it’s due at 11 I would really appreciate it

Answers

Answer:

6. Unit rate = 1.3 yards per second

7. Unit rate = 0.8 page per minute

Step-by-step explanation:

The unit rate is simply the comparison of 2 quantities, whereby dividing both, the denominator must be 1.

For example, in the graph given comparing distance walked over time, when x (time in s) = 3, y (distance in yd) = 4.

Unit rate represented by the slope is the yards covered per second.

Unit rate = [tex] \frac{4}{3} = 1.33 [/tex]

Unit rate ≈ 1.3 yards per second

For the second graph given, unit rate of the slope is the number of pages read per minute.

From the graph, 4 pages is read at 5 minutes.

Thus,

Unit rate = [tex] \frac{4}{5} = 0.8 [/tex]

Unit rate = 0.8 page per minute

help me Please!!!!!!!​

Answers

Answer:

[tex]2\sqrt{14\\}[/tex] = q

Step-by-step explanation:

use geometric mean method

4/s = s/10

s^2 = 40

s = 2[tex]\sqrt{10}[/tex]

consider the triangle STR and using the Pythagorean theorem

[tex]s^{2} +16 = q^{2} \\[/tex]

[tex](2\sqrt{10})^{2} +16 = q^{2}[/tex]

40 + 16 = q^2

56 = q^2

[tex]2\sqrt{14\\}[/tex] = q

asap help !!

How much additional interest is earned if $8000 is invested for 7 years at 6.5% when
interest is compounded annually, as compared with simple interest paid at the same
rate?

Answers

Answer:

put it in a calculator, 8,000 times whatever number u need

HELPPPPPPPPPPPPPPPpppp

Answers

Answer:

Option (A)

Step-by-step explanation:

Two bases of the the given cylinder are circular in shape in the given picture.

When we take a cross-section of the cylinder parallel to the bases or perpendicular to the height, we get a circle exactly same as the bases (As shown on the rectangular slide).

Cross-section will have the same radius as the bases of the cylinder.

Therefore, Option (A) will be the answer.

Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2ab-6a+5b+___ Please include an explanation too!

Answers

Answer:

[tex]2ab - 6a + 5b - 15[/tex]

Step-by-step explanation:

Given

[tex]2ab - 6a + 5b + \_[/tex]

Required

Fill in the gap to produce the product of linear expressions

[tex]2ab - 6a + 5b + \_[/tex]

Split to 2

[tex](2ab - 6a) + (5b + \_)[/tex]

Factorize the first bracket

[tex]2a(b - 3) + (5b + \_)[/tex]

Represent the _ with X

[tex]2a(b - 3) + (5b + X)[/tex]

Factorize the second bracket

[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

To result in a linear expression, then the following condition must be satisfied;

[tex]b - 3 = b + \frac{X}{5}[/tex]

Subtract b from both sides

[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]

[tex]- 3 = \frac{X}{5}[/tex]

Multiply both sides by 5

[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]

[tex]X = -15[/tex]

Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]

[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]

[tex]2a(b - 3) + 5(b - 3)[/tex]

[tex](2a + 5)(b - 3)[/tex]

The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]

Their product will result in [tex]2ab - 6a + 5b - 15[/tex]

Hence, the constant is -15

first correct answer gets best marks ​

Answers

Answer:

the answer would be x is less than 6.

Step-by-step explanation:

the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.

Answer:

B

Step-by-step explanation:

x≤6

We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.

Hope this helps ;) ❤❤❤

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to create a perfect square trinomial?

Answers

Answer:

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Step-by-step explanation:

Let consider a second-order polynomial of the form [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex], [tex]\forall \,x \in\mathbb{R}[/tex]. The procedure is presented below:

1) [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex] (Given)

2) [tex]a\cdot x^{2} + b \cdot x = -c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

3) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c[/tex] (Compatibility with multiplication)

4) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

5) [tex](2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c[/tex] (Perfect square trinomial)

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Answer: D

Step-by-step explanation:

EDGE 2023

Katya has $20.00 to spend at her college bookstore, where all students receive a 20% discount . katya wants to purchase a copy of a book that normally sells for $22.50 plus 10% sales tax. how much dose the book sell for dose katya have enough money bc bc?

Answers

Answer:

here you go :)

Step-by-step explanation:

You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80.

Find the area of the shape shown below

Answers

Answer: 28

Step-by-step explanation:

I can't really think of a way to explain this well without visuals and idk how to add images on my answer. But, what I normally do is draw out the shape on paper divide the shape into different sections. Solve the area of the separate sections. It simplifies the more complex figure and turns them into basic shapes. After solving each shape, add all of them together and that leaves you with the area. Hopefully you understand what I mean. I hope this sort of helped:)

Please help me to solve this . Thank you so much .
And if possible , could you explain the answer too ?

Base on the diagram , state

a) The point which is 2 cm from R and 4 cm from P

b) The point which is more than 2 cm from R and 4 cm from T

c) The location of a moving point X in the diagram such that it is less than 4 cm from P and more than 2cm from R

d) The location of a moving point Y in the diagram such that YR < 2 cm and YP < 4 cm

e)The location of a moving point Z in the diagram such that ZT > 4 cm , ZP > 4 cm and ZR > 2 cm

Answers

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

The graph of g(x) resembles the graph of f(x)=x^2, but it has been changed. Which of these is the equation of g(x)?

Answers

Answer:

A.

Step-by-step explanation:

Anwer A has the following equation:

[tex]g(x)=\frac{3}{5}x^2-3[/tex]

In this equation, we can calculated the intercept replacing x by 0, as:

[tex]g(x)=\frac{3}{5}0^2-3=-3[/tex]

if this is the answer, the graph of g(x) should be through the point (0,-3) and that happens.

Additionally, the roots of the equations are calculated replacing g(x) by 0 and solving for x, so:

[tex]0=\frac{3}{5}x^2-3\\x_1=\sqrt{5}=2.236\\x_2=-\sqrt{5}=-2.236[/tex]

It means that the graph of g(x) should be through the points (2.236,0) and (-2.236,0) and that happens too.

So, the answer is A, [tex]g(x)=\frac{3}{5}x^2-3[/tex]

What is slope and how is it determined from a graph? How do you determine the intercepts from an equation or graph? How can linear equations and functions be written and graphed?

Answers

Hey there! I'm happy to help!

The slope is the steepness or incline of a line. From a graph, it is known as the rise over the run between two integer values. If you have a point at (1,1) and a point at (2,2), the rise (vertical difference) between them in 1 unit, and the run (horizontal difference) is 1 unit. 1/1 is 1, so the slope of a line that passes through these points is 1. This means that for every one unit to the right it goes, it goes one unit up.

The intercepts are where the line hits the x and y axes. By looking at a graph, you can find the y-intercept by seeing on what y-value the line intersects with the y-axis, and for the x-intercept you do so with the x-axis.

The slope-intercept equation is y=mx+b. This b is the y-intercept. To find the x-intercept, you plug in the value 0 for y and solve for x. This is because the x-axis is the line y=0, so you will see where the x is if y is equal to 0.

Linear equations and functions can be written in slope intercept form (y=mx+b), standard form (Ax+By=C), and point slope form [tex]y-y_{1} =m(x-x_{1} )[/tex].

They can be graphed by finding the y and x intercepts from the equation and then connecting the points to draw the line!

Have a wonderful day! :D

Pls help I need help with 12

Answers

Answer:

B. 14

Step-by-step explanation:

22/x = 11/(21-x)

462 - 22x = 11x

462 = 33x

x = 14

Answer: The value of x is 14, answer choice B

Let y be the other line segment connected to x

Using proportions:

[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]

Cross multiply and simplify

[tex]22y=11x[/tex]

[tex]y=\dfrac{1}{2}x[/tex]

We know that x and y add to 21, so we can create the following equation:

[tex]x+y=21[/tex]

Substitute y=(1/2)x

[tex]x+\dfrac{1}{2}x=21[/tex]

Simplify by adding like terms

[tex]\dfrac{3}{2}x=21[/tex]

Divide both sides by 3/2

[tex]x=14[/tex]

Let me know if you need any clarifications, thanks!

simplify: m–(a–k–b) HElp!

Answers

Answer: m-a+k+b

Step-by-step explanation:

m-(a-k-b)= m+-1*(a-k-b). Then, simply use distributive property to simplify the equation into m-a+k+b

Hope it helps <3

A cube has a side length of 5 cm. Determine the surface area of the largest pyramid that will fit inside the cube. Round if necessary.

Answers

Answer:

The surface area of the pyramid is 80.9 cm²

Step-by-step explanation:

The side length, s of the cube is given as 5 cm

Therefore, the largest pyramid that can fit into the cube will have a base side length, s = The side length of the cube = 5 cm

The height, h of the largest pyramid = The height of the cube = 5 cm.

The surface area of a pyramid =  Area of base, A + 1/2 × Perimeter of base, P × Slant height, S

The slant height of the pyramid = √(h² + (s/2)²) = √(5² + (5/2)²) = (5/2)×√5

The perimeter of the base = 4×5 = 20 cm

The area of the base = 5×5 = 25 cm²

The surface area of a pyramid = 25 + 1/2×20×(5/2)×√5 = 80.9 cm².

The surface area of a pyramid =  80.9 cm².

What fraction is equal to six-sevenths times eight-fifths?

Answers

Answer:

1 13/35 (mixed number) or 48/35 (simplified)

Step-by-step explanation:

6/7 times 8/5

= (6 times 8) / (7 times 5)

= 48/35 or 1 13/35

hope this helped :)

Answer:

48/35

Step-by-step explanation:

6/7*8/5=48/35

Please help i will mark brainliest

Answers

I think it’s 2/4x-6

Answer:

See below.

Step-by-step explanation:

To find the equation, we need to find the slope and the y-intercept. Afterwards, we can put the numbers into the slope-intercept form:

[tex]y=mx+b[/tex]

From the graph, we can see that the line crosses the y-intercept at y=-6. Thus, the y-intercept (b) is -6.

Now we need to find the slope. Pick any two points where the line crosses. I'm going to pick (0,-6) and (4,-7).

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-(-6)}{4-0}= -1/4[/tex]

Therefore, the equation of the line would be:

[tex]y=mx+b\\y=-1/4x-6[/tex]

48 - 8x equivalent expression

Answers

Answer:

8(6-x)

Step-by-step explanation:

Both 48 and 8 can be divisible by 8.

48 ÷ 8 = 6

8 ÷ 8 = 1

Therefore you get the answer 8(6-x)

as the simplest form.

Hope this helps.

Which graph represents the solution set for the system x+y greater than or equal to 5 and -3x+2y less than or equal than to -2

Answers

Step-by-step explanation:

in each equation once substitute the value of x as 0 and again y as zero by this way you will get two values of X and y .

then again find the slope for each equation by the formula

slope= -coefficient of x / coefficient of y

for example,

X+y is greater or equals to 5

or, X+y= 5

or, X=5-y

or, when y is equals to zero

X= 5

and when X is equals to zero

y= 5

then plot the above point in the graph with respect to its slope and the shaded part is the solution

Jane, Paul and Peter can finish painting the fence in 2 hours. If Jane does the job alone she can finish it in 5 hours. If Paul does the job alone he can finish it in 6 hours. How long will it take for Peter to finish the job alone?

Answers

Answer: 7.5 hours (or 7 hours 30 minutes)

==================================================

Explanation:

Jane does the job alone and she can finish it in 5 hours. Her rate is 1/5 of a job per hour. By "job", I mean painting the entire fence. Notice that multiplying 1/5 by the number of hours she works will yield the value 1 to indicate one full job is done.

Through similar reasoning, Paul's rate is 1/6 of a job per hour.

Let x be the time, in hours, it takes Peter to get the job done if he worked alone. His rate is 1/x of a job per hour.

Combining the three individual rates gives

1/5 + 1/6 + 1/x = (6x)/(30x) + (5x)/(30x) + (30)/(30x)

1/5 + 1/6 + 1/x = (6x+5x+30)/(30x)

1/5 + 1/6 + 1/x = (11x+30)/(30x)

The expression (11x+30)/(30x) is the total rate if the three people worked together. This is assuming neither worker slows another person down.

Set this equal to 1/2 as this is the combined rate (based on the fact everyone teaming up gets the job done in 2 hours). Then solve for x

(11x+30)/(30x) = 1/2

2(11x+30) = 30x*1 .... cross multiply

22x+60 = 30x

60 = 30x-22x

60 = 8x

8x = 60

x = 60/8

x = 7.5

It takes Peter 7.5 hours, or 7 hours 30 minutes, to get the job done if he worked alone.

--------------

Here's another equation to solve though its fairly the same idea as above

1/5 + 1/6 + 1/x = 1/2

30x*(1/5 + 1/6 + 1/x) = 30x*(1/2) ... multiply both sides by LCD

30x(1/5) + 30x(1/6) + 30x(1/x) = 30x(1/2)

6x + 5x + 30 = 15x

11x + 30 = 15x

30 = 15x-11x

30 = 4x

4x = 30

x = 30/4

x = 7.5

We get the same answer

Answer:  7 . 5 hrs

Step-by-step explanation:

It takes Jane 5 hours to finish the fence so she can get  [tex]\dfrac{1}{5}[/tex] of the job done in 1 hour.

It takes Paul 6 hours to finish the fence so he can get  [tex]\dfrac{1}{6}[/tex] of the job done in 1 hour.

It takes Peter x hours to finish the fence so he can get  [tex]\dfrac{1}{x}[/tex] of the job done in 1 hour.

Together, it takes them 2 hours to finish the fence so they can get  [tex]\dfrac{1}{2}[/tex] of the job done in 1 hour.

Jane + Paul + Peter = Together

[tex]\dfrac{1}{5}\quad +\quad \dfrac{1}{6}\quad +\quad \dfrac{1}{x}\quad =\quad \dfrac{1}{2}[/tex]

Multiply everything by 30x to eliminate the denominator:

[tex]\dfrac{1}{5}(30x) + \dfrac{1}{6}(30x) +\dfrac{1}{x}(30x) =\dfrac{1}{2}(30x)[/tex]

Simplify and solve for x:

6x + 5x + 30 = 15x

      11x + 30 = 15x

              30 = 4x

              [tex]\dfrac{30}{4}=x[/tex]

              7.5 = x

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