Graph the equation.
y-3= -5(x-1)

Answer:

false.........

Step-by-step explanation:

......

Answer:

hope this helps (if it does can i have brainliest, please??)

Step-by-step explanation:

I believe that is <KLJ and <MLJ

Answer:

KLJ and MLJ

Step-by-step explanation:

Supplemenatry angles add up to 180 degrees. Since these two angles form a straight line, it can be assumed that they add up to 180 degrees. Hope it helps :)

Answer:

a) attached below

b) Eigen values : λ1 = -1  and λ2 = - 1/2

  Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

c) since the Oscillator is > 0 hence  it is Overdamped

Step-by-step explanation:

Lets take  : m = 2 , k = 1 and b = 3

a) Second -order differential equation and the first order system

attached below

b) determine the eigenvalues and eigenvectors of the Linear system

Eigen values : λ1 = -1  and λ2 = - 1/2

Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

attached below is the detailed solution

c) The oscillator is classified as OVERDAMPED

To determine if the oscillator is damped, underdamped, or overdamped we will apply the relation below

 b^2 - 4km

 ( 3 )^2 - 4(1)(2)  = 1

since the Oscillator is > 0 hence it is Overdamped

d) Attached below is the phase portrait of the associated linear system

y(0) = 0

v(0) = 0

Answer:

one number is 2

second number if 3 1/3

Step-by-step explanation:

a = one number

b = second number

3a - b = 8

3a + b = 12

add together:

6a = 20

a = 20/6 or 10/3

find 'b':

3(10/3) - b = 8

10 - b = 8

-b = -2

b = 2

Answer:

[tex]Factor = 6w^4 v^3[/tex]

Step-by-step explanation:

Given

[tex]30x^8 w^4 v^3[/tex] and [tex]12w^7 v^5[/tex]

Required

Determine the common factor.

To do this, we simply factorize each. SO, we have:

[tex](1)\ 30x^8 w^4 v^3=: 2 * 3 * 5 * x^8 * w^4 * v^3[/tex]

[tex](2)\ 12w^7 v^5:=\ 2 * 2 * 3 * w^4*w^3 * v^3 * v^2[/tex]

Check for similar factors.

[tex]Factor = 2 *3 * w^4 * v^3[/tex]

[tex]Factor = 6w^4 v^3[/tex]

The above represents the similar factor

Answer:

Here's a graph to help you solve this answer:

Answer:

D

Step-by-step explanation:

This is a pythagoream thereom question, the area of a square can be found by multiplying the sides. All the sides of a sqaure are the same so we are basically sqauring the side lengths. That is where the [tex]BE^{2}[/tex] and [tex]BH^{2}[/tex] come from. The problem tells us that the area of the two small squares are equal to the one bigger square. And the area of the bigger sqaure can be found by squaring that side EH. So [tex]BE^{2}[/tex]+[tex]BH^{2} =EH^{2}[/tex].

Answer:

∠RQO and ∠STV

∠PQO and ∠UTV

Step-by-step explanation:

Answer:

I believe it is 12

Step-by-step explanation:

but I am not 100 percent sure

Answer:

it is likely because the majority of the outcomes are in your favor

Answer:

A

Step-by-step explanation:

Impossible, did it on usatestprep

Answer:

Hope This Helps!

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Sara = x age

Amy = x+2        when Sara  x = 22    Amy is x + 2 = 24

Product of ages = 528 so............

    x(x+2) = 528

    x² + 2x - 528 = 0     solve for x         I did it graphically first to get x = -24, 22

    (x+24) (x-22)  = 0

   (x+24) = 0         (x-22) = 0

           x = -24             x = 22        since you really can't have a negative age

Answer:

3z

Step-by-step explanation:

When you write a number followed by a variable with no operation in between them, it means multiplication.

3 multiplied by z is 3 * z, but you can write it without the multiplication sign simply as 3z.

Answer:

Fraction:[tex]\frac{5}{9}[/tex]

Percent: to the nearest percent 56% or 55.5555555556%

Step-by-step explanation:

There are nine total parts and 5 of those parts are shaded

You would divide 5 by 9 to get the percent then multiply it by 100

Answer:

5/9

or

45%

Step-by-step explanation:

Answer:

12345678910

Step-by-step explanation:

CHARRRRRRRRR joke lang bestie

Answer:

The calculated χ² =  17.0281    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

15                       7.50                                 7.50  

∑                                                               17.0281

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  17.0281    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

Answer:

137/1000

Step-by-step explanation:

Because we have 3 numbers after 0....

hope it helps

Answer:

- The population in 2001 is 23.1 million

- It will reach 28.3 million in 2013

Step-by-step explanation:

Given

[tex]A =23.1e^{0.0152t}[/tex]

Solving (a): Population in 2000.

This implies that

[tex]t = 2000 - 2000[/tex]

[tex]t = 0[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]A =23.1e^{0.0152*0}[/tex]

[tex]A =23.1e^{0}[/tex]

Solve the exponent

[tex]A =23.1*1[/tex]

[tex]A =23.1[/tex]

The population in 2001 is 23.1 million

Solving (b): When will it reach 28.3 million

This implies that:

[tex]A =28.3[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]28.3 = 23.1e^{0.0152t}[/tex]

Divide both sides by 23.1

[tex]1.225 = e^{0.0152t}[/tex]

Take natural logarithm of both sides

[tex]ln\ 1.225 = ln(e^{0.0152t})[/tex]

Rewrite as:

[tex]ln\ 1.225 = 0.0152t\ ln(e)[/tex]

[tex]ln(e) = 1[/tex]

So:

[tex]ln\ 1.225 = 0.0152t*1[/tex]

[tex]ln\ 1.225 = 0.0152t[/tex]

Make t the subject

[tex]t = \frac{ln\ 1.225}{0.0152}[/tex]

[tex]t = \frac{0.2029}{0.0152}[/tex]

[tex]t \approx 13[/tex]

Add the value of t to 2013 to get the actual year

[tex]Year = 2000 +13[/tex]

[tex]Year = 2013[/tex]

It will reach 28.3 million in 2013

Answer:

Answer:

[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex]

by using Pythagoras law:

h²=p²+b²

x²=9²+12²

x=√225=15unit

Answer:

1: mean equals 17.417, median is 12.75, mode is 8.2, range is 33, the minimum is 8.2 the maximum is 41.2. The IQR is 16.55, the quartiles is q1: 8.95, q2: 12.75, q3 is 25.5, there are no outliers.

2: the best middle is 12.75 because the median is usually the middle number but if you orgainze the numbers there will be two but you will end up getting 12.75 as your median. take the two middle number add together then divide by 2 then that is your answer.

Step-by-step explanation:

GOOD LUCK

Answer:

A is 14 and P is 17

Step-by-step explanation:

working is above mentioned

Answer:

the answer is $ 83,634

your welcome

Answer: #1 is the answer. Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.

Step-by-step explanation: Parallel Lines: Definition: We say that two lines (on the same plane) are parallel to each other if they never intersect each other, ragardless of how far they are extended on either side. Pictorially, parallel lines run along each other like the tracks of a train.

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

[tex]H_a: \mu_1 - \mu_2 > 0[/tex]

In which [tex]\mu_1[/tex] is the mean pine trees height while [tex]\mu_2[/tex] is the mean spruce trees height.

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

[tex]X = 35 - 30 = 5[/tex]

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2[/tex]

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}[/tex]

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

[tex]s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495[/tex]

Test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{5 - 0}{2.4495}[/tex]

[tex]z = 2.04[/tex]

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Answer:

sampling distribution = 22.4

sampling deviation = 0.68

Step-by-step explanation:

Given that :

Mean , μ = 22.4

Standard deviation, σ = 5.8

n = 73

Therefore, the sampling distribution of the mean and the standard deviation is

[tex]$\mu_{\overline x} = 22.4$[/tex]

So, [tex]$\sigma_{\overline x}=\frac{\sigma}{\sqrt n}$[/tex]

            [tex]$=\frac{5.8}{\sqrt {73}}$[/tex]

          = 0.68

So the sampling distribution of the mean is 22.4

The standard deviation is 0.68

Answer:

r = 7.1 cm

Step-by-step explanation:

Given the following data;

Volume of hemisphere = 757 cm³

To find the radius of the hemisphere;

Mathematically, the volume of a hemisphere is given by the formula;

Volume of hemisphere = ⅔πr³

Where, r is the radius of the hemisphere.

π = 22/7

Substituting into the formula, we have;

757 = ⅔πr³

Cross-multiplying, we have;

757 * 3 = 2πr³

2271 = 2*22/7*r³

2271 = 44/7*r³

Cross-multiplying, we have;

2271 * 7 = 44r³

15897 = 44r³

r³ = 15897/44

r³ = 361.30

Taking the cube root of both sides, we have;

r = 7.1223

To the nearest tenth of a centimeter;

r = 7.1 cm

Answer:

120

Step-by-step explanation:

LCM of (2^3×3×5) and (3×5) is​

The LCM of the expression will be the product of all the factors that are in both expressions

(2^3×3×5) = 2 * 2 * 2 * 3 * 5

(3 * 5) = 3 * 5

since 3 * 5 is common to both factors, we will not have to repeat it twice to get our LCM again. Hence the LCM is expressed as;

LCM = 2 * 2 * 2 * 3 * 5

LCM  = 8 * 3 *5

LCM = 24 * 5

LCM = 120

Hence the required LCM is 120