H с Homework: 6.2 Homework Question 5, 6.2.11-T Construct the indicated confidence interval for the population mean y using the t-distribution. Assume the population is normally distributed. C= 0.98, *= 12.1, =0.95, n=15 (Round to one decimal place as needed.)

Step-by-step explanation:

Total cost will be

$ 73.56   + 7% of 73.56

$ 73.56 + .07 * $73.56

(1.07) ( 73.56) = $ 78 . 71

The probability of number of 1-2 Children in car and 3 plus children in car is 0.203.

We have,

The possibility of the result of any random event is known as probability. This phrase refers to determining the likelihood that any given occurrence will occur.

The probability of P(1-2 children| car). P (3 plus children| car) is given by:

P = 63/88 × 25/88

P=0.203

The probability of P(Bus| 1-2 children). P (Bus | 3 plus children) is given by:

P = 38/101 × 49/74

P=0.249

The probability of P(Car |1-2 Children) is given by:

P= 63/101

P=0.624

The probability of P(3 plus children | Bus)is given by:

P=49/87

P=0.563

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complete question:

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.

The table shows the mode of transportation to school for families with a specific number of children.

Mode of Transportation

Car

Number of

Children

0.284

1-2

63

38

3+

25

49

Total

88

87

A family from the survey is selected at random. Match the probability to each event.

0.662

Bus

0.203

0.249

101

74

175

0.624

P (3+ Children Bus)

Total

P(1-2 Children Car) - P (3+ Children Car)

Reset

P (Car 1-2 Children)

0.563

P (Bus 1-2 Children) - P (Bus 3+ Children)

▸

44 + 38 can be written in the form a(b + c) as:

44 + 38 = 2(22 + 19) = 2(41)

We may use the distributive property to factor 44 + 38 by first determining their greatest common factor (GCF), which is 2, and then writing the result as follows:

44 + 38 = 2(22) + 2(19)

By removing the second from the equation, we may further reduce it: 44 + 38 = 2(22 + 19).

Therefore, 44 + 38 can be written in the form a(b + c) as:

44 + 38 = 2(22 + 19) = 2(41)

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The probability that at least two of the kittens will be chocolate brown is 0.3087.

We have,

Number of kittens = 5

Each kitten has a 30% chance of being chocolate brown.

So, p = 0.5 and q= 1-0.3 = 0.7

Now, P(X =2) = C( 5, 2) 0.3² (0.7)³

= 5! / 2!3! (0.09) (0.343)

= 10 x 0.03087

= 0.3087

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Therefore, the original purchased price of the medium pizza without a coupon is $10.31.

A coupon is a ticket or document that may be used in marketing to obtain a financial discount or refund when making a purchase of a good.  Customers receive a discount on their initial purchase thanks to the First Order Coupon. The first order coupon sales rule may be configured by admin in the admin area.

It aids in improving conversion rates. Frequently, yearly percentages are used to describe coupon payments. For instance, a bond with a $1,000 face value and an annual payment of $30 is said to have a 3% coupon. If the friend purchased a medium pizza for $10.31 with a 30% off coupon, then the price of the pizza after the discount is:

= 10.31 - 0.30(10.31)

= 10.31 - 3.09

= $7.22

So the price of the medium pizza without a coupon is $7.22 / (1 - 0.30) = $10.31.

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The requried, for a given proportional relationship when x = 9 and z = 10, y is equal to 0.72.

If y varies directly with x and inversely with the square of z, we can write the following proportion:

y ∝ x / z²

To solve for k, we can use the initial condition:

y = k (x / z²)

When x = 4 and z = 2, y = 8. Substituting these values into the equation, we get:

8 = k (4 / 2²)

k = 8

So, the equation for the variation is:

y = 8 (x / z²)

To find y when x = 9 and z = 10, we substitute these values into the equation:

y = 8 (9 / 10²)

y = 0.72

Therefore, when x = 9 and z = 10, y is equal to 0.72.

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The probability that a randomly selected adult has an IQ greater than 133.2 is 0.0436 or 4.36%.

To find the probability that a randomly selected adult has an IQ greater than 133.2, assuming adults have IQ scores that are normally distributed with a mean of 97.6 and a standard deviation of 20.9, follow these steps:

1. Calculate the z-score: z = (X - μ) / σ, where X is the IQ score, μ is the mean, and σ is the standard deviation.
  z = (133.2 - 97.6) / 20.9
  z ≈ 1.71

2. Use a z-table or a calculator to find the area to the left of the z-score, which represents the probability of having an IQ score lower than 133.2.
  P(Z < 1.71) ≈ 0.9564

3. Since we want the probability of having an IQ greater than 133.2, subtract the area to the left of the z-score from 1.
  P(Z > 1.71) = 1 - P(Z < 1.71) = 1 - 0.9564 = 0.0436

So, the probability that a randomly selected adult has an IQ greater than 133.2 is approximately 0.0436 or 4.36%.

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The surface area of the prism is 200 cm².

The total surface area of the prism is calculated by applying the formula for total surface area of prism.

S.A = bh + (s₁ + s₂ + s₃)L

where;

The surface area of the prism is calculated as;

S.A = 8 cm (15 cm) + (8 cm + 15 cm + 17 cm) x 2cm

S.A = 120 cm² + 80 cm²

S.A = 200 cm²

Thus, the surface area of the prism is calculated using the formula for surface of right prism.

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If this is a sample of 4 scores, then By using the definitional formula, SS equals 5. Your answer: 5.

Using the definitional formula, SS can be calculated as:

SS = ∑(x - X)2

where X is the sample mean.

To find X, we can use the formula:

X = ∑x / n

where n is the sample size.

Given that ∑x = 22 and n = 4, we can calculate X as:

X = 22 / 4 = 5.5

Now, we'll plug these values into the formula:

SS = 126 - (22)² / 4

Calculate (∑x)² / n:

(22)² / 4 = 484 / 4 = 121
Now we can plug in the values into the formula for SS:

SS = ∑(x - X)2
  = (1-5.5)2 + (2-5.5)2 + (3-5.5)2 + (4-5.5)2
  = (-4.5)2 + (-3.5)2 + (-2.5)2 + (-1.5)2
  = 20.5

Therefore, SS equals 20.5.

So, using the definitional formula, SS equals 5. Your answer: 5.

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The integral ∫g(x) dv(x) does not converge to a finite value.

To find the integral ∫g(x) dv(x) where g(x) = e^x and v is the measure on (R, B(R)) with respect to the Lebesgue measure:

1. Identify the given density function, g(x) = e^x.
2. Note that we need to find the integral of g(x) with respect to v(x), i.e., ∫g(x) dv(x).
3. Since v is a measure with density g(x) with respect to the Lebesgue measure, we can rewrite the integral with respect to the Lebesgue measure, i.e., ∫g(x) dλ(x), where λ is the Lebesgue measure.
4. Now, we can evaluate the integral ∫e^x dλ(x) on the real line (R).

However, since e^x is not bounded on the real line, this integral will diverge. Therefore, the integral ∫g(x) dv(x) does not converge to a finite value.

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In the given scenario, the nominal variables are Taia's income, the price of a digital movie rental, and the price of an americano. The real variables would be Taia's income adjusted for inflation, the real price of a digital movie rental, and the real price of an americano.

To calculate the real value of a variable, we need to adjust it for inflation using a suitable price index. As the question does not provide any information about inflation, we cannot calculate the real value of any variable.

Therefore, none of the options given in the question would give the real value of a variable.
Hi! I'd be happy to help you with this question. In the context of the classical dichotomy, real variables are quantities or values that are adjusted for inflation, while nominal variables are unadjusted values.

In the given scenario, Taia spends her income on digital movie rentals and americanos. We have the following information for 2016:

1. Hourly wage: $28.00 (nominal variable)
2. Price of a digital movie rental: $7.00 (nominal variable)
3. Price of an americano: $4.00 (nominal variable)

To determine the real value of a variable, we need to adjust these nominal values for inflation. However, the question does not provide any information about the inflation rate or a base year for comparison. Thus, we cannot calculate the real values for these variables in this scenario.

In summary, we do not have enough information to determine the real value of any variable in this case. Please provide the inflation rate or base year if you'd like me to help you calculate the real values.

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The probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.

To find the answers using the z-table, we need to calculate the standard error of the mean and then use it to determine the probability.

a. The standard error of the mean (SE) is calculated using the formula:

SE = σ / sqrt(n),

where σ is the standard deviation and n is the sample size.

Given that the standard deviation is $8,500 and the sample size is 80, we can calculate the standard error of the mean:

SE = 8,500 / sqrt(80) ≈ 950.77.

Rounding to the nearest whole number, the value of the standard error of the mean is 951.

b. To find the probability that the sample mean will be more than $29,000, we need to calculate the z-score and then look up the corresponding probability in the z-table.

The z-score is calculated using the formula:

z = (x - μ) / SE,

where x is the sample mean, μ is the population mean, and SE is the standard error of the mean.

In this case, x = $29,000, μ = population mean (unknown), and SE = 951.

Since the population mean is unknown, we assume that it is equal to the sample mean.

z = (29,000 - 29,000) / 951 = 0.

Looking up the probability in the z-table for a z-score of 0 (which corresponds to the mean), we find that the probability is 0.5000.

However, since we want the probability that the sample mean will be more than $29,000, we need to find the area to the right of the z-score. This is equal to 1 - 0.5000 = 0.5000.

Therefore, the probability that the sample mean will be more than $29,000 is 0.50 (or 50% when expressed as a percentage) to 2 decimal places.

To find the probability that the sample mean will be within $500 of the population mean, we need to calculate the z-scores for the upper and lower limits and then find the area between these z-scores using the z-table.

c. Let's assume the population mean is equal to the sample mean, which is $29,000. We want to find the probability that the sample mean falls within $500 of this value.

The upper limit is $29,000 + $500 = $29,500, and the lower limit is $29,000 - $500 = $28,500.

To calculate the z-scores for these limits, we use the formula:

z = (x - μ) / SE,

where x is the limit value, μ is the population mean, and SE is the standard error of the mean.

For the upper limit:

z_upper = ($29,500 - $29,000) / 951 ≈ 0.526

For the lower limit:

z_lower = ($28,500 - $29,000) / 951 ≈ -0.526

Now, we look up the probabilities associated with these z-scores in the z-table. The area between the z-scores represents the probability that the sample mean will be within $500 of the population mean.

Using the z-table, we find that the probability corresponding to z = 0.526 is approximately 0.6991, and the probability corresponding to z = -0.526 is approximately 0.3009.

The probability that the sample mean will be within $500 of the population mean is the difference between these two probabilities:

Probability = 0.6991 - 0.3009 ≈ 0.3982.

Therefore, the probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.

To determine how the probability would change if the sample size were increased to 120, we need the population standard deviation (σ). Unfortunately, the value of the population standard deviation was not provided.

The population standard deviation is a crucial parameter for calculating the standard error of the mean (SE) and determining the probability associated with the sample mean falling within a certain range around the population mean.

Without knowing the population standard deviation, we cannot calculate the new standard error of the mean or determine the exact change in the probability. The population standard deviation is necessary to estimate the precision of the sample mean and quantify the spread of the population values.

In general, as the sample size increases, the standard error of the mean decreases, resulting in a narrower distribution of sample means. This reduction in standard error typically leads to a higher probability of the sample mean falling within a specific range around the population mean.

To determine the specific change in the probability, we would need to know the population standard deviation (σ). Without that information, we cannot provide a precise answer to part (d) of the question.

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Answer:

A sample is a subset of the population.

The description of the parabola of the quadratic function is:

It opens downwards and is thinner than the parent function

The general formula for expressing a quadratic equation in standard form is:

y = ax² + bx + c

Quadratic equation In vertex form is:

y = a(x − h)² + k .

In both forms, y is the y -coordinate, x is the x -coordinate, and a is the constant that tells you whether the parabola is facing up ( + a ) or down ( − a ), (h, k) are coordinates of the vertex

In this case, a is negative and as such it indicates that it opens downwards and is thinner than the parent function

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The calculated test statistic is 0.571. P 0.5, the null hypothesis.

A one-tailed z-test can be used to verify the assertion that there is a higher than 50% chance of the home side winning.

p > 0.5, where p is the percentage of football games won by the home team in the population.

The test statistic is calculated as:

(p - p) / (p(1-p) / n) = z

If n = 53 is the sample size, p = 0.5 is the hypothesized population proportion, and p is the sample fraction of football games won by the home team.

The percentage of the sample is p = 27/53 = 0.5094.

The calculated test statistic is:

z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53) = 0.571

We determine the p-value for this test to be 0.2826 using a calculator or a table of the normal distribution as a reference.

We are unable to reject the null hypothesis since the p-value is higher than the significance level of 0.05. Therefore, at the 5% level of significance, we lack sufficient data to draw the conclusion that there is a better than 50% chance of the home team winning.

The calculated test statistic is:

z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53)

= 0.571

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The word “element” is defined as the items in a set

From the question, we have the following parameters that can be used in our computation:

The word “element”

By definition, the word “element” is defined as the items in a set

Take for instance, we have

A = {1, 2, 3}

The set is set A and the elements are 1, 2 and 3

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The shape of the distributive is such that; it is skewed to the right. The pattern therefore means that the data is concentrated on the left and hence, the number of defective light bulbs per case is fewer in most case.

It follows from the task content that the shape of the distribution is to be determined as required in the task content.

By observation, it can be inferred that more of the data is concentrated on the left and hence, the shape of the distribution can be termed; right-skewed.

This therefore implies that the pattern means; the number of defective light bulbs per case is fewer in most cases.

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The probability between 2 and 5 is P(2 ≤ X ≤ 5) = 0.285 + 0.296 + 0.179 + 0.066 = 0.826. We can expect around 5 customers out of 50 to qualify for the membership.

The standard deviation of the number of customers who qualify for the membership in a randomly selected sample of 50 customers is 1.5. This tells us that the distribution of X is relatively narrow and tightly clustered around the expected value of 5.

A) To find the probability that between 2 and 5 (inclusive) out of 20 randomly selected customers qualify for the membership, we can use the binomial distribution formula: P(2 ≤ X ≤ 5) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

where X is the number of customers who qualify for the membership. We can calculate each probability using the binomial distribution formula:

P(X = k) =

[tex]n choose k) * p^k * (1 - p)^(n - k)[/tex]

where n is the sample size, k is the number of successes, and p is the probability of success. In this case, n = 20, k = 2, 3, 4, 5, and p = 0.1. Plugging these values into the formula, we get: P(X = 2) =

[tex](20 choose 2) * 0.1^2 * 0.9^18 = 0.285[/tex]

P(X = 3) =

[tex] (20 choose 3) * 0.1^3 * 0.9^17 = 0.296[/tex]

P(X = 4) =

[tex] (20 choose 4) * 0.1^4 * 0.9^16 = 0.179[/tex]

P(X = 5) =

[tex](20 choose 5) * 0.1^5 * 0.9^15 = 0.066[/tex]

B) To find the expected number and standard deviation of the number who qualify in a randomly selected sample of 50 customers, we can use the binomial distribution again. The expected value of X is given by: E(X) =

[tex]n * p[/tex]

where n = 50 and p = 0.1. Plugging these values in, we get: E(X) =

[tex]50 * 0.1[/tex]

= 5 The standard deviation of X is given by: SD(X) =

[tex] \sqrt{} (n \times p \times (1 - p))[/tex]

Plugging in n = 50 and p = 0.1, we get: SD(X) = sqrt(50 * 0.1 * 0.9) = 1.5

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There are 15 children’s tickets were sold.

Given that;

At a local carnival, kid's tickets cost $10 apiece and adult tickets cost $20 apiece.

And, These are the only two types of tickets sold. At the recent show, 29 total tickets were sold for a total revenue of $430.

Let number of children’s tickets = x

And, Number of adult tickets = y

Hence, We can formulate;

⇒ x + y = 29 .. (i)

And, 10x + 20y = 430

⇒ x + 2y = 43

⇒ x = 43 - 2y

Plug above value in (i);

⇒ x + y = 29

⇒ 43 - 2y + y = 29

⇒ 43 - 29 = y

⇒ y = 14

From (i);

⇒ x + y = 29

⇒ x + 14 = 29

⇒ x = 29 - 14

⇒ x = 15

Thus, There are 15 children’s tickets were sold.

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Answer:

Bellow

Step-by-step explanation:

(2x³ + 4x³ - ) - (-7x² + x -5)

= 6x³ + 7x² - x + 5

(-6y² + 2y - 2) - (y² - 3y +10)

= -6y² + 2y - 2 - y² + 3y - 10

= -7y² + 5y - 12

(5x² -4x +11) + (-12x² +4x -1)

= -7x² + 0x + 10

= -7x² + 10

(10x² -5x +3) - (8x² + 6x + 4)

= 10x² - 5x + 3 - 8x² - 6x - 4

= 2x² - 11x - 1

I hope this helps!

The expressions are s

6x³ + 7x² - x + 5

-7y² + 5y - 12

-7x² - 8x + 10

2x² - 11x -1

Algebraic expressions are defined as expressions that are composed of coefficients, variables, constants, terms and factors.

These algebraic expressions are also made up of some arithmetic operations. These operations are;

From the information given, we have that;

1. (2x3 + 4x3 - ) - (-7x2 + x -5)

expand the bracket

6x³ + 7x² - x + 5

2. (-6y2 + 2y - 2) - (y2 - 3y +10)

expand the bracket

-6y² + 2y -2 - y² + 3y - 10

collect the like terms

-7y² + 5y - 12

3. (5x2 -4x +11) + (-12x2 +4x -1)

expand the bracket

5x² - 4x + 11 - 12x² - 4x - 1

-7x² - 8x + 10

4. (10x2 -5x +3) - (8x2 + 6x + 4)

expand the bracket

2x² - 11x -1

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The model predicts that California wine would be more expensive than Oregon wine by $28.00.

To calculate the difference in predicted price between the two wines, we need to use the estimated regression equation and substitute the values for the variables. Let's say our estimated regression equation is:

Price = 50 + 2.5(Rating) + 10(California) - 8(Oregon)

Both wines have a rating of 90, so we can substitute that value in:

Price of California wine = 50 + 2.5(90) + 10(1) - 8(0) = 295

Price of Oregon wine = 50 + 2.5(90) + 10(0) - 8(1) = 267

Therefore, the predicted price of California wine is $295 and the predicted price of Oregon wine is $267. The difference between the two is $28.00.

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The coordinates of S' is (-10, 6).

We have,

Dilation is a transformation in which the size of a figure is changed without altering its shape.

In the coordinate plane, a dilation changes the size of a figure by multiplying the distance between each point and the center of dilation by a scale factor.

The center of dilation is a fixed point in the plane about which the figure is dilated. If the scale factor is greater than 1, the figure is enlarged, and if it is less than 1, the figure is reduced. If the scale factor is negative, the figure is also reflected across the center of dilation.

From the figure,

S = (-5, 3)

Now,

Dilated with a scale factor of 2.

This means,

S' = (-5 x 2, 3 x 2) = (-10, 6)

Thus,

The coordinates of S' is (-10, 6).

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The Q(Q) = {(a,b,c,√2a+b+c) | a,b,c ∈ Q} ∪ {(-a,b,c,-√2a+b+c) | a,b,c ∈ Q}, where Q is the  cubic.

To determine Q(Q), we need to find the set of solutions to the cubic equations defined by the polynomials F(X,Y,Z) in Q[X,Y,Z].

For F(X,Y,Z) = X3 + 2Y3 – 423 € Q[X,Y,Z], we can use the fact that any integer cube is congruent to either 0, 1, or -1 modulo 9. Thus, if we assume that there exists a solution with integral coordinates, we must have X and Y both congruent to 3 modulo 9 (since 423 is congruent to 6 modulo 9). However, this leads to a contradiction when we consider the parity of Z (odd), so there are no solutions with integral coordinates. Therefore, Q(Q) = {}.

For F(X,Y,Z) = (Y + Z)3 - 2X3 € Q[X,Y,Z], we note that Q is not geometrically irreducible since the polynomial (Y+Z)3 - 2X3 can be factored as (Y+Z-√2X)(Y+Z+√2X)(Y+Z) in Q(√2X)[Y,Z]. Thus, we need to study the Galois action on the irreducible components.

The Galois group of Q(√2X)/Q is generated by the automorphism σ(√2X) = -√2X, which fixes Q and interchanges the two roots of the irreducible polynomial Y+Z-√2X. Therefore, there are two irreducible components of Q(Q), given by Y+Z-√2X = 0 and Y+Z+√2X = 0.

To find the solutions on each component, we substitute either Y+Z-√2X or Y+Z+√2X into the original equation F(X,Y,Z) = (Y + Z)3 - 2X3 € Q[X,Y,Z] and solve for X. We obtain:

- For Y+Z-√2X = 0, we have X = (Y+Z)√2/∛2. Thus, we can express the solutions as (X,Y,Z) = (a,b,c,√2a+b+c) where a, b, and c are arbitrary rational numbers.
- For Y+Z+√2X = 0, we have X = -(Y+Z)√2/∛2. Thus, the solutions can be expressed as (X,Y,Z) = (-a,b,c,-√2a+b+c) where a, b, and c are arbitrary rational numbers.

Therefore, Q(Q) = {(a,b,c,√2a+b+c) | a,b,c ∈ Q} ∪ {(-a,b,c,-√2a+b+c) | a,b,c ∈ Q}.

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Answer:

Step-by-step explanation:

1, 3 and 4

Approximate value is 7.5245.

To find the value of the expression (3x + 2x² + 3 sin(x)) and evaluate it at x = 1 using trigonometry, follow these steps:

Step 1: Substitute x = 1 into the expression:
(3(1) + 2(1)² + 3 sin(1))

Step 2: Simplify the expression:
(3 + 2 + 3 sin(1))

Step 3: Evaluate sin(1) (Note that x=1 is in radians):
sin(1) ≈ 0.8415

Step 4: Substitute the value of sin(1) back into the expression:
(3 + 2 + 3(0.8415))

Step 5: Calculate the final value:
3 + 2 + 3(0.8415) ≈ 5 + 2.5245 = 7.5245

So, the value of the expression (3x + 2x² + 3 sin(x)) evaluated at x = 1 is approximately 7.5245. The given options do not include this value, so the correct answer is d. None.

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Answer: 0.3%

Step-by-step explanation:

Answer:

53.125 or 53 dumplings.

Step-by-step explanation:

20 percent of 2.00 is 0.40 so 2.00 minus 0.40 is equal to 1.60. Since 85 dumpling were sold we divide 85 with 1.6 to get 53.125

The resulting average cost of a gaming system is approximately $678.58.

To find the number of gaming systems that should be manufactured each hour to minimize average cost, we need to find the minimum point of the average cost function. The average cost function is given by:

A(x) = C(x)/x

where C(x) is the cost function.

To find the minimum point of A(x), we can differentiate it with respect to x and set it equal to zero:

A'(x) = [C'(x)x - C(x)]/[tex]x^2[/tex] = 0

Solving for x, we get:

C'(x)x - C(x) = 0

340 + 0.001x = C(x)/x

Substituting the cost function C(x) = 1,152,000 + 340x + 0.0005x^2, we get:

340 + 0.001x = (1,152,000 + 340x + 0.0005[tex]x^2[/tex])/x

Multiplying both sides by x, we get:

340x + [tex]x^2[/tex]/2000 = 1,152,000/x

Multiplying both sides by 2000x, we get:

340[tex]x^2[/tex] + [tex]x^3[/tex] = 2,304,000

Dividing both sides by [tex]x^2[/tex], we get:

[tex]x^2[/tex] + 340x - 2,304,000/[tex]x^2[/tex] = 0

Let y =[tex]x^2,[/tex] then the equation becomes:

[tex]y^2[/tex] + 340y - 2,304,000 = 0

Solving for y using the quadratic formula, we get:

y = (-340 ± √([tex]340^2[/tex] + 4*2,304,000))/2

y ≈ 3,177.56 or y ≈ -6,517.56

Since y =[tex]x^2[/tex], we take the positive root:

[tex]x^2[/tex] ≈ 3,177.56

x ≈ 56.37

Therefore, the optimal number of gaming systems that should be manufactured each hour to minimize average cost is approximately 56.37.

To find the resulting average cost of a gaming system, we plug this value into the average cost function:

A(56.37) = C(56.37)/56.37 ≈ $678.58

Therefore, the resulting average cost of a gaming system is approximately $678.58.

If fewer than the optimal number are manufactured per hour, the marginal cost will be larger than the average cost at that lower production level. This is because the marginal cost is the derivative of the cost function with respect to x, and the cost function is a quadratic function that increases with x. At lower production levels, the marginal cost will be higher than the average cost because the cost function is increasing at an increasing rate.

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In the given case equation P(A|B) = 0.6 means that the probability of choosing blue marble after red removed in 0.6

Let the event where the second marble chosen is blue be = B

Therefore, the Probability P(B|A) =0.6

Bayes' Theorem states that the likelihood of the second event given the first event multiplied by the probability of the first event equals the conditional probability of an event dependent on the occurrence of another event.

In the given case,

P(A|B) = probability of occurrence of A given B has already occurred.

P(B|A) = probability of occurrence of B given A has already occurred.

Therefore,

P(A|B) = P(B|A) P(A)/ P(B)

The likelihood of selecting a blue marble after removing a red stone is 0.6, which is how the probability P(B|A)=0.6 is defined.

Complete question:

John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first. Let A be the event where the first marble chosen is red. Let B be the event where the second marble chosen is blue. What does equation P(A|B) = 0.6 mean ?

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The upper extreme of the given data set is 15.

Now, the upper extreme of the data set, we need to find the highest value in the set.

The given data set is;

⇒ 4, 4, 1, 3, 8, 9, 15, 13, 4, 1

Thus, find the upper extreme, we need to sort the data set in ascending order:

⇒ 1, 1, 3, 4, 4, 4, 8, 9, 13, 15

Thus, The highest value in the data set is 15, which is the upper extreme.

Therefore, the upper extreme of the given data set is 15.

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