HBr(aq) and Ca(OH)2(aq) Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

Answer:

The mass of 3.5 moles of Ca is 140 g to two significant figures

Answer:

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Answer:

Sorry I didn't get it

Explanation:

Where is the question?

Based on the nature of the reactants in each of the equations below, which reaction at 25°C will occur at the fastest rate will be-

NaOH + HCl = NaCl + H₂O and the correct option is option B.

The rate of reaction or reaction rate is the speed at which reactants are converted into products. When we talk about chemical reactions, it is a given fact that rate at which they occur varies by a great deal.

Some chemical reactions are nearly instantaneous, while others usually take some time to reach the final equilibrium.

Increasing the surface area of one or more reactants affect the reaction rate of a system will speed up the reaction.

increase the concentration of a reactant will usually speed the reaction rate of a chemical system.

Therefore, based on the nature of the reactants in each of the equations below, which reaction at 25°C will occur at the fastest rate will be-

NaOH + HCl = NaCl + H₂O and the correct option is option B.

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Answer:

6.9

Explanation:

Mass(m)=?

Density (D)=0.75

Volume (v)=9.2

M=D×V

M=0.75×9.2

M=6.9

Answer:   aaaaaaaaaaa

The basic SI unit for volume is the cubic meter (m3), but smaller volumes may be measured in cm3, and liquids may be measured in liters (L) or milliliters (mL).

Explanation:

Answer:

12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

Explanation:

carry on learning

Answer:

0.85 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles (n) corresponding to 660 g of calcium phosphate (solute)

We will use the following expression.

n = m/M

n = 660 g/(310.18 g/mol) = 2.13 mol

Step 3: Calculate the molar concentration (molarity) of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 2.13 mol/2.5 L = 0.85 M

Answer:

See explanation

Explanation:

From the parameters provided;

V=?

n= 1.46 moles

P= 0.982 ATM

T= 13°C + 273 = 286 K

R = 0.0821 L.atm/mol.K

From

PV= nRT

V= nRT/P

V= 1.46 × 0.0821 × 286/0.982

V= 34.9 L

b) Boyle's law states that, the pressure of a given mass of gas is inversely proportional to its volume at constant temperature and pressure. This statement is a correct postulation about ideal gases which can be arrived at from the kinetic theory of gases.

Answer:

1.1 × 10² g

Explanation:

The combustion of gasoline releases energy that is used to move the car. The enthalpy of reaction (ΔH°rxn) of the combustion of gasoline is 47 kJ/g, that is, 47 kiloJoule are produced per gram of gasoline burned. The mass of gasoline to be burned to release 5,375 kJ is:

5,375 kJ × 1 g Gasoline/47 kJ = 1.1 × 10² g

Answer: The molar mass of protein A is 3023.41 g/mol.

Explanation:

To calculate the osmotic pressure, we use the formula:

[tex]\pi=i\times M\times R\times T[/tex]

              OR

[tex]\pi=i\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution}}\times R\times T[/tex]      .....(1)

Where,

[tex]\pi[/tex] = osmotic pressure = 0.285 atm

i = 1

Given mass of protien (solute) = 54.1 mg = 0.0541 g        (Conversion factor: 1 g = 1000 mg)

Volume of solution = 1.5 mL

R = Gas constant = 0.0821 L.atm/mol.K

T = temperature = [tex]18^oC=[18+273]=291K[/tex]

Plugging values in equation 1:

[tex]0.285atm=1\times \frac{0.0541\times 1000}{\text{Molar mass of protein}\times 1.5}\times 0.0821L.atm/mol.K\times 291K\\\\\text{Molar mass of protein}=\frac{1\times 0.0541\times 1000\times 0.0821\times 291}{0.285\times 1.5}\\\\\text{Molar mass of protein}=3023.41g/mol[/tex]

Hence, the molar mass of protein A is 3023.41 g/mol.

The molar mass of the protein is  3018 g/mol.

We know that the osmotic pressure is obtained using the formula;

Osmotic pressure = iMRT

concentration of the  protein = 54.1 * 10^-3g/M/ 1.5 * 10^-3 L

Where M = molar mass of the protein

So;

0.285 atm =  54.1 * 10^-3g/ 1.5 * 10^-3 L M * 0.0821 L.atm/mol.K * 291 K

0.285  = 1.29/1.5 * 10^-3M

M = 1.29/0.285 * 1.5 * 10^-3

M = 3018 g/mol

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Explanation:

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Technology.

Answer:

% yield = 200%

Explanation:

By using 145 gram of aluminium

Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced

Using 145 grams of aluminium, the yield of Aluminium oxide  would have been = (101.96 g/mol/26.982 g/mol)/145 grams

= 547.9282485 gram

Now % yield = actual yield /theoretical yield * 100

Substituting the given values, we get -

% yield = (547.928/270) *100

% yield = 200%

29.26 gram

Explanation:

No of molecules = no of mole × Avogadro's number

No of molecules = mass in gram/ molar mass × Avogadros number

Mass in gram =No of molecules×molar mass / Avogadros number

Mass in gram = 3.012 ×10^23 × 58.5/6.02×10^23

29.26 gram

Answer:

A

Explanation:

because it occurs in nature and all other option are synthesis.

Answer: Bacterial species where observed Typical number on cell Distribution on cell surface

Escherichia coli (common pili or Type 1 fimbriae) 100-200 uniform

Neisseria gonorrhoeae 100-200 uniform

Streptococcus pyogenes (fimbriae plus the M-protein) ? uniform

Pseudomonas aeruginosa 10-20 polar

Explanation:

Pili are structures that extend from the surface of some bacterial cells.

These are hollow, non-helical, filamentous appendages.

Hope it helps you

Explanation:

Correct option is

B

0.750 M

Na3PO4 dissociates as:

Na3PO4⇌3Na++PO43−

∴ conc. of Na+ would be =3×0.250=

hope help

Answer:

No, the product is not chiral

Explanation:

The compound (S)-3-Methylhexane is chiral. However, the bromination of this compound via free radical mechanism yields an achiral intermediate as shown in the image attached to this answer.

This achiral intermediate is a flat and planar tertiary radical. Attack on either face of this radical specie is possible. This leads us to obtain a 50-50 mixture of (R) and (S) - 3-bromo-3-methylhexane.

This is a racemic mixture hence it is optically inactive.

Answer:

12 mol CO₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

Identify

[rxn] 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

[Given] 2 mol C₆H₁₂O₆

[Solve] mol CO₂

Step 2: Identify Conversions

[rxn] 6CO₂ → C₆H₁₂O₆

Step 3: Convert

Answer:

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca^2 , Al^3 ,I^-,S^2-

Explanation:

1)Formula of calcium iodide:

The compound of Ca^2+ and I^-1:

[tex]CaI_2[/tex]

2) Formula of calcium sulfide:

[tex]CaS[/tex]

3) Formula of aluminum iodide:

[tex]AlI_3[/tex]

4) Formul aluminum sulfide:

[tex]Al_2S_3[/tex]

These are the four ionic compounds that are formed.

Answer:

If the density of the material is equal to the density of the material you have been working with it is possible that the samples are the samples

Explanation:

Density is an intensive property of the matter (Doesn't depends of its amount) that is widely used to identify a substance. Density is the ratio between the mass of the substance (In this case 25.62g) and the volume this amount occupies (21.9cm³). The density is:

25.62g / 21.9cm³ =

1.17g/cm³.