Helium gas is being pumped into a rigid container at a constant temperature. As a result, the pressure of helium in the container is increasing. Select the one correct statement below.
a) As the pressure increases, helium atoms move faster, on average.
b) As the pressure increases, helium atoms move more slowly, on average.
c) As the pressure increases, helium atoms stay closer to the wall of the container, on average.
d) As the pressure increases, the volume of the container must decrease.
e) As the pressure increases, there are more collisions of helium atoms with the container wall.

Answers

Answer 1

Answer: e. As the pressure increases, there are more collisions of helium atoms with the container wall.

Explanation:

We are given the information that helium gas is pumped into a rigid container at a constant temperature.

Due to this reason, there was a rise in the pressure of helium in the container. We should note that as the pressure rises, there are more collisions of helium atoms with the container wall.

Answer 2

The increase in the pressure of He atoms results in the increased collision of atoms with the wall. Thus, option E is correct.

The helium in the container is assumed to be an ideal gas. The ideal gas reaction is given as:

[tex]PV=nRT[/tex]

Where,

P= PressureV=volumen=molesR=Rydberg constantT=temperature

What happens to gas with an increase in pressure?

The ideal gas equation depicts that the gas is contained in a closed container. Thus, the moles, n of gas are constant. The pressure is pumped at a constant temperature, thereby T is also constant.

The R is a constant in the ideal gas equation. The increase in the pressure of the container results in the increased kinetic energy of the helium atoms.

The increase in the collisions is observed for the molecules with the container wall.

Thus, with the increase in pressure, the collisions in the atoms increase. Hence, option E is correct.

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Related Questions

how many molecules of sugar are in 4.67 miles of sugar?

Answers

12.69437613miles ( I think)

Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 14. g of hydrochloric acid is mixed with 6.55 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.

Answers

Answer:

8.02 g of HCl could be left over by the chemical reaction

Explanation:

We propose the reaction:

HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)

Ratio is 1:1. First of all, we determine the moles of reactants:

14 g . 1mol / 36.45g = 0.384 mol of acid

6.55 g. 1mol / 40g = 0.164 mol of base

If a determined mass of HCl, could be left; this means that the acid is the excess reagent.

For 0.164 moles of NaOH, we need 0.164 moles of HCl.

As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:

0.220 mol . 36.45 g /1mol = 8.02 g

Which statement is true about the speed of light? (2 points)

Light travels relatively slowly.

Distance in space is measured using the speed of light.

Time in space is measured using the speed of light.

The speed of light is unknown

Answers

Answer:

2nd option is the correct answer of this question

Answer:

yes it is b

Explanation:

How much energy is required to remove a neutron from the nucleus of an atom of carbon-13?

Answers

Answer:

uh i think 12?

Explanation:

A student burned her magnesium sample according to the procedure and obtained a light gray product. Since the crucible looked dirty anyway, she skipped the steps to convert the Mg3N2 contamination to MgO, weighed the gray sample, and calculated the mass of her product. Was her resulting mass likely to be higher or lower the expected

Answers

Answer:

The resulting mass will be higher than expected

Explanation:

We have to keep this in mind; When magnesium is being burnt in air, two reactions are taking place. The first one is;

2Mg(s) + O2(g) ------> MgO(s)   -------1

And

3Mg(s) + N2(g) -------> Mg3N2(s)  ---------2

Now, if the steps that should be taken to convert Mg3N2 to MgO are not taken, the reaction is much quicker but a higher mass of solid is obtained than what was expected.

This higher mass of solid obtained owes to the fact that Mg3N2 from reaction 2 was not converted to MgO leading to contamination of the product.

When 9.00 g C6H12O6 burns with excess oxygen, how many grams
of CO2 will be made?
- 0.44 g
- 6.6 g
- 2.2 g
- 13.2 g

Answers

When 9.00 g C6H1206 burn with excess oxygen is -13.2g

The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-1. If the initial pressure of N2O is 3.50 atm at 730°C, calculate the total gas pressure after one half-life. Assume that the volume remains constant. Insert your answer in decimal notation rounded to 3 significant figures.

Answers

Answer:

 the total gas pressure after one half-life is 4.38 atm

Explanation:

The balanced equation for the decomposition of N2O to N2 and O2 is given as:

2N₂O(gas) ⇒ 2N₂(gas) + O₂(gas)

2 moles of N₂O produce 2 moles of N₂ and 1 mole of O₂

The change in pressure depends on the coefficient (number of moles) of the reactant and product.

                                                          N₂O                    N₂                     O₂

number of moles                                2                        2                        1

Initial pressure (atm)                           3.50                  0                        0

change in pressure                            -2x                    +2x                      x

Final pressure (atm)                            3.50 - 2x           2x                       x

The total final pressure is the sum of the individual total pressure. i.e.:

Total final pressure = final pressure of N₂O + final pressure of N₂ + final pressure of O₂

Total final pressure = (3.5 - 2x) + (2x) + x

Total final pressure = 3.5 + x

After one half life, the initial pressure of N₂O would be half its value.

Final pressure of N₂O = half of the initial pressure of N₂O

3.5 - 2x = 0.5(3.5)

3.5 - 2x = 1.75

2x = 1.75

x = 0.875 atm

Therefore, Total final pressure = 3.5 + x = 3.5 + 0.875

Total final pressure = 4.38 atm to 3 significant figures

How many atoms are in 34 g of Cu?

Answers

Answer:

Babygirl these are double DD'S

Explanation:

OooOOO I'm hurt oh my neck my neck and my back

Select all of the Earth Systems that contain carbon.
Oa Atmosphere
Ob Geosphere
Oc Biosphere
Od Hydrosphere

Answers

Answer:

a, c, d

Explanation:

biosphere atmosphere hydrosphere lithosphere

What are the names of the stable forms of oxygen?

Answers

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

The stable forms of oxygen are molecular oxygen ([tex]O_{2}[/tex]) and ozone ([tex]O_{3}[/tex]). Molecular oxygen is the most common form in the Earth's atmosphere, while ozone is found in the ozone layer of the atmosphere and has a different molecular structure than [tex]O_{2}[/tex].

The most  stable type of oxygen in the Earth's atmosphere is [tex]O_{2}[/tex], sometimes referred to as molecular oxygen or dioxygen. It is made up of two oxygen atoms joined by a link.

Another stable form of oxygen is [tex]O_{3}[/tex], also referred to as ozone. It is a molecule made up of three linked oxygen atoms. The ozone layer in the stratosphere of the Earth contains ozone, which is essential for protecting life on the planet by absorbing damaging ultraviolet (UV) radiation from the Sun.

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Copper(II) chloride hydrate, also known as copper chloride hydrate, is the inorganic compound with the chemical formula CuCl2 . x(H2O), where x can range from 1 to 7. A 2.060 g sample of copper (II) chloride hydrate was dissolved in 50.0 mL of deionized water. The concentration of copper (II) ion in the solution was determined spectrophotometrically using the equation from the calibration curve, was 0.200 M. Determine the formula of the copper (II) chloride hydrate.

Answers

Answer:

CuCl₂·4H₂O

Explanation:

First we calculate the moles of copper (II) ion in the solution, using the given volume and concentration:

50.0 mL ⇒ 50.0/1000 = 0.05 L0.05 L * 0.200 M = 0.01 mol Cu⁺²

For each Cu⁺² mol there's also one CuCl₂ mol.

We convert 0.01 CuCl₂ moles into grams, using its molar mass:

0.01 CuCl₂ mol * 134.45 g/mol = 1.344 g

That means that out of the 2.060 g of the sample, 1.344 g are of CuCl₂. This means that there are (2.060 - 1.344) 0.716 g of water.

We convert those 0.716 g of water to moles:

0.716 g ÷ 18 g/mol = 0.04 mol H₂O

There are four times as many H₂O moles as there are CuCl₂ moles. This means the formula is CuCl₂·4H₂O

Based on your understanding of color's relationship to wavelength, identify the approximate wavelength of light (nm) emitted by strontium when it was burned in Part C. (No quantitative data was collected for this; you are giving an approximate value only, based on what you observed.) Explain your reasoning in full, making sure to cite specific data and observations to support your answer.

Answers

Answer:

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

Explanation:

Visible light is part of the electromagnetic spectrum. The electromagnetic waves are composed of electric and magnetic fields.

The visible spectrum is composed of seven different wavelengths that corresponds to different colours. When a metallic element is exposed flame, one of these colours is observed. This is commonly called the flame test.

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

The approximate wavelength of light (nm) emitted by strontium when it was burned is red, where red has a wavelength of round 620-750 nm.

Wavelength of light emitted by strontium

Generally, Visible mild is phase of the electromagnetic spectrum. the electromagnetic waves are composed of electric powered and magnetic fields. When a metal factor is uncovered flame, one of they seven colors of visible spectrum is seen.

The flame shade of strontium is red, where red has a wavelength of round 620-750 nm.

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In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 5 mL 4.0M acetone 5 mL 1.0 M HCl 5 mL 0.0050 M I2 10 mL H2O While keeping the total volume at 25 mL and keeping the concentration of H ion and I2 as in the original mixture, how could you double the molarity of the acetone in the reaction mixture

Answers

Answer:

Explanation:

pls give me point so i can ask questions

A chemical equation is balanced when the number of each
type of ____ is the same on both sides of the equation.

Answers

Answer:

element

Explanation:

Phosphorus is commercially prepared by heating a mixture of calcium phosphate, sand, and coke in an electric furnace. The process involves two reactions. 2 Ca3(PO4)2(s) 6 SiO2(s) 6 CaSiO3(l) P4O10(g) P4O10(g) 10 C(s) P4(g) 10 CO(g) The P4O10 produced in the first reaction reacts with an excess of coke (C) in the second reaction. Determine the theoretical yield of P4 if 293.5 g Ca3(PO4)2 and 378.5 g SiO2 are heated. (No Response) g If the actual yield of P4 is 44.9 g, determine the percent yield of P4.

Answers

Answer:

76.6% is percent yield of P₄

Explanation:

Percent yield is defined as 100 times the ratio of actual yield and theoretical yield. To solve this quesiton we need to find the theoretical yield of the reaction. Using:

2Ca₃(PO₄)₂(s) + 6SiO₂(s) → 6CaSiO₃(l) + P₄O₁₀(g)

P₄O₁₀(g) + 10C(s) → P₄(g) + 10CO(g)

We need to find the moles of Ca₃(PO₄)₂ and SiO₂ to find limiting reactant. With limiting reactant we can find moles of P₄O₁₀ = Moles of P₄. We must convert the moles of P₄ to mass using Molar mass (P₄ = 123.895g/mol):

Moles Ca₃(PO₄)₂ -Molar mass: 310.1767g/mol-

293.5g * (1mol / 310.1767g) = 0.9462moles

Moles SiO₂ -Molar mass: 60.08g/mol-:

378.5g * (1mol / 60.08g) = 6.30 moles

For a complete reaction of 6.30 moles of SiO₂ there are required:

6.30 moles SiO₂ * (2 moles Ca₃(PO₄)₂ / 6 moles SiO₂) =

2.10 moles Ca₃(PO₄)₂. As there are just 0.9462 moles, Ca₃(PO₄)₂ is limiting reactant

Moles P₄O₁₀ = Moles P₄:

0.9462moles Ca₃(PO₄)₂ * (1mol P₄O₁₀ / 2 mol Ca₃(PO₄)₂) = 0.4731 moles P₄O₁₀ = Moles P₄.

The mass is:

0.4731 moles P₄ * (123.895g / 1mol) = 58.6g = Theoretical yield.

Percent yield is:

44.9g / 58.6g * 100 =

76.6% is percent yield of P₄

what causes deep ocean currents to flow

Answers

Answer:Deep ocean currents (also known as Thermohaline Circulation) are caused by: ... The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.

Explanation:

In order to be in a position to manipulate any operation, one has to know all the fine details of the system and where and how one might apply subtle changes to affect the outcome. When looking at chemical reactions, it is from the study of its kinetics that one gleams the insight necessary to be able to do this. The main use of chemical kinetics is to measure the speed of a chemical reaction. But more importantly, in measuring the speed of a reaction, one gains insight as to what part of the reaction imparts this speed (or lack thereof) and thus allows one to propose a specific mechanism that details the critical pathway for the reaction. Measuring the speed of a chemical reaction is very similar to measuring speed in general, except that instead of talking in terms of distance traveled per unit time we are measuring either reactants consumed per unit time or products produced per unit time. There are many factors that affect the speed of a chemical reaction, some of the more common ones being:

Answers

Answer:

See explanation

Explanation:

Chemical kinetics, the branch of physical chemistry that is concerned with understanding how fast or how slow chemical reactions occur (Encyclopedia Britannica).

The study of the kinetics of a chemical reaction is helpful in many ways. Most important is the fact that it allows one to propose a specific mechanism that details the critical pathway for the reaction.

The factors that affect the rate of chemical reaction includes; concentration of reactants, temperature, nature of reactants , the solvent used, the presence of a catalyst, presence of light, surface area of reactants and pressure for gaseous reactants.

4 points 15. The diagram below shows the relative positions of Earth, the moon, and the sun. The moon is shown at four possible positions around Earth. 3 Sunlight Sun Earth mo Which position of the moon could result in a lunar eclipse? В. 2 A B ​

Answers

Answer:

b c

Explanation:

Answer: b c

Explanation: i did test


Strontium chlorate is mixed with ammonium phosphate

Answers

Explanation:

Please, if I may ask, what is the exact question?

Rotation about C-C single bonds allows a compound to adopt a variety of _____________. conformations configurations formations isomers projections are often used to draw the various conformations of a compound. conformations are lower in energy, while conformations are higher in energy. The difference in energy between staggered and eclipsed conformations of ethane is referred to as strain. strain occurs in cycloalkanes when bond angles deviate from the preferred °. The conformation of cyclohexane has no torsional strain and very little angle strain. The term "ring flip" is used to describe the conversion of one conformation into the other. When a ring has one substituent the equilibrium will favor the chair conformation with the substituent in the position.

Answers

Answer:

Conformation

Explanation:

Conformation refers to "any of the spatial arrangements which the atoms in a molecule may adopt and freely convert between, especially by rotation about individual single bonds"(Oxford dictionary).

Carbon-Carbon single bonds are known to undergo rotations about its axis. These rotations leads to various conformations. The energy difference between conformations may be low or high depending on the structure of the molecule. The difference in energy between conformations determines a molecules's preferred conformation.

How does the average reaction rate differ from an instantaneous reaction rate?
a) The average reaction rate is how quickly the reaction proceeds at a specific time. An instantaneous reaction rate is how quickly the reaction proceeds over time.

b) The average reaction rate is how quickly the reaction proceeds over time considering the reactants. An instantaneous reaction rate is how quickly the reaction proceeds at a specific time considering the products.

c) The average reaction rate is how quickly the reaction proceeds over time. An instantaneous reaction rate is how quickly the reaction proceeds at a specific time.

d) The average reaction rate is how quickly the reaction proceeds over time. An instantaneous reaction rate is how quickly the reaction proceeds compared to another reaction.

Answers

C because the average is receipt rate is how quickly

Answer:

The average reaction rate is how quickly the reaction proceeds at a specific time. An instantaneous reaction rate is how quickly the reaction proceeds over time.

Explanation:

A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M NaCl, 0.1 M Ca(NO3)2, 0.1 M KCH3COO The student decides to add some 0.1 M Pb(NO3)2 to a sample of the reagent in question. Upon stirring, a white precipitate formed. Which of the possible solutions was present in the unlabeled container based on this observation

Answers

Answer:

He kinda lazy ngl

Explanation:

Rgheeghfgufugf

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Answers

Answer:

Thank you for the free points!!

Explanation:

What are metalloids?

Answers

A metalloid is a type of chemical element which has a preponderance of properties in between, or that are a mixture of, those of metals and nonmetals.

Answer:

Metalloid, in chemistry, an imprecise term used to describe a chemical element that forms a simple substance having properties intermediate between those of a typical metal and a typical nonmetal. There is no single property which can be used to unambiguously identify an element as a metalloid.


Which would be another way to make the ice melt faster

Answers

Answer:

d because ur heating the ice and causing friction

Practice Problem Website: https://www3.nd.edu/~smithgrp/structure/workbook.html
1. Click on Do the problems
2. Click on the number for the practice problem to be completed
3. Click on IR
Example of problem 1 from the website:
Formula: C3H5BrO2

IR Peaks:
1717 nm—Strong peak indicates a carbonyl group C=O
2571-2670 nm- medium peak indicates sp3 hybrid C-H.
3067 nm --- Broad medium peak indicates OH group, specifically in a carboxylic acid (Would not be a carboxylic acid without the carbonyl peak as well)

Complete the following problems: 3, 5, 7, 8, 12, 13, 27, 32, 38, and 40.
Be as accurate as possible. I am looking for the frequency and molecular formula to make sense with the functional group you think is represented.

Answers

6787.67458865446899675566

If 27.37ml of 0.2115M NaOH is able to neutralize 37.45 of HCl, what is the concentration of the acid?

Answers

You just gotta match the moles:

moles of NaOH = 0.02737 L * 0.2115 M = 0.005789 mol of NaOH. The amount of moles of HCl it can neutralize should be the same since they are in a 1:1 ratio. Therefore, you can do moles of NaOH divided by 0.003745L to get the answer. It turns out to be 0.1546M.

Some hypothetical alloy is composed of 25 wt% of metal A and 75 wt% of metal B. If the densities of metals A and B are 6.17 and 8.00 g/cm3 , respectively, and their respective atomic weights are 171.3 and 162.0 g/mol, determine whether the crystal structure for this alloy is simple cubic, facecentered cubic, or body-centered cubic. Assume a unit cell edge length of 0.332 nm

Answers

Answer:

Simple cubic

Explanation:

The density of metal A (ρa) = 6.17 g/cm³, The density of metal B (ρb) = 8 g/cm³, The atomic weight of metal A (Aa) = 171.3 g/mol, The atomic weight of metal B (Ab) = 162 g/mol, the unit cell edge length (a) = 0.332 nm, concentration of metal A (Ca) = 25%, concentration of metal B (Cb) = 75%

The average density is given by:

[tex]\rho_{ave}=\frac{100}{\frac{C_a}{\rho_a} +\frac{C_b}{\rho_b} } \\\\\rho_{ave}=\frac{100}{\frac{25}{6.17} +\frac{75}{8} } =7.45\ g/cm^3\\\\The\ average\ atomic\ weight\ is:\\\\A_{ave}=\frac{100}{\frac{C_a}{A_a} +\frac{C_b}{A_b} } \\\\A_{ave}=\frac{100}{\frac{25}{171.3} +\frac{75}{162} } =164.23\ g/mol\\\\The\ number\ of\ atoms\ per\ unit(n)\ is:\\\\n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} \\\\N_A=Avogadro\ constant=6.02*10^{22} \ mol^{-1},a=0.332\ nm=3.32*10^{-8}cm\\\\Substituting:\\\\[/tex]

[tex]n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} =\frac{7.45*(3.32*10^{-8})^3*6.02*10^{23}}{164.23} \\\\n=0.999\\[/tex]

n≅1

Since n≅1, the crystal structure for this alloy is simple cubic

How many significant figures
are in this number?
3 x 10^6

Answers

answer: 1
I solved for the equation and got 1000000 then multiply by 3
Significant figure is “3”
There’s only one number of a significant figure though

54.1miles/gallons how many liters of gas will be consumed traveling 132 km

Answers

Answer:

5.75 L.

Explanation:

From the question given above, the following data were obtained:

Rate = 54.1 miles/gallons

Distance = 132 km

Volume (in L) consumed =?

Next, we shall convert 132 km to mile. This can be obtained as follow:

1 km = 0.621 mile

Therefore,

132 km = 132 km × 0.621 mile / 1 km

132 km = 81.972 mile

Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:

Rate = 54.1 miles/gallons

Distance = 81.972 mile

Volume (in gallon) =?

Rate = Distance / volume

54.1 = 81.972 / volume

Cross multiply

54.1 × volume = 81.972

Divide both side by 54.1

Volume = 81.972 / 54.1

Volume = 1.52 gallon.

Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:

1 gallon = 3.785 L

Therefore,

1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon

1.52 gallon = 5.75 L

Therefore, 5.75 L of the gas will be consumed.

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