Answers
Answer:
Explanation:
Part A
The price per item when q units are sold is given by the function:
[tex]D(q)=-1.3q+260[/tex]When 30 units are sold:
[tex]\begin{gathered} \text{The price per item, }D(30)=-1.3(30)+260 \\ =-39+260 \\ =\$221 \end{gathered}[/tex]Therefore, the total revenue from selling 30 items is:
[tex]R(q)=30\times221=\$6,630[/tex]Part B
• Fixed Cost = $4000
,• Variable Cost = $8 per Item
[tex]\begin{gathered} \text{ Total Cost for 30 items, }C(q)=4000+(8\times30) \\ C(30)=\$4,240 \end{gathered}[/tex]Part C
[tex]undefined[/tex]Related Questions
11 and 1411 and 1914 and 1919 and 24what one is the correct answer?
Answers
√11 ≅ 3.3
√14 ≅3.7
√19 ≅ 4.4
√24 ≅4.9
We have to do the subtractions:
√11 - √14 = 3.3-3.7 = -0.4
√11 - √19 = 3.3 -4.4 = -1.1
√14 - √19 = 3.7-4.4 = -0.7
√19 - √24 = 4.4-4.9=-0.5
√19 and √24 have a difference of about 0.5
should be the answer
Lmk if it helps
Which of these tables represents a function? Table A Input. Output 8 -98 -810 -8Table B Input. Output 4. 117. 127. 13Table C Input. Output -4. 0-3. 3-2. 5Table D Input. Output 10. 010. 43. 7Table A Table BTable C Table D
Answers
Answer:
The table that represents a function is;
[tex]\text{Table C}[/tex]Explanation:
Given the table A,B,C and D.
We want to select the table that represents a function.
For a table to represent a function each input must not have more than one possible value of output.
For table A, the input 8 has two different outputs (-8 and -9). Therefore, it is not a function.
For table B, the input 7 has two different outputs (12 and 13). Therefore, it is not a function.
For table D, the input 10 has two different outputs (0 and 10). Therefore, it is not a function.
For table C, No input has more than one output. Therefore, it is a function.
The table that represents a function is;
[tex]\text{Table C}[/tex]Griffin had dinner at his favorite Indian restaurant. The bill before tax came to $28.50. The tax rate is 9%. Griffin wants to leave the waiter a 20% tip on the pre-tax total. What is Griffin's total for the entire meal including both tax and tip? Round your answer to the nearest cent (hundredth).
Answers
Two polygons are similar. The perimeter of the larger polygon is 120 yards and the ratio of thecorresponding side lengths is 1/6. Find the perimeter of the other polygon.The perimeter of the other polygon isyards.
Answers
The perimeter of the larger polygon is 120 yards.
The scale factor is 1/6.
The perimeter is proportional to the length of the sides, so if the smaller polygon has sides that are 1/6 of the corresponding sides in the larger polygon, then the perimeter is also 1/6 of the perimeter of the larger polygon:
[tex]P_s=\frac{1}{6}P_l=\frac{1}{6}\cdot120=20[/tex]The perimeter is scaled in the same proportion as the sides.
Answer: The perimeter of the other polygon is 20 yards.
consider the expression below
Answers
Solution
For this case we have the following expression:
A.11x^2 +6x-6
B.7x^2 +16x+25
C. 11x^2 -5x+13
D. 7x^2 -3x+8
Then the correct solution :
x^2 +15x +65 +(2x-5)(3x+8)= x^2 +15x +65 +6x^2 +16x -15x -40= 7x^2 +16x +25 (B)
(4x+1)(3x-4) -(5x^2-10x-12)= 12x^2 -16x +3x -4 -5x^2 +10x +12 = 7x^2 -3x +8 (D)
8x^2 +19x+4 + (3x+2)(x-5)= 8x^2 +19x +4 +3x^2-15x +2x -10= 11x^2 +6x -6 (A)
(6x+1)(3x-7) -(7x^2-34x-20)= 18x^2-42x +3x -7 -7x^2 +34x +20= 11x^2 -5x +13 (C)
at the beginning of the year Adrian's savings account balance was $28 each week he deposits another $15 into that account and he doesn't spend any of his savings is his savings account balance proportional to the number of weeks since the start of the year?
Answers
Let W be the number of weeks in a year and S be the saving account balance. Then, Adrian's saving account formula is
[tex]S=15W+28[/tex]so, no, his saving account balance is not proportional because there is a constant term equal to 28. If this last constante was zero the, the answer will be yes.
Rewrite the given equation in slope-intercept form and the graph the line.2x + 5y - 10= 0What is the equation in slope intercept form?(Use integers or simplified fractions for any numbers in the equation)
Answers
Answer:
y=-(2/5)x+2
Explanation:
Given the equation of the line:
[tex]2x+5y-10=0[/tex]The slope-intercept form of a line is given as y=mx+b.
Thus, make y the subject of the given equation.
[tex]\begin{gathered} 5y=-2x+10 \\ \text{Divide all through by 5} \\ y=-\frac{2}{5}x+\frac{10}{5} \\ y=-\frac{2}{5}x+2 \end{gathered}[/tex]The slope-intercept form of the equation is y=-(2/5)x+2.
Next, the lines are graphed using the intercepts.
When y=0
[tex]\begin{gathered} 0=-\frac{2}{5}x+2\implies\frac{2}{5}x=2 \\ \text{Multiply both sides by }\frac{5}{2} \\ \frac{2}{5}\times\frac{5}{2}x=2\times\frac{5}{2} \\ x=5 \end{gathered}[/tex]• The x-intercept is (5,0)
,• From the slope-intercept form, the y-intercept is (0,2).
Join the two points using a straight line as shown below:
help????? what are the parallel line and what's the justification using converse theorems and postulates
Answers
A ) ∠2 is supplementary to angle ∠3
Justification: Collateral internal angles are always supplementary to each other.
B) b║a
Corresponding angles are congruent between themselves.
c) ∠1 and ∠12 are supplementary angles
∠1 and ∠2 are congruent, and ∠2 is supplementary to angle ∠12 that is why ∠1 and ∠12 are supplementary
d) ∠9≅∠12
Vertical angles are always congruent
The manufacturing company manufactures large and small book shelves. Large shelves require 40 pounds of metal to fabricate and small shelves require 30 pounds, but the company has only 400 pounds of metal on hand. If the company can sell each large shelve for $80 and each small shelve for $49, how many each shelve should it manufacture in order to maximize income?
Answers
We know that
• Large shelves require 40 pounds.
,• Small shelves require 30 pounds.
,• The company has only 400 pounds of metal.
,• The selling price of each large shelf is $80.
,• The selling price of each small shelf is $49.
First, let's make a table with the given data of the problem, this will help you organize it.
From the given information, we can define the following constraints.
[tex]\begin{gathered} 40x+30y\leq400 \\ y\ge0 \\ x\ge0 \end{gathered}[/tex]These constraints form the following region:
To find the maximum income possible, we have to evaluate the income function at (0,13.333) and (10,0).
[tex]I(x,y)=80x+49y[/tex]Observe that we formed the income function using the table above. Now, let's evaluate it at each point.
[tex]\begin{gathered} I(0,13.333)=80\cdot0+49\cdot13.333=0+653.317=653.32 \\ I(10,0)=80\cdot10+0=800+0=800 \end{gathered}[/tex]Therefore, they would have to sell 10 large shelves to reach a maximum income of $800.You buy your car in Chicago for $38,535, which has a sales tax(on the car only) of 10.25%. Find the amount of sales tax you will pay for the car
Answers
car rate=38355
tax=10.25%
10.25/100 x38535=3949.83
Thus the tax to be piad is $3949.83
A science class has 7 girls and 1 boy in the seventh grade and 3 girls and 9 boys in the eighth grade. The teacher randomly selects a seventh and an eighth-grader from the class for a competition. What is the probability that the students she selects are both girls?Write your answer as a fraction in the simplest form.
Answers
Answer:
7/32
Explanation:
The seventh-grade class has 7 girls and 1 boy.
[tex]P(\text{selecting a girl from seventh grade)}=\frac{7}{7+1}=\frac{7}{8}[/tex]The eighth-grade class has 3 girls and 9 boys.
[tex]P(\text{selecting a girl from eighth grade)}=\frac{3}{3+9}=\frac{3}{12}[/tex]Therefore, the probability that the students she selects are both girls:
[tex]P(\text{both are girls)}=\frac{7}{8}\times\frac{3}{12}=\frac{7}{32}[/tex]The probability is 7/32.
The grid you see below is in the shape of a reactangle. What is the area, in square units of the shaded part?
Answers
We need to count the number of squares for the length and the width
lenght= L
width=W
L=11
W=5
Area of the complete rectangle
AR=L*W= 11*5=55 u^2
the shaded area is the half of the area of the rectangle
AS= shaded area
AS=55/2=27.5
AS=27.5 u^2
Question 1 (3 points)Evaluate the function when x = -2,0,3p(x) = -8x-2p(-2) =p(0) =p(3) =Blank 1:Blank 2:Blank 3:
Answers
Answer:
p(-2) = 14
p(0) = -2
p(3) = -26
Explanation:
To find the value of p(-2) we need to replace x by -2 on p(x) as:
[tex]\begin{gathered} p(x)=-8x-2 \\ p(-2)=-8\cdot(-2)-2 \\ p(-2)=16-2 \\ p(-2)=14 \end{gathered}[/tex]At the same way, p(0) and p(3) are calculated as:
[tex]\begin{gathered} p(x)=-8x-2 \\ p(0)=-8\cdot0-2 \\ p(0)=0-2 \\ p(0)=-2 \end{gathered}[/tex][tex]\begin{gathered} p(x)=-8x-2 \\ p(3)=-8\cdot3-2 \\ p(3)=-24-2 \\ p(3)=-26 \end{gathered}[/tex]Therefore, the answer is:
p(-2) = 14
p(0) = -2
p(3) = -26
Polygon PQRST is show on the coordinate plane below.8) Given the algebraic representation (x, y) *(x, y), create the image of P'QʻR'ST' on thecoordinate plane.PRS
Answers
1) We have here a Dilation. The image is going to "shrink" under the scale factor of 1/2
2) Let's look at the graph and find the coordinates of each vertex.
Preimage:
P (-5,3) Q (0,4) R( 4,2) S(2,-3) T( -4,-3)
3) Dilating the figure under a scale factor of 1/2 for each x, and y coordinate.
Then the image is going to :
P' (-5/2, 3/2) Q' (0,2) R' (2,1) S' (1,-3/2) T(-2,-3/2)
9) When a Dilation has the scale factor k=1, there is no dilation actually. Since the polygon remains with the same dimensions.
10) K>1
When the scale factor is above 1 the polygon, or any figure enlarges.
11)0The Figure shrinks. It can't be zero, for there's no dilation at 0 as a scale factor.
identify the transformation of the give equations below compared to its parent [tex]y = - 2(x - 5)^{2} + 1[/tex]a)Vertical Stretch by a factor of 2, shifts left 5units, shifts down 1 unit and reflection .b)Vertical compression by a factor of 2, shifts right 5 units, shifts up 1 unit and reflection across the x-axis .c)Vertical stretch by a factor of 2, shifts right units, shifts up 1 unit and reflection across the x-axis .d)Vertical compression by a factor of 2, shifts left 5 units, shifts down 1 unit and reflection across the x-axis .
Answers
Let's begin by identifying key information given to us:
[tex]y=-2\mleft(x-5\mright)^2+1[/tex]The general formula for the transformation is:
[tex]\begin{gathered} f\mleft(x\mright)=a\mleft(x-h\mright)^2+k \\ where\colon \\ h=HorizontalShift, \\ k=VerticalShift \\ a=Stretched/Compressed \end{gathered}[/tex]a)
Vertical Stretch by a factor of 2, shifts left 5units, shifts down 1 unit, and reflection gives:
[tex]\begin{gathered} a=2,h=-5,k=-1 \\ Reflection=-a \\ \Rightarrow g(x)=-2(x+5)^2-1 \end{gathered}[/tex]b)
Vertical compression by a factor of 2, shifts right 5 units, shifts up 1 unit, and reflection across the x-axis gives:
[tex]\begin{gathered} a=\frac{1}{2},h=-5,k=1 \\ Reflection=-a \\ \Rightarrow g(x)=-\frac{1}{2}(x+5)+1 \end{gathered}[/tex]c)
Vertical stretch by a factor of 2, shifts right units, shifts up 1 unit, and reflection across the x-axis gives:
[tex]\begin{gathered} a=2,h=5,k=1 \\ Reflection=-a \\ \Rightarrow g(x)=-2(x-5)^2+1 \end{gathered}[/tex]2) Stephanie made $400 selling cookies at the town fair. Adam made $600 selling cookies at thefair. what is the ratio of Adam's profits to Stephanies profits?
Answers
To find the ratio we have to divide Adam's profit by Stephanie's profit, as follows:
[tex]\frac{\text{ Adam's profit}}{\text{ Stephanie's profit}}=\frac{600\text{ \$}}{400\text{ \$}}=\frac{3}{2}[/tex]Find the value of x. 5x 80°
Answers
Method: The value of x can be obtained by summing 5x and 80 and then equating to 140
5x + 80 = 140
Step 1: collect like terms
5x = 140 - 80
5x = 60
Step 2: Divide both sides by 5
x= 60/5
x= 12
Write an equivalent expression by distributing the"-" sign outside the parentheses:-(-8n +3.9)
Answers
By distributiong the minus sign, we get
[tex]8n-3.9[/tex]because by the law of sign:
which lengths make sense for possible values of b
Answers
The first condition is for the perimeter of the equation so:
[tex]P=2a+b=15.7[/tex]Now the secon condition is that the sum of two sides should be:
[tex]\begin{gathered} a+b>b \\ b+b>a \end{gathered}[/tex]so the negative option and 0 don't make sence dor a distance, then we try with the value of b=0.5
So in the first equation will be:
[tex]\begin{gathered} 2a+0.5=15.7 \\ 2a=15.2 \\ a=7.6 \end{gathered}[/tex]So the condition:
[tex]\begin{gathered} b+b>a \\ 0.5+0.5>7.6 \end{gathered}[/tex]this is false, so the solution is
Find the surface area of a cylinder with radius 25 and height 7the options are 1250 pi, 2500 pi, 350 pi, 1600 pi
Answers
Given:
radius = 25
height = 7
The surface area of cylinder is given as:
[tex]S\mathrm{}A\text{ = 2}\pi rh\text{ + 2}\pi r^{2}[/tex][tex]\begin{gathered} \text{surface area = 2}\pi(rh+r^2) \\ \text{surface area = 2}\pi((25\times7)\text{ + (25}\times25)) \\ \text{surface area = 2}\pi(175\text{ + 625)} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{surface area = 2}\pi(800) \\ \text{surface area of the cylinder = 1600}\pi \end{gathered}[/tex]the relationship between dividing four and multiplying by 1/4 is that ?
Answers
If you divide a number by 4 and multiply it by 1/4 you will obtain the same result, because "1/4" is one fourth of the number which is the same as dividing it by four. So these two operations are equal.
Example:
[tex]\begin{gathered} 100\colon4\text{ = 25} \\ 100\cdot\frac{1}{4}\text{ = 25} \end{gathered}[/tex]What is the square root of 64/81 simplified?
Answers
The square root of 64 / 81 can be expressed mathematically as:
[tex]\sqrt[]{\frac{64}{81}}[/tex]Note that:
[tex]\sqrt[]{\frac{a}{b}}=\frac{\sqrt[]{a}}{\sqrt[]{b}}[/tex][tex]\text{Therefore, }\sqrt[]{\frac{64}{81}}=\text{ }\frac{\sqrt[]{64}}{\sqrt[]{81}}[/tex]Also note that:
[tex]\begin{gathered} \sqrt[]{64}=\text{ 8 and} \\ \sqrt[]{81}=9 \end{gathered}[/tex]Therefore
[tex]\sqrt[]{\frac{64}{81}}=\frac{8}{9}[/tex]Solve the problem and enter your solution for the variable below. Do notinclude units in your answer.The scale below shows the weight, in grams, of two identical blocks. Howmany grams does one of the blocks weigh?
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Since the scale is balanced, the weight on the left end is equal to the weight on the right end.
Let x be the weight of one of the blocks. We'll have that
[tex]\begin{gathered} x+x=10 \\ \rightarrow2x=10\rightarrow x=\frac{10}{2} \\ \rightarrow x=5 \end{gathered}[/tex]Therefore, the weight of one of the blocks is 5
SCC LibraryLet S = {1, 2, 3, ..., 18, 19, 20} be the universal set.Let sets A and B be subsets of S, where:Set A = {2, 4, 5, 6, 10, 13, 16, 18}Set B = {1, 3, 4, 5, 6, 8, 9, 12, 13, 14, 15, 17, 18)Determine the following:n(A) =n(A)n(B) =n(ANB) =n(AUB) =
Answers
n(A)=8. There are 8 numbers in set A
n(not A)=12. There are 12 numbers in S that are not in set A
n(B)= 13. There are 13 numbers in set B
n(A and B)= 5 There are 4 common numbers in both sets A and B
n(AUB)=16 There are 16 numbers in set A and B, not counting repea
Which ordered pair makes both inequalities true?y> -3x + 3y22x-2O (1,0)O (-1,1)O (2.2)Mark this anth esaSave and Exit""43244go m76N
Answers
The solutions of the 2 inequalities must li in the common color area (the area which has both colors) and also, on the solid line (points on the dashed line do not belong to the solutions)
From the given graph we can see
1. The red line is a solid line
2. The blue line is a dashed line
3. The area that contains the 2 colors red and blue has points (1, 0) and (2, 2)
That means the answer is one of then
Since point (1, 0) lies on both lines but it is belonging to the red line only because the blue line is a dashed line which means it does not belong to it
Then it can not be a solution for both inequalities
Since the point (2, 2) lies on the red lines
Since the red line is a solid line
Then the point (2, 2) belongs to the red line and the shaded area
Point (2, 2) is the solution to both equations
The answer is (2, 2) the 3rd choice
In a normal distribution, about _% of the data lie within 1 standard deviation below and 2 standard deviations above the mean
Answers
ANSWER
81.8%
EXPLANATION
The percentage of data that lies between 1 standard deviation below and 2 standard deviations above the mean is the sum of the percentages between those two values,
So this is,
[tex]34.1\%+34.1\operatorname{\%}+13.6\operatorname{\%}=81.8\operatorname{\%}[/tex]Hence, 81.8% of the data lies within 1 SD below and 2 SD above the mean.
Find the sum of the measures of the interior angles and the sum of the measures ofthe exterior angles of the polygon.Sum of the measures of the interior angles:Sum of the measures of the exterior angles:
Answers
Given:
Find-:
a) Sum of the measure of the interior angle
b) Sum of the measure of the exterior angle.
Sol:
Given figure is a hexagon and each Interior angle of the hexagon is 120
So the Sum of interior angles is:
[tex]\begin{gathered} =120+120+120+120+120+120 \\ \\ =720 \end{gathered}[/tex]An exterior angle of the hexagon is:
[tex]\begin{gathered} =180-120 \\ \\ =60 \end{gathered}[/tex]Sum of an exterior angle is:
[tex]\begin{gathered} =60+60+60+60+60+60 \\ \\ =360 \end{gathered}[/tex]The graph of a function is shown on the coordinate plane below. Which relationship represents a function with a lesser rate of change (slope) than the function graphed?
Answers
1. Identify the rate of change of the function given in the graph:
use two points in the graph in the next formula:
[tex]undefined[/tex]i need to make a table to represent data with the numbers given on the problem, but i can’t figure out how to make the table
Answers
Given: The following list of points scored by the winning teams in the NRFL-
[tex]16,32,41,30,53,24,27,50,33,36[/tex]Required: To draw a table for the given data.
Explanation: The given data can be represented by a single-column table as follows-
Final Answer: The table for the data is drawn.
I need help with this problem Evaluate each expression given the variable replacement
Answers
Given the expression:
[tex]\frac{20ab}{\mleft(a-b\mright)^2}[/tex]1. You need to substitute these values given in the exercise into the expression:
[tex]\begin{gathered} a=4 \\ b=-2 \end{gathered}[/tex]Then:
[tex]=\frac{20(4)(-2)}{(4-(-2))^2}[/tex]2. According to the Sign Rules for Multiplication:
[tex]\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ -\cdot+=- \\ +\cdot-=- \end{gathered}[/tex]Knowing this, you can solve the multiplication in the numerator and simplify the denominator:
[tex]=\frac{-160}{(4+2)^2}[/tex][tex]=\frac{-160}{(6)^2}[/tex]You know that:
[tex]6^2=6\cdot6=36[/tex]Then:
[tex]=\frac{-160}{36}[/tex]3. According to the Sign Rules for Division:
[tex]\begin{gathered} \frac{-}{-}=+ \\ \\ \frac{+}{+}=+ \\ \\ \frac{-}{+}=- \\ \\ \frac{+}{-}=- \end{gathered}[/tex]Therefore, since the numerator is negative and the denominator is positive, the fraction is negative:
[tex]=-\frac{160}{36}[/tex]4. You can reduce the fraction by dividing the numerator and the denominator by 4:
[tex]\begin{gathered} =-\frac{160\div4}{36\div4} \\ \\ =-\frac{40}{9} \end{gathered}[/tex]Hence, the answer is:
[tex]=-\frac{40}{9}[/tex]