hello help me please :)

Answer:

coal , oil and natural gas

Answer:

Energy transformation

Explanation:

Energy transformation means the changing of  energy from one type to another.

Answer:

your answer will be 320kg that would be the pressure at the bottom surface of the block

Answer:

The new pressure of the gas is 15.40 kPa.

Explanation:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Mathematically this law indicates that the quotient between pressure and temperature is constant:

[tex]\frac{P}{T}=k[/tex]

On the other hand, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as:

P*V=k

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. Mathematically, this law says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

[tex]\frac{V}{T}=k[/tex]

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

[tex]\frac{P*V}{T}=k[/tex]

Studying an initial state 1 and a final state 2, it is fulfilled:

[tex]\frac{P1*V1}{T1}=\frac{P2*V2}{T2}[/tex]

In this case:

Replacing:

[tex]\frac{10 kPa*200 L}{273 K}=\frac{P2*175 L}{368 K}[/tex]

Solving:

[tex]P2=\frac{368 K}{175 L} *\frac{10 kPa*200 L}{273 K}[/tex]

P2= 15.40 kPa

The new pressure of the gas is 15.40 kPa.

Answer:

4.13×10⁻⁷ m

Explanation:

Applying

v = λf................... Equation 1

Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.

make λ the subject of the equation

λ = v/f....................... Equation 2

Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.

From the question,

Given: f = 7.26×10¹⁴ Hz

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = (3×10⁸)/(7.26×10¹⁴)

λ = 4.13×10⁻⁷ m

Answer:

In parallel combination each appliance gets the full voltage.

If one appliance is switched on/of others are not affected.

The parallel circuit divide the current through the appliances.

In a parallel combination it is very easy to connect or disconnect a new appliance without affecting the working of other appliances.

pls mark me as brainlist

Explanation:

Yep. Those three things are all electronic components.

There are a lot more besides those.

Question: calculate their densties in Si unit.

200mg,0.0004m​³

Answer:

0.5 kg/m³

Explanation:

Applying,

D = m/V........................ Equation 1

Where D = density, m = mass, V = volume.

From the question,

Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³

Substitute these values into equation 1

D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)

D = 2/4

D = 0.5 kg/m³

Hence the density in S.I unit is 0.5 kg/m³

Answer:

D(ensity) = M / V = 6.94 g / 13 cm^3 = .534 g / cm^3

Compare to H20 at 1 gm / cm^3

Answer:

D. Interference patterns of electrons

Explanation:

Answer:

B. they must be intrinsically far more luminous than the brightest galaxies.

Explanation:

Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.

Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."

This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.

Answer:

Efficiency = 20%

Explanation:

Given the following data;

Input energy = 1000 Joules

Output energy = 200 Joules

To find the efficiency of the solar cell;

[tex] Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100 [/tex]

Substituting into the formula, we have;

[tex] Efficiency = \frac {200}{1000} * 100 [/tex]

[tex] Efficiency = 0.2 * 100 [/tex]

Efficiency = 20%

Answer:

Explanation:

This is one-dimensional motion on an incline, which is always tons of fun :/

The equation you need for this is

w*sinθ - f = ma where w is the weight of the girl (NOT the mass), theta is the angle of inclination, f is the frictional force pulling back on the girl, m is the mass of the girl, and a is the acceleration she experiences under these conditions. We have the mass but we need the weight, and weight has its own equation:

[tex]F_n=w=mg[/tex] where Fn is the normal force of the girl (which is the same as weight). Her normal force/weight is

w = 45(9.8) and we need 2 sig fig's for the answer so her weight is

w = 440N

f = μ[tex]F_n[/tex] which is the coefficient of kinetic friction times the normal force/weight of the girl:

f = (.25)(440) and we need 2 sig fig's for this as well so the frictional force is

f = 110

Putting it all together in the main equation looks like this:

440sin45 - 110 = 45a

Multiplication/division rules for sig fig's are different so we have to do them individually.

440sin45 will have 2 sig fig's in the answer:

440sin45 = 310; therefore:

310 - 110 = 45a. Again, because we have subtraction on the left and we will divide eventually, and the rules for both are different, we will subtract first, get that answer in the correct number of sig fig's and then divide that result by 45:

2.0 × 10² = 45a so

a = 4.4 m/s/s

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

We have

[tex]a = \frac{6}{12} = \frac{1}{2} = 0.5 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

The bigger the energy source the more light it makes

Answer:

Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.

for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.

Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.

Answer: Hope This Helps!

Explanation:

1: The first one is true because, if it was full there would be more weight and you would have to apply more force for it to start moving. But an empty one you don't have to apply so much force to it. (Newtons 2nd Law.)

2: The second one is true because, the skate board has a lot of kinetic energy and when it hits the rocks a collosion occurs where all the enrgy points into the front of the board and the back side lifts of the floor so it flips over the rock.(Newtons 1st Law.)

3: The third one is false because, the road cant push onto the tire the tire can push onto the road though. Additional information: Also the when the tire pushes on the road friction happens and because of the rough surface of the road.(Newtons 3rd Law.)

Answer seafloor spreading

The arrow is pointing to the Ocean Trench

Answer:

position 3

Explanation:

in position 3 PE is least as height is least

so KE is most as energy is always conserved

Answer:

A) a snowboarder who increases speed when traveling downhill

A snowboarder who increases speed when traveling downhill will have negative acceleration.

What is acceleration ?

Acceleration is described as the rate of change of velocity with time.

                                                       [tex]a&=\frac{\Delta v}{\Delta t}[/tex]

Here, as the snowboarder is traveling in negative y direction therefore the final velocity will be great than initial velocity with negative sign. It should be noted that velocity and acceleration are vector quantities i.e. depends upon the direction in which they have been applied.

Also negative acceleration is denoted as the situation when the object moves in the direction that is opposite to its direction of velocity.

In the above situation, the force is being applied to travel downhill(speeding up in the negative direction) in the opposite direction which exemplifies negative acceleration.

Thus, option A is the correct answer.

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Answer:

Hey I would say Dust

hope this helped

Answer:

The answer is A/Dust

Explanation:

Answer:

Key terms

TermMeaningTransverse waveOscillations where particles are displaced perpendicular to the wave direction.Longitudinal waveOscillations where particles are displaced parallel to the wave direction

Answer:

gravity and weight of an item

Explanation:

if you drop a rock it would fall straight to the ground

now if you drop a feather it would fall to the ground but will take a longer amount of time

Answer:

C

Explanation:

edge2020

Answer:

its speed will be less than V

Explanation:

When the ball falls a distance d, its final kinetic energy plus rotational kinetic energy of the drum equals its initial potential energy.

K = U

With its speed V at the end of d, we have

1/2mV² + 1/2Iω² = mgd where I = rotational inertia of drum and balls, ω = angular speed of drum and balls and m = mass of box

1/2mV² + 1/2Iω² = mgd

1/2mV² = mgd - 1/2Iω²

V² = [2(mgd - 1/2Iω²)/m]

V = √[2(mgd - 1/2Iω²)/m]

When the four balls are moved inward closer to the drum, their rotational inertia increases and also its angular speed which thus causes an increase in rotational kinetic energy. But, since the box still falls the same distance of d, its final kinetic energy plus rotational kinetic energy of the drum plus balls still equals its initial potential energy

K = U

I' = new rotational inertia of drum and balls, ω' = new angular speed of drum and balls

With its new speed is now V' at the end of d,

1/2mV'² + 1/2I'ω'² = mgd

1/2mV'² = mgd - 1/2I'ω'²

V² = [2(mgd - 1/2I'ω'²)/m]

V' = √[2(mgd - 1/2I'ω'²)/m]

Since I' and ω' increase, the rotational kinetic energy of the drum and balls (1/2I'ω'²) increases. Thus, the difference (mgd - 1/2I'ω'²) < (mgd - 1/2Iω²) which implies that the kinetic energy of the box decreases. Hence, since its kinetic energy decreases, its speed V' also decreases.

So,  V' < V

So, its speed will be less than V.

Given :

Capacity of capacitor is, [tex]C = 10\ \mu F[/tex].

To Find :

At what voltage can a 10 μF capacitor be energized to 0.45 J.

Solution :

We know, energy in capacitor is given by :

[tex]E = \dfrac{CV^2}{2}[/tex]

So,

[tex]V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V[/tex]

Therefore, voltage required is [tex]0.3 \ \mu V[/tex] .

Answer:

A. An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.

The diagram best shows the perceived sound wave heard by a woman after a police car has passed her is

An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.

The correct option is first.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

The diagram representing circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.

Thus, the correct option is first.

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Answer.:

Explanation:

The image is either virtual or real and the height of the image is 10cm.

To find the image type and its height, we need to know about the magnification of convex lens.

          Height of image/height of object or image distance(V) / object distance(U)

So, image height = magnification × object height

                            = 2×5 = 10 cm

Thus, we can conclude that the image is virtual if it's formed on the left of the lens and is real if it's formed on the right of the lens. The height of the image is 10 cm.

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magnification = [tex]\bf\dfrac{height of image}{height of object}[/tex]

= [tex]\bf\dfrac{6cm}{10cm}[/tex]

= 0.6