HElp 64 points and Brainlyiest to who ever can solve the problem question on the picture
Which property was applied in this step?
Addition Property of Equality
O Subtraction Property of Equality
Multiplication Property of Equality
Division Property of Equalit

HElp 64 Points And Brainlyiest To Who Ever Can Solve The Problem Question On The Picture Which Property

Answers

Answer 1

Answer:

Addition Property of Equality

Step-by-step explanation:

You are adding 3/4 to both sides to isolate the x.


Related Questions

[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimensions will produce a box with maximum volume?

Answers

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

Comment on maximum volume, minimum area

In the general case of an open-top box, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a closed top, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

Write the comparison below as a ratio in simplest form using a fraction, a colon, and the word to. 11 oz to 5 oz

Answers

Answer:

Explanation:

11 oz / 5 oz, 11 oz : 5 oz, eleven ounces to five ounces

For the following data at the near-ground level, which location will residents likely see dew on their lawns in the morning? Group of answer choices City C: Dew Point Temperature = 25°F, expected low Temperature = 20°F City A: Dew Point Temperature = 65°F, expected low Temperature = 60°F City B: Dew Point Temperature = 45°F, expected low Temperature = 50°F

Answers

Answer: CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F

Step-by-step explanation:

CITY C: Dew Point Temperature = 25°F, expected low Temperature = 20°F

CITY A: Dew Point Temperature = 65°F, expected low Temperature = 60°F

CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F

city B is going to have dew on their lawn in the morning as the dew point temperature is less than the lowest temperature.

When surface temperature drops, eventually reaching the dew point, atmospheric water vapor condenses to form small droplets on the surface. Thus dew will be formed as the conditions are suitable only for city B.

graph y=8 sec1/5 Ø the answers are graphs I am just unsure of how to answer

Answers

Answer:

Use a graphing calc.

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145 a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

Answers

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Answer:

a. Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. P(at least B) = 0.330

c. P(pass) = 0.855

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years.

He uses the following scale for grading.

Grade     Numerical Score      Probability

A                       4                            0.090

B                       3                            0.240

C                       2                            0.360

D                       1                            0.165

F                       0                            0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

The cumulative probability distribution is given by

Grade = F

P(X ≤ x) = 0.145

Grade = D

P(X ≤ x) = 0.145 + 0.165 = 0.310

Grade = C

P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670

Grade = B

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910

Grade = A

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1

Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

At least B means equal to B or greater than B grade.

P(at least B) = P(B) + P(A)

P(at least B) = 0.240 + 0.090

P(at least B) = 0.330

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Passing the course means getting a grade of A, B, C or D

P(pass) = P(A) + P(B) + P(C) + P(D)

P(pass) = 0.090 + 0.240 + 0.360 + 0.165

P(pass) = 0.855

Alternatively,

P(pass) = 1 - P(F)

P(pass) = 1 - 0.145

P(pass) = 0.855

acccording to this diagram what is cos 28

Answers

Answer:

[tex] \frac{15}{17} [/tex]

Option B is the correct option.

Here,

Adjacent=15

Hypotenuse=17

Now,

[tex]cos \: theta = \frac{adjacent}{hypotenuse} \\ cos \: 28 = \frac{15}{17} [/tex]

Hope this helps..

Good luck on your assignment..

Answer:

B. 15/17

Step-by-step explanation:

(see attached graphic for reference)

Because we have a right triangle (i.e one of the internal angles is 90 degrees), we can use trigonometry to solve

from the diagram, we can see that

cos 28° = adjacent length / hypotenuse

we can also see that the length adjacent to 28° = 15 units and the hypotenuse is 17 units,

hence, substituting these values into the equation:

cos 28° = 15 / 17   (answer)

edit: typo

The number of degrees of freedom for the appropriate chi-square distribution in a test of independence is a. k – 1. b. A chi-square distribution is not used. c. number of rows minus 1 times number of columns minus 1. d. n – 1.

Answers

Answer:

Option C

Step-by-step explanation:

The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.

It tests the claim that the row and column variables are independent of each other.

The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.

If 16 ounces of bulk rice costs $2.50, how much would 24 ounces cost?Also, could you tell me how much it costs per ounce?

Answers

Answer:

24 oz costs $3.75

The rice cost per oz is $0.16

Step-by-step explanation:

Step 1: Set up proportion

16/2.5 = 24/x

Step 2: Cross multiply

16x = 24(2.5)

Step 3: Solve

16x = 60

x = 15/4 or 3.75

i have a question what is 2 plus 2 i will really live it if you respond

Answers

Hi there! Hopefully this helps!

------------------------------------------------------------------------------------------------

2 + 2 = 4.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

You can simply find this answer by getting two of your fingers on your left hand, getting two MORE fingers of your right hand, and counting them. You will end up with 4.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

You could multiply 2 two times, like this:

2 x 2 = 4.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

You could split the numbers into parts and add them back together, like this:

2 = 1 + 1.

           +

2 = 1 + 1.

           =

1 + 1 + 1 + 1 = 4.

Answer:

4

Step-by-step explanation:

problem is if you dont have a fingers... you cant physically count 2 + 2

anyway... just add them using your brain = 2 + 2 makes 4

Among 20 golden hamster litters recorded, there was a sample mean of =7.72 baby hamsters, with a sample standard deviation of s=2.5 hamsters per liter. Create a 98% confidence interval for the mean number of baby hamsters per liter.

Answers

Answer:

[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]

[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex]\bar X= 7.72[/tex] represent the sample mean

[tex]s= 2.5[/tex] represent the sample deviation

[tex] n=20[/tex] represent the sample size

The confidence interval is given by:

[tex] \bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]

The confidence interval is 98% and the significance level is [tex]\alpha=0.02[/tex] the degrees of freedom are given by:

[tex] df= n-1 = 20-1=19[/tex]

And the critical value would be:

[tex] t_{\alpha/2}= 2.539[/tex]

And replacing we got:

[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]

[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]

The 98% confidence interval is between 6.42 hamsters per liter to  9.02 hamsters per liter

Mean (μ) = 7.72, standard deviation (σ) = 2.5, sample size (n) = 20, Confidence (C) = 98% = 0.98

α = 1 - C = 0.02

α/2 = 0.01

The z score of α/2 is the same as the z score of 0.49 (0.5 - 0.01) which is equal to 2.326.

The margin of error E is:

[tex]E = Z_\frac{\alpha }{2} *\frac{\sigma}{\sqrt{n} } \\\\E=2.326*\frac{2.5}{\sqrt{20} } =1.3[/tex]

The confidence interval = (μ ± E) = (7.72 ± 1.3) = (6.42, 9.02)

Hence the 98% confidence interval is between 6.42 hamsters per liter to  9.02 hamsters per liter

Find out more at: https://brainly.com/question/24131141

Evaluate. Write your answer as a fraction or whole number without exponents. 7^–1 =

Answers

Answer:

1/7 = 0.142857... repeating

Step-by-step explanation:

7^(-1) = 1/(7^1) =1/7 = 0.142857... repeating

Answer:

[tex] \frac{1}{7} [/tex]

Solution,

[tex] {7}^{ - 1} \\ = \frac{1}{ {7}^{1} } \\ = \frac{1}{7} [/tex]

Laws of indices:Law of zero index:

[tex] {x}^{0} = 1[/tex]

Product law of indices:

[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

( powers are added in multiplication of same base)

Power law of indices:

[tex] {( {x}^{m} )}^{n} = {x}^{m \times n} [/tex]

law of negative index:

[tex] {x}^{ - m} = \frac{1}{ {x}^{m} } [/tex]

Root law of indices:

[tex] {x}^{ \frac{p}{q} } = \sqrt[q]{ {x}^{p} } [/tex]

[tex]( \frac{x}{y} ) ^{n} = \frac{ {x}^{n} }{ {y}^{n} } [/tex] [tex] {(xy)}^{m} = {x}^{m} {y}^{m} [/tex][tex] \sqrt[n]{x} = x \frac{1}{n} [/tex]

Hope this helps ....

Good luck on your assignment...

Suppose that g(x) = f(x) - 2. Which statement best compares the graph of
g(x) with the graph of f(x)?
A. The graph of g(x) is shifted 2 units to the left.
B. The graph of g(x) is vertically stretched by a factor of 2.
C. The graph of g(x) is shifted 2 units up.
D. The graph of g(x) is shifted 2 units down.

Answers

Answer:

D. The graph of g(x) is shifted 2 units down

Step-by-step explanation:

Since we are modifying b in f(x) = mx + b, we are dealing with vertical movement up and down. Since it is -2, we are moving down 2.

Find the value of x and the value of y. A.x = 15, y = 10 B.x = 20, y = 50 C.x = 50, y = 10 D.x = 50, y = 20

Answers

Answer:

X = 50

Step-by-step explanation:

(5x - 100) + (x - 20) = 180 (sum of angle on a straight line is = 180)

5x + x -100 -120 = 180

6x - 120 = 180

6x = 180 + 120

6x = 300

x = 300/6

x = 50

For y

3y + y + 140 = 180

4y = 180 -140

4y = 40

y = 40/4

y = 10

Find the area


O 60 square meters
O 120 square meters
O None of these
O 156 square meters

Answers

Answer:

120 m²

Step-by-step explanation:

We khow that the area of a triangle is the product of the lenght and the wight

let x be the width

the pythagorian theorem : x²+8²= 17² x² = 17²-8² x²= 225 x= 15

so the lenght is 15

A= 15*8 = 120 m²

Answer:

  120 square meters

Step-by-step explanation:

The missing leg of the right triangle is found from the Pythagorean theorem:

  diagonal² = length² + width²

  length² = diagonal² -width²

  length = √(17² -8²) = √(289 -64) = √225 = 15

So, the rectangle is 8 m by 15 m and has an area that is ...

  A = LW = (15 m)(8 m) = 120 m²

PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this? (it's not 15)

Answers

Answer: 20

Step-by-step explanation:

I guess that we want to distribute all the 7 candies between 4 kids

We have 3 options:

first 3, 2, 1 and 1. (the number of candies that each kid gets)

The possible permutations in this case:

if we leave the 3 fixed, the ones do are equal, so the permutations are only given by the change in the kid that gets 2 candies, we have 3 permutations for this.

And for the fixed 3, we have 4 possible places where we can fix it, so the total number of combinations is:

c = 3*4 = 12.

and the second option is (2, 2, 2, 1)

Here the only change is the kid that gets only one candy, we have 4 options in this case:

c = 4.

the third option is (4, 1, 1, 1)

Here the only change is the kid that gets 4 candies, and we have 4 options for this, so we have 4 combinations:

c = 4.

Then the total number of possible combinations is:

C = 12 + 4 + 4 = 20

I NEED HELP PLEASE, THANKS! :)

Answers

Answer:

  68

Step-by-step explanation:

The number of chips tested is the integral of the rate over the specified time interval: t = 2 to 6.

  [tex]\displaysyle n=\int_2^6{-3t^2+16t+5}\,dt=\left.-3\dfrac{t^3}{3}+16\dfrac{t^2}{2}+5t\right|_2^6\\\\=-(6^3-2^3) +8(6^2-2^2)+5(6-2)=-(216-8)+8(32) +5(4)\\\\=-208+256+20=\boxed{68}[/tex]

The technician can test 68 chips in that time period.

Determine what type of study is described. Explain. Researchers wanted to determine whether there was an association between high blood pressure and the suppression of emotions. The researchers looked at 1800 adults enrolled in a Health Initiative Observational Study. Each person was interviewed and asked about their response to emotions. In particular they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10. Each person's blood pressure was also measured. The researchers analyzed the results to determine whether there was an association between high blood pressure and the suppression of emotions.

Answers

Answer:

Experimental Study

Step-by-step explanation:

In an experimental study, the researchers involve always produce and intervention (in this case they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10) and study the effects taking measurements.

These studies are usually randomized ie subjects are group by chance.

As opposed to observation studies, where the researchers only measures what was observed, seen or hear without any intervention on their parts.

For the triangle show, what are the values of x and y (urgent help needed)

Answers

we just have to use the Pythagoras theorem and then calculate the value of x and y.

a line pass through the point (4,-2) and has a slope of 1/2 what is the value of (-4,a)​

Answers

Answer:

if you are trying to find the value of a then a= -6

Step-by-step explanation:

i used the information along with desmos graphing calculator and i graphed the line and got the second point (-4,-6)

Answer:

a=-6

Step-by-step explanation:

slope=(y2-y1)/x2-x1)

1/2=(a-(-2))/(-4-4)

1/2=(a+2)/-8

a+2=1/2×-8=-4

a=-4-2=-6

PLSSS PEOPLE I NEED HELP

Answers

Answer:C

Step-by-step explanation:

The vertical line test

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.49.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)

Answers

Answer:

(a) matched pair design

(b) n = 30

(c) Reject the null hypothesis.

Step-by-step explanation:

The complete question is:

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.49.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)(c) What is the decision? (Retain or reject the null?)

Solution:

(a)

It s provided that the researcher records the amount of time (in minutes) that parent-child pairs spend on social networking sites.

This implies that the data collected is in the form of paired data.

Thus, the research design that was used was matched pair design.

(b)

Consider the t-statistics provided:

t (29) = 4.021

The number 29 in the bracket is the degrees of freedom.

The degrees of freedom for a matched pair design is,

df = n - 1

Compute the value of n as follows:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, the sample size is n = 30.

(c)

The p-value of the test is:

p < 0.05

The p-value of the test is less than the 5% significance level.

This implies that the null hypothesis will be rejected at 5% significance level.

Identifico el nombre de la propiedad a la que hacen referencia las siguientes expresiones:

Answers

Hacen falta las expresiones para poder responder a tu pregunta, estuve investigando y adjuntaré una imagen que hace referencia a tus preguntas, espero no equivocarme.

Si este es el caso, son 9 expresiones y el nombre de cada propiedad es:

1. Inverso aditivo (Sumar un número por su opuesto el resultado es 0)

2. Ley conmutativa (El orden de los factores no altera el producto)

3. Ley asociativa (Agrupar los términos sin alterar el resultado)

4. Ley de la identidad, (Sumar un número con 0 se obtiene el mismo número)

5. Ley distributiva (La misma respuesta cuando multiplicas un conjunto de números por otro número que cuando se hace cada multiplicación por separado)

6. Ley distributiva

7. Ley distributiva

8. Ley asociativa

9. Ley conmutativa

Hartman Motors has $15 million in assets, which were financed with $6 million of debt and $9 million in equity. Hartman's beta is currently 1.4, and its tax rate is 30%. Use the Hamada equation to find Hartman's unlevered beta, bU. Do not round intermediate calculations. Round your answer to two decimal places.

Answers

Answer:

Unlevered beta ≈ 1.09

Step-by-step explanation:

Unlevered beta is basically the unlevered weighted average cost as it shows the volatility of returns without financial leverage. Unlevered beta is also known as asset beta, while the levered beta is commonly known as equity beta. Unlevered beta is calculated from the hamada equation as:

Unlevered beta = Levered beta/[1 + ((1 - Tax rate) × (Debt / Equity))]

We are given;

Levered beta = 1.4

Tax rate = 30% = 0.3

Debt = $6 million

Equity = $15 million

Thus, plugging these into the hamada equation, we have;

Unlevered beta = 1.4/[1 + ((1 - 0.3) × (6/15))]

Unlevered beta = 1.4/(1 + (0.7 × 0.4)

Unlevered beta = 1.4/(1 + 0.28)

Unlevered beta = 1.4/1.28

Unlevered beta = 1.09375

To 2 decimal places;

Unlevered beta ≈ 1.09

Is the area of this shape approximately 24 cm* ? If not give the correct area.

311
101
True
False

Answers

Answer:

19.2 feet square

Step-by-step explanation:

We khow that the area of an octagon is :

A= 1/2 * h * P where h is the apothem and p the perimeter

A= (1/2)*1.6*(3*8) = 19.2 feet square

Estimate the area under the graph of f(x)=2x^2-12x+22 over the interval [0,2] using four approximating rectangles and right endpoints.

Answers

Answer:

The right Riemann sum is 21.5.

The left Riemann sum is 29.5.

Step-by-step explanation:

The right Riemann sum (also known as the right endpoint approximation) uses the right endpoints of a sub-interval:

[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].

To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using right endpoints you must:

We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].

Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]

Now, we just evaluate the function at the right endpoints:

[tex]f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5\\\\f\left(x_{4}\right)=f(b)=f\left(2\right)=6[/tex]

Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\frac{1}{2}(16.5+12+8.5+6)=21.5[/tex]

The left Riemann sum (also known as the left endpoint approximation) uses the left endpoints of a sub-interval:

[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].

To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using left endpoints you must:

We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].

Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]

Now, we just evaluate the function at the left endpoints:

[tex]f\left(x_{0}\right)=f(a)=f\left(0\right)=22\\\\f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\\\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5[/tex]

Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\frac{1}{2}(22+16.5+12+8.5)=29.5[/tex]

If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?

Answers

Answer:

25%

Step-by-step explanation:

George is 33[tex]\frac{1}{3}[/tex]% ([tex]\frac{100}{3}[/tex]%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + [tex]\frac{100}{3}[/tex]%

                                                           = [tex]\frac{400}{3}[/tex]%

                                                           = 133[tex]\frac{1}{3}[/tex]%

Pete's percent poorer than George can be determined by;

                                                           = [tex](\frac{100}{3})[/tex] ÷ [tex](\frac{400}{3} )[/tex] × 100

                                                           = [tex](\frac{100}{3})[/tex] × [tex]\frac{3}{400}[/tex] ×100

                                                           = 0.25 × 100

                                                           = 25%

Pete is 25% poorer than George.

I need help plz someone help me solved this problem I need help ASAP! I will mark you as brainiest!

Answers

Answer:  k = -9

Step-by-step explanation:

kx² - 12x - 4 = 0

In order to have exactly one solution, it must be a perfect square.

Assume k is negative and factor out a negative 1.

-1(kx² + 12x + 4) = 0

[tex]\bigg(\sqrt{kx^2}+\sqrt4\bigg)^2=0\\\\[/tex]

The middle term = 12x [tex]= 2(\sqrt{kx^2})(\sqrt4)[/tex]

                               12x = 4x√k

                                3   = √k

                                9 = k

                                   

-1(9x² + 12x + 4) = 0

-9x² - 12x - 4 = 0

k=-9

Express it in slope-intercept form.

Answers

Answer:y=3/2x-3

Step-by-step explanation: the slope of the graph is (y2-y1)/(x2-x1)

If we take points (0,-3) (2,0) the slope would be (0--3)/(2-0) = 3/2

And the y-intercept of the slope is -3

Tommy has "n" friends and he wants to give each friend 5 pencils. Write an expression to show how many pencils pencils Tommy will share.

Answers

Answer:

5n

Step-by-step explanation:

Think about it:

If Tommy has 4 friends (n = 4), then he will have to give 5 pencils to each person. The total number of pencils is 5 * n or 5 * 4 = 20.

Similarly, if Tommy has 0 friends (I can relate), then he will have to give 5 pencils to each of his imaginary friends. The total number of pencils he has to give out to his real friends is 5 * n or 5 * 0 = 0.

Betty tabulated the miles-per-gallon values for her car as 26.5, 28, 30.2, 29.6, 32.3, and 24.7. She wants to construct the 95% two-sided confidence interval. Which value should Betty use for the value of t* to construct the confidence interval?

Answers

Answer:

Betty should use T = 2.571 to construct the confidence interval

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.571

Betty should use T = 2.571 to construct the confidence interval

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