!!HELP ILL MARK BRAINLIST !!Write an expression for the area of the square four by combining the areas of the four triangles and two squares

Answer:

Not enough information.

Step-by-step explanation:

AB + BC + CD + DA = 46

In a parallelogram, opposite sides are congruent.

AB + DA + AB + DA = 46

2AB + 2DA = 46

We have two unknowns and only one equation.

There is not enough information to answer the question.

Answer:

Try C it probably is your answer

Answer:

Answering so you can give other person branliest

Answer:

x = 22

Step-by-step explanation:

19+23=2X-2

42 = 2x - 2

-2x = -2 - 42

-2x = -44

x = 22

hope this helps

Responda:

21 dias

Explicação passo a passo:

Total de dias necessários = 70 dias

Dias usados ​​no mês 1 = 25 dias

Dias usados ​​no mês 2 = 24 dias

Dias usados ​​no total = 24 + 25 = 49 dias

Dias restantes :

70 dias - 49 dias

= 21 dias

Answer:

7.0

Step-by-step explanation:

Right angled triangle. To find the hypotenuse, use Pythagorean theorem.

Hypotenuse² =  base² + altitude²

                      = 6.5² + 2.7²

                      = 42.25 + 7.29

                     = 49.54

hypotenuse = √49.54 = 7.04 = 7

Step-by-step explanation:

by using Pythagoras law

h²=p²+b²

missing angle =h let

h²=(2.7)²+(6.5)²

h=√(49.50)=7.03=7

Answer:

[tex]\frac{2x+y}{w}[/tex]

Answer:

arc XY = 46°

Step-by-step explanation:

the arc of an inscribed angle is equal to 2 x the inscribed angle

mXY

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. [tex]\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}[/tex] Therefore, because sin is y/r, r = [tex]\sqrt{5}[/tex] and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = [tex]\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}[/tex]

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = [tex]4\sqrt{2}[/tex]. Now, to find csc, we have to do r/y.

csc = [tex]\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}[/tex]

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = [tex]\sqrt{7/16}[/tex] = [tex]\frac{\sqrt{7}}{4}[/tex]

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -[tex]\sqrt{7/9} = \frac{-\sqrt{7}}{3}[/tex]

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = [tex](\frac{-\sqrt{6}}{2})^{2}[/tex]

1 + cot^2 = 6/4

cot^2 = 2/4

cot = [tex]\frac{\sqrt{2}}{2}[/tex]

tan = [tex]\sqrt{2}[/tex]

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

[tex](\frac{2}{\sqrt{2}})^2[/tex] + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -[tex]\sqrt{3}[/tex]

cos = [tex]\frac{-\sqrt{3}}{3}[/tex]

Hope this helps!! :)

Answer:

sin(θ)=√7/4

tan(θ)= - √7/3

Step-by-step explanation:

c^2= √(4^2-(-3^2))

c^2= √(16-9)

c^2= √7

sin(θ)= opp/hyp=√7/4

tan(θ)= (opp )/adj= - √7/3

Answer:

Triangular prism

Step-by-step explanation:

A triangular prism has 9 edges, 6 vertices and 5 faces. I don't think there is any other shape which fits 9 edges and 6 faces.

Complete Question:

g(x), represents transformations on the parent function of [tex]y = (\frac{1}{2})^x[/tex].

Write the equation for g (x ) with the following transformations:

Reflect over y-axis, and shift right 7

Answer:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Step-by-step explanation:

Given

[tex]y = (\frac{1}{2})^x[/tex]

Represent the function as:

[tex]f(x) = (\frac{1}{2})^x[/tex]

Taking the transformations, one after the other:

Reflect over the y-axis.

This is represented by the rule: (x,y) ==> (-x,y)

So, we have:

[tex]f'(x) = (\frac{1}{2})^{-x}[/tex]

Shift right 7 units

This is represented by (x,y) = (x - b, y)

Where b represents the number of units

So, we have:

[tex]f'(x-7) = (\frac{1}{2})^{-x-7}[/tex]

Hence:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Answer:

18t-72

Step-by-step explanation:

Answer:

B.  [tex]x = -4\,\lor \,x = -1[/tex]

Step-by-step explanation:

Let [tex]\sqrt{-4-5\cdot x} = x[/tex], we solve for [tex]x[/tex] by algebraic means.

1) [tex]\sqrt{-4-5\cdot x} = x[/tex] Given

2) [tex]-4-5\cdot x = x^{2}[/tex] Definition of power/Symmetry of equality

3) [tex]x^{2}+5\cdot x + 4 = 0[/tex] Compatibility with addition/Commutative and associative properties/Existence of additive inverse/Modulative property

4) [tex](x+4)\cdot (x+1) = 0[/tex]         [tex]x^{2}+(a+b)\cdot x +a\cdot b = (x + a)\cdot (x+b)[/tex]

5) [tex]x = -4\,\lor \,x = -1[/tex] Result

Hence, the correct answer is B.

Answer:

24-18=6+6+12

hope this helps you!!

Step-by-step explanation:

Answer:

I dont know what sin is

Step-by-step explanation:

Answer:

Here, it's ratio

Step-by-step explanation:

4/9: 2 and 2/9

simplify

1:5

6/7:x

6/7 x 5 is....

30/7

Mixed number is 4 2/7

BLAM!!!

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

357 = L * 6 ft * 17/2 feets

357 feets³ = L * 51 feets²

L = 357 feets³ / 51 feets²

Length, L = 7 feets

Answer:

0 = -16t² + 3200 → 16t²= 3200 → t² = 200 → t = 10√2 s ≈ 14 s

The time taken by the skydiver to reach the ground is 14.1 second.

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

Given that, the height of a skydiver jumping out of an airplane is given by n = -16t² + 3200.

Here, n=0

-16t² + 3200=0

-16t²=-3200

t²=200

t=√200

t=14.14

t=14.1 second

Therefore, the time taken by the skydiver to reach the ground is 14.1 second.

To learn more about the solution of quadratic equation visit:

https://brainly.com/question/18305483.

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Answer:

B) ΔGRS ≈ ΔART by SAS Similarity

Step-by-step explanation:

Answer: $117,000

Step-by-step explanation:

The maximum that Arianna may borrow is 2.5 times her annual income.

First step therefore, would be to calculate her annual income:

= 900 * 52 weeks

= $46,800

She may borrow 2.5 times this:

= 46,800 * 2.5

= $117,000

Answer:

1152

Step-by-step explanation:

Answer:

7 melons

Step-by-step explanation:

So we first figure out the unit price of each melon by dividing 7.5 with 3 and you get $2.5 per melon. Then you divide 17.5 by 2.5 and then you should get 7.

Answer:

Percent of change each year = 5%

Step-by-step explanation:

P.S - The exact question is -

Given - The number of carbon atoms in a fossil is given by the function,

             y (x)= [tex]5100(0.95)^{x}[/tex], where x represents the number of years since

             being discovered.

To find - What is the percent of change each year? Explain how you arrived

              at your answer

Proof -

Given that, the number of carbon atoms in a fossil is y(x) = [tex]5100(0.95)^{x}[/tex]

Initially, the number of fossils be

y(0) = [tex]5100(0.95)^{0}[/tex] = 5100

After 1 year, The number of fossils be

y(1) = [tex]5100(0.95)^{1}[/tex] = 5100(0.95) = 4845

Now,

Change in 1 year = y(0) - y(1) = 5100 - 4845 = 255

Now,

Percent of chance  = [tex]\frac{255}{5100}[/tex] × 100%

                                = 0.05 × 100%

                                = 5%

⇒Percent of chance = 5%

∴ we get

Percent of change each year = 5%

Answer:

5b

Step-by-step explanation:

Answer:

what sign is between 4b and 5b

Step-by-step explanation:

Answer:

y=-2x+5

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

Answer:

6-12.

Step-by-step explanation:

Between 6 to 12 two numbers must the third side of the card fall.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that Sarah is creating a triangular birthday card for her teacher.

Thus in order to glue lace around the outside of the card, Sarah needs to know the length of each side.

It should be known that two of the sides measure 4 inches and 9 inches.

Therefore, in between 6 to 12 the third number must be lie.

More about the Algebra link is given below.

brainly.com/question/953809

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Answer:

[tex]\frac{10\sqrt{6} }{3}[/tex] and [tex]\frac{11\sqrt{3} }{3}[/tex]

Step-by-step explanation:

(a)

A = [tex]\frac{1}{2}[/tex] × 4[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = 2[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = [tex]\frac{10\sqrt{2} }{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

= [tex]\frac{10\sqrt{6} }{3}[/tex] units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4[tex]\sqrt{2}[/tex] )² + ([tex]\frac{5}{\sqrt{3} }[/tex] )²

    = 32 + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{96}{3}[/tex] + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{121}{3}[/tex] ( take the square root of both sides )

h = [tex]\sqrt{\frac{121}{3} }[/tex] = [tex]\frac{11}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

h = [tex]\frac{11\sqrt{3} }{3}[/tex]