Answers
Answer:
The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;
C. Increasing the angle from 25° to 50° will increase the total time spent in the air
Explanation:
The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;
[tex]T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}[/tex]
Where;
T = The time of flight of the projectile = The time spent in the air
u = The initial velocity of the projectile
θ = The angle of launch of the projectile
g = The acceleration due to gravity ≈ 9.81 m/s²
Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;
Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;
[tex]T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]
[tex]T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}[/tex]
sin(50°) > sin(25°), therefore, we have;
[tex]\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} > \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]
Therefore;
T₂ > T₁
Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.
Related Questions
a 200 kg rock lies on the surface of a planet. the acceleration due to gravity on the surface of the planet is 6,0. calculate the mass of the planet if it's radius is 700km
Answers
Answer:
4.41 × 10²² kg
Explanation:
Let the mass of planet be M, rock be m
Therefore,
[tex]net \: force \: on \: rock \: = weight \\ (200)(6) = \frac{(6.67 \times 10 {}^{ - 11})(200)(m) }{(700000) {}^{2} } \\ m = 4.41 \times 10 {}^{22} \: kg[/tex]
When electrons are shared unequally a/an
bond is formed
Answers
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its temperature and that of its surroundings. Suppose that the temperature of a cup of coffee obeys Newton's law of cooling. If the coffee has a temperature of 190190 degrees Fahrenheit when freshly poured, and 11 minutes later has cooled to 172172 degrees in a room at 6060 degrees, determine when the coffee reaches a temperature of 122122 degrees.
Answers
Answer:
4.9 minutes
Explanation:
Given; T(t) = Ce^-kt + Ts
Now;
T(t) = 190 degrees Fahrenheit
Ts = 60 degrees
To obtain C;
190 = Ce^0 + 60
190 - 60 = C
C = 130
Hence, to find k when t=11
172 = 130 e^-11k + 60
172 -60/130 = e^-k
e^-k = 0.86
ln(e^-k) = ln( 0.86)
-k = -0.15
k = 0.15
Hence at 122 degrees, t is;
T(t) = Ce^-kt + Ts
122 = 130e^-0.15t + 60
122 - 60/130 = e^-0.15t
0.477 = e^-0.15t
ln (e^-0.15t) = ln (0.477)
-0.15t = -0.74
t = 0.74/0.15
t = 4.9 minutes
A 1,000 kg car traveling 15.0 m/s brakes and comes to a stop after traveling 20.0 m.
a. What is the car’s initial kinetic energy?
b. What is the car’s final kinetic energy?
c. How much work does it take to stop the car?
d. How much constant force is applied in bringing the car to a stop?
Answers
Ek=1/2mv ²
Ek=1/2(1000)(15²)
Ek=112,500J
b. final kinetic energy=0J
as it comes to a stop so v=0
c. Work = ∆Energy
Or
Work=Fs
∆E/W= initial energy - final energy
∆E/W=112,500-0
∆E/W=112,500 J
d.W=Fs
112,500=F(20)
112,500/20 =F
F=5625 N
A. The car’s initial kinetic energy is 112500 J
B. The car’s final kinetic energy is 0 J
C. The amount of work done to stop the car is –112500 J
D. The force applied in bringing the car to a stop is –5625 N
A. How to determine the initial kinetic energy Mass (m) = 1000 KgInitial velocity (u) = 15 m/sInitial kinetic energy (KEᵢ) =?KEᵢ = ½mu²
KEᵢ = ½ × 1000 × 15²
KEᵢ = 112500 J
B. How to determine the final kinetic energy Mass (m) = 1000 KgFinal velocity (v) = 0 m/sFinal kinetic energy (KEբ) =?KEբ = ½mv²
KEբ = ½ × 1000 × 0²
KEբ = 0 J
C. How to determine the workdone Initial kinetic energy (KEᵢ) = 112500 J Final kinetic energy (KEբ) = 0 JWorkdone (Wd) =?Wd = KEբ – KEᵢ
Wd = 0 – 112500
Wd = –112500 J
D. How to determine the forceWe'll begin by calculating the acceleration. This can be obtained as follow:
Initial velocity (u) = 15 m/sFinal velocity (v) = 0 m/sDistance (s) = 20 mAcceleration (a) =?v² = u² + 2as
0² = 15² + (2 × a × 20)
0 = 225 + 40a
Collect like terms
0 – 225 = 40a
–225 = 40a
Divide both side by 40
a = –225 / 40
a = –5.625 m/s²
Finally, we shall determine the force. This is illustrated below:
Mass (m) = 1000 KgAcceleration (a) = –5.625 m/s²Force (F) =?F = ma
F = 1000 × –5.625
F = –5625 N
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Kepler's second law states that a line from the sun to a planet sweeps out equal areas in equal times. 2 d coordinate system with an elliptical orbit of planet around the sun. The elliptical orbit is centered at the origin. The Sun is located on the x axis between the origin and the far left edge of the orbit. The Planet is on the orbital path in the first quadrant and has a velocity vector that is pointing counter-clockwise on the orbital path. There is a line connecting the sun and the planet. The Perihelion is marked as the point where the orbit crosses the x axis closest to the Sun. The Aphelion is marked as the point where the orbit crosses the x axis farthest away from the Sun. The aphelion is the point in the orbit where the planet is the furthest distance from the sun, The perihelion is the point at which the planet is closest to the sun. At which point must the speed of the planet be greater
Answers
Answer:
the speed is higher in the PERIHELIUM
Explanation:
As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.
L = r x p = m r x v
where m is the planet mass and the Sun is considered fixed
Let's analyze this expression, if the anglar momentum is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed
So the speed is higher in the PERIHELIUM
A macro element that is a component of ATP
Answers
Phosphorus is a macro element that is a component of ATP.
Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
A. Elements with intermediate numbers of valence electrons are the last chemically stable.
B. Elements with the highest number of valence electrons are the most chemically stable.
C. Elements with intermediate number of valence electrons are the most chemically stable.
D. Elements wit the lowest number of valence electrons are the most chemically stable.
Answers
Answer:
C. Elements with intermediate number of valence electrons are the most chemically stable.
A volleyball of mass 0.28 kg is dropped from the top of the bleachers (height equals 12 m). What is the speed of the volleyball right before it hits the gym floor?
Answers
Answer:
hope this help pls give me brainless
The speed of the volleyball with a mass of 0.28 kg and height of 12 m will be 15.336 m/s.
What is Speed?
Speed is the rate of change of distance of an object with respect to time. Speed is a scalar quantity as it has only magnitude and no direction. The SI unit of speed is meter per second (m/s).
PE = KE
Potential Energy = Kinetic energy
mgh = 1/2 mv²
where, m is the mass of object,
g is the acceleration due to gravity,
h is the height of the object,
v is the speed of the object
gh = 1/2v²
2gh = v²
v = [tex]\sqrt{2gh}[/tex]
v = [tex]\sqrt{2(9.8)(12)}[/tex]
v = [tex]\sqrt{235.2}[/tex]
v = 15.336 m/s
Therefore, the speed of the volleyball will be 15.336 m/s.
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Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu intensitatea de 0,28 A
Answers
Answer:
Resistencia = 12.5 Ohmios
Explanation:
Dados los siguientes parámetros;
Voltaje = 3.5 Volts
Corriente = 0.28 Amps
Para encontrar el resistencia;
La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.
Matemáticamente, La ley de Ohm viene dada por la fórmula;
Voltaje = corriente * resistencia
Resistencia = voltaje/corriente
Resistencia = 3.5/0.28
Resistencia = 12.5 Ohmios
Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.
.
[tex]25 {?}^{?} \times \frac{?}{?} [/tex]
Answers
Answer:
what is your exact question.
The image above shows a raging mountain river in full flood. What do you think is making the water brown in color?
Answers
Answer:
FloodPlains
Explanation:
The floodplains mix with the dirt in the water in which then makes it brown. You're welcome:)
The floodplain is making the water brown in color.
A flood plain area can be defined as a specific land area prone to be flooding.Floodplain areas are often found in the coastline of streams and/or rivers.The brown color is due to the presence of soil that mixes with water.In conclusion, the floodplain is making the water brown in color.
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This was merely an accident and I did not mean to post a question.
Answers
Answer:
ok a good rest of your day
Explanation:
A satellite orbits earth at constant speed in circular orbit.Which statement is correct? A The resultant force on the satellite is zero. B The resultant force on the satellite is towards the Earth. C The resultant force on the satellite is away from the Earth. D The resultant force on the satellite is in the direction of motion.
Answers
Answer:
B The resultant force on the satellite is towards the Earth.
Explanation:
In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth
So as per the given situation, the option B is correct
And, the rest of the options would be wrong
And, the same would be relevant
8.How long is a day? A year?
Answers
Answer:
24 hours. 365 days
Explanation:
An object of mass 1.5 kg is moving forwards along the floor against an applied force of
40.0 N [backwards]. If the coefficient of kinetic friction is 0.25, determine the
acceleration of the object.
Answers
Answer:
The acceleration of the object is -29.12 m/s².
Explanation:
The acceleration of the object can be calculated by Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex] - F - F_{\mu} = ma [/tex]
[tex] - F - \mu mg = ma [/tex]
Where:
F: is the applied force = 40.0 N
μ: is the coefficient of kinetic friction = 0.25
m: is the mass of the object = 1.5 kg
g: is the acceleration due to gravity = 9.81 m/s²
a: is the acceleration =?
[tex] a = \frac{- F - \mu mg}{m} = \frac{-40.0 N - 0.25*1.5 kg*9.81 m/s^{2}}{1.5 kg} = -29.12 m/s^{2} [/tex]
The minus sign is because means that the object is decelerating due to the applied force and the friction.
Therefore, the acceleration of the object is -29.12 m/s².
I hope it helps you!
What is Newton’s 3rd Law of Motion?
a. Name an example and be sure to tell HOW it demonstrates the law.
Answers
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.
Explanation:
____________ is the rate at which the electric charges move through a given area.
Magnetism
Current
Induction
Flux
Answers
Answer:
current is the rate at which the electric charges move through a given areado the planets orbit the sun in a perfect circle
Answers
Answer:
All the planets in the Solar System orbit the Sun. When planets orbit the Sun, they don’t move around in a perfect circle. They all follow an 'elliptical path', meaning it looks more like an oval.
Explanation:
Answer:no planets orbit the sun in a perfect circle because they travel in a slightly elliptical orbit
Explanation:
A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x10⁻⁷ Ωm. Calculate the length of the wire.
Answers
Answer:
100 m
Explanation:
From the question,
R = Lρ/A.................... Equation 1
Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.
But,
A = πr².................... Equation 2
Where r = radius of the wire.
Substitute equation 2 into equation 1
R = Lρ/πr²
Make L the subject of the equation
L = Rπr²/ρ...................... Equation 3
Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm
Constant: π = 3.14
Substitute these values into equation 3
L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)
L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)
L = 100 m
Hence the length of the wire is 100 m
1. On planet Jupiter, the acceleration due to
gravity is about 26 m/s2. How high would a boy
be able to throw a ball on Jupiter if he can
throw it vertically 10m high on Earth?
Answers
Answer:
The boy can throw the ball to a height of 3.85 m on Jupiter
Explanation:
We'll begin by calculating the initial velocity at which the ball is thrown on EARTH. This can be obtained as follow:
On Earth:
Acceleration due to gravity (g) = 10 m/s²
Maximum height (h) = 10 m
Final velocity (v) = 0 m/s (at maximum height)
Initial velocity (u) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = u² – 2 × 10 × 10
0 = u² – 200
Collect like terms
0 + 200 = u²
200 = u²
Take the square root of both side
u = √200 m/s
Finally, we shall determine the maximum height of the ball at JUPITER. This can be obtained as followb
On Jupiter:
Acceleration due to gravity (g) = 26 m/s²
Initial velocity (u) = √200 m/s
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =..?
v² = u² – 2gh (since the ball is going against gravity)
0² = (√200)² – 2 × 26 × h
0 = 200 – 52h
Collect like terms
0 – 200 = –52h
–200 = –52h
Divide both side by –52
h = –200 / –52
h = 3.85 m
Thus, the boy can throw the ball to a height of 3.85 m on Jupiter.
A fruit basket of mass 44.5 kg weighs approximately how much in newton? (Answer should have a number and a proper unit) *
Answers
Answer:
445N
Explanation:
F=mg
m=44.5kg
g=10m/s2
F=44.5 * 10
=445N
Some people say that you can contract HIV by sharing a drink with someone who has HIV. True or false? Why?
Answers
Answer: This is definitely false... you have to.. have séx with someone who has H.I.V to actually get H.I.V
Temperature is independent of mass
A- True
B- False
Answers
Answer:
False. Temperature is independent of volume
Answer: the answer False sorry if its wrong
Explanation: have a nice day\night buddy
Can anyone help me!!!
I need this really soon!!!!
Q. Rama's weight is 40kg . She is carrying a load of 20 kg up to a height of 20 metres. What work does she do? Also mention the type of work
Also show step by step explanation. please!!
No links!!!!
No spams!!!!
Answers
Answer:
W = 1,176 10⁴ J
Explanation:
Work is defined by
W = F . d
bold indicates vectors
W = F d cos θ
In this case we must find the force to raise the load and the branch, suppose that the rate of rise is constant, this is the most common case
Σ F = 0
F - W₁ - W₂ = 0
where W1 is the weight of the branch and w2 wl weight of the load
F = (m₁ + m₂) g
This force is directed upwards and the displacement is upwards, therefore the angle is zero and the cos 0 = 1
we substitute in the work equation
A = (m₁ + m₂) g d
let's calculate
W = (40 + 20) 9.8 20
W = 1,176 10⁴ J
This is the work done by the external force
The body needs small amounts of ________ to help enzymes break down proteins.
Answers
Answer:
I would say vitamin B-6
Explanation:
it is also known as pyridoxine. it helps ebzymes break down protein and carry the dismantled amino acids to the blood stream
Hope this helps ✌✌
Answer:
The body needs small amount of vitamin B-6 to help enzymes break down protein and carry the dismantled amino acids to the blood stream.
Un coche que lleva una velocidad constante de 90 km/hora durante 2 horas ¿Cuánto espacio recorre?Si encuentra un obstáculo en la carrera y tiene que parar 10 segundos calcula la aceleración
Answers
Answer:
(i) El coche recorre 180 kilómetros.
(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Explanation:
El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.
Primera parte - Viaje a velocidad constante
La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:
[tex]x = v\cdot t[/tex] (1)
Donde:
[tex]x[/tex] - Distancia recorrida, en kilómetros.
[tex]v[/tex] - Velocidad, en kilómetros por hora.
[tex]t[/tex] - Tiempo, en horas.
Si sabemos que [tex]v = 90\,\frac{km}{h}[/tex] y [tex]t = 2\,h[/tex], entonces la distancia recorrida por el coche es:
[tex]x = v\cdot t[/tex]
[tex]x = 180\,km[/tex]
El coche recorre 180 kilómetros.
Segunda parte - Deceleración
Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:
[tex]a = \frac{v-v_{o}}{t}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.
[tex]v[/tex] - Velocidad final, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
Si sabemos que [tex]v_{o} = 25\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], entonces la deceleración experimentada por el coche es:
[tex]a = -2.5\,\frac{m}{s^{2}}[/tex]
El coche decelera a razón de 2.5 metros por segundo al cuadrado.
A light wave has a frequency of 5 x 108. What is the wavelength of the light wave? (Assume the speed of light to be 3 x 108.)
Answers
Answer:
Wavelength of light wave = 0.6 m
Explanation:
Given:
Frequency of wave = 5 x 10⁸
Speed of light = 3 x 10⁸ m/s
Find:
Wavelength of light wave
Computation:
The size of a wave form is its spatial duration, or the duration in which the wave's form repeats.
Wavelength of light wave = Speed of light / Frequency of wave
Wavelength of light wave = [3 x 10⁸] / [5 x 10⁸]
Wavelength of light wave = 0.6 m
A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder
Answers
Answer:
[tex]1311.5\ \text{Nm}[/tex]
Explanation:
l = Length of ladder = 8.57 m
m = Mass of ladder = 21.4 kg
F = Force on ladder = 258 N
[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Net torque is given by
[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]
The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].
A car moves 8 km from home to school and then back to the home. a) Calculate the Distance covered by this car. b) What is the Displacement for the whole trip?
Answers
Explanation:
Distance covered = Total distance travelled by the car
Since the car travels to school and back to home again,
Total diatance covered = 8 + 8 = 16km
Displacement = Shortest distance between start point and destination.
Since, the car returns back to home from school,
the start and destination point are same.
So Displacement = 0
Please solve Question 10
Answers
Answer:
Time = 0.6secs
Explanation:
10) Distance = speed * time
Given the following
Distance = 204m
Speed/velocity = 340m
Get the time
Time = distance/velocity
Time = 204/340
Time = 0.6secs