help me please this is science

Answer:

It’s C

Explanation:

Answer:

its the area method

Explanation:

i did it on edge nuity and i got it correct.

Answer:

b might be correct

Explanation:

because alcohol react complete different manner in presence of catlyst

Answer:

Using V= IR

I= 0.2307 Ampere

Answer:

The tesla is the SI unit for the magnetic field (T). One tesla is the magnetic field in which a charge of one coulomb travelling perpendicular to the magnetic field at a velocity of 1 m/s receives a force of one newton.

OAmalOHopeO

Answer:

One of the most common is to use pH strips.

Explanation:

Answer:

T

Explanation:

I did sme answer

Answer:

9.8kW

Explanation:

Given data

Mass= 60kg

Hieght= 4m

Time= 4.2seconds

We know that the energy possessed is given as

PE=mgh

PE=60*9.81*4

PE= 2354.4 Joulse

Also, the expression for power is

Power=Energy*Time

Power= 2354.4*4.2

Power=9888.48 watt

Power= 9.8kW

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

The answer is A. Just did it.

Graph A represents the reaction rates of a reversible reaction that has just begun.

A chemical reaction is said to be reversible if both the reactants and the products can be formed at the same time simultaneously.

Here,

Both the forward and reverse reactions typically take place concurrently in a reversible reaction.

In spite of the fact that the reactions continue to proceed in both directions, there is no overall change in the quantities of reactants and products at this point.

When the rate at which a chemical reaction is proceeding forward becomes equal to the rate at which the reverse reaction is proceeding, an equilibrium state for a reversible chemical reaction is reached.

Hence,

Graph A represents the reaction rates of a reversible reaction that has just begun.

To learn more about reversible reaction, click:

https://brainly.com/question/31950205

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Answer:

Kinectic

Explanation:

kinetic energy can be regarded as the energy that is been posses by a body as a result of motion, it can be reffered to as work that is required in accelerating a body having a given mass from rest up to a particular velocity. Once this energy is gained during acceleration, the Kinectic energy is maintained by the body unless there is change in speed.

Formula

K.E= 1/2 mv^2

Where m= mass of the object

v= velocity

Therefore, the energy of a semi-truck doing 100 kph on the kighway is a " Kinectic energy"

Answer:

The total force is [tex]F_{tot}=4.29\: N[/tex]

The direction is [tex]\omega=32.43^{\circ}[/tex]

Explanation:

First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).

Let's use the tangent function.

[tex]tan(\alpha)=\frac{2}{1.5}[/tex]

[tex]\alpha=53.13^{\circ}[/tex]  

Now, let's find the magnitude of the force F(12).

[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]

Where:

[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]

[tex]|F_{12}|=3.6\: N[/tex]

The magnitude of the force F(23) will be:

[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]

The distance between these charges is:

[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]

[tex]d_{23}=2.5\: m[/tex]

[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]

[tex]|F_{23}|=2.88\: N[/tex]

So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.

We just need to add these two forces (vectors) and get the total force acting on q2.

Total force in x-direction:

[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]

[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]

[tex]F_{tot-x}=-5.33\: N[/tex]

Total force in y-direction:

[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]

[tex]F_{tot-y}=2.88sin(53.13)[/tex]

[tex]F_{tot-y}=2.3\: N[/tex]

Therefore, the magnitude of the total force will be:

[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]

[tex]|F_{tot}|=4.29\: N[/tex]

and the direction is:

[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]

[tex]\omega=32.43^{\circ}[/tex]

I hope it helps you!

Answer:

0.2 m/s²

Explanation:

acceleration formula is given by the difference in velocities over the time

hence final velocity - intial velocity / time

= 36-12/120

=0.2m/s²

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

Answer:

A small charged particle.

Explanation:

Answer:

affects about 5.7 million adult Americans at age 18 or older every year

Explanation:

Answer:

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a = [tex]\frac{v^2}{r}[/tex]

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v = [tex]\sqrt{\mu g r}[/tex]

we calculate

      v = [tex]\sqrt{0.1 \ 9.8 \ 3}[/tex]

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

Answer:

The answer is "perpendicular and distance".

Explanation:

The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.

The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.

Answer:

I would choose A. and B

Explanation:

The parent and daughter elements are different and the number of atoms is not conserved.

Answer: 6 x 1024 kg =  6144 kg

3 x 1025 kg = 3075 kg

5,6 x 1020 N = 5712 N

6144 + 3075 = 9 219 kg

9219 x 5712 = 52 658 928 de distance

je ne suis pas sur de mon cacul

Explanation:

Answer:

0.21486 mm

Explanation:

The formula for the maximum intensity is given by;

I = I_o•cos²(Φ/2)

Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)

Where;

y is the distance from the central maximum

d is the distance between the slits

λ is the wavelength

L is the distance to the screen

Thus;

I = I_o•πdy/(λL)

We are given;

d = 0.05 mm = 0.5 × 10^(-3) m

λ = 540 nm = 540 × 10^(-9) m

L = 1.25 m

I/I_o = 50% = 0.5

From earlier, we saw that;

I = I_o•πdy/(λL)

We have I/I_o = 0.5

Thus;

I/I_o = πdy/(λL)

Plugging in the relevant values;

0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)

Making y the subject, we have;

y = (0.5 × 540 × 10^(-9) × 1.25)/(π × 0.5 × 10^(-3))

y = 0.00021486 m

Converting to mm, we have;

y = 0.21486 mm

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

Answer:

1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move

2. Mike

Explanation:

According to Newton's second law of motion, force is proportional to te rate of change of momentum produced

Mathematically, we can write the above law as follows;

F = m × a

Where;

F = The force acting on the object

m = The mass of object in motion

a = The acceleration of the object

1. The given parameters in the question are;

The weight of Tim = 311 Newtons (70 lbs.)

The weight of Mike = 50 Newtons (50 lbs.)

The minimum force required to pull the wagon to constant speed = The weight of the wagon

With the assumption that the wagon has very little weight, we have

Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a

Given that mass is proportional to weight, we can write;

Force from mike, Tim on the wagon F₁ = 311 N × a₁

Similarly when they switched places, we have;

Force from Tim, Mike on the wagon  = F₂ = 50 N × a₂

Therefore, for the same force, F₁ = F₂ = F, we have;

a₁ = F₁/(311 N) = F/(311 N)

a₂ = F₂/(50 N) = F/(50 N)

By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁

The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move

2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we  are also given that F₃ > F₁

By Newton's second law of motion, we have;

a₃ = F₃/(50 N) and a₁ = F₁/(50 N)

From F₃ > F₁, we have;

F₃/(50 N) > F₁/(50 N)

Therefore;

a₃ > a₁

The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike

Therefore, Mike is on the wagon when it has the greatest acceleration.

Answer:

I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”

Hope this help!:)

Answer:

 m = 4.0

Explanation:

For this exercise in geometric optics we will use the equation of the constructor

         [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and image, respectively.

In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]

let's calculate

         [tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6

         [tex]\frac{1}{q}[/tex] = -0.125

         q = -8 cm

the magnification is

        m = - q / p

        m = 8/2

        m = 4.0

Answer:

vz vc

Explanation:

v b

Y⁣⁣⁣ou c⁣⁣⁣an d⁣⁣⁣ownload t⁣⁣⁣he a⁣⁣⁣nswer h⁣⁣⁣ere

bit.[tex]^{}[/tex]ly/3a8Nt8n

Answer:

a) El trabajo realizado es de 274,680 J

b) La potencia de la carretilla elevadora es de 4578 Watts.

c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas es de 274.680 Joules.

e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J

Explanation:

a) Los parámetros dados son;

La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s

La masa que debe levantar la carretilla elevadora, m = 700 kg

La altura a la que se levantará la masa, h = 40 m

El trabajo realizado, W = Fuerza, F × Distancia, h

 La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g

Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²

∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J

b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos

∴ Potencia = Trabajo / tiempo

Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts

c) Energía cinética, K.E. = 1/2 · m · v²

La energía cinética de la carretilla elevadora, K.E. se da como sigue;

Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas a 40 m, P.E. = m · g · h

∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios

e) La energía mecánica, M.E. = P.E. + K.E.

∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J

La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.