Help me please!!!!!!!

Answer:

put it on the calculator

Answer:

its 136

Step-by-step explanation:

Answer:

The first ">" should be underlined in the equation.

..

The rules for solving inequalities are the same as those used for solving regular equations except for one important rule, that is, when you multiply both sides of an inequality by -1, the inequality sign reverses.

..

5-4x≥17

-4x≥12

-x≥3

Step-by-step explanation:

Answer:

hope it helps.

Answer:

D. and F.

Step-by-step explanation:

Answer:

m=  1/2

y=1

Step-by-step explanation:

you go up 2 over 4 but you simplify it to 1/2

you then go to the first point for y intercept, which is 1 (because it follow the patteren)

Answer:

1.86

Step-by-step explanation:

Since decimals are the same as fractions, we can convert 4/5 to .80. And since "of" means multiply, we can convert .80 of 9.3 to:

.8 x 9.3 = 7.44

This is the amount of pears, so we subtract:

9.3 - 7.44 = 1.86

The weight of the apples is 1.86.

Answer:

6 passengers got off at New Jersey

Step-by-step explanation:

let the number of passengers who got off be x and let the number of passengers who boarded the bus be y

y=2x

44 - x + y=50

y=50-44+x

y=6+x

subst y=2x

2x=6+x

2x-x=6

x=6

Number of years to make a worth of $45000 with Depreciation rate of 12% and Total worth $45000 is 4 years

Years= 4 year

The term depreciation refers to an accounting method used to allocate the cost of a tangible or physical asset over its useful life. Depreciation represents how much of an asset's value has been used. It allows companies to earn revenue from the assets they own by paying for them over a certain period of time.

Given that:

limousine costs $75000

Depreciation rate = 12% per year= 0.12

Total worth= $45000

By using the formula for year we have

total worth = cost of object [tex](1- Depreciation \;rate)^{year}[/tex]

45000= 75000x [tex](1-0.12)^{year}[/tex]

0.6= [tex](0.88)^{year}[/tex]

Now taking log on both side we have

log 0.6= year x  log0.88

-0.2218 = year x -0.05551

year= 4.049

year≈ 4 year(rounding off nearest year)

Learn more about depreciation here:

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Answer:answer is 2.5v+5<5v A.k.a:A

Step-by-step explanation:

Answer:

4.2

Step-by-step explanation:

By intersecting chords theorem:

[tex]x \times 10 = 6 \times 7 \\ \\ 10x = 42 \\ \\ x = \frac{42}{10} \\ \\ x = 4.2[/tex]

Answer:

Its A let me know if im wrong!

Answer:

Fourth option is most suitable here.

Answer:

The angle between the two blades is 120 degree.

Step-by-step explanation:

number of blades = 3

The blades are equally spaced.

The total angle around a circle is 360 degree.

So, the angle between the two blades is given by

[tex]\theta =\frac{360}{n}\\\theta =\frac{360}{3} = 120^{o}[/tex]

The answer to the above statement is: $k$ has a perfect square trinomial value of 16.

To determine the value of $k$ such that $9x^2 - 16x + k$ is a perfect square trinomial, we can follow these steps:

Identify the form of a perfect square trinomial. A perfect square trinomial can be written in the form $(ax + b)^2$, where $a$ and $b$ are constants.

Examine the $9x2 - 16x + k$ trinomial in comparison to the perfect square trinomial form.  We need to match the quadratic term and the linear term.

The quadratic term in the perfect square trinomial is $(ax)^2 = a^2x^2$, which corresponds to $9x^2$ in our trinomial.

The linear term in the perfect square trinomial is $2abx$, which corresponds to $-16x$ in our trinomial.

By comparing the terms, we can set up the following equation: $2abx = -16x$. This implies that $2ab = -16$.

Solve for $a$ and $b$ using the equation $2ab = -16$.

Let's consider possible factor pairs of $-16$: $(1, -16)$, $(2, -8)$, and $(4, -4)$.

We need to find a pair $(a, b)$ such that $2ab = -16$. Checking the options, we find that $(a, b) = (2, -4)$ satisfies the condition since $2(2)(-4) = -16$.

To determine the value of $k$, substitute the values of $a$ and $b$ into the perfect square trinomial form.

The perfect square trinomial form is $(ax + b)^2 = (2x - 4)^2 = 4x^2 - 16x + 16$.

We can see that $k = 16$ by comparing the derived form to the supplied trinomial $9x2 - 16x + k$.

As a result, $k$ has a Perfect Square Trinomial value of 16.

For such more questions on Perfect Square Trinomial

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Answer:

71

Step-by-step explanation:

ndndnrbrjen3n3nn3b2n2b2b

Answer:

The most efficient method is completing the square because the equation can be written in the form [tex]x^2 - d[/tex]

x ~ 2.24

x ~ -2.24

Step-by-step explanation:

Solve the equation using any method that is efficient. The most efficient method is completing the square, because the equation can be written in the form [tex]x^2 - d[/tex]. Use this method to solve the problem, since the equation is already in the format, [tex]x^2 - d[/tex], all one has to use is inverse operations to solve the equation.

[tex]-5x^2 = -25\\/-5\\\\x^2 = 5\\\sqrt{}\\\\x = +- \sqrt{5}[/tex]

x ~ 2.24

x ~ -2.24

Answer:

Taking 45 degree as reference angle

Then using sine rule

sin 45=

p/h

replacing the value of sin 45 degree by 1/root 2.so

1/root 2=9/c

doing cross multiplication

9*root 2=1*c

9 root 2 =c

therefore the value of c is 9 root 2

Step-by-step explanation:

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

I'll do problem 1 to get you started

First sort the values from smallest to largest and you should end up with this set

{1, 6, 7, 11, 13, 16, 18, 21, 22, 23}

The smallest value is 1 and the largest value is 23, so the min and max are 1 and 23 in that order.

We have ten values in this set. The middle-most number is going to be between the 10/2 = 5th slot and the 6th slot. The numbers 13 and 16 are in the fifth and sixth slots respectively. Average those values to get (13+16)/2 = 29/2 = 14.5

The median is 14.5 which is another name for the second quartile (Q2).

Now split the data set into two halves

L = lower half of values smaller than the median

U = upper half of values larger than the median

In this case,

L = {1, 6, 7, 11, 13}

U = {16, 18, 21, 22, 23}

sets L and U have five items each

Find the median of set L and U to get 7 and 21 respectively. These medians of L and U represent the values of Q1 and Q3 in that order.

Q1 = first quartile = 7

Q3 = third quartile = 21

===================================================

Answer:

The five number summary for problem 1 is

Answer:

What?

Step-by-step explanation:

G8ve me more info and Ill answer again

Answer:

hope this helps

Step-by-step explanation:

31 divided by 2 = 15.5 then do 15.5 x 15.5= 240.25 then you do 240.25 x 3.14 = 754.385

Answer:

12

Step-by-step explanation:

Answer:

Hello! answer: 62.8

Step-by-step explanation:

Cirmcumfrence is just diameter × pi so since we are using 3.14 for pi we can just do 3.14 × 20 so...

3.14 × 20 = 62.8 Therefore the circumference is 62.8 Hope that helps!

Answer:

There is a 1/3 chance it lands on each section

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

Because there are 2 numbrs that are greater than 3.

Hope this helped!

Stay Safe!

Answer:

c≈5.2

Step-by-step explanation:

c=a2+b2=1.412+52≈5.19501

Answer:

8 1/3 or 8.33 yards per second

Step-by-step explanation:

100/12 = 8 1/3

Answer:

Step-by-step explanation:

so we know that a triangle degrees have to add up to 180 in the inside right? So we know c is 90 and so you need to find A and B. The left over degrees you have is 90 so the sum of B and A would have to be 90, thats all i can help you with sorry.

Answer:

4/3

Step-by-step explanation:

7x + 4 = 10x

4 = 3x

x = 4/3