HELP ME PLSSSS

Heights of Males (in inches)



The heights of eight males in inches were used to make the box plot shown above. Which of the following is the median of the set of heights?
A. 69
B. 75.5
C. 73
D. 73.5

brainliest, extra points.

i understand if u need points , so u can go to my old questions and answer.

pls only answer if your for sure it's correct!

Answer:

number of people / land area = population density

57,714 / 836,109 ≈ 0.07 people/[tex]mi^2[/tex]

Answer:

.07 people per square mile

Step-by-step explanation:

We can just divide the people by area

57714/836109=.06902688525 or about .07 people per square mile

I think you got confused about the division and what to divide by what

Look over here we divide the PEOPLE by the AREA so we get the amount of PEOPLE per square mile

If we did it the opposite way we get THE AREA that EACH PERSON HAS

Answer:

answer is 63 min

Step-by-step explanation:

math+calculator   like and subscribe to yourmom.com31  

Answer:

B. 4,500

Step-by-step explanation:

1 liter = 1,000 milliliters

4.5 x 1,000= 4,500

:DDDD Glad I could help

Answer:

1d674hh

Step-by-step explanation:

drrx+mub

Answer:

Formula = (x1+x2 , y1+y2)

2. 2

Step-by-step explanation:

(-5.5 -0.5. ,-6.1+9.1)

2. 2

(-6. 3 )

2 , 2

m= (-3, 3 )

2

Answer:

X=$96

Y=$19

Step-by-step explanation:

x=4y+20

X+Y=$115

4Y+20+Y=$115

5Y+20=$115

-20 -20

5Y=$95

/5 /5

Y=$19

X=4 x $19 + $20

X=$76+$20

X=$96

In linear equation,  cost of calculator = $96 , cost of textbook = $19 is the   cost  of each item .

What are instances of linear equations?

let cost of calculator = x

cost of textbook = y

x=4y+20  .................(1)

X+Y= 115  .................(2)

put value of equation 1 in 2

4Y+20+Y= 115

5Y+20= 115

5Y = 115 - 20

5Y =  95

Y = 95/5

Y = 19

Put value of y in equation 1

X=4 x 19 + 20

X= 76+ 20

X= 96

cost of calculator = 96

cost of textbook = 19

Learn more about linear equation

brainly.com/question/11897796

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✧ [tex] \underline{ \underline{ \pink{\large{ \tt{E \: X \: P \: L\: A \: N \: A \: T \: I \: O \: N}}}}}: [/tex]

Part 1 :

☃ [tex] \underline{ \large{ \sf{Vertical \: Line \: Test}}} : [/tex] ⇾ All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called the vertical line test.

( See the attached picture )

Part 2 :

☂ The set of all the images of the elements of domain under the function ' f ' is called the range of a function. In other words , the set of second components of a function is called range. We are given the function :

The above numbers [ in bold ] are the range of given function. Now, If we arrange these numbers in ascending order, we get ( -9 , -3 , 0 , 5 , 7 ).

Hence , Choice B [ {y | y = –9, –3, 0, 5, 7} ] is correct.

♕ Hope I helped! ♡

☄ Have a wonderful day / night ! ☼

✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ☥

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Sample Response:

The vertical line test is a way to determine if a relation is a function. This test determines if one input has exactly one output on the graph. If any vertical line passes through more than one point on the graph, then the relation is not a function because two different outputs have the same input.

Answer:

200.96

Step-by-step explanation:

pi*r^2

Answer:

Step-by-step explanation:

1)  

The given angle is 57°   at least I think it is .  so we need to look at the triangle being formed inside the circle.   the legs from the center to the edge are both the radius. so they are the same lengths.   so that triangle is an isosceles.  and the two angle at the circles perimeter are going to be both the same, b/c that's a rule of an isosceles triangle.   so now we not both angles on the perimeter of the circle of that inner triangle are both 57°  :)  that's great, b/c now we can find the angle of the inner point of that triangle.   it's going to be  180 = 57 + 57 +  inner angle x  

180 - 57 -57  = inner angle x

66 = x    , so that inside angle on the isosceles is 66°  

that's great to know, that angle is also part of the bigger triangle that goes outside the circle and I'm pretty sure the angle that is at the top of the triangle , at least in the picture,  is a right angle or 90° sooo we now know two angle of the triangle and can figure our the  "?"  one.  :)

180 = 66 + 90 + ?

180-66-90 = ?

24 = ?

so that angle at the point with the "?" is 24 °  :)

2)

The given angle is 24°  :0   look above.. that last we we solved was also 24°

everything is the same in drawing 2, as in drawing 1.   We can simply use all the things we know about drawing 1..    The inside angle at the center of the circle will be 66 °  and the two angle out by the perimeter of the circle will be 57° just like in drawing 1.     They made that a little too easy  :D  Le'ts hope we get a few more like that  :)

3)

I'm just sure why the drew the circle in this drawing.  we don't need it to solve this triangle.  Maybe  you're not supposed to use this very common way to solve the triangle yet?   but maybe it's good to introduce it anyway?  since we are given the hypotenuse (long side) and the adjacent side (next to)  the angle we can just use SOH CAH TOA to find any angle or side of this triangle.    I'll put the useful remind of how trig functions ( sin, cos, ect.) fit on triangles and then we'll use them to find the parts we want. :)

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

copy the above down.  and put in in a handy place on your computer , for quick reference any time you have to solve a triangle.  it's really super helpful :)

okay now look at the triangle in question 3)  what do we know, and what do we want to find?   we know the Hyp and Adj and one angle and want to find the Opposite  (Opp) side from the known angle.  sooo we have a choice of SOH or TOA.. let's use SOH,  

SOH ⇒ Sin(Ф) = Opp / Hyp

Sin(53) = Opp/ 10

algebra skill engage :P

10* Sin(53) = Opp

7.9863551 = Opp  

so that side with the question mark is 8.0  long. ( rounded to nearest 10th)

4)

On this triangle we are given the Opp and the Adj sides and an angle and are asked to find the Hyp

which trig function would you like to use?

Let's use CAH this time.  We could also use SOH , but we just used that one. let's try out the "tools" of the trade :)

CAH ⇒ Cos(Ф) = Adj / Hyp

Cos(37) = 8/Hyp

use algebra skillz

Hyp = 8 / Cos(37)

use calculator to find  Cos(37) :/

Hyp = 10.01708

? = 10.0  ( rounded to nearest 10th )

5)

oh for this one we do need the circle, and I don't know why they want people to know this , nobody uses this math  :?  Anyway,  

there is a confusing formula for this type of problem

∠ = (bigger arc - smaller arc ) / 2

since we're given the 65° , we know that 2*65= 130 which is the angle of the bigger arc - smaller arc = 130 °

now we have to use our really keen algebra skillz to see that

if the total all the way around a circle is 360 and we have 130 of those left  so

eq. 1)  360 = big arc + small arc

then

360-smal arc = big arc

and

eq. 2)  130 = big arc - small arc

plug in for "big arc" what we know from above :P

130 = 360-small arc - small arc

130 = 360 - 2small arc

130 + 2 small arc = 360

2 small arc = 230

small arc = 115

:0  wow.. we solved it..  that was a lot of fancy algebra huh  :P

? = 115°  ( the small arc)

6)

same as 5

given 72°

72*2=144°

eq. 1)   360 = big arc + small arc

eq. 2 ) 144 = big arc - small arc

solve for big arc this time

360-bigl arc = small arc

now plug into eq. 2

144 = big arc - (360-big arc)

144 = big arc - 360 + big arc

144 = 2big arc - 360

144+ 360 = 2 big arc

504 =  2 big arc

252° = big arc

yay solved !! phew.. that was a lot of algebra.. :P

5 and 6 are tough, ask the teacher how many others got it  :)

Answer:

The store will make money for each option/event. For the first option, the store will earn extra $72. For the second option, the store will earn extra $14.4.

Step-by-step explanation:

120 x 1.6 = 192

192 x 0.7 = 134.4

For problem 1, the answer is $192

For problem 2, the answer is $134.4

The store will make money for each option/event.

192-120=72

134.4-120=14.4

Answer:

The answer is B 100 in^2

Step-by-step explanation:

add 15+11+24 = 50 X 2 = 100

so yeah

good luck :D

Answer:

1.

mean= 84.6

median=84

mode=84

2.

mean=10.14

median=9

mode=9

3.

mean=22.3

median=21

mode=phi

Step-by-step explanation:

mean: the sum of of the quantities by their number

median: the median value after rearranging the values

mode: the value that occurs most frequently

in the second question

mean = (8+9+9+9+9+10+11+15)/8

median(even number) =(9+9)/2=9

mode=9

Answer:

for data set 1

1.mean-84.6

2.median-(84+84)/2 = 84

3.mode-84

for data set 2

1.mean-9.25

2.median-(9+9)/2 = 9

3.mode-9

for data set 3

1.mean-22.3

2.median-21

3.mode-no mode with this data set

hope this helped!!

Answer:

|6| > -8

Step-by-step explanation:

The absolute value of |6| is 6. Because positives are greater than negatives, 6 is greater than -8.

Answer: greater than

Step-by-step explanation: Absolute value shows a number's distance from zero on a number line. 6's distance from 0 is still 6. 6 is greater than -8, therefore l6l>-8

1. Radius (r) of the sphere = 10 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (10)²

Surface area of the sphere = 4 × π × 10 × 10

Surface area of the sphere = 400π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (10)³

Volume of the sphere = 4/3 × π × 10 × 10 × 10

Volume of the sphere = 4000π/3

Volume of the sphere = 1333.3π cubic units. [approx] (Ans)

__________________________________

2. Diameter of the sphere = 16 units. (Given)

Radius (r) of the sphere = 16/2 = 8 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (8)²

Surface area of the sphere = 4 × π × 8 × 8

Surface area of the sphere = 256π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (8)³

Volume of the sphere = 4/3 × π × 8 × 8 × 8

Volume of the sphere = 2048π/3

Volume of the sphere = 682.6π cubic units. [approx] (Ans)

__________________________________

3. Radius (r) of the sphere = 5 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (5)²

Surface area of the sphere = 4 × π × 5 × 5

Surface area of the sphere = 100π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (5)³

Volume of the sphere = 4/3 × π × 5 × 5 × 5

Volume of the sphere = 500π/3

Volume of the sphere = 166.6π cubic units. [approx] (Ans)

__________________________________

4. Diameter of the sphere = 18 units. (Given)

Radius (r) of the sphere = 18/2 = 9 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (9)²

Surface area of the sphere = 4 × π × 9 × 9

Surface area of the sphere = 324π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (9)³

Volume of the sphere = 4/3 × π × 9 × 9 × 9

Volume of the sphere = 2916π/3

Volume of the sphere = 972π cubic units. (Ans)

__________________________________

Answer:

40 gallons of milk

Step-by-step explanation:

trust me that's the answer

The farmer will get 35 gallons of milk from 14 cows.

Process:

1) find the unit rate. do this by taking the independent value and divide it by the dependent value

10/4=2.5

2) Take this number and multiply it by the next dependent value

2.5 x 14 = 35

Answer:

The 3rd one

Step-by-step explanation:

Answer:

x = 1 and y = −2

Step-by-step explanation:

Rewrite equations:

x + 2y = −3

3x − 2y = 7

Step 1: Solve x+2y=−3 for x:

x + 2y = −3

x + 2y + −2y = −3 + −2y (Add -2y to both sides)

x = −2y − 3

Step 2: Substitute −2y − 3 for x in 3x − 2y = 7:

3x − 2y = 7

3(−2y − 3) − 2y = 7

−8y − 9 = 7 (Simplify both sides of the equation)

−8y − 9 + 9 = 7 + 9 (Add 9 to both sides)

−8y = 16

−8y/−8 = 16/−8 (Divide both sides by -8)

y = −2

Step 3: Substitute −2 for y in x = −2y − 3:

x = −2y − 3

x = (−2)(−2) − 3

x = 1 (Simplify both sides of the equation)

Answer:

62 in

Step-by-step explanation:

You can split up the rectangles and find the surface area of each on them add them

Hope this helps!

Answer:

Step-by-step explanation:

Add the first two columns - third column. See if it equals last column.

Number one is correct, number 2 is off by $1.00,etc

let me know if you are still confused

Step-by-step explanation:

I am sorry I didn't know the answer

Answer:

2nd option

Step-by-step explanation:

The secant- secant angle CAD is half the difference of the intercepted arcs, that is

∠ CAD = [tex]\frac{CD-GE}{2}[/tex]

Answer: 7

Step-by-step explanation:

We know that the ratio adults: children must be 1:8.

So if there are 58 children the ration is x: 56

56/8 (to find the number of adults) = 7

7:56 = 1:8

Step-by-step explanation:

p^2+2p=63

p^2+2p+1^2=63+1^2

p^2+2p+1=64

(p+1)^2=64

p+1=8

p=8-1

p=7

Answer:

hi

Step-by-step explanation:

i think it is A

because

[tex] \frac{x}{3} + 10 = \frac{15}{3} + 10 = 5 + 10 = 15[/tex]

hope it helps

have a nice day

Answer:

answer is A and C

hope it helps

Answer:

x = 20

Step-by-step explanation:

60 = x+40

subtract 40 from both sides and you get

20 = x

so x = 20

Answer:

this is the answer A

Step-by-step explanation:

Considering the provided information in the given question, we have :

We have to find the area of the parallelogram.

As we know that,

⇒ Area of parallelogram = Base × Height

Substituting the values,

⇒ Area of parallelogram = 5.5 cm × 2.5 cm

⇒ Area of parallelogram = 13.75 cm²

Therefore, area of the parallelogram is [tex] \bf 13.75 \: cm^2 [/tex]

Answer:

enlarged

Step-by-step explanation:

imagine there are two figures, figure A and B.  figure A has a length of 10cm and the scale factor is 1.2

the length of figure B = 10 X 1.2 = 12

Figure B has a longer length than figure A. thus figure B is an enlarged version of figure A.

Conversely, if the factor is 0.2

the length of figure B = 10 X 0.2 = 2cm

the length of figure B is less than that of figure A. Thus, figure B is a scaled image of A