Help me. Two numbers have a sum of 30. Half of their difference is 7. Find the numbers.

Answer:

the answer is x equals 22 and y equals 8

Step-by-step explanation:

first equation is x+y=30

Second equation is x-y/2=7 that simplify's to x-y=14

then you add then so they will cancel out and you are left with 2x=44 so divide two by both sides which gives x=22

then you subsitute the 22 in the first equation. It will be 22+y=30 then you subtract 22 from the 30 that gives you y=8

so the two numbers are 22 and 8

Hope this helps!!!!

The numbers satisfying the given conditions are 22 and 8.

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight line can be also written as -

Ax + By + C = 0

By = - Ax - C

y = (- A/B)x - (C/A)

We have the following problem -

Two numbers have a sum of 30. Half of their difference is 7.

We can write the equations as -

x + y = 30

1/2(x - y) = 7

Rearranging, we get -

y = - x + 30

y = x - 14

Plot the graph, the point of intersection is the solution. The number will be 22 and 8.

y = - x + 30

y = x - 14

Equating both, we get -

- x + 30 = x - 14

30 + 14 = 2x

2x = 44

x = 22

and

y = 22 - 14

y = 8

Therefore, the numbers satisfying the given conditions are 22 and 8.

To solve more questions on straight lines, visit the link below-

brainly.com/question/29030795

#SPJ2

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