help me with this please

Answer:

35

Step-by-step explanation:

V=Bh

V = 6(5)

V= 35

Answer: the answer is A.  10/9 cubic in.

Step-by-step explanation:

Answer:

5x/1/2 = 1x



answer  1.12 <3


hope it helps


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Step-by-step explanation:

Answer:

811

Step-by-step explanation:

i d k

Answer:

Step-by-step explanation:

Both data sets have a median of 3 and gave similar means, 3.19 and 2.57, so the answer should be B.

Answer:

4:18

6:27

8:36

Hope this helps! :)

Answer:

-4<x≤5

Step-by-step explanation:

An open circle means 'less than' or 'greater than' while a closed cirlce means 'less than or equal to' or 'greater than or equal to'

Answer:

In geometry, a vertex form is a point where two or more curves, lines, or edges meet.

Step-by-step explanation:

this equation is stander form

Answer: 24/5=4.8  36/8=4.5

Step-by-step explanation: First, let's start off by dividing 24 by 5. We can turn this into 24.0 divided by 5 to make it a bit simpler. We know that 240 by 5 = 48, then since there is a decimal 1 digit to the left in 24.0, we apply that decimal 1 digit to the left in 48, making it 4.8! Now let's do 36 by 8. We can do what we did for problem 1 and turn 36 into 36.0, 360 by 8 = 45 and applying the same logic we used before, 360 turns into 36.0, and 45 turns into 4.5! Therefore, Kalel is wrong, and the two equation is not equal.

P.S. Using long division, Kalel is technically kind of right, but there's still that unaccounted for '4' that we still need to divide.

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}[/tex]

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

From the complete information, it should be noted that the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal. This is because both functions are not equal for x < 0. This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

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The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Two functions are equal if they have the same domain and codomain and their values are the same for all elements of the domain.

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal.

This is because both functions are not equal for x < 0.

This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

Hence, the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Learn more about functions on:

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Answer:

Step-by-step explanation:

The z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

The z-scores give us information about how many standard deviations from the mean the data are. This difference can be negative, if the data are n deviations to the left of the mean, or it can be positive if the data are n deviations to the right of the mean.

To calculate the Z scores, we calculate the difference between the value of the data and the mean and then divide this difference by the standard deviation.

[tex]Z=\dfrac{X-\mu}{\sigma}[/tex]

Where x is the value of the data, μ is the mean and σ is the standard deviation

In this case :

μ = 12 $/h

[tex]\sigma[/tex] = 2 $/h

We need to calculate the Z-scores for x=17 and x=13

[tex]Z_{13}=\dfrac{13-12}{2}=0.5[/tex]

[tex]Z_{17}=\dfrac{17-12}{2}=2.5[/tex]

Thus the z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

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The sum-product pattern

If the polynomial is of the form x 2 + b x + c x^2+bx+c x2+bx+cx, squared, plus, b, x, plus, c and there are factors of c that add up to b.

I am not sure what you meant but hopefully you meant this

Answer:

If the polynomial is of the form x2 + bx + cx²+bx+cx2+bx+cx, squared, plus, b, x, plus, c and there are factors of c that add up to b.

Step-by-step explanation:

Do mark BRAINLIEST

Step-by-step explanation:

please mark me as brainlest

Answer:

  10 mm

Step-by-step explanation:

You can find the missing dimension using the triangle area formula with the dimensions you know.

  A = 1/2bh

  40 mm² = 1/2(b)(8 mm)

  b = 40 mm²/(4 mm) = 10 mm . . . . . . . divide by the coefficient of b

The triangle's base is b = 10 mm.

Answer:

h=[tex]-\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]6h-1=-3\\6h=-2\\h=-\frac{2}{6} \\h=-\frac{1}{3}[/tex]

Answer:

Step-by-step explanation:

Isolate by the h from one side of the equation.

6h-1=-3

First, add by 1 from both sides.

[tex]\sf{6h-1+1=-3+1}[/tex]

Solve.

-3+1=-2

Rewrite the problem down.

6h=-2

Then, you divide by 6 from both sides.

[tex]\sf{\dfrac{6h}{6}=\dfrac{-2}{6} }[/tex]

Solve.

-2/2=-1

6/2=3

Rewrite as a fraction.

[tex]\boxed{\sf{h=-\dfrac{1}{3}=0.33}}[/tex]

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

[tex]\boxed{a = 6.4}[/tex]

Step-by-step explanation:

Given:

[tex]x:y = (4):(5)[/tex]

Let the value of "x" be known as "a".

[tex]x:y = a:8[/tex]

Setting up the proportion:

[tex]\rightarrow 4:5 = a :8[/tex]

Multiplying the middles and the extremes:

[tex]\rightarrow 5a = 4 \times 8[/tex]

Simplifying the RHS:

[tex]\rightarrow a = \dfrac{4 \times 8}{5}[/tex]

[tex]\rightarrow \boxed{a = 6.4}[/tex]

Thus, the value of x is 6.4 when y is 8.

Answer:

[tex]\sf x=\dfrac{32}{5}[/tex]

(or x = 6.4 if you want it in decimal form)

Step-by-step explanation:

If y and x have a proportional relationship, then:

Given:

Substitute the given values into the equation to find k:

⇒ 5 = k(4)

⇒ k = 5/4

Therefore, [tex]\sf y=\dfrac54x[/tex]

When y = 8, substitute y = 8 into the equation and solve for x:

[tex]\sf \implies \dfrac54x=8[/tex]

[tex]\sf \implies x=8 \cdot \dfrac45[/tex]

[tex]\sf \implies x=\dfrac{32}{5}[/tex]

Answer:

x = 71

Step-by-step explanation:

The horizontal lines are parallel, right?

So that means the degrees shown are complimentary angles(they add up to 180 degrees, a straight line)

so that means the algebraic equation is 109 + x = 180

x = 180-109

x = 71

Hope this helps. Mark brainliest if best., if not, hope it helps anyway.

Answer:

decreased by 7

Step-by-step explanation:

Based off of the table after each day, the money left on the card decreases by 7 after each day

eg. On Monday there is $40 on the card. On Tuesday there is $33 on the card. The money on the card decreases by 7 from Monday to Tuesday. It continues to decrease by this constant amount as the days pass.

Answer:

With each day additional day, the amount left on the card decreased by $7

Step-by-step explanation:

After each day you could see that the amount of money was lower and if you subtracted Monday by Tuesday, Tuesday by Wednesday, Wednesday by Thursday, and Thursday by Friday, you could see that it fell $7 each time.

Step-by-step explanation:

inscribed angles subtended by the same arc are equal.

the central angle of a circle is twice any inscribed angle subtended by the same arc.

the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.

the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.

and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y

so,

360 - 106 = 2y

254 = 2y

y = 127°

Answer:

13.  [tex]x^2+y^2+2x-3\sqrt{x^2+y^2}=0[/tex]

14.  [tex]r=3\cos(\theta)-2\sin(\theta)[/tex]

Step-by-step explanation:

Question 13

Conversion from Polar equation to rectangular equation:

[tex]x=r \cos(\theta) \implies \cos(\theta)=\dfrac{x}{r}[/tex]

[tex]y=r \sin(\theta) \implies \sin(\theta)=\dfrac{y}{r}[/tex]

[tex]x^2+y^2=r^2 \implies r=\sqrt{x^2+y^2}[/tex]

Given:

[tex]r=3-2\cos(\theta)[/tex]

[tex]\textsf{Substitute }\cos(\theta)=\dfrac{x}{r}:[/tex]

[tex]\implies r=3-\dfrac{2x}{r}[/tex]

Multiply both sides by r:

[tex]\implies r^2=3r-2x[/tex]

[tex]\implies r^2+2x-3r=0[/tex]

[tex]\textsf{Substitute }x^2+y^2=r^2\:\textsf{and }r=\sqrt{x^2+y^2}:[/tex]

[tex]\implies x^2+y^2+2x-3\sqrt{x^2+y^2}=0[/tex]

---------------------------------------------------------------------------------------------

Question 14

Conversion from Rectangular equation to polar equation:

[tex]x=r \cos(\theta)[/tex]

[tex]y=r \sin(\theta)[/tex]

[tex]x^2+y^2=r^2 \implies r^2\cos^2(\theta)+r^2\sin^2(\theta)=r^2[/tex]

Given:

[tex]x^2+y^2-3x+2y=0[/tex]

[tex]\textsf{Substitute }x^2+y^2=r^2\:\textsf{and }x=r \cos(\theta)\:\textsf{and }y=r \sin(\theta):[/tex]

[tex]\implies r^2-3r\cos(\theta)+2r\sin(\theta)=0[/tex]

Factor out common term r:

[tex]\implies r(r-3\cos(\theta)+2\sin(\theta))=0[/tex]

Divide both sides by r:

[tex]\implies r-3\cos(\theta)+2\sin(\theta)=0[/tex]

Rewrite to make r the subject:

Answer:

[tex] \sf \: x = 2[/tex]

Step-by-step explanation:

Let's solve your equation step-by-step.

[tex] \sf 6x+6=10x−2 [/tex]

Step 1: Subtract 10x from both sides.

[tex] \sf6x+6−10x=10x−2−10x[/tex]

[tex] \sf−4x+6=−2[/tex]

Step 2: Subtract 6 from both sides.

[tex] \sf−4x+6−6=−2−6[/tex]

[tex] \sf−4x=−8[/tex]

Step 3: Divide both sides by -4.

[tex] \sf \frac{−4x}{−4}=\frac{−8}{−4}[/tex]

[tex] \sf x=2[/tex]

Answer:

g is 50 degrees

g is a supplement of 130 so they add up to 180

Answer:

The angel G:
= 50 degrees

A straight line is 180 degrees. The is already an angel has shown that takes up the majority of the line which is 130 degrees.

180 degrees - 130 degrees = 50 degrees

Step-by-step explanation:

Have a great rest of your day
#TheWizzer

The area of the triangle def round to the nearest tenth of a square unit is 10.3 square units.

When the two sides and an angle of a  triangle is known, then the area of the triangle can be found out with the following formula.

[tex]A=ab\sin\left(\dfrac{C}{2}\right)[/tex]

Here, a,b are the adjacent sides and C is the angle made between them.

The image of the triangle DEF is attached below. In this the two adjacent sides are given with the length 5 units ans 8 units long.

The angle made between them has the measure of 31 degrees. Put the values in the above formula as,

[tex]A=(5)(8)\sin\left(\dfrac{31}{2}\right)\\A=10.3\rm\; unit^2[/tex]

Hence, the area of the triangle def round to the nearest tenth of a square unit is 10.3 square units.

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Answer: A, 10.3

Step-by-step explanation: edge 2022

Answer:

Step-by-step explanation:

The standard equation for a circle is '[tex](x-h)^2+(y-k)^2=r^2[/tex]

      --> Standard form:

              [tex](x - )^2 +(y-(-5))^2=2^2\\x^2+(y+5)^2=4[/tex]

Hope that helps!

Answer:

x^2 + (y + 5)^2 = 4.

Step-by-step explanation:

Standard form is (x - a)^2 + (y - b)^2 = r^2

 - where (a, b) is the center and radius = r.

So our equation is:

(x - 0)^2 + (y - (-5))^2 = 2^2

x^2 + (y + 5)^2 = 4.

Answer:

The correct answer is 351.

Step-by-step explanation:

We will use order of operations to solve this problem. Recall that order of operations, AKA PEMDAS, states we should simplify numeric expressions in the following order:

Parentheses

Exponents

Multiplication/Division (ordered left to right)

Addition/Subtraction (ordered left to right)

Begin by evaluating the parentheses:

[tex]2+7^3+4(9-6)^2\div6\\2+7^3+4(3)^2\div6[/tex]

Simplify the exponents:

[tex]2+7^3+4(3)^2\div6\\2+343+4(9)\div6[/tex]

Multiply:

[tex]2+343+4(9)\div6\\2+343+36\div6[/tex]

Divide:

[tex]2+343+36\div6\\2+343+6[/tex]

Add:

[tex]2+343+6\\345+6\\351[/tex]