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Answer:

The gravitational force on the elevator = 4500N

Explanation:

The given parameters are;

The force applied by the elevator, F  = 4500 N

The acceleration of the elevator = Not accelerating

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;

F = W + Mass of elevator × Acceleration of elevator

∴ F = W + Mass of elevator × 0 = W

F = 4500 N = W

The net force on the elevator is F - W = 0

The gravitational force on the elevator = W = 4500N.

The gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.

Given data:

The magnitude of force on the elevator is, F = 4500 N.

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows,

F = W + ma

Here, a is the acceleration of the elevator. Since, the elevator is not accelerating. Then, a = 0 .

The weight of the elevator is due to the gravitational force. So, we need to obtain the weight as gravitational force.

Solving as,

[tex]F = W+ma\\\\F=W +(m \times 0)\\\\4500=W\\\\W = 4500 \;\rm N[/tex]

Thus, we can conclude that the gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.

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Answer:

It is not connected by any way

Answer:

Tension = 60 N

Explanation:

The ball is executing a motion like a pendulum. The lowest point of a pendulum's motion is the mean position, where its potential energy becomes zero and kinetic energy becomes maximum. At this point the rope becomes straight vertical. Hence, the tension in the rope becomes exactly equal to the weight of the object at the lowest point. Also, in this case when the ball swings through the lowest point during its motion like a pendulum, the tension in the rope will become equal to the weight of the ball.

Tension = Weight

Tension = 60 N

Answer:

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

Explanation:

A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.

Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.

When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma

When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma

However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg

When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0

Answer:

B

Explanation:

The pattern that the double slit experiment produces is a diffraction pattern (made as a result of single and double slit interference).

Answer:

B. It is the result of diffraction.

Explanation: a p e x

Answer: nah

Explanation:

A wet lab experiment for Coulomb's law involves measuring the force between charged objects immersed in a liquid. The experiment is called a "wet" lab because it involves liquid or aqueous solutions.

Coulomb's law is an equation that describes the electrostatic force between two charged particles.

It states that "the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them."

The equation is given by:

F = k×(q₁ × q₂) / r²

Where

F = the electrostatic force,

k =Coulomb's constant,

q₁ and q₂= the charges of the particles,

r =the distance between the.

In this question,

In the experiment, two conductive objects are charged with opposite charges using a high-voltage power supply, which can be controlled to vary the magnitude of the charges.

The two objects are then immersed in a non-conductive liquid, such as oil or water, and positioned a fixed distance apart.

Using a force sensor or a balance, the force between the two objects is measured as they move toward each other. By measuring the force at different distances, the experiment can verify Coulomb's law, which predicts that the force between two charged objects is proportional to the product of their charges and inversely proportional to the square of their separation distance.

The experiment can be performed with different pairs of charged objects with different magnitudes of charge and separation distances, allowing the relationship between the force and these variables to be investigated. This provides insight into the electrostatic interaction between charged objects in a liquid, which has applications in various fields, including electrochemistry, material science, and biophysics.

Therefore, in a wet lab experiment on Coulomb's law, we have to immerse the apparatus in aqueous solutions.

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Answer:

An example would be "The soup is boiling hot and has a temperature of 100 °C, whereas the water in the tub is just comfortably warm, with a temperature of about 38 °C. Although the water in the tub has a much lower temperature, it has greater thermal energy".

Explanation:

Thermal energy and temperature are closely related. Both reflect the kinetic energy of moving particles of matter. However, temperature is the average kinetic energy of particles of matter, whereas thermal energy is the total kinetic energy of particles of matter.

I can try and help whats it about?

Answer:

The objects meet after 2.033722438s, at a height 136.5334679m from the ground.

Explanation:

Call the object being dropped A and the object being thrown B.

When the objects meet, the time ('t') for both objects will be equal, and the sum of their distances will be equal to 156.8m.

Figure out the distance for A in terms of time, t:

s = ut + (1/2)at²

= 0t +(1/2)(9.8)t²

=4.9t²

Figure out the distance for B in terms of time, t:

s = ut + (1/2)at²

=(77.1)t + (1/2)(-9.8)t²

=77.1t - 4.9t²

We now adding the distances gives us 156.8, so can write:

(4.9t²) + (77.1t - 4.9t²) = 156.8

77.1t = 156.8

∴ t = 2.033722438s

To find the distances, plug in this value for t:

For A: 4.9t² → 20.26653209m

For B: 77.1t - 4.9t² → 136.5334679m

The objects will meet 155.2 meters below the top of the tower after 15.7 seconds.

The formula to calculate the time it takes for the object thrown upwards to return to the ground:

Time = 2 * Initial velocity / gravitational acceleration

Plugging in the values given in the question, you can calculate the time as follows:

Time = 2 * 77.1 m/s / 9.8 m/s^2 = 15.7 seconds

To determine when and where the objects meet, you can use the following formula to calculate the height of the object thrown upwards at any given time:

[tex]Height = Initial velocity * time - (1/2) * gravitational acceleration * time^2[/tex]

Plugging in the time calculated above and the initial velocity and gravitational acceleration given in the question, you can calculate the height of the object at the time it returns to the ground as follows:

Height = 77.1 m/s * 15.7 s - (1/2) * 9.8 m/s^2 * (15.7 s)^2 = -1.6 meters

This means that the object thrown upwards returns to the ground 1.6 meters below the point where it was launched. The object dropped from the top of the tower will also have fallen a distance of 156.8 meters in the same amount of time, so the two objects will meet at a point 156.8 meters - 1.6 meters = 155.2 meters below the top of the tower

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Answer:

Option C. vi = 0

Explanation:

An object held at a particular height above the ground is considered to be at rest. If the object is release from that height, the initial velocity (vi) is considered to be zero since the object is at rest or at a stand still position.

Thus,

Initial velocity (vi) = 0

Answer:

T = 0.009 s

Explanation:

It is given that, an OC makes about 112 full wing swings in one second. We need to find the oscillation period of the wasp's wings.

No of oscillations per unit time is called the frequency of an object. It means 112 is the frequency of wing swings. Let T is the oscillation period. It is equal to the reciprocal of frequency as follows :

[tex]T=\dfrac{1}{f}\\\\T=\dfrac{1}{112}\\\\= 0.00892\ s\\\\=0.009\ s[/tex]

Hence, the oscillation period is 0.009 s.

Answer:

yes it's a matter of probability

Answer:

Absolutely!

Explanation:

Its almost impossible that we are the only goldilocks planet when there are billions of stars, each of them being suns with planets. Some other planet somewhere must be able to support life, don't you think?

Answer:

current trust me thoo pls

Answer:

Current

Explanation:

Right on edge ✅

Answer:

Alpha particles are Helium nuclei consisting of 2 protons and two neutrons (mass number 4, atomic number 2, no electrons and so carry a 2+ charge).

Explanation:

Answer:

its alot

Explanation:

Answer:

The orbital speed is approximately 17,325.57 m/s

The number of Earth days it would take lo to complete its orbit is approximately 1.77 days

Explanation:

The given parameters are;

The mass of lo, m ≈ 7.22 × 10²² kg

The radius of lo, R ≈ 1.82 × 10⁶ m

The mean distance between Jupiter and lo = 4.22 × 10⁸ m

The orbital equation is given as follows;

[tex]\dfrac{m \cdot v^2}{R} = \dfrac{G \times M \times m}{R^2}[/tex]

[tex]\therefore v = \sqrt{\dfrac{G \cdot M}{R} } = \sqrt{\dfrac{ 6.67408 \times 10^{-11} \times 1.898 \times 10^{27}}{4.22 \times 10^8} } = 17,325.57 \ m/s[/tex]

The orbital speed ≈ 17,325.57 m/s

The time to complete one orbit = (2 × π × 4.22 × 10⁸)/(17325.57) ≈ 153039.94 s

The time to complete one orbit ≈ 153039.94 s ≈ 1.77 days

The number of Earth days it would take lo to complete its orbit ≈ 1.77 days.

The number of Earth days it would take lo to complete its orbit will be 1.77 days. While the orbital speed will be 17,325.57 m/s.

The speed required to establish an equilibrium between gravity's pull on the satellite and the inertia of the satellite's motion is referred to as orbital speed.

The given data in the problem is;

m is the mass of lo≈ 7.22 × 10²² kg

R is the radius of lo ≈ 1.82 × 10⁶ m

The mean distance between Jupiter and lo = 4.22 × 10⁸ m

The orbital speed is given as;

[tex]\rm V= \sqrt{\frac{GM}{R} } \\\\ \rm V= \sqrt{\frac{6.67 \times 10^{-11} \times 1.898 \times 10^{27}}{4.22 \times 10^8} } \\\\ \rm V=17,325.57 \ m/sec[/tex]

The time to complete one orbit is given as;

[tex]\rm T=\frac{ (2 \times \pi \times 4.22 \times 10^8)}{17325.57 } \\\\ \rm T= 153039.94 \ s[/tex]

In one day  there are 86400 seconds from that calculation the number of days required to complete one orbit will be 1.77 days

Hence the number of Earth days it would take lo to complete its orbit will be 1.77 days. While the orbital speed will be 17,325.57 m/s.

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Answer:

velocity

Explanation:

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Answer:

Skin serves as a protective barrier, a way to sense the world, and a layer that keeps nutrients and water inside the body. Four types of cells make up the skin, and they are produced mainly in the epidermis near the basement membrane. Keratinocytes contain structural keratin and make up the bulk of the epidermis.

Explanation:

Answer:

True

Explanation:

Atoms of the same element will always have the same atomic mass or the mass listed in the periodic table.

Answer:

I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.

Explanation:

Answer:

Explanation:

mechanical advantage = output force / input force

= 740 N / 55 N

= 13.45

Answer:

18.5 m/s

Explanation:

Just did it on EdPuzzle

The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.

The y-component of a velocity vector = 37 × sin 30

                                                                   = 18.5 m / s

Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.

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Answer:

Problem 1 is D

Problem 2 is C

See the comments.

Explanation:

Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Explanation: