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Answer:D..the diagonals bisect each other. Since bisectors divide the diagonals equally in two parts.

Answer:

C.

Step-by-step explanation:

Answer:

6561

Step-by-step explanation:

3^2= 3*3=9   9^4= 9*9*9*9= 6561

Answer:

[tex]((3)^2)^4 = (9)^4 = 6561\\\\\\OR\\\\\\(3)^2)^4= 3^8 = 6561[/tex]

Answer:

SD = 2x

UD = x[tex]\sqrt{3}[/tex]

Step-by-step explanation:

The hypotenuse of a 30-60-90 triangle is 2 times the length of the shorter leg.

SU is the shorter leg = x

So, SD = 2x

The longer leg of a 30-60-90 triangle is [tex]\sqrt{3}[/tex] times the shorter leg.

So, UD = x[tex]\sqrt{3}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

In  a 30-60-90 triangle the sides are in the ratio 1:√3:2 so if the shortest side SU = x then the long leg = √3x and the hypotenuse = 2x.

Answer:

1.4 · 10³

Step-by-step explanation:

6.58 · [tex]10^{6}[/tex] ÷ 4.7 · 10³

6.58 ÷ 4.7 = 1.4

[tex]10^{6}[/tex] - 10³ = 10³

1.4 · 10³

Answer:

3.0926 x 10^10

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The graph of this square root function extends upward and to the right of the point (-5, -1). The domain is the horizontal extent of the graph, so is ...

  x ≥ -5

The range is the vertical extent of the graph, so is ...

  y ≥ -1

Answer:

95.2

Step-by-step explanation:

because u multiply 8.5 by 11.2 and get 95.2

Answer:

B

Step-by-step explanation:

Y=MX+C , where y=slope intercept, m=gradient and C=y-intercept

-5=6(-6)+c

-5=-36+c

-5+36=c

C=31

Hence,

y=MX+c

y=6x+31

Answer:

17

Step-by-step explanation:

Range is the biggest number minus the smallest number. So 20-3=17

Answer:

Step-by-step explanation:

-1  -1  3

1  -2 -2

The new coordinates of the vertices after a 90° clockwise rotation about the origin are:

[tex]\left[\begin{array}{ccc}-1&1&-3\\1&2&2\\\end{array}\right][/tex]

If we rotate a triangle 90° counter clockwise about the origin,

Then if one of its vertices be (x, y), it will be changed to (y, x).

The triangle is given as follows:

[tex]\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\\\end{array}\right][/tex]

To rotate the given triangle 90° clockwise about the origin, we can use the rotation matrix:

[tex]\left[\begin{array}{ccc}cos90^{o}&-sin90^{o}\\sin90^{o}&cos90^{o}\\\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}0&-1\\1&0\\\end{array}\right][/tex]

To apply this rotation matrix to each vertex of the triangle, we multiply it with the coordinate vector of each vertex.

Let's denote the vertices of the triangle as A, B, and C.

A = (-1, -1)

B = (2, -1)

C = (2, 3)

Applying the rotation matrix to each vertex, we have:

[tex]A' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} -1 \ -1 \end{bmatrix} = \begin{bmatrix} 1 \ -1 \end{bmatrix}[/tex]

[tex]B' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 2 \ -1 \end{bmatrix} = \begin{bmatrix} 1 \ 2 \end{bmatrix}[/tex]

[tex]C' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 2 \ 3 \end{bmatrix} = \begin{bmatrix} -3 \ 2 \end{bmatrix}[/tex]

Therefore, the new coordinates of the vertices after a 90° clockwise rotation about the origin are:

A' = (1, -1)

B' = (1, 2)

C' = (-3, 2)

This can be written as follows:

[tex]\left[\begin{array}{ccc}-1&1&-3\\1&2&2\\\end{array}\right][/tex]

Learn more about the rotating triangle here:

https://brainly.com/question/22878771

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Answer:

option E

Step-by-step explanation:

have a great day

9514 1404 393

Answer:

  C.  17.25

Step-by-step explanation:

The product of distances from the common point to the two circle intersection points is the same for each secant.

  5(5+12) = 4(4+a)

  69 = 4a . . . . . . . . subtract 16, simplify

  17.25 = a . . . . . . . divide by 4

Answer:

Multiply the radius, r, by 2. Keep the angle measure x.

Step-by-step explanation:

The area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is that Mancuso wants to draw a sector whose area is 2 times the area of the sector shown.

The area of the sector given is -

A = {x/180} x πr²

For the area to be double, we can write the area of the sector as -

A{new} = 2 × {x/180} × πr²

A{new} = {x/90} × πr²

Therefore, the area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

To solve more questions on sectors, visit the link-

brainly.com/question/29014197

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Answer:

24

Step-by-step explanation:

if you add all of them together u get 108 divide it by 44 and u get 24

Answer:

70

Step-by-step explanation:

∠J and ∠K are supplementary angles

Supplementary angles have a sum of 180°

Thus, ∠J + ∠K = 180

110 + ∠K = 180

subtract 110 from each side

180 - 110 = 70

110 - 110 cancels out

we're left with ∠K = 70°

Given:

The radius of the circle is 17 in.

Central angle of intercepted arc is 0.7 radians.

To find:

The length s of the intercepted arc.

Solution:

The formula for the length of intercepted arc is:

[tex]s=r\theta[/tex]

Where, r is the radius of the circle and [tex]\theta [/tex] is the central angle in radians.

Substituting [tex]r=17,\ \theta =0.7[/tex] in the above formula, we get

[tex]s=17\times 0.7[/tex]

[tex]s=11.9[/tex]

Therefore, the length of the intercepted arc is 11.9 inches.

Answer:its C because the base is the bottom of the figure and C goes to the middle point at the bottom of the figure

Step-by-step explanation:

Answer:

indeed it does

Step-by-step explanation:

wheres the diagram exactly?