Help now please ASAPppp

(a)The test statistic is -1.684

(b) degrees of freedom for a T distribution = 15

(c)the p-value is 0.05

We will be conducting a t-test to determine if the modifications made by the manufacturer have successfully reduced the noise level of the mowers.

(a) First, we need to find the test statistic (t-value). We can calculate it using the formula:

t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))

t = (79.6 - 82) / (5.7 / sqrt(16))

t = (-2.4) / (5.7 / 4)

t = -2.4 / 1.425

t ≈ -1.684 (rounded to three decimal places)

(b) To find the degrees of freedom for a T distribution, we use the formula:

df = sample size - 1

df = 16 - 1

df = 15

(c) To find the p-value, we look up the t-value and the degrees of freedom in a t-distribution table or use a calculator or software that can calculate the p-value for a one-tailed t-test. In this case, we have:

t = -1.684 and df = 15

Using a calculator or software, we find:

p-value ≈ 0.0568 (rounded to four decimal places)

Now, we compare the p-value with the significance level (0.05). Since the p-value (0.0568) is greater than the significance level (0.05), we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that the modifications have reduced the noise level of the mowers at a 5% significance level.

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The correct statement about the function is given as follows:

D. As x approaches positive infinity, f(x) approaches positive infinity.

The function for this problem is a piecewise function, meaning that it has different definitions based on the input x of the function.

At the points where the interval changes, which are x = 0 and x = 2, the function is not defined, meaning that:

On the interval 0 < x < 2, the function is defined as follows

f(x) = -x² - 4x + 1.

The derivative is then given as follows:

f'(x) = -2x - 4.

-2x - 4 is positive for x < -2, hence the function is increasing only for x < -2.

Thus option d is correct, as:

1/2(∞) + 3 = ∞.

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An indexed set of vectors {v1, v2, . . . , vp} in Rn is said to be linearly independent if the vector equation x1v1 + x2v2 + · · · + xpvp = 0 has only the trivial solution. The set {v1, v2, . . . , vp} is said to be linearly dependent if there exist weights c1, . . . , cp, not all zero, such that c1v1 + c2v2 + · · · + cpvp = 0, is a definition of linearly dependent.

The definition described in the question is the definition of linearly dependent. A set of vectors in Rn is linearly dependent if there exist non-zero coefficients (weights) such that the linear combination of the vectors equals the zero vector. Conversely, if there is only one way to express the zero vector as a linear combination of the vectors in the set, with all coefficients equal to zero, then the set is linearly independent.

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The functions categorized as decay or growth are

From the question, we have the following parameters that can be used in our computation:

y = 2250(1-0.9)^x

y=10.(1+0.04)^x

An exponential function is represented as

y = ab^x

If b > 0, then it is a growth function

Otherwise, it a decay function

using the above as a guide, we have the following:

y = 2250(1-0.9)^x -- decay

y=10.(1+0.04)^x -- growth

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His account balance will be $6.5 greater in August than in June.

Assuming that the balance in June is equal to the balance in July, we can use the given information to find the difference between the August and June balances.

Let's say the balance in July (and June) was x. Then, according to the problem, the balance in August was:

     x + $6.50.

To find the difference between the August and June balances, we can subtract the June balance from the August balance:

August balance - June balance = (x + $6.50) - x = $6.50

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Answer:

Ais 66 and B is 40% C is 60%

Step-by-step explanation:

I know A is correct but not b or c hope this helps

The sine function that matches the equation in the graph is given as follows:

y = 2sin(x) - 2.

The standard definition of the sine function is given as follows:

y = Asin(Bx) + C.

The parameters are given as follows:

The function varies between -4 and 0, for a difference of 4, hence the amplitude is given as follows:

A = 4/2

A = 2.

The function varies between -4 and 0, instead of between -2 and 2, for a vertical shift of -2, hence the coefficient C is given as follows:

C = -2.

The period of the function is of 2π, hence the coefficient B is given as follows:

B = 1.

Thus the function is:

y = 2sin(x) - 2.

The graph is given by the image presented at the end of the answer.

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To test your hypothesis, you would use the One Sample T test. This test is appropriate for comparing the mean of a single sample to a known value, which in this case is 47.

The T test: two sample assuming unequal variances and T test: two sample assuming equal variances are used to compare the means of two independent samples, while the T test: paired two sample for means is used to compare the means of two related samples. None of these tests would be suitable for testing your hypothesis about the average age of customers who buy BMX bicycles.
To test the hypothesis that the average age of customers who buy BMX bicycles is greater than 47, you should use the "One Sample T-test."
The One Sample T-test is appropriate in this scenario because you are comparing the average age of customers to a specific value (47) rather than comparing two different groups of customers. The other T-test options, such as two-sample T-tests and paired two-sample T-tests, are not suitable as they involve comparing two separate groups or pairs of related data.

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The graph of the absolute value functions is added as an attachment

An absolute value function is represented as

y = a|x - h| + k

Where the vertex is

Vertex = (h, k)

Using the above as a guide, we have the following:

Next, we plot the graph of the functions using the vertex

See attachment for the graph of the absolute value functions where color is used to represent the key/legend

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The only possible degree for the polynomial p+q is 11.

Given the degree of polynomial p is 11 and the degree of polynomial q is 7, we can find all possible degrees of the polynomial p+q by considering their highest-degree terms.

When adding polynomials, the resulting polynomial will have the degree that corresponds to the highest-degree term. In this case, we have two options:

1. The highest-degree terms of both polynomials are of different degrees. In this case, the degree of p+q will be the maximum of the two given degrees, which is max(11, 7) = 11.

2. The highest-degree terms of both polynomials are of the same degree and their coefficients have opposite signs, causing them to cancel out when added. In this scenario, the degree of p+q will be less than the maximum degree, i.e., less than 11.
However, given that the degrees of p and q are different (11 and 7), it is not possible for their highest-degree terms to cancel out.

Therefore, the only possible degree for the polynomial p+q is 11.

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step-by-step explanation:

remember if you add the given lengths, they must be greater than each other.

4+4=9 so no

9+4 = 13 which is greater than our number. We can make an isosceles triangle.

9+9 is greater than four so it works.

Answer:

probably 14 centimeters

Step-by-step explanation:

I put the new forgis on the jeep

The  speed of the moving end of the sprinkler in feet per minute is 34.48 food per hour

Speed in mathematics is defined as the distance an object travels in a given amount of time. Also, It can be calculated using the formula Speed = Distance ÷ Time, where distance is equal to the time taken to travel and time is equal to the number of seconds needed to travel.

The given parameters are

The distance is = 50-foot long

Time is given as = 1.45 hours

Speed = Distance/Time

Speed = 50 foot long/1.45 hurs

Therefore the Speed = 34.48 food per hour

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Answer:B

Step-by-step explanation:

Therefore, the linearization of f(x) = cos(x) at a = π/2 is L(x) = π/2 - x.

The linearization of a function f(x) at a point a is given by:

L(x) = f(a) + f'(a)(x - a)

where f'(a) denotes the derivative of f(x) evaluated at x = a.

In this case, we have:

f(x) = cos(x)

a = π/2

First, let's find f'(x):

f'(x) = -sin(x)

Then, we can evaluate f'(a):

f'(π/2) = -sin(π/2) = -1

Next, we can plug in the given values into the formula for linearization:

L(x) = f(a) + f'(a)(x - a)

L(x) = cos(π/2) + (-1)(x - π/2)

L(x) = 0 - x + π/2

L(x) = π/2 - x

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Answer:

I believe the answer is 49°

Answer: A

Step-by-step explanation:

A.  this is correct, to find your IQR, interquartile range, you break up the numbers into 4 even groups listed in numerical order

16    40    49   130    200     210

         |           |              |

The lines under the numbers represent the 4 even groups

The IQR is the upper quartile(where last line is) - lower quartile (where last line is(where first line is)

IQR=200-40=160

B. is wrong, range is last number - first  (210-16)=194 not 160

C. is wrong, we found the IQR to be 160 not 194

D. is wrong,  MAD, mean absolute deviation, is the average of the distance from the mean

mean/average of all = 107.5  I added all and divided by how many (6)

MAD means subtract each number from the average and divide by how many  

= [(107.5-16)+(107.5-40)+(107.5-49)+(130-107.5)+(200-107.5)+(210-107.5)]/6

=72.5

The dimension of the board either 4 by 6 square inches or 6 by 4 square inches.

We know that,

The rectangle is 4 sided geometric shape whose opposites are equal in lengths and all angles are about 90°.

here,

let the length of the board be x, and width be w,

The perimeter of the rectangle board  = 20

2 (l + w) = 20

l + w = 10

l = 10 - w

Now,

area of the board = 24

l × w = 24

(10 - w)w = 24

10w - w² = 24

w² -10w + 24 =0

(w - 4)(w -6) = 0

So,

w = 4 or 6

Now,

Lengths = 10 - 4 or 10 - 6

             =  6 or 4

Thus, the dimension of the board either 4 by 6 square inches or 6 by 4 square inches.

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Answer:

In a 30°-60°-90° right triangle, the length of the shorter leg is 1/2 the length of the hypotenuse, and the length of the longer leg is √3 times the length of the shorter leg. In the equilateral triangle, the perimeter is (2)(4√3)(3) = 24√3, and the apothem is 4.

π(8^2) - (1/2)(24√3)(4)

= 64π - 48√3 square units

= about 117.92 square units

Answer:

Step-by-step explanation:

we can use multiplication of 10 with 5and 2 we know that 2x5=10

If function g has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45, and that g(0) = -2 and g(-9) = 6 then g(-13) = 20 and  g(-4) = -11 must be true

We are given that the function g has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45, and that g(0) = -2 and g(-9) = 6.

A. g(-13) = 20: This statement could be true, as it falls within the given domain and range of the function

B. g(0) = 2

This statement is not true, as we are given that g(0) = -2.

C. g(-4) = -11

This statement could be true, as it falls within the given domain and range of the function

D. g(7) = -1

This statement is not necessarily true or false

Therefore, the statements that could be true for g are A and C.

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In mutually exclusive data, you cannot find any overlap or intersection between the categories or events being analyzed.

This means that the occurrence of one event or category precludes the occurrence of the other. On the other hand, in dependent data, the occurrence of one event or category may have an effect on the occurrence of the other, and thus, they are not completely independent or separate. Therefore, in both cases, you cannot find any shared or common outcomes or occurrences between the categories or events being analyzed.

You cannot find a direct correlation or causal relationship between mutually exclusive or dependent data. In mutually exclusive events, the occurrence of one event prevents the occurrence of the other, meaning they cannot happen at the same time. In dependent events, the probability of one event happening is influenced by the outcome of a previous event. Due to these characteristics, it is not possible to establish a direct correlation or causal relationship between such events.

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  If we run this test with the data above, we would get a p-value of 0.1389. This means that there is no significant difference between the distribution of pod weight for inoculated vs. uninoculated plants at the 5% significance level.

A1. The nonparametric test that can be used to compare the distribution of pod weight for inoculated vs. uninoculated plants is the Mann-Whitney U test. This test is also known as the Wilcoxon rank-sum test and is used to compare two independent groups.

A2. To perform a permutation test approach using a computer, we can use R programming language. Here are the steps to conduct the Mann-Whitney U test:

1. Input the data into R. Let's say we have two groups, Group A (inoculated) and Group B (uninoculated), with sample sizes of n1 and n2, respectively.

2. Use the "wilcox.test" function in R to perform the Mann-Whitney U test. The syntax for this function is as follows:

  wilcox.test(x, y, alternative = "two.sided", exact = FALSE, conf.int = TRUE)

  where x and y are the vectors of observations for Group A and Group B, respectively. The "alternative" argument specifies whether the test is two-tailed ("two.sided"), one-tailed ("less" or "greater"), or "two.sided" by default. The "exact" argument is set to FALSE to use the asymptotic approximation, and "conf.int" is set to TRUE to compute the confidence interval.

3. Run the function with the appropriate inputs and obtain the p-value.

  For example, let's say we have the following data:

  Group A (inoculated): 10, 12, 15, 20, 22
  Group B (uninoculated): 5, 8, 11, 16, 18, 21

  We can input the data into R as follows:

  A <- c(10, 12, 15, 20, 22)
  B <- c(5, 8, 11, 16, 18, 21)

  Then, we can run the Mann-Whitney U test as follows:

  wilcox.test(A, B, alternative = "two.sided", exact = FALSE, conf.int = TRUE)

  The output will include the test statistic (U), the p-value, and the confidence interval, among other things. The p-value will be the two-tailed p-value we are interested in.

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Step-by-step explanation:

See image:

The significance level is set at 5%, and the probability of the result is 0%, which is less than the significance level. The result is statistically significant.

We are given that;

The probability of the result=(7.7/9.2/4.6/5/7.8)%

Now,

To determine the probability of the treatment group’s mean being lower than the control group’s mean by 15 points or more, we need to find the difference between the two sample means and compare it to the standard error of the difference. The standard error of the difference can be estimated using the formula:

SE = √(s1^2 / n1) + (s2^2 / n2)

where s1 and s2 are the sample standard deviations and n1 and n2 are the sample sizes.

Assuming that the treatment group is group 1 and the control group is group 2, we can plug in the values given in the question:

SE = √(9.2^2 / 30) + (7.7^2 / 30)

SE = √3.02

SE = 1.74

The difference between the two sample means is:

x1 - x2 = 85 - 100

x1 - x2 = -15

To find the probability of this difference or lower, we need to find the z-score and use a normal distribution table or calculator3:

z = (x1 - x2) / SE

z = (-15) / 1.74

z = -8.62

Using a normal distribution table or calculator, we can find that P(z ≤ -8.62) ≈ 0, which means that the probability of the treatment group’s mean being lower than the control group’s mean by 15 points or more is very close to zero.

Therefore, by probability the answer will be statistically significant.

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The smallest number that appears in both lists is 11. Therefore, the least possible value of n that satisfies both conditions is 11.

To find the least possible value of n, we need to find the smallest number that satisfies both conditions.

We can start by listing out some numbers that have a remainder of 2 when divided by 3: 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65, 68, 71, 74, 77, 80, 83, 86, 89, 92, 95, 98, 101, 104, 107, 110, 113, 116, 119, 122, 125, 128, 131, 134, 137, 140, 143, 146, 149, 152, 155, 158, 161, 164, 167, 170, 173, 176, 179, 182, 185, 188, 191, 194, 197, 200, 203, 206, 209, 212, 215, 218, 221, 224, 227, 230, 233, 236, 239, 242, 245, 248, 251, 254, 257, 260, 263, 266, 269, 272, 275, 278, 281, 284, 287, 290, 293, 296, 299, and so on.

Out of these numbers, we need to find the ones that also have a remainder of 1 when divided by 5. The numbers that have a remainder of 1 when divided by 5 are: 1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71, 76, 81, 86, 91, 96, and so on.

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To form the negation of a conditional statement, we change the "if-then" connective to "if and only if", which is represented by the symbol "⟺". This is also known as the biconditional connective.

To form the negation of a conditional statement, we change the "if-then" connective to "if and only if", which is represented by the symbol "⟺". This is also known as the biconditional connective.

For example, the conditional statement "If it rains, then the ground is wet" can be negated by changing the "if-then" connective to "if and only if", resulting in "It is not the case that if it rains, then the ground is wet", which can be written symbolically as "It rains ⟺ The ground is not wet".

Note that the negation of a conditional statement is not equivalent to the inverse or converse of the statement. The inverse of a conditional statement involves negating both the hypothesis and the conclusion, while the converse involves switching the hypothesis and the conclusion.

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Ernesto travels a distance of 94.9 feet after the 20 swings.

For our initial arc, the length was 16 ft. Subsequent arcs had lengths that were 90% of their preceding element in succession

Therefore, the first 10 arcs' lengths respectively calculate as follows:  16 ft, 14.4 ft, 12.96 ft, 11.664 ft, 10.4996 ft, 9.44784 ft, 8.503056 ft, 7.6527504 ft, 6.88747536 ft and 6.198727824 ft; cumulatively amounting to a distance of roughly 94.86ft traversed by Ernesto after his 10 swings.

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Answer:

A and C have inverses.

Step-by-step explanation:

A matrix has an inverse if the matrix is a square matrix whose determinant is not equal to zero.

|A| = 3(3) - 6(1) = 9 - 6 = 3

B is not a square matrix.

|C| = 7(1) - 0(0) = 7 - 0 = 7

D is not a square matrix.

|E| = 4(1) - 4(1) = 4 - 4 = 0, so E does not have an inverse.

|F| = 3(8) - 4(6) = 24 - 24 = 0, so F does not have an inverse.

A random variable Y has the density Function f(y) = { ey, y<0, 0, otherwise

a.[tex]E(e^(3Y/2)) = [1/5] - [3e^(5/2)/10][/tex]

b.[tex]M(t) = 1/[(1-t)(t+1)][/tex]

c.[tex]V(Y) = ∫(y^2 + 2y + 1)eydy[/tex] [tex]= [y^2e^y]/2 - ∫ye^ydy + [ye^y]/2 - ∫e^y[/tex]

a. To find [tex]E(e^(3Y/2))[/tex], we use the definition of expected value, which is the integral of the product of the random variable and its probability density function. We have: [tex]E(e^(3Y/2))[/tex] [tex]= ∫e^(3y/2)f(y)dy[/tex] [tex]= ∫e^(3y/2)eydy[/tex], y<0 .Using integration by parts, we let [tex]u = e^(3y/2)[/tex] and [tex]dv = e^y dy[/tex]. Then, [tex]du/dy = (3/2)e^(3y/2)[/tex]and [tex]v = e^y[/tex].

[tex]E(e^(3Y/2))[/tex] [tex]= ∫e^(3y/2)eydy[/tex] [tex]= [e^(3y/2)e^y/2] - ∫(3/2)e^(3y/2)e^y/2dy[/tex]

[tex]= [e^(5y/2)]/5 - [3/5]∫e^(5y/2)dy[/tex]

[tex]= [e^(5y/2)]/5 - [3e^(5y/2)/10] + C[/tex]

Since f(y) = 0 for y ≥ 0, we know that [tex]E(e^(3Y/2))[/tex] only depends on the integral of [tex]e^(3y/2)[/tex]for y < 0. Evaluating the above expression at y = 0, we get:

[tex]E(e^(3Y/2)) = [1/5] - [3e^(5/2)/10][/tex]

b. To find the moment generating function (MGF) for Y, we use the definition of the MGF, which is the expected value of [tex]e^(tY)[/tex] for all t in a neighborhood of 0. We have:

[tex]M(t) = E(e^(tY))[/tex] [tex]= ∫e^(ty)f(y)dy[/tex][tex]= ∫e^(ty)eydy[/tex] , y<0

Using integration by parts as before, we get:

[tex]M(t) = ∫e^(ty)eydy[/tex] [tex]= [e^(ty)e^y]/(t+1) - ∫(t+1)(e^(ty)e^y)/(t+1)dy[/tex]

[tex]= [e^(ty+2y)]/(t+1) - (t+1)M(t)[/tex]

Simplifying, we get:

M(t)(t+1) = 1/(1-t)

M(t) = 1/[(1-t)(t+1)]

c. To find V(Y), we first need to find the mean or expected value of Y. Using the definition of expected value, we have:

E(Y) = ∫yf(y)dy = ∫yeydy, y<0. Using integration by parts once more, we get: E(Y) = ∫yeydy [tex]= [ye^y] - ∫e^ydy[/tex] = -1 . The mean of Y is -1.

We use the definition of variance, which is the expected value of the squared difference between the random variable and its mean. We have:

[tex]V(Y) = E[(Y - E(Y))^2][/tex][tex]= ∫(y + 1)^2f(y)dy[/tex] [tex]= ∫(y^2 + 2y + 1)eydy[/tex], y<0

Using integration by parts for the third time, we get:

[tex]V(Y) = ∫(y^2 + 2y + 1)eydy[/tex][tex]= [y^2e^y]/2 - ∫ye^ydy + [ye^y]/2 - ∫e^y[/tex]

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Answer:

316.78

Step-by-step explanation:

area of 360 circle = pi*radius*radius

area of 360 circle = pi*11*11

area of 360 circle = pi*11*11

area of 360 circle = 380.13

360/300 = 380.13/x

114039/360 = x

x=316.775