Answers
Answer:
a) 314 m²
b) Estimate is 5 bags
c) Estimate for b is an underestimate (choice B)
Step-by-step explanation:
The garden is in the shape of a circle so the area of the garden will be the area of the circle
Part a
The area of a circle given radius r is
A = πr²
The diameter is given as 20m so radius = diameter/w = 20/2 = 10m
With π = 3.14
Area of the garden is 3.14 x 10² = 3.14 x 100 = 314 m² (Answer a)
Part b
We are asked to provide an estimate of the number of bags required to seed the garden by rounding to 1 significant figure
314 estimate to 1 significant figure = 300
58 estimate to 1 significant figure = 60
Estimate of number of bags = 300/60 = 5 (Answer b)
Part c
To determine if the estimate is over or under let's calculate the actual number of bags required.
= 314/58 ≈ 5.41
Our estimate of 5 bags is below the true requirement of 5.41 bags
So our estimate for b) is an underestimate (Choice B)
Related Questions
what is the solution to 2x+10=28
Answers
Given the equation:
[tex]2x+10=28[/tex]to solve for x, first we have to move the constant 10 to the right side of the equation. When we do this, we have to change its sign to a negative sign:
[tex]\begin{gathered} 2x+10=28 \\ \Rightarrow2x=28-10=18 \\ 2x=18 \end{gathered}[/tex]Now we can divide both sides of the equation by 2 to get the following:
[tex]\begin{gathered} \frac{1}{2}(2x=18)\Rightarrow\frac{2}{2}x=\frac{18}{2}=9 \\ \Rightarrow x=9 \end{gathered}[/tex]therefore, x = 9
help pleaseeee how do i do this
Answers
Answer:
A' (-1, -3)
B' ( 5,-5)
C' (6,-1)
Step-by-step explanation:
A card is drawn at random from a standard deck of cards. Find the probability of drawing:
1. A queen or a spade.
II. A black or a face card.
III. A red queen.
Answers
Given that a card is drawn at random from a standard deck of cards. We are asked to find the probabilities of
1) A queen or a spade.
2) A black or a face card.
3) A red queen.
This can be seen below;
Explanation
The formula for the probability of an event is given as;
[tex]\text{Pr(event) =}\frac{\text{number of events}}{\text{number of total possible outcomes}}[/tex]For a given deck of cards, the number of total possible outcomes is 52 different cards. Next, we find the number of events for each case
[tex]\begin{gathered} n(\text{queen)}=4 \\ n(\text{spades)}=13 \\ n(\text{black)}=26 \\ n(\text{face card)=}12 \\ n(\text{red queen) =2} \end{gathered}[/tex]Therefore we can find the probability in each case. Recall that "or" in probability implies we will add the values of the probabilities we are comparing.
1) A queen or a spade
[tex]Pr(\text{queen or spade)= }\frac{4}{52}+\frac{13}{52}=\frac{17}{52}[/tex]Answer
[tex]Pr(\text{queen or spade)=}\frac{17}{52}[/tex]
2) A black or a face card
[tex]Pr(black\text{ or }facecard)=\frac{26}{52}+\frac{12}{52}=\frac{38}{52}=\frac{19}{26}[/tex]
Answer:
[tex]Pr(\text{black or facecard)=}\frac{\text{19}}{26}[/tex]3) A red queen
[tex]Pr(A\text{ }red\text{ }queen)=\frac{2}{52}=\frac{1}{26}[/tex]
Answer
[tex]Pr(A\text{ }red\text{ }queen)=\frac{1}{26}[/tex]
If Jimmy's age is one year less than the sum of his ages of his siblings serena and tyler. which equation represents Jimmy's age?
Answers
Jimmy's age = (serena age + tyler age) - 1
A food processor has an efficiency of 0.4. It gives a useful power output of 350 W. Calculate the total power input to the food processor.
Answers
A food processor has an efficiency of 0.4. It generates 350 W of usable power. The total power input of the food processor is 349.6W.
What is meant by power input?The amount of energy that goes into a device is known as input, and the amount of energy that comes out is known as output. A device can change the type of energy but not the amount. For example, a light bulb's input energy is electrical energy, and its output energy is light and heat. Efficiency. A power supply that provides alternating current (AC) power to a load is known as an alternating current (AC) power supply. AC or DC power input is available. Power from wall outlets (mains supply) and various power storage devices is frequently incompatible with the power requirements of the load.Therefore,
Efficiency equals total power in less usable power out.
Efficiency =0.4 effective power =350 watts
total power input is,
0.4 = 350350 - 0.4
Simplifying the above equation,
= 349.6
Hence, A food processor has an efficiency of 0.4. It generates 350 W of usable power. The total power input of the food processor is 349.6W.
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Ari and Matthew are both running toward the soccer ball during a game.Ari's path is represented by the parametric equations x(t)=36+1/6t,y(t)=24+1/8t, where t is on the interval [0,50] and t is measured in tenths of seconds.Matthew's path is represented by the parametric equations x(t)=32+1/4t,y(t)=18+1/4t, where t is on the interval [0,50] and t is measured in tenths of seconds.Do the boys collide? If so, when do they collide?A. Ari and Matthew do not collide.B. Ari and Matthew collide at 3.2 seconds.C. Ari and Matthew collide at 4.8 seconds.D. Ari and Matthew collide at 2.4 seconds.
Answers
Answer:
C. Ari and Matthew collide at 4.8 seconds.
Explanation:
Ari and Matthew will collide when they have the same x and y position. Since Ari's path is given by
x(t) = 36 + (1/6)t
y(t) = 24 + (1/8)t
And Matthew's path is given by
x(t) = 32 + (1/4)t
y(t) = 18 + (1/4)t
We need to make x(t) equal for both, so we need to solve the following equation
Ari's x(t) = Matthew's x(t)
36 + (1/6)t = 32 + (1/4)t
Solving for t, we get
36 + (1/6)t - (1/6)t = 32 + (1/4)t - (1/6)t
36 = 32 + (1/12)t
36 - 32 = 32 + (1/12)t - 32
4 = (1/12)t
12(4) = 12(1/12)t
48 = t
It means that after 48 tenths of seconds, Ari and Mattew have the same x-position. To know if they have the same y-position, we need to replace t = 48 on both equations for y(t)
Ari's y position
y(t) = 24 + (1/8)t
y(t) = 24 + (1/8)(48)
y(t) = 24 + 6
y(t) = 30
Matthew's y position
y(t) = 18 + (1/4)t
y(t) = 18 + (1/4)(48)
y(t) = 18 + 12
y(t) = 30
Therefore, at 48 tenths of a second, Ari and Mattew have the same x and y position. So, the answer is
C. Ari and Matthew collide at 4.8 seconds.
Answer: C "Ari and Matthew collide at 4.8 seconds."
Step-by-step explanation: I took the test.
is -3x+2y=23 a linear equation
Answers
-3x+2y=23
Yes, the above equation is linear equation.
A block exerts a force of 7 N on the ground. Calculate the pressure the block exerts on the ground, in N/m?, when it is a) flat on the ground, so that the area of its base is 0.04 m b) standing up on its side, so that the area of its base is 0.035 m2
Answers
Answer:
0.007 n/m
Step-by-step explanation:trust cuh
a. The pressure is 175 N/m² the block exerts on the ground when it is flat ground. b. The pressure is 200 N/m²the block exerts on the ground when it is standing up on its side.
What is the pressure?The force divided by the area perpendicular to the force across which the force is applied is referred to as pressure.
a) To calculate the pressure the block exerts on the ground when it is flat ground, we use the formula:
pressure = force/area
where force = 7 N and area = 0.04 m²
pressure = 7 N / 0.04 m² = 175 N/m²
b) To calculate the pressure the block exerts on the ground when it is standing up on its side, we use the same formula, but with a different area.
pressure = force/area
where force = 7 N and area = 0.035 m²
pressure = 7 N / 0.035 m² = 200 N/m²
The pressure exerted on the ground by the block will be greater when it is standing on its side than when it is flat on the ground due to the decrease of the area in contact with the ground
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Select the correct answer.The equation of a line in the point-slope form is shown below.y - 9 = 1/5(x - 2)What is the slope of this line?A. 2B. 1/9C. 5D. 1/5
Answers
Consider that the point-slope form of a line that has slope 'm' and passes through a given point (x1,y1) is given by,
[tex]y-y_1=m\cdot(x_2-x_1)[/tex]The equation of the given line is,
[tex]y-9=\frac{1}{5}(x-2)[/tex]Comparing the coefficients,
[tex]m=\frac{1}{5}[/tex]Thus, the slope of the given equation is 1/5.
Therefore, option D is the correct choice.
I need help with a couple questions that I need to take a picture of to do?
Answers
Hello!
Let's solve these questions to find the corresponding values.
First box:[tex]\begin{cases}y+12=x^2+x\text{ equation I} \\ x+y=\text{ }{3\text{ equation II}}\end{cases}[/tex]Let's rewrite equation II (I'll just change the side of the values and their signal, to isolate one variable).
[tex]\begin{gathered} x+y=3\rightarrow\boxed{y=3-x} \\ \end{gathered}[/tex]Now, where's Y, we will replace it with (3 -x) in the second equation.
[tex]\begin{gathered} y+12=x^2+x\rightarrow(3-x)+12=x^2+x \\ \\ 3-x+12=x^{2}+x \\ 0=x^2+x+x-12-3 \\ 0=x^2+2x-15 \end{gathered}[/tex]Solving it, we'll obtain two values for x:
• x', = -5
,• x", = 3
Now, let's calculate y' and y" by replacement:
[tex]\begin{gathered} y^{\prime}=3-x^{\prime} \\ y^{\prime}=3-(-5) \\ y^{\prime}=3+5 \\ y^{\prime}=8 \\ \\ y"=3-x" \\ y"=3-3 \\ y"=0 \end{gathered}[/tex]So, the solution for the first box is:
{ {-5, 8}; {3, 0} }
Third box:[tex]\begin{cases}y+5={x^2-3x} \\ 2x+y={1}\end{cases}[/tex]Let's solve it in a similar way:
[tex]y=1-2x[/tex]So, we have:
[tex]\begin{gathered} 1-2x+5=x^2-3x \\ 0=x^2-3x-1+2x-5 \\ 0=x^2-x-6 \end{gathered}[/tex]Solving it, we'll obtain two values for x:
• x', = -2
,• x", = 3
Finding y' and y" by replacement, we have:
[tex]\begin{gathered} y^{\prime}=1-2x\~ \\ y^{\prime}=1-2(-2) \\ y^{\prime}=1-(-4) \\ y^{\prime}=1+4 \\ y^{\prime}=5 \\ \\ y"=1-2x" \\ y"=1-2(3) \\ y"=1-6 \\ y"=-5 \end{gathered}[/tex]So, the solution for the third box is:
{ {-2, 5}; {3, -5} }
Calculate the circumference of the circle (x+5)2+(y+6)2=42 round your answer to the nearest tenths
Answers
Note that in any standard form of the circle :
(x - h)^2 + (y - k)^2 = r^2
The center is at (h ,k) and radius is r
From the given problem :
(x + 5)^2 + (y + 6)^2 = 49
This can be written as :
(x + 5)^2 + (y + 6)^2 = 7^2
So the radius of the circle is 7 units
Now the formula for the circumference of a circle is :
C = 2πr
Substitute the radius :
C = 2π(7)
C = 43.98 units or 44.0 units
A sc to . S 12 10 Р 8 6 6 4. 2 - 20-18-16-14-12-10 -8 6 41-2 – 2 2 4 6 8 10 12 14 16 18 20 R. -4 6 S. -8 - 10 - 12 Which transformations of quadrilateral PQRS would result in the image of the quadrilateral being located only in the first quadrant of the coordinate plane?
Answers
We are asked to determine which transformation will result in the image being entirely in the I quadrant. This means that we need to determine which transformation will result in each image point of each vertex (x',y') being x' >0 and y'>0.
we can use the following transformation:
A rotation of 90° counterclockwise around the point Q = (4, 12).
The law associated with this transformation is:
[tex](x^{\prime},y^{\prime})=(-y+a+b,x+b-a)[/tex]Where (a,b) is the point around which the rotation is made, that is (a, b) = (4, 12). Replacing we get:
[tex](x^{\prime},y^{\prime})=(-y+4+12,x+12-4)[/tex]Solving the operations:
[tex](x^{\prime},y^{\prime})=(-y+16,x+8)[/tex]Now we transform each vertex. For vertex S = (-3,-7). replacing in the transformation:
[tex]S^{\prime}(x^{\prime},y^{\prime})=(-(-7)+16,-3+8)[/tex]Solving the operation:
[tex]S^{\prime}(x^{\prime},y^{\prime})=(9,5)[/tex]Since both coordinates are positive, this vertex is in the first quadrant.
For vertex P = (-3, 7). Replacing:
[tex]\begin{gathered} P^{\prime}(x^{\prime},y^{\prime})=(-7+16,5+8) \\ P^{\prime}(x^{\prime},y^{\prime})=(9,13) \end{gathered}[/tex]Therefore P' is in the first quadrant.
For vertex Q = (4,12)
[tex]undefined[/tex]Fill in the missing spaces in the table below.g(x)= 3x² +6x-4(0, -4)--7)Featuresf(x)= - - 2x² ++ 8x + 1y-interceptvertex(2,axis ofx= 2symmetrymaximum orminimum valueopens upwardor downwardminimumupwardFeaturesy-interceptvertexf(x) = - 2x + 8x+1(0,1)g(x)= 3x² +6x-4(0,- 4)0.-7)(Type an ordered pair.)(Simplify your answer.)
Answers
Part A
Given f(x) defined below:
[tex]f(x)=-2x^2+8x+1[/tex]The y-intercept is the value of y when x=0.
[tex]\begin{gathered} f(0)=-2(0)^2+8(0)+1=1 \\ y-\text{intercept:}(0,1) \end{gathered}[/tex]Vertex
Since the axis of symmetry is given as x=2:
[tex]\begin{gathered} f(2)=-2(2)^2+8(2)+1 \\ =-2(4)+16+1 \\ =9 \\ \implies\text{Vertex:}(2,9) \end{gathered}[/tex]Minimum/Maximum Value
Since the coefficient of x² is negative, there is a maximum value.
• Maximum Value = 9
,• The graph opens downwards.
Part B
Given g(x) defined below:
[tex]g(x)=3x^2+6x-4[/tex]The axis of symmetry is derived using the formula below:
[tex]\begin{gathered} x=-\frac{b}{2a},a=3,b=6 \\ x=-\frac{6}{2\times3}=-\frac{6}{6} \\ x=-1 \end{gathered}[/tex]• Axis of Symmetry: x=-1
,• Vertex: (-1,-7)
Put answer in order with comma and space between them
Answers
a) sin 30 = x/24
x = 24 sin 30
x = 24(0.5)
x = 12
b) B = 90°
A = 45°
C = 45°
[tex]\begin{gathered} \text{ sin 45 = }\frac{x}{18\sqrt[]{2}} \\ \text{ x = 18}\sqrt[]{2}\text{ }\frac{\sqrt[]{2}}{2} \\ \text{ x = 18}\frac{2}{2} \\ \text{ x = 18} \end{gathered}[/tex]the length = 18 units
Which item has a unit rate of $6.50?O caps: 4 for $25.00o posters: 3 for $20.25o tote bag: 4 for $30.00O T-shirts: 5 for $32.50
Answers
The t-shirts has a unit rate of $6.50
The manager of a movie theater found that Saturday's sales were $335. He knew that a total for 65 tickets were sold. Adult tickets, a, cost $7, and child tickets, c, cost $4. The system of equations shown can be used to represent the situation.
Answers
Solve by substitution, use the first equation and solve in terms of c
[tex]\begin{gathered} a+c=65 \\ c=65-a \end{gathered}[/tex]Substitute this to the second equation and solve for a
[tex]\begin{gathered} 7a+4c=335 \\ 7a+4(65-a)=335 \\ 7a+260-4a=335 \\ 7a-4a=335-260 \\ 3a=75 \\ \frac{3a}{3}=\frac{75}{3} \\ a=25 \end{gathered}[/tex]Substitute the value of a back to the first equation
[tex]\begin{gathered} a+c=65 \\ 25+c=65 \\ c=65-25 \\ c=40 \end{gathered}[/tex]With a = 25, and c = 40, we can conclude that there are 25 adult tickets, and 40 child tickets sold on Saturday.
Julie went to the post office and bought both $0.41 stamps and $0.26 postcards. She spent $51.40. The number of stamps was 20 more than twice the number of postcards. How many of each did she buy?
Answers
The number of postcards she bought is 40.
What are a formula and an equation?Your example is an equation since an equation is any expression with an equals sign. Due of mathematicians' love of equal signs, equations are commonly used in mathematical expressions.
A formula is a collection of guidelines for producing a specific outcome.
Write the equation by adding the total values of each item.
0.41 (2p+20)+0.26p = 51.40
We can solve this equation for p to find the number of postcards.
0.41(2p+20)+0.26p =51.40
0.82p+8.20+0.26p=51.40
1.08p=43.2
p=40
So, the number of postcards she bought is 40. Since the number of 41-cent stamps is 20 more than twice the number of postcards, the number of 41-cent stamps is 2(40)+20=100.
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Please helpppFind the slope of the line containing the following points:(-5,8) (-5,9)
Answers
The slope of the line is given by the formula
m=(y2-y1)/(x2-x1)
we have
(x1,y1)=(-5,8)
(x2,y2)=(-5,9)
substitute the values in the formula
m=(9-8)/(-5+5)
m=1/0
is undefined
The slope of the line is undefined because is a vertical line
Part 2) Find the slope of the line containing the following points: (8,-6) (9,-6)
we have
(x1,y1)=(8,-6)
(x2,y2)=(9.-6)
substitute in the formula
m=(-6+6)/(9-8)
m=0/1
m=0
The slope of the line is zero because is a horizontal line
4A recipe calls for the ratio of sugar to flour to be 8: 5. If there are 24 tablespoons of sugar in the recipe,how many tablespoons of flour would be required?
Answers
The ratio of sugar to flour is 8:5. The amount of sugar present in the recipe is 24 table spoon.
Therefore,
total ratio = 13
total table spoon = a
[tex]\begin{gathered} \frac{8}{13}\times a=24 \\ 8a=312 \\ a=\frac{312}{8} \\ a=39 \\ \text{flour}=\text{ 39-24=15 table spoon} \end{gathered}[/tex]Help, please? make sure it is simplified this is for an IXL
Answers
Answer:
- 12k² + 9k - 10
Step-by-step explanation:
note that + (-) = -
9k + (- 10) + (- 7k²) + 2k² - 7k²
= 9k - 10 - 7k² + 2k² - 7k² ← collect like terms
= - 12k² + 9k - 10
How do i slove this promblem i need help 9.92÷8
Answers
EXPLANATION
The division is equal to:
First we need to write the problem in long division format:
8.0 /_ 9.92
Divide 9 by 8 to get 1:
1
8.0 /_ 9.92
Multiply the quotient digit (1) by the divisor 8:
1
8.0 /_ 9.92
8
Subtract 8 from 9:
1
8.0 /_ 9.92
8
1
Add a decimal point to the solution
Bring down the next number of the dividend
1.
8.0 /_ 9.92
8
19
8 The model below represents the equation What is the value of x?
Answers
Let's now find the value of x,
[tex]\text{ x +7 = -4}[/tex]Applying additive inverse property, we get,
[tex]\text{ x + 7 - 7 = (-4) - 7}[/tex][tex]\text{ x = -11}[/tex]draw the following triangle after a 90-degree counterclockwise rotation about the origin
Answers
The rule for a 90 counterclockwise rotation is
[tex](x,y)\longrightarrow(-y,x)[/tex]From the given picture, we can see that the triangle has vertices at
[tex]\begin{gathered} (-3,-2) \\ (-5,-4) \\ (-1,-5) \end{gathered}[/tex]after applying the rule from above, we get
[tex]\begin{gathered} (-3,-2)\longrightarrow(2,-3) \\ (-5,-4)\longrightarrow(4,-5) \\ (-1,-5)\longrightarrow(5,-1) \end{gathered}[/tex]Then, the triangle will be
# 2 given that ABC DEF solve for x and y
Answers
Given,
The triangle ABC is similar to triangle DEF.
Required
The value of x and y.
The similar triangle have equal ratio of the corresponding sides.
[tex]\begin{gathered} \frac{y}{7}=\frac{8}{5} \\ y=\frac{8\times7}{5} \\ y=\frac{56}{5} \\ y=11.2 \end{gathered}[/tex]The value of y is 11.2 units.
[tex]\begin{gathered} \frac{14}{x}=\frac{8}{5} \\ x=\frac{14\times5}{8} \\ x=\frac{70}{8} \\ x=8.75\text{ units} \end{gathered}[/tex]Hence, the value of x is 8.75 units and the value of y is 11.2 .
Fine the distance d(A,B)between points A and B A(4,-3); B(4,5)
Answers
The distance between points A and B can be calculated with this formula:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]\begin{gathered} A=(4,-3) \\ x_1=4 \\ y_1=-3 \\ B=(4,5) \\ x_2=4 \\ y_2=5 \end{gathered}[/tex]Now inputting the values above into the formula, we will proceed thus:
[tex]\begin{gathered} d(A,B)=\sqrt[]{(4-4)^2+(5-(-3))^2} \\ d(A,B)=\sqrt[]{0^2+8^2} \\ d(A,B)=\sqrt[]{64} \\ d(A,B)=8 \\ \text{The distance betw}een\text{ points A and B is 8 units.} \end{gathered}[/tex]What is the equation of this line?
Answers
⇒If you check by inspection the line passes through the points (0,-3) and (2.-2)
⇒Note I only chose those points because they will help me figure out the gradient of the line . You van use the points of you choice to find the gradient using the formula
[tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} } \\m=\frac{-2-(-3)}{2-0} \\m=\frac{-2+3}{2} \\m=\frac{1}{2}[/tex]
We know that the general equation to find the straight line equation is y=mx+c
⇒Now to find the value of the the unknown variable which in this case is c we can substitute the known (x,y) which is a point of your choice and m which is thew gradient you calculated above as variable m
⇒Note I will use the point (0,-3) to find the value of c
[tex]-3=\frac{1}{2} (0)+c\\c=-3[/tex]
⇒This brings us to a conclusion of saying the equation of the straight line is :
⇒[tex]y=\frac{1}{2}x-3[/tex]
The first option is the answer
GOODLUCK!!!!!!!!
A large fastfood restaurant is having a promotional game where game pieces can be found on various products customers can win food or cash prizes according to the company the probability of winning a prize larger small with any eligible purchases is 0.185 consider your next 29 purchases that produce a game piece calculate the following
Answers
The formula for binomial probability is expressed as
P(x) = nCx * p^x * q^(n - x)
where
n = number of trials
x = number of successes
p = probability of success
q = probability of failure
From the information given,
n = 29
p = 0.185
q = 1 - p = 1 - 0.185 = 0.815
a) For the probability that you win 6 prices, x = 6
P(x = 6) = 29C6 * 0.185^6 * 0.815^(29 - 6)
P(x = 6) = 0.1723
b) For the probability that you win more than 8 prices, x = 8. From the binomial probability distribution calculator,
[tex]P(x>8)\text{ = 0.0729}[/tex]c) we would find the probability that you win more than 4 prizes and subtract it from the probability that you win 7 or lesser pizes. x = 4 and x = 7
From the binomial probability distribution calculator,
[tex]\begin{gathered} P(x>4)\text{ = 0}.6438 \\ P(x\text{ }\leq7)\text{ = 0.8468} \\ P(4\text{ }\leq\text{ x }\leq7)\text{ = 0.8468 - 0.6438 = 0}.203 \end{gathered}[/tex]d) For the probability that you win 3 prizes or fewer, x = 3. From the binomial probability distribution calculator,
[tex]P(x\leq3)\text{ = 0}.1890[/tex]directions in the picture (we only need to do part A and part C)
Answers
Given the equation of the function:
[tex]d(t)=-0.086t^3+3.71t^2-53.7t+643[/tex]A) we will graph the function for:
[tex]1\le t\le23[/tex]the graph of the function over the given interval will be as shown in the following figure:
the behavior of the graph on this interval is the function decreasing.
C) This model can be used for years before 1995 or after 2018
Because there are no critical points on the graph which indicate the function will be showings a decrease as time increase.
Table
In a group of 120 Students, 7 2 of them play football, 65 play.
Tennis and 53 play Hockey. If 35 of the students play both
Football and Table Tennis, 30 play both Football and trockey,
21 play both Table Tennis and Hockey and each of the students
Play at least one of the three grames,
a) Draw a venn diagram to illustrate this information.
b) How many of them play!
All the three games;
Exactly two of the three games;
u Exactly one of the three games
football alone?
Answers
zero number of students play all the three games,86 students play two of the three games,18 students play Exactly one of the three games and 7 players for football.
What is Set?A set is a collection of well defined objects.
Given The total number of students=120
7 2 of them play football=F
65 play Tennis=T
and 53 play Hockey=H
35 of the students play both Football and Table Tennis
F∩T=35
F∩H=30
T∩H=21
The venn diagram is given in the attachment.
zero number of students play all the three games.
Exactly two of the three games;
35+30+21=86
Exactly one of the three games
7+9+2=18
Only seven players played football alone.
Hence zero number of students play all the three games,86 students play two of the three games,18 students play Exactly one of the three games and 7 players for football.
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For Exercises 35–48, identify p, q, and r if necessary. Then translate each argument to symbols and use a truth table to decide if the argument is valid or invalid.If it snows, I can go snowboarding.It did not snow.∴ I cannot go snowboarding.
Answers
SOLUTION
Step 1 :
In this question, we are meant to translate each argument to symbols and use a truth table to decide if the argument is valid or invalid.
Step 2 :
Let p represents: If it snows
Let q represents: I can go snowboarding
Then
[tex]\begin{gathered} \approx\text{ p represents : It did not show} \\ \approx\text{ q represents : I cannot go snowboarding} \end{gathered}[/tex]Hence, the argument is VALID
Answer:
Step-by-step explanation: