Help please thank you

Answer:

I THINK it's A but I'm not completely sure

Answer:

I think no.2 the answer

Because socialization and social resources are both for me

The correct answer is 4. cultural resources. Knowledge and skills learned through socialization.

Knowledge and skills learned through socialization refer to the cultural, social, and behavioral norms and values that individuals learn through interaction with others in their environment. This process of learning begins in childhood and continues throughout an individual's life, through various social institutions such as family, education, religion, media, and peer groups.

Here,
The correct answer is 4. cultural resources. Knowledge and skills learned through socialization are an example of cultural resources because they are shaped by the cultural norms, values, and beliefs of the society in which an individual grows up.

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Answer:

40m/s

Explanation:

Answer:

The mass will stay the same if the bag stays sealed.

Explanation:

Answer:

A)2.811 × 10^-12 F

B)4.09V

Explanation:

(a) What is the capacitance?

Capacitance of coaxial cylinder can be determined using below expresion

C= (2π ε0 L)/ Ln[ rb/ra]

Where

ε0= permittivity of free space= 8.85×10^−12 Fm^-1

L= length of each cylinder =13.0 cm= 13×10^-2m

rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m

ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m

If we substitute the values we have,

C= (2π ε0 L)/ Ln[ rb/ra]

C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[

7.20×10^-3/0.550×10^-3]

C=( 7.2288×10^-12 )/2.5729

C=2.811 × 10^-12 F

B) (b) What applied potential difference is necessary to produce these charges on the cylinders?

Vba= Q/C

Where Vba=potential difference

Q= charge on each = 11.5 pC. = 11.5×10^-12

C= capacitance= 2.811 × 10^-12 F

If we substitute the values we have

Vba=(11.5×10^-12)/2.811 × 10^-12

= 4.09V

Answer:

A harmonica.

Explanation:

The structure of a harmonica is built in such a way that when the air is blown by the player in it, the air moves within the rectangular structure and making sound vibrations. Sound is heard when an object vibrates. The movement of this vibration creates sound waves, and these waves enter our ears in the form of music.

Therefore, the instrument that will make the slowest vibration among the given instrument will be the harmonica. Thus option D is correct.

Answer:

increases

Explanation:

due to less speed

Answer:

The human body can be a source of magnetic fields. Charged particles when moving through a magnetic field experiences a force. This magnetic force on a moving charge is at right angles to the velocity which makes it possible to use the knowledge of the magnetic field on charged particles to shield yourself from radiation exposure by staying at a right angle to the velocity of the field since magnetic fields tend to shield moving charged particles that is at a right angle to the field. Though the charged particle’s kinetic energy and speed will remain constant.

Explanation:

A magnetic field is a vector field that is generated whenever an electrical charge is moving,

Answer:

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Please mark as brainliest

Have a great day, be safe and healthy

Thank u  

XD

Answer:

GRAVITY:

In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.

Answer:

the answer is d the world  trade organization

Explanation:

Answer:

(a) The reduced pressure is 0.2711 MPa

The reduced temperature is 2.54 K

(b) The initial volume of the piston is approximately 0.806 m³

(c) The mass of CO₂ is approximately 16.9884 kg

(d) The work done, W is approximately 388.023 kJ

(e) The heat transfer is approximately -2,650.1904 kJ

Explanation:

The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K

The initial pressure of the gas, P₁ = 2 MPa

The final temperature of the gas, T₂ = 350°C

The final volume of the gas = 1 m³

(a) For an isobaric process, we have;

The reduced pressure,

[tex]P_r = \dfrac{P}{P_c}[/tex]

The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa

[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]

The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa

The critical temperature, [tex]T_c[/tex] = 304.13 K

The reduced temperature, [tex]T_r[/tex], is given by the following formula;

[tex]T_r = \dfrac{T}{T_c}[/tex]

Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K

The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K

(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁

∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³  ≈ 0.806 m³

The initial volume of the piston, V₁ ≈ 0.806 m³

(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;

n = P·V/(T·R)

The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles

The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg

(d) The work done, W = P·([tex]V_f - V_i[/tex])

W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227

The work done, W ≈ 388.023 kJ

(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)

[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)

∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ

Therefore, the heat transfer = dQ = -2,650.1904 kJ

Answer:

False

Explanation:

I believe it's false.

Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

Evidence is defined as an object or information introduced to make the existence of a fact more or less probable that of testimony, document, photograph, video, voice recording, DNA test, or other tangible objects. can take form.

Evidence is used to prove an argument made by individuals or groups that believe something is true or a fact that can be used to refute or disprove a fact or argument that people disagree with, or considered false.

Thus, Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

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Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.

Explanation: hope this helps!

Explanation:

it is played as a sequence of alternating strokes

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

[tex]v_i = 4.0 \ m/s[/tex]

then,

[tex]v_f=\frac{4.0}{2}[/tex]

    [tex]=2.0 \ m/s[/tex]

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]

On substituting the given values, we get

⇒    [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]

⇒    [tex]=\frac{4-8}{37}[/tex]

⇒    [tex]=\frac{-4}{37}[/tex]

⇒    [tex]=0.108 \ m/s^2[/tex]

As we know,

⇒  [tex]f=ma[/tex]

and,

⇒  [tex]\mu_rmg=ma[/tex]

⇒       [tex]\mu_r=\frac{a}{g}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{0.108}{9.8}[/tex]

⇒       [tex]=0.011[/tex]

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down

Speed = distance/time

Speed = (200m)/(20s)

Speed = 10 m/s

Answer:

The Moon's monthly

cycle of phases

results from the

changing angle of

its illumination by the Sun.

Because its period of

revolution is the same as its

period of rotation, the Moon

always keeps the same face

toward Earth.

Answer:

Explanation:

For Doppler effect in radar the formula is as follows

Δf = f₀ x 2v /c

Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .

Δf  = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .

2460 =  1.0525 x 10¹⁰ x 2 v / 3 x 10⁸

2460 = 105.25 x 2 v / 3

v = 2460 x 3 / (105.25 x 2 )

v = 35 .06 m /s .

(b)

Since the observed frequency is less , the source is moving away from the observer .

option (2) is correct .

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Yes

Explanation:

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Answer:

c. Line - voltage thermostats and controls are not as sensitive as low - voltage thermostats.

Explanation:

Line voltage thermostat is a regulator which senses the temperature and maintains it to keep the desired level of the voltage. The license in required for the electricians to work on the voltage control wirings. There is technical aspects which an electrician must understand before working on the circuits and voltage lines.

Answer:

basically needing sunlight and water

Explanation:

hope it helps

Answer:

While catching a ball, a cricket player lowers his hands, because by doing so, he increases the time of catch. That is, the person increases the time to bring about a given change in momentum, and hence rate of change of momentum decreases. Thus, a small force is exerted by ball on the hands.

Explanation:

:)

Answer:

it is your answer....... if it is helpful plzz like and comment

Answer:

R = 46,25 (Ω)

L = 0,07363 (H)

C = 2,7 *10⁻⁶ (F)

Explanation:

Statement problem does not specify if  160 (V) is peak voltage or RMS value. If 160 (V) is the peak value then for a sinusoidal wave,  RMS value is  V(rms) = 160 /√3

V(rms) =  92,49 (V)

In each branch: we have

V = I*Z         V = voltage through the impedance in (V) , I current in (A)

and Z impedance in Ω

Resistor case    Z = R  then V = 92,49 = 2 * R

R = 92,49/2       R = 46,25 (Ω)

Inductor case   |Z| = wL    Then Z = 2*π*f*L   V = 0,8 * |wl|

Inductor L in (H)       |wL| * 0,8 = 92,49   |wL| = 92,5/0,8    w = 2*π*f   2*3,14*250= 1570

1570*L = 92,49/0,8

L = 0,07363 (H)

In the case of the capacitor

|Z|  = 1/wc    = 1/1570*c

The current is 2 + 0,8 = 2,8          2,8 - 2,5 = 0,3 (A)

Again  V = I*Z        92,49 = 0,3 /1570*C

C = 0,3 / 1570*92,49

C = 2,7 *10⁻⁶ (F)

Answer:

D (not so sure, look in the explanation and judge yourself)

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

Minimum force required = 0.25 x 34 x 9.81

= 83.385 N

So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.

Answer:

1 : b  2: d

Explanation:

Answer:

a) v_{2f} = 12.0 m / s,  b) v_{2f} = 9.6 m / s

Explanation:

This is an exercise in conservation of momentum, let's start by defining a system formed by the two balls, so that the forces during the collision have been internal and the moment is preserved.

Initial instant. Before the crash

          p₀ = m v₁₀ + m v₂₀

where we use index 1 for the green ball and index 2 for the blue ball.

Final moment. After the crash

         p_f = m v_{1f} + m v_{2f}

the moment is preserved

         p₀ = p_f

         m v₁₀ + m v₂₀ = m v_{1f} + m v_{2f}

they tell us that the blue ball is at rest before the crash

        m v₁₀ = m v_{1f} + m v_{2f}

a) it is indicated that the green ball stops after the collision v1f = 0

        m v₁₀ = m v_{2f}

        v_{2f} = v₁₀

        v_{2f} = 12.0 m / s

b) the speed of the green ball is v_{1f} = 2.4 m / s

         m v₁₀ = m v_{1f} + m v_{2f}

         v_{2f} = v_{1o}- v_{1f}

         v_{2f} = 12.0 - 2.4

         v_{2f} = 9.6 m / s

Explanation:

The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).

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Solution :

Given :

Weight = 4 lb

Stretched of a spring in  equilibrium,Δ = 2 ft

a). We know that

F = kΔ

4 = k x 2

k = 2 lb/ft

∴ Stiffness of the spring is, k = 2 lb/ft

Motion is critically damped.

[tex]$\epsilon = 1$[/tex]

[tex]$\epsilon=\frac{C}{C_c} = 1$[/tex]

[tex]$C=C_c[/tex]

[tex]$C=C_c=\sqrt{4k_m}[/tex]

[tex]$C=\sqrt{4 \times 2 \times \left(\frac{4}{32.174}\right)}[/tex]

C = 0.99729 lb.s/ft.

b). Displacement

   [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

[tex]$\dot{y}(t)= y_0 \omega \cos (\omega t)$[/tex]

[tex]$[\dot{y}(t)]_{mon}= y_0 \omega $[/tex]

Initial displacement = 6 inches

    [tex]$y_0 = 0.5 \ ft , \ \ \ \dot y (t) = 3 \ ft/sec$[/tex]

  [tex]$\Rightarrow 3=0.5 \times \omega$[/tex]

 [tex]$\Rightarrow \omega = 6$[/tex]

Therefore, displacement :

    [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

   [tex]$y(t)=0.5 \sin (6 t)$[/tex]