HELP PLEASE. The product of the roots of the equation ax^2+x-24=0 is equal to -2 2/5. Find the value of a in the equation.

Answer: yes !!

Step-by-step explanation:

first we have to simplify

25:5 = 5:1

10:2 = 5:1

yes, they are

When two ratios are in proportion the ratios are said to be equivalent.

The ratios 25:5 and 10:2 are equivalent because they are in proportion.

It is the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

We have,

25:5 and 10:2

The ratio must be in proportion to be equivalent.

25:5 = 25/5 = 5 / 1

10:2 = 10/2 = 5/1

25:5 = 10:2

25/5 = 10/2

(5x5) / 5 = (5x2) / 2

5/1 = 5/1

We see that the ratio is equivalent.

Thus,

The ratios 25:5 and 10:2 are equivalent because they are in proportion.

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Answer:

Divide the no. by three

Step-by-step explanation:

153÷3 = 51

so, 51+51+51 = 153

Answer:

an odd number can be expressed as 2n+1 (2n would be even, add 1 = odd)

first number = 2n+1

second number = 2n+3 -> skip + 2 because it would make it even

third number = 2n+5

2n+1+2n+3+2n+5=153

6n+9=153

6n=144

n=24

24*2+1=48+1=49

24*2+3=48+3=51

24*2+5=48+5=53

the numbers are 49, 51, and 53.

Answer:

y = -1/2x - 1/2

Step-by-step explanation:

lmk if you want an explanation

Answer:

Axis interception points of -52 :

Y intercepts : (0,-52 )

Answer:

48%

Step-by-step explanation:

24 is almost 25 which is half of 50 you it would be 48%, hope this helps!:)

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkk

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Sum of angles of a pentagon is ~ 540°

Therefore,

Value of x = 95°

Answer:2508

Step-by-step explanation:

Answer:

5:36

Step-by-step explanation:

12 inches = 1 foot, so 6 feet = 72 inches

10:72, reduces to 5:36

The sum of the square of the constants is 3/4

Given the equation [tex]\frac{1}{a+1} +\frac{1}{b+1} +\frac{1}{c+1} =2[/tex]

The partial form of the equation is given as:

Solve for the constant "a"

[tex]\frac{1}{a +1} = 2\\a+1 = \frac{1}{2} \\a = \frac{1}{2} - 1\\a =-\frac{1}{2}[/tex]

Hence [tex]a=b=c=-\frac{1}{2} \\[/tex]

Taking the square of the constant, we will have:

[tex]a^2 + b^2 + c^2 =(-1/2)^2 +(-1/2)^2+(-1/2)^2\\a^2 + b^2 + c^2 =1/4 + 1/4 + 1/4\\a^2 + b^2 + c^2 =3/4[/tex]

Hence the sum of the square of the constants is 3/4

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Answer -the sum of the square of the consonants is 3/4

Using the t-distribution, it is found that:

a) Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

b) The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

Item a:

At the null hypothesis, it is tested if there is no difference, that is, the subtraction is at most 0, hence:

[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]

At the alternative hypothesis, it is tested if there is difference, that is, the subtraction is positive, hence:

[tex]H_1: \mu_1 - \mu_2 > 0[/tex]

The standard errors are given by:

[tex]s_1 = \frac{32.07}{\sqrt{60}} = 4.14[/tex]

[tex]s_2 = \frac{43.29}{\sqrt{30}} = 7.9[/tex]

The distribution of the difference has mean and standard deviation given by:

[tex]\overline{x} = \mu_1 - \mu_2 = 112.63 - 94.26 = 18.37[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{4.14^2 + 7.9^2} = 8.92[/tex]

The standard deviation are given for the samples, hence, the t-distribution is used.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the hypothesis.

Hence:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

[tex]t = \frac{18.37 - 0}{8.92}[/tex]

[tex]t = 2.06[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 30 + 60 - 2 = 88 df is [tex]t^{\ast} = 1.66[/tex]

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

Item b:

The interval is:

[tex]\overline{x} \pm t^{\ast}s[/tex]

Hence:

[tex]\overline{x} - t^{\ast}s = 18.37 - 1.66(8.92) = 3.56[/tex]

[tex]\overline{x} + t^{\ast}s = 18.37 + 1.66(8.92) = 33.18[/tex]

The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

A similar problem is given at https://brainly.com/question/25812826

Answer:

The third option, 1/2..

Answer: B Stan has $42 and Cory has $108.

Step-by-step explanation:

The awnser is Stan has $42 and Cory has $108 and $108 + $42 = $150.

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Answer:

84mm

Step-by-step explanation:

square = LxW = 6x6 =36

triangle = bxh/2 = 6x8/2 =24

add together 24x2+36=84

The value of given expression when x=-4 and y=4 is 1250.

The expression is missing in the question which is [tex]\dfrac{x^6-x}{4y}[/tex].

We have to solve it for x= -4 and y = 4.

Now putting the value of x and y we get,

[tex]\dfrac{x^6-x}{4y}=\dfrac{(-4)^6-(-4)}{4}[/tex]

[tex]\dfrac{x^6-x}{4y}=\dfrac{4096+4}{4}[/tex]

[tex]\dfrac{x^6-x}{4y}=1250[/tex]

Hence the value of given expression when x=-4 and y=4 is 1250.

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The approximate value of q in the equation is [tex]0.774[/tex]

The equation is given as:

[tex]q\log_2(6) = 2[/tex]

Divide both sides of the equation by [tex]\log_2(6)[/tex].

So, we have:

[tex]q= \frac{2}{\log_2(6) }[/tex]

Determine log(6) base 2

[tex]q= \frac{2}{2.585}[/tex]

Divide 2 by 2.585

[tex]q= 0.774[/tex]

Hence, the approximate value of q in the equation is [tex]0.774[/tex]

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Answer:

The prime factorization of 110 is: 2 x 5 x 11.

I think its the third one but im not completly sure

Answer:

-t-5>-1.5

Step-by-step explanation:

Just ask.

Hope this helps! :)

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

C=πd

C=?

π=3

d=32

C=3×32

Therefore C=96

2000-200 = 1800

1800-180 = 1620

1620 - 162 = 1458

1458- 148.8 = 1309

1309 - 130.9 = 1178

1178- 117.8 = 1060.2

1060 - 106 = 954

= 7 years

The value of the car is $956.5938 after 7 years and this can be determined by using arithmetic operations.

Given :

The following steps can be used in order to determine the total number of years will the computer have a value of less than $1,000:

Step 1 - The 10% of $2000 is $200. So, the value of the car after 1 year is $1800.

Step 2 - The 10% of $1800 is $180. So, the value of the car after 2 years is $1620.

Step 3 - The 10% of $1620 is $162. So, the value of the car after 3 years is $1458.

Step 4 - The 10% of $1458 is $145.8. So, the value of the car after 4 years is $1312.2.

Step 5 - The 10% of $1312.2 is $131.22. So, the value of the car after 5 years is $1180.98.

Step 6 - The 10% of $1180.98 is $118.098. So, the value of the car after 6 years is $1062.882.

Step 7 - The 10% of $1062.882 is $106.2882. So, the value of the car after 7 years is $956.5938.

Therefore, the correct option is C).

For more information, refer to the link given below:

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Answer:

7

Step-by-step explanation:

basically just subtract 10-3=7 then to check 3+7=10

Answer:

x = 7

Step-by-step explanation:

3 + x = 10

-3         -3

x = 7

you subtract by 3 on both sides (because the opposite property of addition is subtraction) to cancel it out and isolate the x.

Answer:your mom

Step-by-step explanation:

[tex]\huge \bf༆ Answer ༄[/tex]

Any value multiplied by Zero gives Zero, therefore ~

Answer:

B. 2/5

Step-by-step explanation:

I hope this helps!

Answer:

B 2/5

Step-by-step explanation:

Answer:

2.5

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

15x30 = 450

Answer:

She purchased 30 shirts.

Step-by-step explanation:

She paid only $400 Dollars, because she got a discount of $50.

So the total before getting the discount was $450.

If you divide $450 by $15 (the price for 1 shirt) you come up with 30.

450/15 = 30

the domain is the x value (first number) and the range is the y value (second number)

(if a number appears more than once in the domain or range, like in number 1 you don't have to write it again.)

to graph the domain and range you just plot the points,

and to map them you have to put the x values in the first oval and the y values in the second, usually in order from smallest to largest.

then you have to draw arrows connecting each x value to the y value that was in the same pair. just like when writing down the domain/range, if a number comes up again you don't have to write it down again. instead, you might have two or more arrows connecting to the same  number.

Answer:

Step-by-step explanation: