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What are the coordinates of the vertices of a rectangle with an perimeter of 12 units and an area of 5 sq. units.
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Answer: The perimeter of the rectangle is: P = 2( w + L) = 2 ( 8+5) = 26 units
The area of the rectangle is A = L w, A = 8 x 5 = 40 units to the 2nd power
Step-by-step explanation:
In order to solve this problem you need to find the distances between the vertices. By inspection the points (5,3) and (5,-2) form one the of the rectangle w = √ ( 5-5)2 + ( -2-3)2 = 5
The length can be obtained by finding distance between the points (5,3) and ( -3,3),
L = √(3-3)2+(-3-5)2 = 8
= 26 units
The perimeter of the rectangle is: P = 2( w + L) = 2 ( 8+5) = 26 units
The rectangle is the quadrilateral with 4 right angles. It could also be defined as, an equiangular quadrilateral, since equiangular means that the all of this angles are = (360°/4 = 90°); and the parallelogram containing a right angle. A rectangle with 4 sides of equal length is a square. The term oblong is occasionally used to refer to a non square rectangle.
The area of rectangle is A = L w, A = 8 x 5 = 40 units to the 2nd power
In order to solve this question you want to find the distances between the vertices. By inspection the points (5,3) and (5,-2) form 1 the of the rectangle w = √ ( 5-5)2 + ( -2-3)2 = 5
The length can be obtained by finding distance between the points (5,3) and ( -3,3),
L = √(3-3)2+(-3-5)2 = 8
The perimeter of rectangle is: P = 2( w + L) = 2 ( 8+5) = 26 units
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