Answer:
$5.70
Step-by-step explanation:
1. 25.00 - 2.20 = $22.80
2. 22.80 divided by 4 = $5.70
Answer:
$5.70
Step-by-step explanation:
let the price for each canvas be $x
hence the price of 4 canvases will be $4x
It is given that after she paid for 4 canvases, she had a balance of $2.20 on her orginally $25 gift card.
Hence we can assemble an equation:
$4x + $2.20 = $25
4x + 2.2 = 25 (subtract 2.2 from both sides)
4x = 25 - 2.2
4x =22.8 (divide both sides by 4)
x = 22.8 / 4
x = 5.7
Hence each canvas cost $5.70
Your family used two full tanks ofgasoline on a road trip. Your car drives about 25 miles per gallon, andthe tank holds 12 gallons of gasoline.a. Find the approximate number of gallons of gasoline used on the trip.b. Find the approximate number of miles you drove on the trip.c. Calculate Assume gasoline costs $1.50 per gallon. How much didyou spend per mile on gasoline?d. Apply You have $20 to spend on gasoline for another trip. The trip is350 miles. You spend the same amount per mile on gasoline as onthe first trip. Do you have enough money for gasoline? Explain.
Answer:
a. 24
b.600
c.36
d. No
Step-by-step explanation:
a.You know the approximate number of gallons is about 24 gallons because each tank holds twelve and your family used 2 of them.
b. You know you drove about 600 miles. This is because you used 24 gallons And each gallon should get you 25 miles. multiply The 2 together to get 600 miles. Or you could set a thing like 1/25=24/x and solve for x.
c. It cost 36 dollars because each gallon is 1.5 and you used 24 gallons so mul the two together to get 36
d. First find the amount of gallons used by dividing 350 by 25 to get 14. Then multiply 14 by 1.5 to get 21. 21 is greater than 20 so you don’t have enough money.
What is the surface area of the regular pyramid? What is the surface area of a square pyramid with a height of 10.4 m and a base side length of 12.4 m? a. 141.4 cm c. 167.4 m b. 162.4 cm d. 188.4 cm
Answer:
A. 141.4 cm
Step-by-step explanation:
The piramide is 141.4cm
Type the correct answer in each box. If necessary, use / for the fraction bar. Complete the statements about series A and B. Series A: 10+4+8/5+16/25+32/125+⋯ Series B: 15+3/5+9/5+27/5+81/5+⋯ Series__ has an r value of___where 0<|r|<1. So, we can find the sum of the series. The sum of the series is___ need help guys please :/
Answer:
Series A has an r value of 2/5 and series A has an r value of 3. The sum of the series A is 50/3
Step-by-step explanation:
A geometric sequence is in the form a, ar, ar², ar³, . . .
Where a is the first term and r is the common ratio = [tex]\frac{a_{n+1}}{a_n}[/tex]
For series A: 10+4+8/5+16/25+32/125+⋯ The common ratio r is given as:
[tex]r=\frac{a_{n+1}}{a_n}=\frac{4}{10} =\frac{2}{5}[/tex]
For series B: 1/5+3/5+9/5+27/5+81/5+⋯ The common ratio r is given as:
[tex]r=\frac{a_{n+1}}{a_n}=\frac{3/5}{1/5} =3[/tex]
For series A a = 10, r = 2/5, which mean 0 < r < 1, the sum of the series is given as:
[tex]S_{\infty}=\frac{a}{1-r}=\frac{10}{1-\frac{2}{5} } =\frac{50}{3}[/tex]
Dylan uses the expressions (x2 – 2x + 8) and (2x2 + 5x – 7) to represent the length and width of his bedroom. Which expression represents the area (lw) of Dylan's room?
Answer:
2x⁴+x³-x²+54x+56
Step-by-step explanation:
Given the expression length of dylan room = (x² – 2x + 8) and width = (2x² + 5x – 7), assuming the shap of the room is rectangular in nature, the formula for calculating area of a triangle is given as;
Area of rectangle = Length *Width
Area of the rectangle = (x² – 2x + 8)(2x² + 5x – 7)
Area of the rectangle = x²(2x² + 5x – 7) - 2x (2x² + 5x – 7) + 8(2x² + 5x – 7)
= (2x⁴+5x³-7x²)-(4x³+10x²-14x)+(16x²+40x-56)
expanding the bracket
= 2x⁴+5x³-7x²-4x³-10x²+14x+16x²+40x-56
Collecting the like terms;
= 2x⁴+5x³-4x³-7x²-10x²+16x²+40x+14x+56
= 2x⁴+x³-x²+54x+56
Hence, the expression that represents the area (lw) of Dylan's room is 2x⁴+x³-x²+54x+56
Answer:
2x^4+ x^3 - x^2 + 54x - 56 expression represents the area of Dylan’s room
Step-by-step explanation:
C on edge :)
Please help ASAP! I’ll give brainliest:))
Answer with explanation:
After dilation about the origin(0,0) with the scale factor of 'k" , the image of the original point (x,y) becomes (kx,ky)
From the given graph, the coordinates of point C = (0,6) [Since it lies on y-axis , the x-coordinate is zero]
After a dilation about the origin(0,0) with the scale factor of [tex]\dfrac{1}{2}[/tex], the new point will be [tex](\dfrac{1}{2}\times0,\dfrac{1}{2}\times6)=(0,3)[/tex]
Now plot this point on y-axis at y=3 as given in the attachment.
What is the midpoint of the line segment with endpoints (3.5, 2.2) and (1.5, -4.8)
Answer:
2.5, -1.8
Step-by-step explanation:
½(x¹+x²) ,½(y¹+y²)
½(3.5+1.5) ,½(2.2+(-4.8)
½(5.0), ½(2.2-4.8)
2.5 ,½(-3.6)
2.5, -1.8
Answer: It’s 2.5, -1.3, the other person must’ve misclicked lol
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
Construct and interpret the 95% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.
(Round to three decimal places as needed.)
A. The proportion of students who eat cauliflower on Jane's campus is between___ and __ 95% of the time.
B.There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between __ and __.
C. There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between __ and__.
D. One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between __ and __.
Answer:
A 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus is [0.012, 0.270].
Step-by-step explanation:
We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 who eat cauliflower.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of students who eat cauliflower
n = sample of students
p = population proportion of students who eat cauliflower
Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.
So, 95% confidence interval for the population proportion, p is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
Now, in Agresti and Coull's method; the sample size and the sample proportion is calculated as;
[tex]n = n + Z^{2}__(\frac{_\alpha}{2})[/tex]
n = [tex]24 + 1.96^{2}[/tex] = 27.842
[tex]\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}[/tex] = [tex]\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}[/tex] = 0.141
95% confidence interval for p = [ [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]
= [ [tex]0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] , [tex]0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] ]
= [0.012, 0.270]
Therefore, a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus [0.012, 0.270].
The interpretation of the above confidence interval is that we are 95% confident that the proportion of students who eat cauliflower on Jane's campus is between 0.012 and 0.270.
Below given are the details of transaction of a bank account of three brother Ram, Rahul and Rohit having AED 1000 in each account. a. Ram – Credits AED 500 on 12th May 2020 b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020. c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020. Who has more amount in his account at the end of the month Arrange the amounts in ascend
Answer:
Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:
Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.
Step-by-step explanation:
In banking and finance, a credit transaction on a bank account indicates that an additional amount of money has been added to the bank account and the balance has increased. This gives a positive balance in the account
On the other hand, a debit transaction on a bank account indicates that an amount of money has been deducted or withdrawn from the bank account and the balance has therefore reduced. This gives a negative balance in the account.
Based on the above, we have:
a. Ram – Credits AED 500 on 12th May 2020
Since there is no any other credit or debit transaction during the month, this implies that Ram still has Credits AED 500 in his account at the end of the month.
The Credits AED 500 indicates that Ram has a positive balance of AED 500 in his account at the end of the month.
b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020.
The balance in the account of Rahul gives Debits of AED 200 as follows:
Debits AED 700 - Credits AED 500 = Debits AED 200
The Debits AED 200 indicates that Rahul has a negative balance of AED 200 in his account at the end of the month.
c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020.
The balance in the account of Rohit gives Credits of AED 200 as follows:
Credits AED 700 - Dedits AED 500 = Credits AED 200
The Credits AED 200 indicates that Rohit has a positive balance of AED 200 in his account at the end of the month.
Conclusion
Arrangement of numbers or amounts of money in ascending order implies that they are arranged from the smallest to the largest number or amount.
Since Credits implies positive amount and Debits implies negative amount, Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:
Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.
Which option is it??????
Answer:
both the equation and it's inverse are functions
please help me explain this correctly..
Answer:
Yes, the ordered pair is correct.
Explanation:
You can check the if the ordered pair by substituting the values into the equation. If you substitute the ordered pair (1, 3), then you can make sure the ordered pair is correct. The equation with the substitution will be 3 = 1 + 2, which results in the true equation 3 = 3, therefore the ordered pair is correct.
first correct answer gets best marks and make it short not super-long please and hurry
Answer:
b > 3 2/15
Step-by-step explanation:
To make it easier to solve convert the mixed fraction to a fraction.
2 3/5 = 13/5
Now, multiply the fraction by 3/3 so that you will have a common denominator.
13/5 × 3/3 = 39/15
Now you solve for b.
39/15 < b - 8/15
39/15 + 8/15 < (b - 8/15) + 8/15
47/15 < b
b > 47/15
Convert the fraction to a mixed fraction to find the answer
47/15 = 3 2/15
b > 3 2/15
A plane started on a flight at 9:30 a.m and arrived at its destination at 1:45pm. The plane used 51 gallons of gas. The number of gallons used per hour was
Will mark Brainlist
Answer:
12 gallons per hour
Step-by-step explanation:
Given the following :
Start time of flight = 9:30 a.m
Arrival time of flight = 1:45p.m
Gallons of gas used during duration of flight = 51 gallons
Number of hours spent during flight:
Arrival time - start time
1:45 pm - 9:30 am = 4hours and 15minutes
4hours 15minutes = 4.25hours
If 4.25hours requires 51 gallons of gas;
Then 1 hour will require ( 51 / 4.25)gallons
= 51 / 4.25
= 12 gallons
juice is $1.79 for 8-4.23 ounce boxes. What is the unit price
Answer:
I believe the unit price would be 2.39 per unit
Step-by-step explanation:
Can someone help me on this finance problem?
Charlie is laying down mulch in his front yard. It takes Charlie 4 minutes to lay down 11 cubic yards of mulch and
16 minutes to lay down 44 cubic yards of mulch.
Plot five data points and the line that represent this direct variation relationship.
Answer with explanation:
Given: Charlie is laying down mulch in his front yard. It takes Charlie 4 minutes to lay down 11 cubic yards of mulch and 16 minutes to lay down 44 cubic yards of mulch.
Here, Time(Independent variable (x)) is directly proportion to the Volume of mulch(dependent variable (y)) lied by Charlie.
Let k be the constant of proportionality, such that
[tex]k=\dfrac{y}{x}[/tex]
For x= 4 and k= 11, [tex]k=\dfrac{11}{4}[/tex]
Required equation: [tex]y=\dfrac{11}{4}x[/tex]
Two points are given in question: (4,11) , (16,44).
Take x= 8 , [tex]y=\dfrac{11}{4}(8)=22[/tex]i.e. point (8,22)
Similarly, for x= 12, y=33 i.e. point (12, 33)
For x= 20 , y= 55 i.e. point (20,55)
Five data points: (4,11) , (16,44), (8,22), (12, 33), (20,55).
Now, we plot these points on graph and join them
Answer:
Here
Step-by-step explanation:
Solve. 8x² + 5 = 35 Round to the nearest hundredth. Enter your answers in the boxes. The solutions are approximately and .
Answer:
x=1.94
x = - 1.94
Step-by-step explanation:
8x² + 5 = 35
Subtract 5 from each side
8x² + 5-5 = 35-5
8x² = 30
Divide each side by 8
8x² /8 = 30/8
x² = 15/4
Take the square root of each side
sqrt( x²) = ±sqrt(15/4)
x = ±sqrt(15/4)
x=1.93649
x = - 1.93649
To the nearest hundredth
x=1.94
x = - 1.94
Answer:
1.94
Step-by-step explanation:
[tex]8x^2+5=35\\8x^2=30 \\x^2=30/8\\x^2=3.75\\\sqrt{3.75} \\[/tex]
≈ ±1.94
Find m2ABC.
PLZZZ ASAPPPP
Answer:
83
Step-by-step explanation:
You're given two vertical angles, and vertical angles are congruent. This means that (6x - 7) = (4x + 23); x = 15. Plug it into ABC (which is (6x - 7)) to get 6(15) - 7 = 90 - 7 = 83
In65 - lnX = 39
What does X=?
Answer:
The answer is 7.47Step-by-step explanation:
In this problem we are going find the natural logarithmic of the numbers involved and solve for x
[tex]ln65-Ln x= 39\\[/tex]
from tables
ln 65= 4.17[tex]4.17-ln x= 39\4.17-39= lnx\\-34.83=lnx\\[/tex]
taking the exponents of both sides we have
[tex]e^-^3^4^.^8^3= x\\x= 7.47[/tex]
Complete the table below to solve the equation 2.5x − 10.5 = 64(0.5x).
Answer:
x = 5 is the solution
Step-by-step explanation:
See the attachment for table values.
f(x) = g(x) for x = 5
The solution to the equation ...
2.5x -10.5 = 64(0.5^x)
is x = 5.
Pls answer QUICKLY I need this
Answer:
pretty sure this is right
Find the product.
(5ab3b) (2ab)
PLEASE HELP!!! ASAP!!!
Answer:
10a²b²6ab²
Step-by-step explanation:
Distribute the 2ab the other values
which of the following is equivalent to [ (x^ 2 y^ 3 )^ -2/ (x^ 6 y^ 3 z)^3]? worth 60 points!
Answer:
[tex]\dfrac{1}{x^{48}y^{36}z^{6}}[/tex]
Step-by-step explanation:
[tex] (\dfrac{(x^2y^3)^{-2}}{(x^6y^3z)^{2}})^3 = [/tex]
[tex] = (\dfrac{1}{(x^6y^3z)^{2}(x^2y^3)^{2}})^3 [/tex]
[tex] = (\dfrac{1}{x^{12}y^6z^{2}x^4y^6})^3 [/tex]
[tex]= (\dfrac{1}{x^{16}y^{12}z^{2}})^3[/tex]
[tex]= \dfrac{1}{x^{48}y^{36}z^{6}}[/tex]
Answer:
[tex]\displaystyle \frac{1}{x^{48}y^{36}z^6}[/tex]
Step-by-step explanation:
[tex]\displaystyle[\frac{(x^2 y^3)^{-2}}{(x^6 y^3 z)^2 } ]^3[/tex]
[tex]\displaystyle \frac{(x^2 y^3)^{-6}}{(x^6 y^3 z)^6 }[/tex]
[tex]\displaystyle \frac{(x^{-12} y^{-18})}{(x^{36} y^{18}z^6 ) }[/tex]
[tex]\displaystyle \frac{x^{-48} y^{-36}}{z^6 }[/tex]
[tex]\displaystyle \frac{1}{x^{48}y^{36}z^6}[/tex]
If cos0=-3/5 in quadrant II, what is sin0
Answer:
[tex]\displaystyle \sin \theta = \frac{4}{5}[/tex] if [tex]\displaystyle \cos\theta = -\frac{3}{5}[/tex] and [tex]\theta[/tex] is in the second quadrant.
Step-by-step explanation:
By the Pythagorean Trigonometric Identity:
[tex]\left(\sin \theta\right)^2 + \left(\cos\theta)^2 = 1[/tex] for all real [tex]\theta[/tex] values.
In this question:
[tex]\displaystyle \left(\cos\theta\right)^2 = \left(-\frac{3}{5}\right)^2 = \frac{9}{25}[/tex].
Therefore:
[tex]\begin{aligned} \left(\sin\theta\right)^2 &= 1 -\left(\cos\theta\right)^2 \\ &= 1 - \left(\frac{3}{5}\right)^2 = \frac{16}{25}\end{aligned}[/tex].
Note, that depending on [tex]\theta[/tex], the sign [tex]\sin \theta[/tex] can either be positive or negative. The sine of any angles above the [tex]x[/tex] axis should be positive. That region includes the first quadrant, the positive [tex]y[/tex]-axis, and the second quadrant.
According to this question, the [tex]\theta[/tex] here is in the second quadrant of the cartesian plane, which is indeed above the [tex]x[/tex]-axis. As a result, the sine of this
It was already found (using the Pythagorean Trigonometric Identity) that:
[tex]\displaystyle \left(\sin\theta\right)^2 = \frac{16}{25}[/tex].
Take the positive square root of both sides to find the value of [tex]\sin \theta[/tex]:
[tex]\displaystyle \sin\theta =\sqrt{\frac{16}{25}} = \frac{4}{5}[/tex].
Which sum or difference is modeled by the algebra tiles?
Answer:
(C)[tex]x^2+4x-2-(-x^2+2x-4)=2x^2+2x+2[/tex]
Step-by-step explanation:
The expression represented by the upper tiles is: [tex]x^2+4x-2[/tex]
The expression represented by the lower tiles is: [tex]x^2-2x+4[/tex]
Adding the two
[tex]x^2+4x-2+(x^2-2x+4)=2x^2+2x+2[/tex]
Writing it as a difference, we have:
[tex]x^2+4x-2-(-x^2+2x-4)=2x^2+2x+2[/tex]
The correct option is C.
Answer:
yeah, what newton said :]
[tex]Let $u$ and $v$ be the solutions to $3x^2 + 5x + 7 = 0.$ Find\[\frac{u}{v} + \frac{v}{u}.\][/tex]
By the factor theorem,
[tex]3x^2+5x+7=3(x-u)(x-v)\implies\begin{cases}uv=\frac73\\u+v=-\frac53\end{cases}[/tex]
Now,
[tex](u+v)^2=u^2+2uv+v^2=\left(-\dfrac53\right)^2=\dfrac{25}9[/tex]
[tex]\implies u^2+v^2=\dfrac{25}9-\dfrac{14}3=-\dfrac{17}9[/tex]
So we have
[tex]\dfrac uv+\dfrac vu=\dfrac{u^2+v^2}{uv}=\dfrac{-\frac{17}9}{\frac73}=\boxed{-\dfrac{17}{21}}[/tex]
The value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].
What is quadratic equation?A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is[tex]ax^{2} +bx+c=0[/tex], where a and b are the coefficients, x is the variable, and c is the constant term.
What is the sum and product of the roots of the quadratic equation?If [tex]ax^{2} +bx+c = 0[/tex] be the quadratic equation then
Sum of the roots = [tex]\frac{-b}{a}[/tex]
And,
Product of the roots = [tex]\frac{c}{a}[/tex]
According to the given question.
We have a quadratic equation [tex]3x^{2} +5x+7=0..(i)[/tex]
On comparing the above quadratic equation with standard equation or general equation [tex]ax^{2} +bx+c = 0[/tex].
We get
[tex]a = 3\\b = 5\\and\\c = 7[/tex]
Also, u and v are the solutions of the quadratic equation.
⇒ u and v are the roots of the given quadratic equation.
Since, we know that the sum of the roots of the quadratic equation is [tex]-\frac{b}{a}[/tex].
And product of the roots of the quadratic equation is [tex]\frac{c}{a}[/tex].
Therefore,
[tex]u +v = \frac{-5}{3}[/tex] ...(ii) (sum of the roots)
[tex]uv=\frac{7}{3}[/tex] ....(iii) (product of the roots)
Now,
[tex]\frac{u}{v} +\frac{v}{u} = \frac{u^{2} +v^{2} }{uv} = \frac{(u+v)^{2}-2uv }{uv}[/tex] ([tex](a+b)^{2} =a^{2} +b^{2} +2ab[/tex])
Therefore,
[tex]\frac{u}{v} +\frac{v}{u} =\frac{(\frac{-5}{3} )^{2}-2(\frac{7}{3} ) }{\frac{7}{3} }[/tex] (from (i) and (ii))
⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{\frac{25}{9}-\frac{14}{3} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{25-42}{9} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{-17}{9} }{\frac{7}{3} }[/tex]
⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{-17}{21}[/tex]
Therefore, the value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].
Find out more information about sum and product of the roots of the quadratic equation here:
https://brainly.com/question/14266582
#SPJ3
ASAP! I really need help with this question! Please do not send nonsense answers. Full solutions please!
Answer:
first option
Step-by-step explanation:
Given
[tex]\frac{15}{x}[/tex] + 6 = [tex]\frac{9}{x^2}[/tex]
Multiply through by x² to clear the fractions
15x + 6x² = 9 ( subtract 9 from both sides )
6x² + 15x - 9 = 0 ( divide through by 3 )
2x² + 5x - 3 = 0 ← in standard form
Consider the factors of the product of the coefficient of x² and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 3 = - 6 and sum = + 5
The factors are + 6 and - 1
Use these factors to slit the x- term
2x² + 6x - x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x + 3) - 1(x + 3) = 0 ← factor out (x + 3) from each term
(x + 3)(2x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = 0.5
Solution set is { - 3, 0.5 }
Solve the proportion 26/z = 13/22
Answer:
z = 44
Step-by-step explanation:
26/z = 13/22
Using cross products
26 * 22 = 13*z
Divide each side by 13
26/13 * 22 = 13z/13
2 *22 =z
44 =z
Answer:
Z=44
To solve this proportion, you have to isolate z. You have to do what you do on one side of the equal sign to the other as well.
Of the 30 people riding the bus to work today, 3 rode a bike to work yesterday, 7 drove a car to work yesterday, and the rest rode the bus to work yesterday. If one of the 30 people riding the bus to work today is selected at random, what is the probability that the person selected will ride the bus to work tomorrow?
Answer:
2/3Step-by-step explanation:
This is a probability question and we have to calculate the sample size.
given the sample size S= 30
3 rode a bike
7 drove a car
20 rode bus
The probability of selecting a person that will take a bus is
[tex]Pr(bus)= 20/30= 2/3[/tex]
Please answer it now in two minutes
Answer: 3.2 yd
Step-by-step explanation:
Notice that TWV is a right triangle.
Segment TU is not needed to answer this question.
∠V = 32°, opposite side (TW) is unknown, hypotenuse (TV) = 6
[tex]\sin \theta=\dfrac{opposite}{hypotenuse}\\\\\\\sin 32=\dfrac{\overline{TW}}{6}\\\\\\6\sin 32=\overline{TW}\\\\\\\large\boxed{3.2=\overline{TW}}[/tex]
Your math teacher caught you text messaging in class, again, so the teacher is making you give a presentation to your math class next week. Your assignment is to analyze the scatter plot that shows people's ages and the number of text messages sent in a day. In 3-5 sentences, explain what you see in the scatter plot below.
Answer: If a scatterplot is included in the assignment
The dots plotted on the graph might closely follow the graph of exponential decline. There is a large number of texts per day by 19-20-21 year-olds, but the number seems to decline exponentially as age increases. With a little work, it may be possible to plot the curve and write an equation to model the decline.
Step-by-step explanation: Look at some graphs of exponential decay. Also consider harmonic and hyperbolic decay. The trend in the data is evident. The main challenge is to look at the data and create an equation that models it.