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What is the total pressure of a wet gas mixture at 60°C, containing water vapor, nitrogen, and helium. The partial pressures are

Pnitrogen - 53.0 kPa and Phelium = 25.5 kPa.

Answers

Answer 1

Answer:

98.4 kPa

Explanation:

Step 1: Given and required data

Partial pressure of water vapor at 60°C (pH₂O): 19.9 kPa (this info is tabulated)Partial pressure of nitrogen (pN₂): 53.0 kPaPartial pressure of helium (pHe): 25.5 kPa

Step 2: Calculate the total pressure of the gaseous mixture

The total pressure of the gaseous mixture (P) os equal to the sum of the partial pressures of the gases that form it.

P = pH₂O + pN₂ + pHe

P = 19.9 kPa + 53.0 kPa + 25.5 kPa = 98.4 kPa

Answer 2

The total pressure of the wet gas mixture is 98.4 KPa

Dalton's law of partial pressure

This law states that at constant temperature, the total pressure of a mixture of gases is equal to the sum of the partial pressure exerted by each gas. Mathematically, it is expressed as

Total pressure = partial pressure of A + partial pressure of B

How to determine the total pressure Partial pressure of water vapor at 60°C (pH₂O) =  19.9 KPa Partial pressure of nitrogen (pN₂) =  53.0 KPa Partial pressure of helium (pHe) = 25.5 KPa Total pressure (P) =?

P = pH₂O + pN₂ + pHe

P = 19.9 + 53 + 25.5

P = 98.4 KPa

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Answers

Answer:

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Explanation:

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Answer in M

Answers

Am I doing this right?

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Answer in M
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2.
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A
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B
Not enough information
C
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Answers

Answer:

A. 6atm

Explanation:

Using pressure law equation:

P1/T1 = P2/T2

Where;

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T1 = initial temperature (K)

P2 = final pressure (atm)

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According to this question;

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Answer:

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