help!
the potential difference between two points, a and b, in an electric field is 2.00 volts. the energy required to move a charge of 8.00x10^-19 coulomb from point a to point b is

Help!the Potential Difference Between Two Points, A And B, In An Electric Field Is 2.00 Volts. The Energy

Answers

Answer 1

Answer:

1.60 x 10^-18 J

Explanation:

we know that, Work done = Voltage x Charge,

hence we get as,

Energy = V x Q

E = 2 x (8.0 * 10^-19)

==> E = 16 x 10^-19

=> E = 16/10 x 10^-18

==> E = 1.60 x 10^-18 J


Related Questions

As the Moon revolves around the Earth, it also rotates on its axis. Why is it that the same side of the Moon is always visible from Earth?

Answers

Answer: The speed of the moon's rotation keeps the same side always facing Earth.

Explanation: Please mark me brainiest

Answer:

The speed of the Moon's rotation keeps the same side always facing Earth.

Explanation:

got it right on study island :)

What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!

Answers

Answer:

Voltage is required for there to be a current but resistance can effect the amount of current.

Answer:

the answer is voltage

Explanation:

we just finished this unit in class

A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of radius 20.0 m. If an electron were moving at the same speed perpendicular to the same magnetic field, what would be the radius of the circle the electron would move in

Answers

Answer:

0.0109 m ≈ 10.9 mm

Explanation:

proton speed = 1 * 10^6 m/s

radius in which the proton moves = 20 m

determine the radius of the circle in which an electron would move

we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)

For proton :

Mp*V^2 / rp  = qp *VB   ∴  rp = Mp*V / qP*B    ---------- ( 1 )

For electron:

re = Me*V/ qE * B -------- ( 2 )

Next: take the ratio of equations 1 and 2

re / rp = Me / Mp                                 ( note: qE = qP = 1.6 * 10^-19 C )

∴ re ( radius of the electron orbit )

= ( Me / Mp ) rp

= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20

= ( 5.45 * 10^-4 ) * 20

= 0.0109 m ≈ 10.9 mm

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?

A) Θ decrease

B) Θ increase

C) Θ remains the same

D) distant between spheres increases

Answers

Answer:

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)

Explanation:

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How far are two protons if they exert a force of 0.5 N on one another?

Answers

Answer:

5.08 metres

Explanation:

The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron

The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.

As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.

According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;

[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]

ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]

Learn more about Coulomb's Law here:

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Electric current is a measure of
Group of answer choices

a. the amount of resistance provided by the circuit.
b. the amount of electric charge that passes within a certain amount of time.
c. the amount of electric potential an electron gains passing through a battery
d. the amount of protons that pass through a resistor.

Answers

Answer:

b. the amount of electric charge that passes within a certain amount of time

Answer:

The answer is B which is the amount of electric charge that passes within a certain amount of time in my opinion.

Which choice is an example of an effect of agricultural techniques on the environment? increased oxygen levels in a pond due to fertilizer runoff sediment accumulation in a lake near a farm soil compaction caused by tillage increased plant growth caused by application of herbicides

Answers

Answer:

sediment accumulation in a lake near a farm.

Explanation:

In Agriculture, there are various techniques adopted by farmers for the growth and development of their crops. An effective and efficient agricultural technique would have a significant impact on the level of productivity attained by the farmers and as such meeting the unending requirements or needs of the consumers.

There are various agricultural techniques used in farming and these includes;

I. Mixed farming.

II. Arable farming.

III. Pastoral farming.

IV. Bush fallowing.

V. Shifting cultivation.

VI. Nomadic herding.

VII. Subsistence farming.

Generally, these agricultural techniques adopted by farmers has an effect or impact on the environment where it is practiced.

For example, one of such effect on the environment is the accumulation of sediments in a lake near the farm. Thus, this could lead to the formation of new materials such as silt, sand, clay, organic debris, etc., inside the lake.

Answer:

sediment accumulation in a lake near a farm.

Explanation:

Quia
Active
16:05:5
A plant root is an example of

Answers

Answer:A plant root is an example of an organ

Explanation:The main function of the root is to collect nutrients and water from the soil.

Answer:

hi sorry i just want points YOSHIII :3

Explanation:

What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you

Answers

Answer:

The frecuency is 1.2*10¹¹ Hz.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).

The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ.

In this case:

v= 300,000,000 m/sf= ?λ= 0.0025 m

Replacing:

300,000,000 m/s= f* 0.0025 m

Solving:

f= 300,000,000 m/s ÷0.0025 m

f= 1.2*10¹¹ [tex]\frac{1}{s}[/tex] =  1.2*10¹¹ Hz

The frecuency is 1.2*10¹¹ Hz.

Which of the following is NOT an event in track and field?
A: 110 meter hurdles
B: Dressage
C: Pole Vault
D: Discus

Answers

Dressage. It’s an event in horseback riding.

Answer:

B

Explanation:

Dressage is a horse racing sport.

give 3 uses of mirrors in everyday life ​

Answers

Answer:

Putting on makeup lol

Driving

Magnification and Science

Photography

Explanation:

I did an extra one if the makeup one wasn't allowed hahah

1. Fixing hair
2. Getting ready
3. Brushing teeth

A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?

A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm

Answers

Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of

a = v ² / R

where v is the tangential speed of the ball and R is the length of the string.

The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration

F = m a   →   a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²

where m is the ball's mass.

Solve for R :

a = v ² / R   →   R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm

35. What would a ship's position be if that ship started at
point B and traveled at an average velocity of 35 km/h
west to point D in a time period of 1.2 h?

Answers

Answer:

The final position of the ship after the given time period is  42 km West of B.

Explanation:

Given;

average velocity of the ship, v = 35 km/h

time taken for the ship to reach point D, t = 1.2 hours

The position of the ship after the given time period is calculated as follows;

x = v x t

x = (35 km/h) x 1.2 h = 42 km

x  = 42 km West of B.

Therefore, the final position of the ship after the given time period is  42 km West of B.

When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY

DRIVERS ED PLEASE HELP

Answers

Answer: 5-15MPH

Explanation: Trust me

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Answers

Answer:

Bjsjsjsiisudujdgjkkgywuuuyyyuwu

Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,

a) Which point has the highest potential; A, B or C?

b) What will a negative test charge do when it is released from rest at B?​

Answers

B is the answer hope this helps with the time bus boy

A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to θ(t)=γt+βt3θ(t)=γt+βt3, where γ=γ= 0.450 rad/srad/s and β=β= 1.10×10−2 rad/s3rad/s3. Part A Calculate the angular velocity of the merry-go-round as a function of time. Express your answer in terms of the variables ββ, γγ, and tt. ωz(t)ωz(t) = nothing rad/srad/s SubmitRequest Answer Part B What is the initial value of the angular velocity? ωzωz = nothing rad/srad/s SubmitRequest Answer Part C Calculate the instantaneous value of the angular velocity ωzωz at t=t= 5.25 ss . ωzωz = nothing rad/srad/s SubmitRequest Answer Part D Calculate the average angular velocity ωav−zωav−z for the time interval t=0t=0 to t=t= 5.25 ss .

Answers

Answer:

hufiui

fihgpfghlfikgergkfkjhfkhjgkffhhh

Explanation:

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Two children are sitting on a see-saw, as shown. Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw.

Answers

We have that for the Question "Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw"

It can be said that

The distance = [tex]1.8m[/tex]

From the question we are told

weights are = 300 N and 500 N

length l = 6 m

take x distance from the 300 N

total torque is zero

[tex]300*3 = 500x\\\\x = 1.8 m[/tex]

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The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error

Answers

Answer: Steeper slopes mean lower speeds.

Explanation:

If it’s a flat slope then it’s c
But if it’s a wavy slope then it’s a

A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere

Answers

Answer:

[tex]F \approx 19.5 N[/tex]

Explanation:

From the question we are told that:

Pressure of  [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]

Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]

 

Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by

[tex]P_r=P_{CO_2}-P_a[/tex]

Where

[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]

[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]

[tex]P_r=0.487*10^5 pa[/tex]

Generally the equation for Force exerted by screw F is give as is mathematically given by

[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]

[tex]F \approx 19.5 N[/tex]

People with schizophrenia are most likely to have delusions that reflect the theme of

Answers

Answer:

llogical or bizarre ideas or fantasies.

Explanation:

The sky diver travels download at a speed of 56m/s for 40s calculate the distance travelled during this time. use the equation distance travelled= speed x time

Answers

i don’t know i just need points 44

A freight train car is moving at a constant speed with respect to the ground of Vcg. A man standing on a flatbed car throws a ball into the air and catches it as it falls. Relative to the flatbed car, the initial velocity of the ball is Vibc straight up. a. What are the magnitude and direction of the initial velocity of the ball as seen by a second man standing on the ground next to the track

Answers

Answer:

chiicken

Explanation:

what is the process that creates wind.

Answers

Answer:

Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.

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If a car is traveling at a speed of 65 miles per hour, how can this be rewritten as a velocity?

Answers

Answer:

i.e 65 mph, and a direction, say "east'.

Explanation:

A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move between adjacent tracks. What is the longest time needed to read an arbitrary sector located anywhere on the disk

Answers

Answer:

the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

Explanation:

 Given the data in the question;

first we determine the rotational latency

Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms

To get the longest time, lets assume the sector will be found at the last track.

hence we will access all the track, meaning that 127 transitions will be done;

so the track changing time = 127 × 15 = 1905 ms

also, we will look for the sectors, for every track rotations that will be done;

128 × 8.33 = 1066.24 ms

∴The Total Time = 1066.24 ms + 1905 ms

Total Time = 2971.24 ms

Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

[TG.05H]A geothermal plant has been built in a location. Which of these is the most likely impact of the plant on the location?

depletion of fossil fuels like coal
damage to hot springs and geysers
decrease in average annual temperature
increase in emission of greenhouse gases

Answers

The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.

What is a geothermal plant?

A geothermal plant makes use of both heat and water in the generation of electricity.

The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.

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A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.

Answers

Answer:

[tex]v=15.9499m/s[/tex]

Explanation:

From the question we are told that:

Mass of wood [tex]m=1kg[/tex]

force constants [tex]k= 200N-m[/tex]

Coefficient of kinetic friction [tex]\mu= 0.2[/tex]

Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]

Spring compresion [tex]y=15cm \approx 0.15 m[/tex]

Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by

Complete Question

[tex]K.E_b=spring potential energy+work done against friction[/tex]

[tex]K.E_b=\frac{1}{2} mbv^2[/tex]

[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]

[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]

[tex]v=15.9499m/s[/tex]

[tex]v\approx16m/s[/tex]

Darcy is going to make raspberry jam for the county fair.
• Her recipe calls for exactly 55 raspberries per jar.
Darcy has 1,700 raspberries.

Answers

Answer:

She can make have 30 jars with raspberries in them with 50 left over.

Explanation:

1,700 divided by 55

30 equally

but 50 left over

This means that she can make have 30 jars with raspberries in them with 50 left over.

Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.

Answers

Explanation:

give me more detail and i well help you out

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