hey found that 27 occurred in the Spring, 39 in the Summer, 31 in the Fall, and 53 in the Winter. Can it be concluded at the 0.05 level of significance that car accidents are not equally distributed throughout the year

Answers

Answer 1

This question is incomplete, the complete question is;

A Driver's Ed program is curious if the time of year has an impact on numer of car accidents in the U.S.

They assume that weather may have a significant impact on the ability of drivers to control their vehicles. They take a random sample of 150 car accidents and record the seasons each occurred in. They found that 27 occurred in the Spring, 39 in the Summer, 31 in the Fall, and 53 in the Winter. Can it be concluded at the 0.05 level of significance that car accidents are not equally distributed throughout the year

a) Yes, because the p-value = 0.0145

b) No, because the p-value = 0.0145

c) Yes, because the p-value = 0.0291

d) No, because the p-value = 0.0291

Answer:

p-value = 0.0145

Since p-value ( 0.0145 ) is less than Significance level ∝ ( 0.05 ),

We reject Null hypothesis.

Hence, There is sufficient evidence to conclude that car accidents are NOT equally distributed through out the year.

[ Option a) Yes, because the p-value = 0.0145 ] is the correct answer.

Step-by-step explanation:

Given the data in the question;

number of car accident = 150

Observed Frequencies O are;

Spring = 27

Summer = 39

Fall = 31

Winter = 53

Significance level ∝ = 0.05

Hypothesis

Null hypothesis            H₀ : The car accidents are equally distributed through out the year

Alternative hypothesis H₀ : The car accidents are NOT equally distributed through out the year

Now, Expected Frequency E will be;

Spring = 150/4 = 37.5

Summer = 150/4 = 37.5

Fall = 150/4 = 37.5

Winter = 150/4 = 37.5

Test Statistics;

[tex]X^2_{stat^[/tex] = ∑[ ( O-E )² / E ]

so

[tex]X^2_{stat^[/tex] = [ ( 27-37.5 )² / 37.5 ] + [ ( 39-37.5 )² / 37.5 ] + [ ( 31-37.5 )² / 37.5 ] + [ ( 53-37.5 )² / 37.5 ]

[tex]X^2_{stat^[/tex] = 2.94 + 0.06 + 1.1267 + 6.4067

[tex]X^2_{stat^[/tex] = 2.94 + 0.06 + 1.1267 + 6.4067

[tex]X^2_{stat^[/tex] = 10.5334

Degree of Freedom DF = n-1 = 4 -1 = 3

Now,

p-value = P( [tex]X^2[/tex] - [tex]X^2_{stat^[/tex] ) = P( [tex]X^2[/tex] - 10.5334 ) = 0.0145

p-value = 0.0145

Since p-value ( 0.0145 ) is less than Significance level ∝ ( 0.05 ),

We reject Null hypothesis.

Hence, There is sufficient evidence to conclude that car accidents are NOT equally distributed through out the year.

[ Option a) Yes, because the p-value = 0.0145 ] is the correct answer.


Related Questions

The zeros of a function f(x) are 8 (double root) and -3 and the y-intercept is -768. Write the equation of f(x) in factored form.

Answers

9514 1404 393

Answer:

  f(x) = -4(x +3)(x -8)²

Step-by-step explanation:

Each zero (z) gives rise to a factor (x -z). The given zeros mean the factored form is ...

  f(x) = a(x -8)²(x +3)

The value of this at x=0 is ...

  f(0) = a(-8)²(3) = 192a

We want the value to be -768, so ...

  -768 = 192a

  -4 = a . . . . . . . . divide by the coefficient of 'a'

Then the factored form is ...

  f(x) = -4(x +3)(x -8)²

(easy math question please help) find the value of x question #9

Answers

Answer:

Step-by-step explanation:

25+125+(-5x)=180 degree(sum of interior angles of a triangle is 180 degree)

150-5x=180

-5x=180-150

x=30/-5

x=-6

The data below shows the grams of fat for a variety of snacks. Morris wants to calculate the standard error of the sample mean for this set of data. Snack Grams of Fat Snack 1 9 Snack 2 13 Snack 3 21 Snack 4 30 Snack 5 31 Snack 6 31 Snack 7 34 Snack 8 25 Snack 9 28 Snack 10 20 What is the standard error for this set of data

Answers

Answer:

the standard error of data set is 2.628

Step-by-step explanation:

Given the data in the question;

set;

x = 9, 13, 21, 30, 31, 31, 34, 25, 28, 20

To get the standard of Error for this data set, we use the formual

S.E = s / √n

First we determine the mean average;

Mean x' = ∑x / n =  ( 9 + 13 + 21 + 30 + 31 + 31 + 34 + 25 + 28 + 20 ) / 10

x' = 242 / 10

Mean x' = 24.2

Next we find the standard deviation s:

x             (x-x')²

9           231.04

13          125.44

21          10.24

30         33.64

31         46.24

31         46.24

34        96.04

25        0.64

28        14.44

20        17.64

Total ∑(x-x')² = 621.6

so Variance = ∑(x-x')² / (n-1) = 621.6 / ( 10 - 1 )  = 621.6 / 9

Variance = 69.0667

Standard deviation S = √Variance

Standard deviation S = √69.0667

Standard deviation S = 8.3106

So we substitute into our formula to get the standard of error;

S.E = 8.3106 / √10

S.E = 2.628

Therefore, the standard error of data set is 2.628

Answer:

2.63

Step-by-step explanation:

Which best describes the strength of the model?
O a weak positive correlation
a strong positive correlation
a weak negative correlation
O a strong negative correlation

Answers

Answer: A weak positive correlation

Step-by-step explanation: Took the testtt

Answer:

Weak negative correlation

Step-by-step explanation:

From the data given, we can fit the model using technology,

The correlation Coefficient obtained is - 0.129 ; this value being negative means that there exist a negative relationship between the two variables. Also, the correlation Coefficient value is closer to 0 ; this also depicts a weak relation ship between the variables, hence, resulting in the conclusion that the variables have a weak negative correlation.

Write an equation of a function with each domain:
a. [ 2 , ∞ )
b. ( -∞ , ∞ )

Answers

Answer:

a. [ 2 , ∞ )

Step-by-step explanation:

Irrational number between 3.077243 and 3.0721​

Answers

Answer:

3.066543

Step-by-step explanation:

This number is between 3.077243 and 3.0721

What sample size should be used if we would like to estimate the mean age of the college students at a particular campus with 95% confidence? We would like to be accurate to within three years, and we will assume the population is normally distributed with a standard deviation of 5.1 years. a. 12 b. 23 c. 204 d. 8

Answers

Answer:

The sample size should be:

c. 204

Step-by-step explanation:

This is based on the assumption that in this campus, there are no more than 2040 students.  The sample size should be around 10% of the population, which is considered a good representative of the real population for the specific study.  If, however, the population is so large that 10% of the population will be more than 1,000, then the sample size should be limited to 1,000.

Expand ( x - 1/x^2)^4

Answers

Answer:

We want to expand the expression:

[tex](x - \frac{1}{x^2} )^4[/tex]

We can just do it by brute force, this is:

First, rewrite our expression as the product of two square factors:

[tex](x - \frac{1}{x^2} )^4 = (x - \frac{1}{x^2} )^2*(x - \frac{1}{x^2} )^2[/tex]

Now we can expand each one these two factors:

[tex](x - \frac{1}{x^2} )^2 = (x - \frac{1}{x^2} )*(x - \frac{1}{x^2} ) = x^2 + \frac{1}{x^4} -2*x*\frac{1}{x^2}[/tex]

That can be simplified to

[tex]x^2 - \frac{2}{x} + \frac{1}{x^4}[/tex]

Now we can replace that in our original expression to get:

[tex](x^2 - \frac{2}{x} + \frac{1}{x^4})*(x^2 - \frac{2}{x} + \frac{1}{x^4})[/tex]

Now we can expand that last product, to get:

[tex](x^2)^2 + 2*(x^2)*(-\frac{2}{x} ) + 2*(x^2)*(\frac{1}{x^4}) + 2*(\frac{-2}{x})*(\frac{1}{x^4}) + (\frac{-2}{x} )^2 + (\frac{1}{x^4})^2[/tex]

We can simplify that to:

[tex]x^4 - 4x + 2x^2 - \frac{4}{x^5} + \frac{4}{x^2} + \frac{1}{x^8}[/tex]

That is the expanded expression.

help me I got 25 missing assignments

Answers

Answer:

think it's the last one

Step-by-step explanation:

sorry if i'm wrong


I’m confused:/ can somebody help me??

Answers

Answer:

I got ya :D

the answer is

[tex] \binom{ - 18 \: \: \: 10 }{5 \: \: \: - 3} [/tex]

explanation in the attachment

What is the area of a circle with a radius of 87.1 cm?​

Answers

Answer:

23833.41cm²

Step-by-step explanation:

A=πr2=π·87.12≈23833.40992cm²

That rounds up to 23833.41cm²

Step-by-step explanation:

its formula is pi r square so calculate iin own

solve for system of equations -x+2y=8, x-2y=-8

Answers

Answer:

0.. everything just cancels out

-5<3 true or false llssss answer I need to knowwwwww

Answers

Answer:

True

Step-by-step explanation:

Because this sign < eats the 3

Hdisowiejejkwoeooeoe

Answers

Answer:

98

Step-by-step explanation:

The absolute value of a number different from 0 is always positive

- * - = +

15 + 83 = 98

a portion of 7200 is invested at 5 1/2 percent interest, and the rest is invested at 5 percent interest. if the yearly income from the money is rs. 387 how much is invested at each rate ?​

Answers

Answer:

A 5.5% = 5400 B 5% = 1800

Step-by-step explanation:

A + B = 7200

A * 0.055 + B * 0.05 = $387

A = 7200 - B

(7200 - B)*0.055 + B*0.05 = 387

396 - 0.055B + 0.05B = 387

396 - 0.005B = 387

0.005B = 9

B = 1800

A = 7200 - B = 7200 - 1800

A = 5400

At two digits is such that the Sum of its to digits is ten. if the digit are reversed the number formed exceed the original number by 18. Find the number

Answers

Answer:

46

Step-by-step explanation:

the number is 46

PLEASEEEE HELPPPPP IM BEGGING SOMEONE HELPPP PLEASEEEEEEEEE PLEASEEEEEEEE​

Answers

Answer:

x = -1

y = 6

Step-by-step explanation:

We can multiply the second equation by two, so we can have opposite y terms:

2 (3x - 2y = -15)

6x - 4y = -30

Now, we can add the equations, and the y terms can cancel out:

  7x + 4y = 17

+ 6x - 4y = -30

13x = -13

x = -1

Now, we can plug in x:

3(-1) - 2y = -15

-3 - 2y = -15

-2y = -12

y = 6

X= -1
Y= 6
That’s the answer

Assume that y varies inversely with the
square of x, then solve.
When x is 5, y is 4/5. Find y when x is 8.

Answers

Answer:

y = 5/16

Step-by-step explanation:

[tex]y\ \alpha\ \frac{1}{x^2}\\\\y = k \times \frac{1}{x^2}\\\\y = \frac{4}{5}, x = 5.\\\\\frac{4}{5} = k \times \frac{1}{5^2}\\\\\frac{4}{5} \times 5^2 = k\\\\20 = k\\\\Now \ find\ y, \ when \ x = 8\\\\y = k \times \frac{1}{x^2} = 20 \times \frac{1}{8^2} = 20 \times \frac{1}{64} = \frac{5}{16}[/tex]

5/6 x 2/5 Help pls!!!

Answers

Step-by-step explanation:

10/30

hope this helps.............

The Pentagon's ABCDE & PQRST are similar find the length X of QR


Please help I will give 50 points and give branliest!!!!

Answers

Answer:

x = 3.2

Step-by-step explanation:

Since they are similar the ratio of the side lengths must be the same

Using the bottom side and the unknown side from the left figure and the right figure

5            4

----- = --------

4            x

Using cross products

5x = 4*4

5x = 16

Divide by 5

x = 16/5

x =3.2


2. Find(f/g)(x) when f(x) = 6x2 + 12x and g(x) = 2x2 + 8x + 8. Show your work.

Answers

Answer:

:)

Step-by-step explanation:

[tex](\frac{f}{g}) (x) = \frac{f(x)}{g(x)} = \frac{6x^2 + 12x}{2x^2 + 8x + 8}[/tex]

                    [tex]= \frac{6x(x + 2)}{2(x^2 + 4x + 4)}\\\\=\frac{3x(x+2)}{(x+2)(x+2)}\\\\=\frac{3x}{(x+2)}[/tex]

Can someone please help me?!!!!

Answers

Answer:

The answer is:

0.18

0.92

0.15

1.80

The manager of a new supermarket wished to estimate the likely expenditure of his customers. A sample of till slips from a similar supermarket describing the weekly amount spent by 500 randomly selected customers was collected and analysed. This expenditure was found to be approximately normally distributed with a mean of $50 and a standard deviation of $15.
Find the probability that any shopper selected at random spends more than $80 per week?
Find the percentage of shoppers who are expected to spend between $30 and 80 per week?

Answers

Answer:

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

88.54% of shoppers are expected to spend between $30 and 80 per week.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of $50 and a standard deviation of $15.

This means that [tex]\mu = 50, \sigma = 15[/tex]

Find the probability that any shopper selected at random spends more than $80 per week?

This is 1 subtracted by the p-value of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 50}{15}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

Find the percentage of shoppers who are expected to spend between $30 and 80 per week?

The proportion is the p-value of Z when X = 80 subtracted by the p-value of Z when X = 30.

X = 80

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 50}{15}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.9772

X = 30

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 50}{15}[/tex]

[tex]Z = -1.33[/tex]

[tex]Z = -1.33[/tex] has a p-value of 0.0918

0.9772 - 0.0918 = 0.8854

0.8854*100% = 88.54%

88.54% of shoppers are expected to spend between $30 and 80 per week.

Here are two datasets: Dataset A: 64 65 66 68 70 71 72 Dataset B: 64 65 66 68 70 71 720 For dataset A, the mean and median are 68. Looking at dataset B, notice that all of the observations except the last one are close together. Which measure will be affected by this last observation in dataset B

Answers

Answer:

Mean will be affected.

Step-by-step explanation:

The mean value of the data set will be affected as it depends on the magnitude of data points and not its position. The median however will not change since it depends on the relative position of data points.

Solve AABC. Round your answers to the nearest hundredth, if necessary

Answers

Answer:

[tex]C=25^{\circ},\\a\approx 10.72,\\b\approx 11.83[/tex]

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees. Thus, angle C must be [tex]180-90-65=25^{\circ}[/tex].

In any triangle, the Law of Sines is given by [tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex].

Therefore, we have:

[tex]\frac{\sin 90^{\circ}}{b}=\frac{\sin 25^{\circ}}{5},\\\\b=\frac{5\sin90^{\circ}}{\sin 25^{\circ}}=11.8310079158\approx \boxed{11.83}[/tex]

[tex]\frac{a}{\sin 65^{\circ}}=\frac{5}{\sin25^{\circ}},\\a=\frac{5\sin 65^{\circ}}{\sin25^{\circ}}=10.7225346025\approx \boxed{10.72}[/tex]

A third-grade class is using plaster of Paris to make impressions of their hands. Each student needs 12 ounces of plaster to make an impression. There are a total of 20 students in the class. How many pounds of plaster will the teacher need for the activity?

Answers

Answer:

15 pounds of plaster

Step-by-step explanation:

First, convert ounces to pounds.

In 1 pound, there are 16 ounces. Create a proportion to convert 12 ounces to pounds.

[tex]\frac{1}{16}[/tex] = [tex]\frac{x}{12}[/tex]

Cross multiply and solve for x:

16x = 12

x = 0.75

So, each student will need 0.75 pounds of plaster. Multiply this by 20 to find the total amount the teacher will need:

20(0.75)

= 15

So, the teacher will need 15 pounds of plaster

Answer:

15 pounds

Step-by-step explanation:

how many years (to two decimal places) will it take an investment of $17,000 to grow to $41,000 if it is invested at 2.95% compounded continuously

Answers

Answer:

30 years

Step-by-step explanation:

Given data

P=$17,000

A= $41,000

R=2.95%

the expressio for the time is

t= ln(A/P)/r

t= ln(41,000 /17000)/0.0295

t= ln(2.41176)/0.0295

t= 0.8803/0.0295

t= 29.8

about 30 years

Find the volume of the solid. Round your answer to the nearest tenth

Answers

Answer:

Solution given:

Volume of cone=⅓πr²h

Volume of cylinder=πr²h

1.

volume =πr²h=π*(10/2)²*6=471.23mm³

2.

Volume =πr²h=π*8*12.5=314.16in³

3.

volume =⅓πr²h=⅓*π*4²*3=50.26cm³

4.

Volume =⅓πr²h=⅓*π*(8/2)²*12=201.06in³

Help asap, please!!..

Answers

that alot of work no cap

HELP!! Pauline Wong spends 3hours selling a used car and 5hours selling a new car. She works no more than 31hours per week. In order to receive a bonus, she must sell at least twoused car and twonew cars each week. In that case, she receives a bonus of $200for each used car and $300for each new car. How many new cars and how many used car should she try to sell to maximize her bonus? What is the maximum bonus?
a) Define the variables to use
b) Goal function
c) Constraints

Answers

The correct answer is b

Answer:

B)Goal Function

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