Answers
Answer:
The answer is b
Hope this helps you!
Related Questions
Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 newtons while Andy pushes the table from the opposite side with a force of 125 newtons. Ignoring the masses of Eli and Andy, what is the resultant acceleration of the table if its mass is 10.0 kilograms?
Answers
Answer:
a = 0.5 m/s²
Explanation:
the type of problem is called a Newtons second law of motion.
and the equation would be the sum of F = m * a where m = mass and a = acceleration
forces are 125N and the opposite direction is 120N
Eli pushes the table with a force of 120N towards Andy
and
Andy pushes the table with a force of 125N towards Eli
mass of table given as 10 kg.
using the equation
120N - 125N = 10kg * a
a = (120-125) / 10
a = -0.5 m/s² so the acceleration is in the direction of Andy's force towards Eli.
therefore a = 0.5 m/s²
Answer:
B.
0.50 meters/second2
Explanation:
you walk 6 block east, 2 blocks north, 3 blocks west and then 2 blocks north. the total distance you travel is blocks
Answers
Answer:
The answerI travel 13 blocksThe same motor is used in rockets with different masses. The rockets have different accelerations. According to Newton’s second law, how is acceleration expected to change as the rocket mass increases? As rocket mass increases, acceleration decreases. There are no changes in acceleration, as it would depend on the amount of force. As rocket mass increases, acceleration increases. Acceleration cannot be predicted based on changes in mass.
Answers
Answer:
As rocket mass increases, acceleration decreases.
Explanation:
From Newton's second law of motion;
F= ma
Where;
m= mass of the object
a= acceleration of the object
Hence we can write;
a= F/m
This implies that an increase in mass (m) will lead to a decrease in acceleration if the force on the object is held constant.
Hence, if the rockets have different masses, they will have different accelerations.
Hello!
---------
As rocket mass increases, acceleration decreases.
Hope this helps! The rest are available on Quizlet at "Unit 6: Lesson 4 Force, Mass and Acceleration". Thanks and good luck!
A metal disk lies in the xy-plane, centered about the origin, and rotates with a constant angular velocity about the z-axis. There is a uniform 0.0314 T magnetic field parallel to the z-axis. The radius of the disk is 1.56 m. At what rate is the disk turning if an E of 3.86 V develops between the center of the disk and a point on its rim
Answers
Answer:
w = -101 rad / s
Explanation:
For this exercise we will use Faraday's law
E = - dФ / dt
where the magnetic flux is
Ф = B. A = B A cos θ
In this case, the angle between the magnetic field and the normal to the disk is zero, cos 0 = 1, they indicate that the field is constant, let's find the area
The area rotated by the disk is
A = ½ r s
if we express the angles in radians
θ = s / r
s = r θ
where is the arc supported
A = ½ r (r θ)
let us substitute in the Faraday equation
E = - d (B ½ r² θ) / dt
E = - ½ B r² dθ/dt
the definition of angular velocity is
w = dθ/dt
E = - ½ B r² w
w = - 2E / B r²
let's calculate
w = - 2 3.86 / (0.0314 1.56²)
w = -101 rad / s
Enample: the motion of moon around the earth Describe the motion of an object in which its speed constant but the velocity is changing
Answers
Answer:
To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.
Explanation:
Speed refers to how fast an object is moving. It can be thought of as the rate at which an object covers distance.
Velocity refers to the rate at which an object changes its position. If you picture a person moving rapidly - one step forward and one step back- always returning to the original starting position, the speed is very rapid, but the velocity is zero. Because the person always returns to the original position, this motion would bébé result in a change in position. Since velocity is defined as the rate at which the position changes, this motion results in zero velocity. To maximize velocity, every effort must be made to maximize the amount an object is displaced from its original position. Every movement should be moving the object further from where it started. Velocity is DIRECTION AWARE. When evaluating the velocity of an object, you have to keep track of direction. This is one of the essential differences between speed and velocity: speed does not keep track of direction, while velocity is directionally aware.
So, when the moon moves around the Earth, the speed remains constant, but since it's moving in an elliptical orbit, it's direction is constantly changing.
the standard unit of measurement of preasure
2. What is
N/m square or Pascal
Answers
Answer:
Both are the same.
Explanation:
[tex]pressure= \frac{force}{area} = \frac{f}{a} = \frac{n}{m {}^{2} } [/tex]
The SI unit was named after Bláise Pascal to honor him.
Hope this helps ;) ❤❤❤
if the radius of a coin is 1 cm then calculate its area.
Answers
Answer:
3.14*1²
3.14 cm²
I hope this will help
Answer:
3.14 cm squared
Explanation:
I hope this will help.
If the spring constant is 10 N/m and the spring is stretched 1 m, what is the Force?
Answers
Answer:
10N
Explanation:
Applying the Hooke law:
F = kx
F: Force
k: stiffness coefficient
x: stretched distance
F = 10N/m x 1m = 10N
Based on its location on the periodic table, which element would be most likely to form a negative ion? A. Bromine (Br) B. Strontium (Sr) C. Potassium (K) D. Magnesium (Mg)
Answers
your answer is...
C. potassium
A 30-µF capacitor is charged to an unknown potential V and then connected across an initially uncharged 10-uF capacitor. If the final potential difference across the .10-µF capacitor is 20 V, determine V
Answers
Answer:
V = 26.6 volts
Explanation:
Let Initial Potential Difference be V.
Charge (Q) accumulated in 30 mF Capacitor =
Q = C * V
Q= 30 * V
Now, Common Potential after connecting to uncharged 10mF capacitor in parallel = 20 Volt
Total Charge =Total Capacity * Common Potential
30 * V = ( 30 + 10) * 20
V = 26.6 volts
The unknown potential across the 30-µF capacitor is 6.67 V.
The given parameters;
initial capacitance of the capacitor, C = 30 µFunknown potential in the 30 µF capacitor = V₁potential difference in 10 µF capacitor = 20 VSince the potential difference between the two capacitors are different, the two capacitors are in series connection.
In series circuit arrangement, the quantity of charge flowing in each capacitor is the same.
[tex]Q_{30\ \mu F} = Q_{10 \ \mu F}[/tex]
[tex]Q_{10 \ \mu F} = CV = 10\times 10^{-6} \times 20 = 0.0002 \ C[/tex]
The potential difference are different and the total potential is given as;
[tex]V_{T} = V_1 + V_2\\\\V_1 = \frac{Q}{C_1} \\\\V_2 = \frac{Q}{C_2} \\\\V_1+V_2 = \frac{Q}{C_1} + \frac{Q}{C_2}\\\\V_1 + V_2 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1 + 20 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1+ 20 = \frac{Q(C_2+ C_1)}{C_1 C_2} \\\\V_1 = \frac{Q(C_2+ C_1)}{C_1 C_2} - 20[/tex]
[tex]V_1 = \frac{0.0002(10\times 10^{-6}\ + \ 30\times 10^{-6})}{(30\times 10^{-6}) (10\times 10^{-6})} - 20\\\\V_1 = \frac{8\times 10^{-9}}{3\times 10^{-10}} - 20\\\\V_1 = 26.67 - 20\\\\V_1 = 6.67 \ V[/tex]
Thus, the unknown potential across the 30-µF capacitor is 6.67 V.
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One glass microscope slide is placed on top of another with their left edges in con- tact and a human hair under the right edge of the upper slide. As a result, a wedge of air exists between the slides. An interference pattern results when monochromatic light is incident on the wedge. What is observed at the left edge of the slides? a. A dark fringe b. A bright fringe c. Impossible to determine
Answers
Answer:
A dark fringe
Which of the following would be the SI unit to use in measuring the temperature of hot liquid
Answers
Answer:
Kelvin
Explanation:
The SI unit to use in measuring the temperature of hot liquid is kelvin (K)
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The system is held in place. At time t=0 the blocks are released. The blocks move off in opposite directions with velocities v1 and v2. how much was the spring compressed?
Answers
Answer:
The spring was compressed the following amount:
[tex]\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }[/tex]
Explanation:
Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount [tex]\Delta x[/tex]), and the total final energy is the addition of the kinetic energies of both masses:
[tex]E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2[/tex]
[tex]E_i=E_f\\[/tex]
[tex]\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }[/tex]
ASAP TWENTY POINTS What type of image is formed by a mirror if m = -0.4?
Answers
Answer:
OPTION (C)
Explanation:
m(magnification) = -0.4 means a real, inverted and diminished image is formed in front of the mirror.
Convert 85 cm/min to m/s.
Answers
Explanation:
meter=100cm
cm=10^-2 m
min=60 sec
0.0141666667 m / s
The conversion of 85 cm/min would be 0.0133 m/s
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem position-time graph of an object.
As we know that slope of the position time curve represents the velocity of the object
As given in the problem we have to convert 85 cm/min to m/s.
Let us first convert the displacement in cm to meters
100 cm = 1 m
1 cm = 1/100 m
85 cm = 85×1/100 m
= 0.85 m
similarly, convert time given in minutes to the seconds
1 min = 60 s
velocity = displacement /time
velocity = 0.85 / 60 m/s
=0.01333 m/s
Thus, we converted 85 cm/m into 0.0133 m/s
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Có một số điện trở giống nhau R0 = 3
. Cần ít nhất bao nhiêu điện trở để có một
đoạn mạch có điện trở Rtđ = 8
Answers
Answer:
hlo
Explanation:
hlo olz mark me as brainlest
A fish inside the water 12cm below the surface looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 the radius of circle is
Answers
Answer:
13.6 cm
Explanation:
From Snell's law:
n₁ sin θ₁ = n₂ sin θ₂
In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.
Given n₂ = 4/3:
1 = 4/3 sin θ
sin θ = 3/4
If x is the radius of the circle, then sin θ is:
sin θ = x / √(x² + 12²)
sin θ = x / √(x² + 144)
Substituting:
3/4 = x / √(x² + 144)
9/16 = x² / (x² + 144)
9/16 x² + 81 = x²
81 = 7/16 x²
x ≈ 13.6
i) A 100 W and 60 W bulb are joined in series and connected to the mains. Which bulb
will glow brighter? Why?
ii) A 100 W and a 60 W bulb are joined in parallel to the mains. Which bulb will
glow brighter? Why?
Answers
Answer:
i) 60 W
ii) 100 W
Explanation:
In each case, the bulb that dissipates the most power is the bulb that glows brighter. Power is voltage times current (P = VI). Using Ohm's law, we can rewrite this as P = I²R or P = V²/R.
Bulbs are rated at a certain power for a certain voltage. P = V²/R, so the bulb with the lower resistance will have the higher power rating. Therefore, the 100 W bulb has a lower resistance than the 60 W bulb.
i) They are in series, so they have the same current. P = I²R, so the bulb with the higher resistance will glow brighter. That's the 60 W bulb.
ii) They are in parallel, so they have the same voltage. P = V²/R, so the bulb with the lower resistance will glow brighter. That's the 100 W bulb.
which of the following are possible units for a spring constant? A. N/nm B. nm/N C. nm/J D. J/nm
Answers
Answer:
Since N/m is the unit of spring constant N/nm would be the possible unit for a spring constant.
A. N/nm is the possible unit for a spring constant.
Is spring constant in N m?The units at the spring regular are Newton/meter (N/m). The poor signal within the above equation is an indication that the direction that the spring stretches is opposite the path of the pressure that the spring exerts.
Because the force is measured in Newtons and the spring consistent is multiplied with the aid of the gap in meters, the spring constant need to have devices that get rid of meters, ensuing most effective force. The most effective devices that work for the spring regular are for that reason, Newtons in step with the meter.
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URGENT!! Look at attached image to see question.
Answers
Explanation:
The answer is option B
The number of reactant molecules and product molecules is even.
A block is attached to the end of a spring. The block is then displaced from its equilibrium position and released. Subsequently, the block moves back and forth on a frictionless surface without any losses due to friction. Which one of the following statements concerning the total mechanical energy of the block-spring system this situation is true?
1. The total mechanical energy is dependent on the maximum displacement during the motion.
2. The total mechanical energy is at its maximum when the block is at its equilibrium position
3. The total mechanical energy is constant as the block moves back and forth.
4. The total mechanical energy is only dependent on the spring constant and the mass of the block.
Answers
Answer:
The correct option is;
3. The total mechanical energy is constant as the block moves back and forth
Explanation:
The total mechanical energy is the sum of the potential and kinetic energies of the system
For a system that is isolated from the effects of external forces, but being acted upon by the internal conservative forces within the system, the total mechanical energy is constant
For a black and spring system, we have total mechanical energy, E = 1/2×K×A².
Where;
K = Constant
A = The amplitude of motion
Therefore, where there is no loss to friction, with A, remaining constant, the total mechanical energy will be constant.
an athlete had lifts a load with a mass of 150kg.
1) calculate the gravitational potential energy gained
2) if the mass of the load is increased to 200kg, calculate the gravitational potential energy gained by the load.
3) based on answers in 1&2, state the relationship between the mass of the load and the gravitational potential energy.
Answers
[tex]\\ \sf\longmapsto P.E=mgh[/tex]
[tex]\\ \sf\longmapsto P.E=150(2)(10)[/tex]
[tex]\\ \sf\longmapsto P.E=3000J[/tex]
In 2nd case
Mass =m=200kgHeight=h=2mg=10m/s^2[tex]\\ \sf\longmapsto P.E=200(2)(10)[/tex]
[tex]\\ \sf\longmapsto P.E=4000J[/tex]
We can observe that
If mass of body increases gravitational potential energy will increase.a.
more iOCUS
8.
A force of 8N is applied to the body to cover 50 cm distance. How much work is done
by this fore?
400J
b. 40J
d. 40kg
a.
C.
Answers
Answer:
[tex] \boxed{\sf Work \ done = 4 \ J} [/tex]
Given:
Force = 8 N
Distance covered by the body = 50 cm = 0.5 m
Explanation:
Work Done = Force × Distance covered by the body
= 8 × 0.5
= 4 J
A wave is represented by the equation y = 0.20 sin [ 0.4π (x – 60t)], where x and y are in cm and t is in s. The velocity of the wave is...
Answers
Answer:
v = 60 m/s
Explanation:
It is given that,
A wave is represented by the equation :
[tex]y=0.2\sin [0.4\pi (x-60)t][/tex]
We need to find the velocity of the wave
The general equation of a wave is given by :
[tex]y=A\sin (kx-\omega t)[/tex] ....(1)
Equation (1) can be written as :
[tex]y=0.2\sin (0.4\pi x-24\pi t)[/tex] ...(2)
If we compare equation (1) and (2) we get :
[tex]k=0.4\pi[/tex]
[tex]\omega=24\pi[/tex]
The velocity of a wave is given by :
[tex]v=\dfrac{\omega}{k}\\\\v=\dfrac{24\pi}{0.4\pi}\\\\v=60\ m/s[/tex]
So, the velocity of the wave is 60 m/s.
what will be the gravitational force between two bodies if the mass of each is doubled and the distance between them is halved?
Answers
Answer:
Gravitational force will be 16 times more.
Explanation:
we know;
Gravitational force (F) = (Gm1m2)/d^2
when mass of each is doubled and distance between them is halved;
F= (G2m1×2m2)/(d/2)^2
=(4Gm1m2)/(d^2/4)
=4×4(Gm1m2)/d^2
=16(Gm1m2)/d^2
=16F
Suppose an experiment is designed to test the durability of batteries in different conditions. All of the batteries tested are double-A (AA) Brand X. All sets of batteries are preconditioned in different environmental conditions for exactly 168 hours (1 week).
Set 1: 0°C (freezing point of water)
Set 2: 24°C (approximately room temperature)
Set 3: 37°C (approximately body temperature)
The batteries are then continuously used to power identical mechanical drummer toys. As long as the toy keeps drumming the battery is considered functional. The drumming time for each toy is measured as an indication of battery durability. In this experiment, which condition is not controlled?
A.) temperature
B.) brand of batteries
C.) test for durability
D.) type of battery (battery size)
Answers
Answer:
I assume its c. Since its talking about testing.
Explanation:
Answer:
The answer is test of durability
Explanation:
A bat is flitting about in a cave, navigating via ultrasonic bleeps. Assume that the sound emission frequency of the bat is 38.9 kHz. During one fast swoop directly toward a flat wall surface, the bat is moving at 0.015 times the speed of sound in air. What frequency does the bat hear reflected off the wall?
Answers
Answer:
40085 Hz
Explanation:
We are given; Sound frequency emmision of bat;f = 38.9 kHz = 38900 Hz
Bat is moving at 0.015 times the speed of sound in air.
Speed of sound in air = 343 m/s
The formula for waves reflected off the wall is calculated from Doppler equation as:
f' = f(v + v_d)/(v - v_s)
Where;
f is the frequency = 38900 Hz
f' is the detected frequency,
v_d is the velocity of the detector = 0.015 × 343 = 5.145
v_s is the velocity of the source = 0.015 × 343 = 5.145 m/s
v is the velocity of the sound = 343 m/s
Thus;
f' = 38900(343 + 5.145)/(343 - 5.145)
f' ≈ 40085 Hz
A ball is thrown upward from an initial height of 1.5m the ball reaches a height of 5m then falls to the ground . What Is the distance traveled by the ball?
Answers
Answer:
The distance traveled by the ball is 8.5 m
Explanation:
Initial height of the ball, h₁ = 1.5 m above the ground
final height of the ball, h₂ = 5m
Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m
Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m
Total distance traveled = upward distance + downward distance
Total distance traveled = 3.5 m + 5m = 8.5 m
Therefore, the distance traveled by the ball is 8.5 m
Determine the magnitude of the force that must be applied to a wooden block whose weight has a magnitude of 8N, so that it acquires an acceleration of 0.5 m / s²
Answers
Answer:
F = 0.408 N
Explanation:
It is given that,
Weight of a wooden block, W = 8 N
Weight, W = mg
m is mass of wooden block
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{8\ N}{9.8\ m/s^2}\\\\m=0.816\ kg[/tex]
Acceleration of the block, a = 0.5 m/s²
Force, F = ma
[tex]F=0.816\ kg\times 0.5\ m/s^2\\\\F=0.408\ N[/tex]
So, the magnitude of force applied to the wooden block is 0.408 N.
A golfer misjudges a putt and leaves her ball way short, the ball going only half of the way to the hole. If the speed of the ball leaving the putter in the first case was vo and the force of resistance due to the grass remains the same, what speed should she have given to the ball to make the original putt?
Answers
Answer:
Using
1/2mv^2 = work done by friction
work done = force x distance
lets call the force 3 N
lets call v = 3 m/s
lets call mass = 2 kg
0.5 x 2 x 3^2 = 9 J
9/3N = 3 m/s
now times 3 m/s by square root of 2 of which is 1.4142
3 x 1.4142= 4.2426 m/s
0.5 x 2 x 4.2426^2 = 18
18/2N = 9 m