Hii, Ok so basically I really need help with these questions they are really difficult and don't worry rewards are plenty a come. On the last question whoever give the right answer and is the quickest will get brainliest. But do not worry whoever answers this question will get a

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So you may be wondering what the question is well take a look oh and by the way please do not give a random answer and its a maths question

Given that angle A = 284 degrees, work out x

Answer:Measures of Exterior Angles

They are formed on the outer part, that is, the exterior of the angle.

The corresponding sum of the exterior and interior angles formed on the same side = 180°.

Step-by-step explanation: is that what u mean?

Answer:

Step-by-step explanation:

Divide the pentagon radially into 5 congruent, isosceles triangles.

Area of one triangle = ½×7.2×4.955 = 17.838 mm²

area of pentagon = 5×17.838 mm ≅ 89.2 mm²

Answer:

x = 4

Step-by-step explanation:

6(+4)=48

6+24=48

6+24=48

6+24−24=48−24

6=24

6=24

6/6=24

...

Answer:2nd i think i hope this helps ! :)

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

2 cookies + 2 cookies = 4 cookies!

The more cookies the better!

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time [tex]t[/tex]

At [tex]t=0, the weight of the bucket is 6+36=42 \mathrm{lb}[/tex]

After [tex]t[/tex] seconds, the weight of the bucket is [tex]42-0.15 t \mathrm{lb}[/tex]

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after [tex]t[/tex] seconds is [tex]x=1.5 t[/tex]

Since the well is 80 ft deep, the time to pull out the bucket is [tex]\frac{80}{2}=40 \mathrm{~s}[/tex]

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

[tex]W=\int_{t=0}^{t=36} F d x[/tex]

Use [tex]x=1.5 t[/tex] and [tex]F=42-0.15 t[/tex]

[tex]W=\int_{0}^{36}(42-0.15 t)(1.5 d t)[/tex]

[tex]=\int_{0}^{36} 63-0.225 t d t[/tex]

[tex]=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}[/tex]

[tex]=\left[63 t-0.2 t^{2}\right]_{0}^{36}[/tex]

[tex]W=3200 \mathrm{ft} \cdot \mathrm{lb}[/tex]

Answer:

Step-by-step explanation:

Given that:

[tex]\int^2_0 \int^2_x \ sin (y^2) \ dy dx \\ \\ \text{Using backward equation; we have:} \\ \\ \int^2_0\int^2_0 sin(y^2) \ dy \ dx = \int \int_o \ sin(y^2) \ dA \\ \\ where; \\ \\ D= \Big\{ (x,y) | }0 \le x \le 2, x \le y \le 2 \Big\}[/tex]

[tex]\text{Sketching this region; the alternative description of D is:} \\ D= \Big\{ (x,y) | }0 \le y \le 2, 0 \le x \le y \Big\}[/tex]

[tex]\text{Now, above equation gives room for double integral in reverse order;}[/tex]

[tex]\int^2_0 \int^2_0 \ sin (y^2) dy dx = \int \int _o \ sin (y^2) \ dA \\ \\ = \int^2_o \int^y_o \ sin (y^2) \ dx \ dy \\ \\ = \int^2_o \Big [x sin (y^2) \Big] ^{x=y}_{x=o} \ dy \\ \\= \int^2_0 ( y -0) \ sin (y^2) \ dy \\ \\ = \int^2_0 y \ sin (y^2) \ dy \\ \\ y^2 = U \\ \\ 2y \ dy = du \\ \\ = \dfrac{1}{2} \int ^2 _ 0 \ sin (U) \ du \\ \\ = - \dfrac{1}{2} \Big [cos \ U \Big]^2_o \\ \\ = - \dfrac{1}{2} \Big [cos \ (y^2) \Big]^2_o \\ \\ = - \dfrac{1}{2} cos (4) + \dfrac{1}{2} cos (0) \\ \\[/tex]

[tex]= - \dfrac{1}{2} cos (4) + \dfrac{1}{2} (1) \\ \\ = \dfrac{1}{2}\Big [1- cos (4) \Big] \\ \\ = \mathbf{0.82682}[/tex]

Answer:

Don't worry I will help to solve this problem OK.Sorry I don't understand please ask with other OK .

Step-by-step explanation:

base = 40

height = 16

Area of parallelogram = b×h = 40× 16= 640

Answer:

the area of the shaded area is 160 cm ²

Step-by-step explanation:

Hey There!

so the first step in solving this problem is to find the area of the whole shape

This is a trapezoid and the formula for area of a trapezoid is

[tex]A=\frac{a=b}{2} h[/tex]

a = base 1 (20)

b = base 2  (40)

h = height (16)

now we plug in the values

[tex]A=\frac{40+20}{2} 16\\40+20=60\\\frac{60}{2} =30\\30*16=480[/tex]

so the area of the trapezoid is 480

The next step is to find the area of the triangle

To do so we use this formula

[tex]A=\frac{hb}{2}[/tex]

h = height (16)

b = base (20)

now we just plug in the values

[tex]A=\frac{16*20}{2} \\16*20=320\\\frac{320}{2}=160\\[/tex]

The area of the triangle is 160

The mistake is in the first step. You seem to want to divide through by 7, but you only did it correctly with the x ² term. What you should have after doing this is

7x ² + 9x + 2 = 0

→   x ² + 9/7 x + 2/7 = 0

This step isn't actually necessary to begin with since the starting quadratic is easily factorized:

7x ² + 9x + 2 = (7x + 2) (x + 1) = 0

Then

7x + 2 = 0   or   x + 1 = 0

7x = -2   or   x = -1

x = -2/7   or   x = -1

Answer:

I think it's 2000

Step-by-step explanation:

Answer:

2 11/12 cups of flour

Step-by-step explanation:

2 recipes are 2 1/2 cups of flour  

1/3 is 1/3 x 1 1/4= 1/3 + 1/12= 5/12  

So, 2 11/12 cups of flour

Answer:

46.091 m

Step-by-step explanation:

Given that

Height of the range finder, = 496 feet

Angle of elevation, θ = 0.875 Rad = 50°

Velocity of increment, = 0.225 rad/min

For starters, we try and assume that it all takes place in a triangular shape. Using Pythagoras theorem, we then know that

Tanθ = y / 496

y = 496 tanθ

On differentiating, we have

dy/dt = 496 sec²θ

dy/dt = 496 * 0.413 * de/df

dy/dt = 204.848 * de/df

dy/dt = 204.848 * 0.225

dy/dt = 46.091 m

Answer:

Step-by-step explanation:

x/50 = 12/24

24x = 600

x= 25

Answer:

Im pretty sure it is 48 but it could be 96

Step-by-step explanation:

I just found the area and halved that.

Answer:

can you give us the whole sheet?

Step-by-step explanation:

Answer:

45% Of the cars are there

because it says 45% so I am pretty sure that is it

Answer:

4 7/15

Step-by-step explanation:

Hope this helps :)

1/4 / 5 is equal to 4x5, or 20.

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hope it helps

Answer:

False

Step-by-step explanation:

The circle could be circumscribed about the quadrilateral is false because the sum of the opposite angles is not 180 degrees.

It is defined as the four-sided polygon in geometry having four edges and four corners. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

As we know, the circle can be circumscribed around a quadrilateral if and only if the quadrilateral's opposite angles add up to 180 degrees.

But,

80 + 85 < 180

100 + 95 > 180

Thus, the circle could be circumscribed about the quadrilateral is false because the sum of the opposite angles is not 180 degrees.

Learn more about the quadrilateral here:

brainly.com/question/6321910

#SPJ2

Answer:

p/6 division

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

[tex]90 = 60 + 3x \\ 30 = 3x \\ x = 10[/tex]

Answer:

10

Step-by-step explanation:

Answer:

h(-3) = -27

Step-by-step explanation:

Given that,

[tex]h(x)=-2x^{(2)}+3x[/tex]

We need to find the value of h(-3).

Put x = -3 in the given expression.

[tex]h(-3)=-2(-3)^{(2)}+3(-3)\\\\=-2\times 9-9\\\\=-27[/tex]

So, the value of h(-3) is equal to -27.

Answer:

The area of Alison's pizza would be 30 in.

Answer:

rrir

Step-by-step explanation:

e8

Answer:

maybe u should have paid attention in class buddy

Step-by-step explanation:

L

Answer:

9,2 and 2,9

Step-by-step explanation:

x+y=11

xy=18

Since they are asking for integers you can simply look through and see what integers multiply out to 18 and then check if they add up to 11. The answers for x and y are 9 and 2. but 9 can be for y as well and 2 can be for x.

How to solve it algebraically

18/y=x

x+y=11(insert 18/y for x)

18/y+y=11(factor it)

(y^2+18)/y=11(multiply both sides by y)

y^2+18=11y (subtract both sides by 11y)

y^2-11y+18=0

complete the square

y^2-11y    = -18

(-11/2)^2=121/4 (add in on both sides)

y^2-11y+121/4=49/4

(y-11/2)^2=49/4 (square root both sides)

y-11/2=±7/2

y=11/2±7/2

y=9 or y=2

so

x=9 or x=2

Hope this helps :)

Please give brainliest

Answer:

132 ft³

Step-by-step explanation:

L=11    W=3   H=4

V=LWH

V=(11)(3)(4)

V=132 ft³