Answer: In the chlor alkali process, sodium hydroxide is prepared from common salt (sodium chloride). The byproducts are hydrogen gas and chlorine gas. Electrolysis of aqueous sodium chloride (brine solution) in Castner-kellner cell gives sodium hydroxide, chlorine gas and hydrogen gas.
Answer: Useful substances are obtained from common salt by the process of electrolysis
Which process occurred when the water droplets formed on the grass? Choose the correct answer. Responses deposition deposition sublimation sublimation evaporation evaporation condensation condensation Skip to navigation
Answer:
Condensation is the process that took place when the water droplets formed on the grass.
Explanation:
Condensation is the process that took place when the water droplets formed on the grass. This occurs when airborne water vapour meets a colder surface, like the grass blades in the morning, and transforms into liquid form, generating tiny water droplets on the surface.
hodah runs the sales team for a paper distributor. in order to help the sales team boost their numbers, hodah has devised a bonus system. for every new client that land, the team member recieves a $250 gift card. For every 10 pallets of paper they sell, they can take home a $100 gift card. The sales team is excited and hits their phones, attempting to pull in as many new clients and sales as possible. what kind of leadership theory would you say hodah subscribes to?
a. transactional theory
b. situational leadership theory
c. trait theory
d. contingency theory
Answer:
Based on the given scenario, Hodah's leadership style can be described as a transactional theory. This theory suggests that leaders provide rewards or punishments based on the performance of their followers. In this case, Hodah has devised a bonus system to motivate the sales team to perform better by providing them with incentives such as gift cards for every new client and pallets of paper sold. This approach focuses on providing rewards to motivate and improve performance.
You are compiling the temperature profile of a lake, which requires taking temperature readings at different depths. You collect the following data:
What depth range does the epilimnion occupy in this lake?
a. 0 to 3
b. 8 to 12
The depth range of the epilimnion in this lake is most likely a. 0 to 3 meters. Option A is correct.
To determine the depth range of the epilimnion, we need to identify the layer of the lake where the temperature change is most rapid, which indicates the transition between the warm surface layer and the colder deep layer.
Looking at the temperature readings, we can see that there is a significant temperature difference between the surface layer (0-3 meters) and the layer below (4-7 meters).
However, the temperature change between 4-7 meters and 8-12 meters is not as dramatic, indicating that the transition between the warm surface layer and the colder deep layer occurs somewhere between 3 and 8 meters.
Hence, A. 0 to 3 is the correct option.
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this diagram shows rock formations forming. which statement describes one or both formations
Answer:
c
Explanation:
formation is an igneous rock
WILL GIVE BRAINLIEST!! PLS HELP!!!
Answer:
Thermal energy is the sum of the kinetic and potential energy of all the atoms in an object or substance.
(This statement is true for ideal gases, but for solids and liquids, thermal energy also includes the energy associated with intermolecular forces.)
which factor is most sensitive to changes in temperature- x) the frequency of collisions, y) the orientation factor, or z) the fraction of molecules with energy greater than the activation energy?
The factor that is most sensitive to changes in temperature is the fraction of molecules with energy greater than the activation energy.
The statement that best represents the effect of temperature on reaction rates is called the Arrhenius equation. It is expressed as [tex]k = Ae^{-Ea/RT},[/tex]
where k is the rate constant,
A is the pre-exponential factor or frequency factor,
Ea is the activation energy,
R is the gas constant, and T is the absolute temperature.
At high temperatures, the reaction rate increases, and at low temperatures, the reaction rate decreases.
The Arrhenius equation shows that the rate constant depends on two factors:
the activation energy and the fraction of molecules with energy greater than the activation energy.
Thus, the most sensitive factor to changes in temperature is the fraction of molecules with energy greater than the activation energy.
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To earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units
A pack of 51 wolves has 15 births and 8 deaths. What is the growth rate for this wolf pack?
To calculate the growth rate of the wolf pack, we need to find the difference between the birth rate and death rate and divide that by the total wolf population. Therefore, the growth rate of the wolf pack is 0.27%.
Do deaths factor into the growth rate?The difference between births less deaths and the difference between immigrants and emigrants in a given country, territory, or geographic area at a given year is what is used to describe the annual increase in population size.
Growth rate = (birth rate - death rate) / total population
Birth rate = 15/51 = 0.294
Death rate = 8/51 = 0.157
Total population = 51
Growth rate = (0.294 - 0.157) / 51 = 0.137 / 51 = 0.0027 or 0.27%
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CHEMISTRY QUESTION, PLEASE HELP!!!
Reaction B (attached); The change in enthalpy for the forward reaction is -91kJ/mol. (Energy is a product, flowing from the chemical reaction to the surroundings. )
The forward reaction for Reaction B (attached) is.
- endothermic
- exothermic
If Reaction B (attached) was ta equilibrium and then was heated ______ CH3OH would be present after the reaction adjusts to the new temperature.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then the pressure in its container was increased, ____ CH3OH would be present after the reaction adjusts to the new pressure.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then H2 was added, _____ CH3OH would be present after the reaction adjusts.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then H2 was added, ____ CO would be present after the reaction adjusts.
- more
- less
- the same amount
The forward reaction for Reaction B is endothermic, as indicated by the negative change in enthalpy (-91 kJ/mol) for the forward reaction.
If Reaction B was at equilibrium and then was heated, the amount of CH₃OH would be less after the reaction adjusts to the new temperature. This is because the forward reaction is endothermic, meaning that an increase in temperature would shift the equilibrium towards the reactants side to counteract the increase in temperature.
If the pressure in the container of Reaction B was increased, the amount of CH₃OH would be more after the reaction adjusts to the new pressure. This is because the forward reaction produces fewer moles of gas than the reverse reaction, so increasing the pressure would shift the equilibrium towards the side with fewer moles of gas (the products side) to counteract the increase in pressure.
If H₂ was added to Reaction B at equilibrium, the amount of CH₃OH would be more after the reaction adjusts. This is because H₂ is a reactant in the reverse reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂.
If H₂ was added to Reaction B at equilibrium, the amount of CO would be less after the reaction adjusts. This is because CO is a product in the forward reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂, resulting in a decrease in CO.
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PLEASE HELP!!!
How many particles Fe2O3 will produce in an aqueous solution (in water).
Question 11 options:
2
3
4
5
Hydrolysis occurs when Fe2O3 is dissolved in water, resulting in the formation of Fe(OH)3 and H+ ions. For every Fe in Fe2O3, there are 1.5 O. Thus, the iron content of Fe2O3 is reduced.
An aqueous solution is what?Water in the liquid state serves as the solvent in an aqueous solution. In other words, water molecules surround and integrate solute (dissolved) ions and molecules into their web of bonds. Following that, the dissolved species dispersed all over the water.
Why is water referred to as an aqueous solution?Aqueous solutions are made up of water and one or more dissolved materials. Solids, gases, or other liquids can all dissolve in an aqueous solution.
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Question:
How Many Particles Fe2O3 Will Produce In An Aqueous Solution (In Water).
magnesium sulfate reacts with barium chloride according to the following balanced equation. how many moles of barium sulfate are formed from 0.0831 mol of magnesium sulfate?
Therefore, the number of moles of barium sulfate formed from 0.0831 mol of magnesium sulfate is equal to 0.0831 mol.
How does the body respond to magnesium sulphate?By possibly inhibiting calcium-mediated contraction, reducing acetylcholine release from neuromuscular junctions, and decreasing histamine-induced airway spasm, magnesium sulphate (MgSO4) can calm smooth muscles.
The balanced chemical equation for the reaction between magnesium sulfate and barium chloride is:
MgSO4 + BaCl2 → BaSO4 + MgCl2
According to the equation, one mole of magnesium sulfate (MgSO4) reacts with one mole of barium chloride (BaCl2) to produce one mole of barium sulfate (BaSO4).
So, 0.0831 mol of magnesium sulfate will produce 0.0831 mol of barium sulfate.
This is because the stoichiometric ratio of magnesium sulfate to barium sulfate is 1:1, which means that for every mole of magnesium sulfate that reacts, one mole of barium sulfate is produced.
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What volume of a 3. 00 M glucose stock solution is necessary to prepare 2500 mL of 0. 400 M solution
Answer:333.3333 mL or 333mL
Explanation:
M1V1 = M2 V2
M1= 3.00 M
V2= 2500 ml
M2= 0.400M
V1= solving for
V1= M2V2/M1
0.400 X 2500 / 3.00 =
Carbon NMR spectroscopy produces a spectrum of Choose... The number of carbon signals in the spectrum corre only carbon-13 nuclei only carbon-12 nuclei Choose.. in the mol all carbon nuclei In most carbon NMR spectra, the carbon signals appear as Choose... in a sample Carbon NMR spectroscopy produces a spectrum of Choose.. The number of carbon signals in the spectrum corresponds to the number of ✓ Choose... in the molecule. all the carbons unique carbon environments signals appear as Choose... symmetrical carbon environments in a sample Carbon NMR spectroscopy produces a spectrum of Choose... The number of carbon signals in the spectrum corresponds to the number of Choose... in the molecule. In most carbon NMR spectra, the carbon signals appear as Choose... quartet peaks doublet peaks singlet peaks Consider the structure of toluene. CHE peaks. The methyl peak will appear The carbon NMR of toluene should have v Choose... 5 Choose... the carbon 7 3 4 Consider the structure of toluene. CH3 peaks. The methyl peak will appear The carbon NMR of toluene should have Choose... Choose... the carbons of the ring. further upfield than further downfield than in a similar location as
Carbon NMR spectroscopy is a powerful analytical tool for determining the number of unique carbons present in a molecule, as well as their respective chemical environments. By analyzing the quartet, doublet, and singlet peaks, scientists can identify unique carbon environments and the associated chemical structure of the molecule.
Carbon NMR spectroscopy produces a spectrum of signals that represent the unique chemical environment of each carbon atom in a molecule. The number of carbon signals in the spectrum corresponds to the number of carbons in the molecule, meaning all carbons will be detected in the NMR spectrum. In most carbon NMR spectra, the carbon signals appear as quartet, doublet, and singlet peaks, each of which represent different types of carbon environments.
For example, consider the structure of toluene. CH3 peaks. The methyl peak will appear further upfield than the carbons of the ring. This is because the methyl group has a more electronegative environment than the ring carbons due to the three hydrogens that are attached to the carbon, resulting in a higher electron density. As a result, the methyl peak will appear further upfield than the carbons of the ring.
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Most of the volume of an atom is taken up by the ________ , and most of the mass of an atom is found in the _______.
A. Nucleus; electron clouds
B. Nucleus; nucleus
C. Electron clouds; nucleus
Most of the volume of an atom is taken up by the Electron clouds, and most of the mass of an atom is found in the nucleus.
Most of the volume of an atom is taken up by the electron clouds. This is because electrons occupy the space surrounding the nucleus in orbitals and they have a relatively large amount of space between them. The electron clouds represent the region in which electrons are likely to be found at any given time.
Most of the mass of an atom is found in the nucleus. The nucleus is made up of protons and neutrons, which have a much larger mass compared to electrons. Although the nucleus is much smaller in size compared to the electron clouds, it contains almost all of the mass of an atom.
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What mass of methane (CH4) must be burned to give 1575 kJ of energy? (891 KJ/Mol)
The mass of methane (CH4) must be burned to give 1575 kJ of energy is 28.4 g.
The first step is to determine the number of moles of methane required to produce 1575 kJ of energy. We can do this using the conversion factor provided:
891 kJ of energy is produced by 1 mole of methane (CH4)
1575 kJ of energy is produced by how many moles of methane?
1575 kJ / 891 kJ/mol = 1.77 mol
Next, we can use the molar mass of methane to convert it from moles to grams:
Molar mass of methane = 12.01 g/mol (for carbon) + 4 x 1.01 g/mol (for hydrogen) = 16.05 g/mol
Mass of methane = number of moles x molar mass
Mass of methane = 1.77 mol x 16.05 g/mol = 28.4 g
Therefore, 28.4 g of methane must be burned to produce 1575 kJ of energy.
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How much heat will be transferred when 0. 54g of sulfur reacts with 0. 54g of oxygen to produce
sulfur trioxide according to the following reaction:
2 S +3 02 +2 SO3 + 790kJ
The amount of heat transferred would be -8.85 kJ.
Heat transferTo calculate the heat transferred, we need to first determine the limiting reactant, which is the reactant that is completely consumed in the reaction. This will determine the amount of product that can be formed and hence the amount of heat released.
We start by calculating the moles of sulfur and oxygen:
Moles of sulfur = 0.54 g / 32.06 g/mol = 0.0168 mol
Moles of oxygen = 0.54 g / 31.998 g/mol = 0.0169 mol
The balanced equation shows that 2 moles of sulfur react with 3 moles of oxygen to produce 2 moles of sulfur trioxide. So, the ratio of moles of sulfur to oxygen in the reaction is 2:3. Since the ratio of moles of sulfur to oxygen in the reactants is less than 2:3, oxygen is the limiting reactant.
The amount of sulfur trioxide produced can be calculated using the mole ratio from the balanced equation:
Moles of sulfur trioxide produced = 0.0169 mol * (2 mol SO3 / 3 mol O2) = 0.0112 mol
The heat transferred in the reaction can be calculated using the heat of reaction per mole of sulfur trioxide:
Heat transferred = 0.0112 mol * (-790 kJ/mol) = -8.85 kJ
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Macmill
20.8 g 0₂ x
grams of KCIO:
122.55 g KCIO,
32.00 g 0₂
74.55 g KCI
Answer Bank
1 mole KCIO,
1 mole O₂
1 mole KCI
2 moles KCIO,
3 moles 0₂
2 moles KCI
= g KCIO,
g KCIO,
Answer:
To solve this problem, we need to use the balanced chemical equation for the reaction between oxygen gas (O₂) and potassium chloride (KCI) to form potassium chlorate (KCIO₃):
2KCI + 3O₂ → 2KCIO₃
We can use the given mass of O₂ (20.8 g) and the molar mass of O₂ (32.00 g/mol) to find the moles of O₂:
20.8 g O₂ x (1 mol O₂ / 32.00 g O₂) = 0.65 mol O₂
According to the balanced equation, 3 moles of O₂ react with 2 moles of KCI to produce 2 moles of KCIO₃. Therefore, we can use the moles of O₂ to find the moles of KCIO₃:
0.65 mol O₂ x (2 mol KCIO₃ / 3 mol O₂) = 0.43 mol KCIO₃
Finally, we can use the molar mass of KCIO₃ (122.55 g/mol) to convert moles of KCIO₃ to grams of KCIO₃:
0.43 mol KCIO₃ x (122.55 g KCIO₃ / 1 mol KCIO₃) = 52.71 g KCIO₃
Therefore, the grams of KCIO₃ that can be produced from 20.8 g O₂ is 52.71 g KCIO₃. However, the problem does not ask for the grams of KCIO₃, but instead asks for the grams of KCIO, which is not a valid compound. It is possible that there is a typo in the problem and that it should have asked for the grams of KCIO₃ instead.
Explanation:
How many chlorine atoms are there in 2 molecules of CCl^5
The number of chlorine atoms present in 2 molecules of CCl₄ is 4.82×10²⁴ atoms
How do I determine the number of chlorine atoms?We'll begin by obtaining the mole of chlorine, Cl present in 2 molecules of CCl₄. This is shown below:
1 molecule of CCl₄ contains 4 moles of Cl
Therefore,
2 molecule of CCl₄ will contain = 2 × 4 = 8 moles of Cl
Finally, we shall determine the number of chlorine atoms present in the compound. Details below:
Number of mole of Cl = 8 molesNumber of chlorine atoms =?1 mole of Cl = 6.02×10²³ atoms
Therefore,
8 moles of Cl = (8 mole × 6.02×10²³ atoms) / 1 mole
8.1 moles of Li = 4.82×10²⁴ atoms
Thus, we can conclude that the number of chlorine atoms is 4.82×10²⁴ atoms
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Complete question:
How many chlorine atoms are there in 2 molecules of CCl₄
how to calculate equilibrium concentration from initial concentration without kc with acids and bases
We can determine the equilibrium concentration when we are given the initial concentration and reaction of an acid or base. In the given reaction,
HA is an acid that dissociates in water to form its conjugate base A− and a hydronium ion H3O+.
HA(aq) + H2O(l) ⇌ A−(aq) + H3O+(aq)
For any weak acid, the dissociation constant is defined as follows:
Ka = [A−][H3O+]/[HA]
We can determine the equilibrium concentration from the above formula by using the initial concentration.
Let’s consider a weak acid HA with an initial concentration of [HA]0.
It will form [A−] and [H3O+] at equilibrium.
If the degree of dissociation of the acid is x, then the concentration of [H3O+] at equilibrium will be [H3O+] = x, and the concentration of [A−] will be [A−] = x. And the concentration of [HA] at equilibrium will be [HA] = [HA]0 − x.
So, we can write the equilibrium expression for the dissociation of HA as:
Ka = [A−][H3O+]/[HA]Ka = x * x/([HA]0 − x)
By solving the above equation, we can obtain the value of x, which is the degree of dissociation of the acid.
At equilibrium, the equilibrium concentration of HA is [HA] = [HA]0 − x. The equilibrium concentration of A− is [A−] = x. The equilibrium concentration of H3O+ is [H3O+] = x. Thus, we can determine the equilibrium concentration from the initial concentration of a weak acid or base without using the equilibrium constant Kc.
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suppose you have a cache of radium, which has a half-life of approximately 1590 years. how long would you have to wait for 1/5 of it to disappear? you would have to wait years for 1/5 of the radium to disappear.
You would have to wait approximately 3,180 years for 1/5 of the radium to disappear. This is because the half-life of radium is approximately 805.4 years.
Suppose you have a cache of radium, which has a half-life of approximately 1590 years.
To determine how long you would have to wait for 1/5 of the radium to disappear, you need to use the formula for radioactive decay:
A=A₀(1/2)^(t/T)
where:
A₀ = initial amount of radium
A = amount of radium remaining after t years
T = half-life of radium
Firstly, note that 1/5 of the radium has disappeared, meaning that you have 4/5 of the radium remaining.
Therefore, A=4/5 A₀
We want to find t, the time it takes for 1/5 of the radium to disappear. This means that we need to find the time it takes for A to be reduced to 1/5
A₀ (or 2/5 A).2/5 A₀=A₀(1/2)^(t/T)2/5=(1/2)^(t/1590)
Taking the logarithm of both sides, we get:
t/1590=log(2/5)/log(1/2)
Solving for t, we get:
t = 805.4 years
Therefore, you would have to wait approximately 805.4 years for 1/5 of the radium to disappear.
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n experimental beer's law for the copper(ii) ions in solution at 814nm was determined to be if a solution has an absorbance of 0.929, what is the concentration of the solution?
The concentration of the solution is 7.02 × 10⁻⁴ mol/L.
The Beer-Lambert law or Beer's law states that the amount of light absorbed by a solution is directly proportional to the concentration of the absorbing material in the solution, the path length, and the absorption coefficient.
According to Beer's law,
A = εcl
where A is the absorbance, ε is the molar absorptivity, c is the concentration, and l is the path length.
Let's find the concentration of the solution from the given data using Beer's law.
A = εcl
0.929 = ε × c × l
Let's find the molar absorptivity (ε) from the data given.
Experimental beer's law for copper(ii) ions in solution at 814 nm was determined to be
ε = 1.32 × 10³ mol⁻¹ L cm⁻¹
From the data given, the path length is not mentioned.
Let's consider the path length as 1 cm.
So, l = 1 cm.
0.929 = (1.32 × 10³ mol⁻¹ L cm⁻¹) × c × 1 cmc
= 0.929/1.32 × 10³ mol/L
= 7.02 × 10⁻⁴ mol/L
The concentration of the solution is 7.02 × 10⁻⁴ mol/L.
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A 750.0 mL metal bulb is filled with 42.1 g of CH4 and 3.23 g of NH3. If the amount of pressure contributed by CH4 is 111.2 atm, then what is pressure due to NH3?
If the pressure contributed by CH4 is 111.2 atm, the pressure due to NH3 would be 109.1 atm.
Pressure calculationTo solve the problem, we can use the ideal gas law equation:
PV = nRT
where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
We need to find the pressure due to NH3, so let's start by finding the number of moles of each gas:
moles of CH4 = 42.1 g / (16.04 g/mol) = 2.623 molmoles of NH3 = 3.23 g / (17.03 g/mol) = 0.190 molNow, we can use the pressure contributed by CH4 to find the total pressure:
Ptotal = PCH4 + PNH3
111.2 atm = PCH4 + PNH3
Finally, we can solve for the pressure due to NH3:
PNH3 = Ptotal - PCH4PNH3 = 111.2 atm - 0.190 mol x (0.0821 L·atm/mol·K) x (298 K) / 0.750 LPNH3 = 109.1 atmTherefore, the pressure due to NH3 is 109.1 atm.
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14) If 3 moles of methane reacts with oxygen to produce carbon dioxide and water,
what mass of water is produced?
Answer:
The balanced chemical equation for the combustion of methane (CH4) with oxygen (O2) is:
CH4 + 2O2 → CO2 + 2H2O
This equation tells us that for every mole of methane that reacts, we get 2 moles of water produced. So, for 3 moles of methane, we would get:
3 moles CH4 × (2 moles H2O / 1 mole CH4) = 6 moles H2O
Now we need to convert moles of water to mass. The molar mass of water (H2O) is 18.015 g/mol. So, the mass of water produced is:
6 moles H2O × 18.015 g/mol = 108.09 g
Therefore, if 3 moles of methane reacts with oxygen to produce carbon dioxide and water, 108.09 g of water is produced.
Explanation:
Chadwick worked to isolate the neutral particle Rutherford had proposed.
True
False
Answer: True
Explanation: Chadwick, a British physicist, worked to isolate the neutral particle that Rutherford had proposed. This particle, known as the neutron, was hypothesized by Rutherford to exist within atomic nuclei. In 1932, Chadwick successfully conducted experiments that confirmed the existence of the neutron and provided evidence for its role in nuclear structure.
Rutherford's model of the atom suggested that the nucleus contains positively charged protons and that electrons orbit around it. However, this model could not explain why the positively charged protons did not repel each other and cause the nucleus to break apart. Rutherford proposed the existence of neutral particles, later identified as neutrons, to account for the stability of the atomic nucleus.
Chadwick's work involved bombarding various elements with alpha particles and observing the resulting radiation. Through careful experimentation, he was able to demonstrate that the radiation consisted of neutrons, which had the ability to penetrate and interact with atomic nuclei without being deflected by electromagnetic forces. This discovery revolutionized our understanding of atomic structure and paved the way for further advancements in nuclear physics.
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Answer:
True
Explanation:
I answered so the person who answered first can get branliest!
How is the acidic concentration of a solution determined?
How do you know when the endpoint is reached in a titration? When does this occur?
PLEASE BE ACCURATE! THANK YOU!!:)
Answer:
A. The acidic concentration of a solution can be determined by titrating with a strong base. You calculate the number of moles of strong base required to reach the equivalence point of the titration. Then, using the mole ratio from the balanced neutralization equation, convert from moles of strong base to moles of acid. [source, Khan Academy]
B. The endpoint is reached in a titration when the indicator used changes color (i.e, pink).
Explanation:
For B, if you do it correctly, the equivalence point is eventually reached and this is signified by the change in color of the indicator in the analyte solution.
PLEASE HELP!!
Infant Tylenol contains 0.16 g of acetaminophen (C8H9NO2) in every 5 mL of medicine. What is the Molarity of Tylenol?
Question 6 options:
32 M
0.21 M
0.0002 M
0.32 M
The molarity of Tylenol is 0.21 M, rounded to two significant figures. Hence, the correct option is (B) i.e. 0.21 M.
To find the molarity of Tylenol, we need to know the number of moles of acetaminophen present in 5 mL of medicine.
First, let's calculate the molecular weight of acetaminophen:
C = 12.011 g/mol x 8 = 96.088 g/mol
H = 1.008 g/mol x 9 = 9.072 g/mol
N = 14.007 g/mol x 1 = 14.007 g/mol
O = 15.999 g/mol x 2 = 31.998 g/mol
Total molecular weight = 96.088 g/mol + 9.072 g/mol + 14.007 g/mol + 31.998 g/mol = 151.165 g/mol
Next, we can use the given mass of acetaminophen in 5 mL of medicine to calculate the number of moles:
0.16 g acetaminophen x (1 mol / 151.165 g) = 0.001058 mol
Finally, we can use the definition of molarity to calculate the molarity of Tylenol:
Molarity = moles of solute / volume of solution in liters
Since we have 0.001058 moles of acetaminophen in 5 mL of medicine, which is equivalent to 0.005 L of solution, we can calculate the molarity as:
Molarity = 0.001058 mol / 0.005 L = 0.2116 M
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A solution is made using 145. 7 g of water (MM = 18. 02 g/mol) and 120. 0 g of ethanol (MM = 46. 07 g/mol). What is the mole fraction of the water in the solution?
Mole fraction of the water in the solution made using 145.7 g of water and 120.0 g of ethanol is 0.7564 mole.
Mass of water = 145.7 g
molar mass of water = 18.02 g/mole
Number of moles = mass ÷ molar mass
= 145.7 g ÷ 18.02 g/mole
= 8.085 mole
mass of ethanol = 120 g
molar mass of ethanol = 46.07 g/mole
Number of moles = mass ÷ molar mass
= 120 g ÷ 46.07 g/mole
= 2.6047 mole
Total number of moles = moles of water + moles of ethanol
= 8.085 mole + 2.6047 mole
= 10.6897 mole
The term mole fraction is also known as molar fraction. It is defined as unit of the amount of a constituent divided by the total amount of all constituents in a mixture.
Mole fraction of water = moles of water ÷ Total number of moles
= 8.085 mole ÷ 10.6897 mole
= 0.756335
= 0.7564 mole approximately.
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Ca + 2H2O → Ca(OH)2 + H2.
How many moles of H2O are needed to exactly react with 2. 0 moles of Ca?
Answer:
The balanced chemical equation shows that 1 mole of Ca reacts with 2 moles of H2O to produce 1 mole of Ca(OH)2 and 1 mole of H2.
Therefore, to react with 2.0 moles of Ca, we need 2.0 moles of Ca x (2 moles H2O / 1 mole Ca) = 4.0 moles of H2O.
So, 4.0 moles of H2O are needed to exactly react with 2.0 moles of Ca.
HELP ME ASAP
What is the frequency of an
orange light with a wavelength of
483 nm?
? ] × 10[²]
10
c = 3.0 x 108 m/s
Hint: Watch your units!
[?
Hz
Be sure to enter both the coefficient and the exponent.
Coefficient (green)
Exponent (yellow)
Answer:
Explanation:
λν = c
Wavelength, λ (lambda), times frequency, ν (nu), equals the speed of light.
c = 3.0 x 108 m/s
===
We are given a wavelength of 483 nanometers. 1 nanometer = 1x10^-9 meter. 483nm = 4.83x10^-7 meters
---
λν = c
ν = c/λ
ν = (3.0x10^8 m/s)/(4.83x10^-7 m)
ν = 6.21x10^14 Hz (1/s)
Grain Alcohol (C2H5OH) can be produced by the fermentation of glucose. If 125g of alcohol is obtained from the fermentation of .511 kg of glucose, what is the percent yield?
In this equation, 2mg + o2 arrow 2mgo, what is the subscript of the oxygen molecule?
The subscript of the oxygen molecule in the equation 2Mg + O2 → 2MgO is 2.
This means that two oxygen molecules (O2) are involved in the reaction, and they combine with two magnesium atoms (2Mg) to form two magnesium oxide molecules (2MgO). The subscript "2" in front of MgO indicates that two MgO molecules are formed as a result of the reaction. The equation 2Mg + O2 → 2MgO represents a combustion reaction in which magnesium (Mg) reacts with oxygen (O2) to produce magnesium oxide (MgO). This is an example of an exothermic reaction, which releases energy in the form of heat and light.
learn more about exothermic reaction here:
https://brainly.com/question/579952
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