Answer:
C
Explanation:
The force the rocket exerts on the air is in the direction opposite to
the force that the air exerts on the rocket.
Newton's third law describe the forces affecting a rocket as it descends to Earth's surface because: C. The force the rocket exerts on the air is in the direction opposite to the force that the air exerts on the rocket.
Newton's Third Law of Motion states that for every action there exist an equal but opposite reaction.
This ultimately implies that, Newton's Third Law of Motion is a law that is generally based on action-reaction force pairs.
Generally, action-reaction force pairs make it possible for;
Birds to fly.Kicking a ball.Rowing a banca.Cars to move.Objects being in motion.Fishes to swim.Throwing a stone.Rockets descending to Earth's surface.Based on Newton's Third Law of Motion, the force a rocket exerts on the air is in the direction opposite to the force that the air exerts on the rocket.
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You and your friends are going on a picnic in a very small car. On your way, the car breaks down and you try to push it to get it to move but in vain. You ask your friends to help you and the car starts moving and revs up. How are you and your friends applying Newton's second law of motion here? What if the car you were traveling in was a large SUV?
Answer:
The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.
Explanation:
Newton's work on forces regarding motion can never be neglected by scientists. Sir Isaac Newton when he was alive, among several of his works he proposed the three laws guiding the forces of motion. In this question we are only going to be treating only one out of the three Newton's Law of motion and that is the second Law Of Newton's laws of motion.
The second Law Of Newton's laws of motion states that the acceleration of an object is directly proportional to the applied force and inversely proportional to the object's mass.
(1). Now, to the question: " How are you and your friends applying Newton's second law of motion here? "
The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.
According to the law, the more the Force, the more the acceleration.
(2). For the second part of the question, " What if the car you were traveling in was a large SUV?"
From the law stated above we see that the acceleration is inversely proportional to the mass, thus if the car is a large SUV, It means that more force is needed to change the car's velocity.
Answer:
When a friend joins you in pushing the small car, the net force on it increases. Therefore, it starts to move. The mass of a SUV is much greater than that of a small car. You would thus need the help of more friends to help push it.
Explanation:
Plato/Edmentum
The shortest path between two points is:
1) displacement
2) breadth
Answer:
the shortest path between two points is displacement..
Explanation:
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Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.
PLSSSSSSSS ASAP!!!!!!
If the distance and time of an object are given, and I need to find speed, I will *
1.add the distance and time
2.divide the distance and time
3.multiply the distance and time
Answer:
2. divide the distance and time
speed=distance÷time
can you help me doing an essay about actual self
Answer:
yes absolutely
Explanation:
why not
PLEASE HELP ASAP WILL MARK BRAINLIEST
Select ALL the correct answers.
Which of these factors make hydrogen fuel cells a better option than burning fossil fuels?
1.Hydrogen fuel cells have a higher energy efficiency.
2.Hydrogen fuel cells create less pollution.
3.Burning fossil fuels relies on outdated devices and technology.
4.Hydrogen is the most abundant element in the universe.
5.Hydrogen fuel cells are more expensive than fossil fuels.
Answer:
1) and 2)
Explanation:
Hydrogen fuel is very efficient. More energy is extracted from this fuel source than with conventional power technologies, according to Tobin Smith for Billion Dollar Green. Fossil fuels have a high combustion rate and are capable of releasing tremendous amount of energy.
field lines point out from all sides on a object. Some of the lines point into a second object nearby. Which statement best describes the objects? A. both objects are permanent magnets B. both objects are electromagnets C. the first object is negatively charged, and the second object is positively charged D. the first object is positively charged, and the second object is negatively charged
Answer:
The first object is positively charged, and the second object is negatively charged. (D)
Explanation:
16. True/False: Protons are exchanged between objects by induction
7. A car is moving at 50.0 mph when the driver applies brakes. Determine the distance it
covers before coming to a halt. Coefficient of static friction between the tires and surface of
the road is 0.514. Mass of the car is 1000 kg.
Answer:
The distance to come to a halt is approximately 49.53 meters
Explanation:
Thee given parameters are;
The speed of the car, v = 50 mph = 22.35 m/s
The mass of the car, m = 1000 kg
The coefficient of friction, = 0.514
The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N
The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J
The work done by the brake = Force of the brake × Distance, d, to come to halt
By conservation of energy, we have;
The work done by the brake = The initial kinetic energy of the car
∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt
The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt
∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters
The distance to come to a halt ≈ 49.53 meters.
The car will cover 49.65 m distance before stopping due to application of brake.
Given data:
The mass of car is, M = 1000 kg.
The initial speed of car is, u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s.
The coefficient of static friction is, [tex]\mu = 0.514[/tex].
The given problem can be solved using the third kinematic equation of motion. Which is,
[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)
Here, v is the final speed, v = 0 (Because car is finally stopping)
s is the distance covered before stopping and a is the magnitude of acceleration.
Now, since frictional force opposes the motion. Then,
[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]
Substituting the values in equation (1) as,
[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]
Thus, the car will cover 49.65 m distance before stopping due to application of brake.
Learn more about the Kinematic equations of motion here:
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If a substance has a density of 2.7g/cm3 and a mass of 86.4g, what is its volume?
Answer:
32cm³
Explanation:
Given parameters:
Density of substance = 2.7g/cm³
Mass of substance = 86.4g
Unknown:
Volume of substance = ?
Solution:
Density is the mass per unit volume of a substance.
Density = [tex]\frac{mass}{volume}[/tex]
Since the unknown is volume we solve for it;
mass = density x volume
86.4 = 2.7 x volume
volume = [tex]\frac{86.4}{2.7}[/tex] = 32cm³
A student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons. What is the force of the wall pushing back on the student? What is the acceleration of the student as she moves away from the wall?
Answer:
F=-100N; a=1.3m/s^2
Explanation:
Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.
The force of the wall pushing back on the student would be 100 Newtons, and the acceleration of the student as she moves away from the wall would be 1.33 m/s²
What is Newton's third law of motion?Newton's third law of motion state that for every action force there exists a complementary reaction force that balances it.
As given in the problem a student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons,
The force of the wall pushing back the student = 100 Newtons
The acceleration of the student = 100/75
=1.33 m/s²
Thus, The student would be pushed back against the wall by a force of 100 Newtons, and she would accelerate away from the wall at a rate of 1.33 m/s².
Learn more about Newton's third law of motion here, refer to the link;
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A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°. what is the horizontal component of the velocity?
Answer:
The horizontal component of the velocity is approximately 13.22 m/s
Explanation:
The velocity of the kick which the football player gives the ball = 21 m/s
The angle of the path taken by the ball = 51°
The velocity can be represented vectorially, showing the vertical and horizontal components as follows;
v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]
Where we have;
The horizontal component of the velocity = 21 × cos(51°)
The vertical component of the velocity = 21 × sin(51°)
Therefore;
The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s
The horizontal component of the velocity ≈ 13.22 m/s.
help do number 16 and 17
Answer:
16 is d and i have no idea for 17
Which of the statements below is true?
An object’s weight and mass are equal.
An object’s weight is proportional to its mass.
An object’s weight is inversely proportional to its mass.
An object’s weight is always twice its mass.
Answer:
An object’s weight is proportional to its mass.
Determine the weight of a 10.0-kg person who is running with a speed of 5.0 m/s. Enter a
numerical answer.
Answer:
weight=mass*gravity
weight=10.0*10
so weight=100N
4. Which of the following statements is correct?
A Mass and weight are different names for the same thing
B The mass of an object is different if the object is taken to the Moon
C The weight of a cer is one of the forces acting on the car.
D The weight of a chocolate beris measured in kilograms
Answer:
Explanation:
A: wrong. Mass and weight are different.
B: Wrong. The mass here and the mass on the moon are the same. The weight, which is Mass * the acceleration is equal to weight.
C: Correct.
D: Wrong. Weight is not measured in Kg. Mass is.
chemical formulawhat is the chemical formula
Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule
matter makes up all ? and ?
Calculate the TOTAL mechanical energy of pendulum is it swings from his highest point to its lowest point. Pendulum mass is 4 kg. Use your equations for gravitational potential energy and kinetic energy to determine these values based on the data given below. Total energy is the sum of gravitational potential energy and kinetic energy. In this problem, round gravity to: g = 10 m/s^2.
Answer:
its should be 2.0 and 4.5 on it
Why should you never do an exercise such as the bench press without a spotter?
Answer:
you could hurt yourself
Explanation:
Answer
You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.
Explanation:
1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?
A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 32 m.
B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 16 m/s
C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a
distance of 16 m
A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 24 m/s
E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 30 m.
1 of 14
2
3
5 6 7 8
9
Answer:
12
Explanation:
12
Two ropes are attached a wagon one horizontal to the west with a tension force of 75N and other east and at an angle of 38 degrees upward from horizontal with a lension force of 125 N Find the components of the net force on the cart Show your work
Answer:
The components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N acting east
The vertical force, [tex]F_y[/tex] ≈ 76.96 N
Explanation:
The parameters given in the question are;
The magnitude of the force on the rope acting horizontally to the west = 75 N
The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N
The angle to the horizontal of the force on the other rope east to the horizontal = 38°
Therefore, we have;
The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N
The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;
∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N
Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N
The net vertical force, ∑F[tex]_y[/tex], is given as follows;
∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N
Therefore, the components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N
The components of the net force on the cart are 23.5 Newton and 76.96 Newton.
Given the following data:
Tension force (horizontal) due west = 75 NTension force (horizontal) due east = 125 NAngle of inclination = 38°To find the components of the net force on the cart:
First of all, we would determine the horizontal component of the force acting due east.
[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]
Next, we would find the resultant horizontal forces:
[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]
Therefore, the horizontal component of the net force acts in the opposite direction due east.
Horizontal component of the net force = 23.5 Newton
For the vertical component of the net force:
[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]
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Three toy boats with the same mass were in a lake. Two boats were moving and one was stopped. Each boat got bumped by another boat, but not in the same direction. All the boats changed speed as a result of being bumped. Use the information in the diagram to answer. Which toy boat exprienced the strongest force when it was bumped ? How do you know ?
The answer is " The orange and gray toy boats experienced the strongest force because both gained the same force as they sped up the blue boat lost force so it slow down
Explanation:
Trust me I did this one for an assignment
The boat that will experience the strongest force is the boat that has the highest speed.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
[tex]F = \frac{mv}{t}[/tex]
where;
F is the force experienced by the objectv is the velocity of the objectt is the time of motionThe force experienced by the boats is directly proportional to the velocity of their motion. Since the boats have the same mass, the force experienced by each boat will depend on the speed with which the boat moves.
Thus, the boat that will experience the strongest force is the boat that has the highest speed.
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Which property describes the number of waves that move past a point each second.
A) Speed
B) Frequency
C) Period
D) Wavelength
Answer:B) Frequency
Explanation:
Answer:
B) Frequency
Explanation:
14. Trying to be on time for class, a girl moves at 1.4 m/s down a 52 m-long 7 points
hallway, 1.8 m/s down a much more crowded hallway that is 79 m long, and
the last 25 m to her class at 2.4 m/s. How long does it take her to reach her
class?
88S
Answer:
Option (2)
Explanation:
To find the time taken by the girl we will use the formula,
Time = [tex]\frac{\text{Distance traveled}}{\text{Speed}}[/tex]
Time taken by a girl who moves down 52 m long and 1.4 m per second,
[tex]t_1=\frac{52}{1.4}[/tex]
[tex]t_1[/tex] = 37.14 sec.
Time taken to move through crowded hallway,
[tex]t_2[/tex] = [tex]\frac{79}{1.8}[/tex]
[tex]t_2=43.89[/tex] sec
Time taken to cover 25 m with speed 2.4 meter per sec,
[tex]t_3=\frac{25}{2.4}[/tex]
[tex]t_3=10.42[/tex] sec
Total time taken by the girl = [tex]t_1+t_2+t_3[/tex]
= 37.14 + 43.89 + 10.42
= 91.45
≈ 91 seconds
Option (2) will be the answer.
Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and
dimes (d) Yodelin has?
Answer:
q + d = 50
25q + 10d = 980
Explanation:
The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:
q + d = 50...(1)
25q + 10d = 980...(2)
Multiplying (1) by 25
25q + 25d = 1250 ...(3)
25q + 10d = 980...(4)
subtracting (4) from (3)
15d = 270
d = 18
q = 50 - 18
= 32
The system of the equations could be
q + d = 50
25q + 10d = 980
Calculation of the equation and the number of quarters and dimes:Since Yodelin has fifty quarters and dimes. Their total value is $9.80.
So here the equations be
q + d = 50...(1)
25q + 10d = 980...(2)
Now we have to Multiplying (1) by 25
So,
25q + 25d = 1250 ...(3)
25q + 10d = 980...(4)
Now
subtracting (4) from (3)
15d = 270
d = 18
So,
q = 50 - 18
= 32
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The planet's hawks and block their near each other in the door again system the dworkin's have very advanced technology and a dork and scientist want to increase the pull of gravity between the 2 planets which proposals with the scientists make to accomplish this goal check all that aply
Answer: A,B, and E
Explanation: Just checked I got them right:)
A skydiver jumps from an airplane traveling 120. km/hr at a height of 1000. m. If his parachute must open 500. m above the ground, how long does he have for the chute to open?
Answer:
The parachute to open in 15 sec.
Explanation:
Given that,
Velocity = 120 km/hr
Height = 1000 m
If his parachute must open 500. m above the ground.
We need to calculate the time for parachute to open
Using formula of time
[tex]v=\dfrac{d}{t}[/tex]
[tex]t=\dfrac{d}{v}[/tex]
Where, d = distance
t = time
v = velocity
Put the value into the formula
[tex]t=\dfrac{500}{120\times\dfrac{5}{18}}[/tex]
[tex]t=15\ sec[/tex]
Hence, The parachute will be open in 15 sec.
Who am I answer key
Answer:
huh
Explanation:
Which information did the Glomar Challenger study in 1968?
Answer:
c
Explanation:
i took the test