how can we deducve the presence and measure the mass of a supermassivce black hole in the center of a galaxy

Answers

Answer 1

Astronomers can study how clusters of stars and gas move around the galactic center in nearby galaxies and use those movements to calculate the mass of the central black hole.

How can we calculate the black hole's mass at the galactic center?

By monitoring the star motions in the galaxy's center, Webb will calculate the black hole's mass. Astronomers will calculate the mass of that black hole using NASA's James Webb Space Telescope. The outcome may appear to be unimportant, but a black hole's mass controls how it feeds and interacts with its surroundings.

Black holes are discovered when nearby material, such as gas, is pulled by gravity into a disk around the black hole. The gas molecules in the disk of the black hole are spinning so quickly that they heat up and release X-rays. From Earth, one can observe these X-rays.

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Related Questions

a race car traveling at a constant speed of 50 m/s drives around a circular track that is 500 m in diameter. what is the magnitude of the acceleration of the car

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The magnitude of the acceleration of the car was 10m/s^2

what is magnitude?

Magnitude is defined in physics as an object's maximal size and direction. Magnitude is utilised in vector and scalar variables as a common factor. Scalar quantities, by definition, are those with only magnitude. Whereas vector quantities have both magnitude and direction.

Magnitude can be used in a variety of contexts. Some of them include

The magnitude of the earthquake

Charge magnitude on an electron

Force magnitude

The magnitude of the displacement

Gravitational force magnitude

acceleration (a)= v^2/r

v=speed

r=radius

d=diameter=500

r=d/2=500/2=250

a= 50^2/250

=10 m/s^2

Therefore the acceleration was found to be 10m/s^2

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what is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?

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The net displacement of a point on the blade's rim as a result of the deceleration is 10.0 in. or 0.254 m..

In reality, the term "deceleration" refers to an acceleration that has been reversed. We are aware that deceleration is the rate at which an object slows down and that acceleration is the pace at which an object accelerates. For instance, when we apply the brakes while driving, we are employing the benefits of deceleration to lower the speed of the car.

When we sense ourselves going forward in relation to the car while driving, we are decelerating. Deceleration in this context is a specific case of acceleration that only applies to moving things. It is hence the speed at which an object slows down.

Since acceleration must be reported as both a magnitude and a direction, it is a vector. Whenever there is one-dimensional motion.

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gigi used to do a lot of yoga, so she had great range of motion. however, she has not been able to exercise for several months and is planning on getting back into yoga. what range of motion should she expect in her first yoga class back after such a long break?

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She has probably lost some of her range of motion.So Full Range of Motion should she expect in her first yoga class back after such a long break.

Due to the distinctive design of our skeletal system, the range of motion is defined as the way our bodies move through space. especially how the bones adhere to one another at the joints. Because of each person's unique skeletal structure, every joint in the body has a defined range of motion. A joint's range of motion (ROM) refers to how far it can move actively or passively in a given direction. As opposed to passive ROM, which occurs when an external force moves the joint, active ROM occurs when muscles do so. There are active and passive joints (hip, knee, shoulder) and regions of the spine (neck). Performing yin yoga helps to dissolve adhesions in these tissues, restoring their ability to move freely. Vinyasa yoga extends your range of motion as well.

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Mars has an orbital period of 4333 earth days, find the semi major axis of it's orbit ​

Answers

Answer:372

Explanation:

On a wet road, is a higher coefficient of friction on the tires safer or a lower one and pls explain I don’t get it. I would love to make this question worth more points but someone stole all 20 points without helping me, I’m rlly exhausted please help

Answers

In plain terms, COF measures how slippery a surface is, and how much friction it generates. More friction is better, because more friction means better traction and thus a lower likelihood of slipping. A low COF means there is less friction, and thus, it is easier to fall.

Jones and Childers report coefficients of friction of about 0.7 for dry roads and 0.4 for wet roads. The tread design represents an "all weather" compromise. If you were an Indianapolis race driver, you would use "slick" racing tires with no tread. On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1 .


which layer of the atmosphere is the hottest due to the large amount of kinetic energy of it's molecules

Answers

The hottest part of the atmosphere is called the thermosphere.

This region is the hottest because UV rays cause ionization, and because solar radiation is absorbed here, temperature rises with altitude.

What are the atmospheric layers?The troposphere, stratosphere, mesosphere, and thermosphere are the four principal layers of the atmosphere. Depending on how it is defined, the atmosphere's thickness ranges from 100 to 10,000 kilometers.The troposphere is generally warm at the base and cools as it rises. At its base, the stratosphere is quite cool, but as you ascend, it becomes hotter.Ozone generation generates heat, which causes temperatures to rise from an average of -60°F (-51°C) at the tropopause to a maximum of roughly 5°F (-15°C) at the top of the stratosphere. Because of the temperature gradient with height, warmer air is found above cooler air.

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a solid disk of mass m and radius r undergoes an acceleration a. a second disk also with a mass m only accelerates at a/4 when the same torque is applied. what is the radius of the second disk?

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A solid disk of mass m and radius r undergoes an acceleration a The radius of the second disk is 4m.

The resistance of the body to acceleration (change of velocity) in the presence of a net force is also measured. The gravitational pull of an object to other bodies is also influenced by its mass.

The kilogramme serves as the mass basis unit in the SI (kg). In physics, mass is not the same as weight, despite the fact that weight is frequently measured using a spring scale as opposed to a balance scale and direct comparison with known masses to calculate mass. The lower gravity on the Moon causes an object to weigh less than it does on Earth, but it still has the same mass. Given that mass is a property of space rather than a force.

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A 5 kg block is pulled across the ground to the right by a tension force of 40 N with a frictional force of 8 N opposing the motion. What is the acceleration of the object?

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The Acceleration of the object = 6.4 m/s²

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

Frictional force opposing the motion (F₂) = 8 N

Acceleration of the object (a) = ?

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

You must use Fnet=ma

Ft-Ff=ma

40-8=5*a

a=6.4m/s^2

male lions and human sprinters can both accelerate at about 10.0 m/s2. if a typical lion weighs 170 kg and a typical sprinter weighs 75 kg, what is the difference in the force exerted by the ground during a race between these two species? (both the forward and normal forces should be calculated.)

Answers

The difference in the force exerted by the ground during a race between these two species is 259.25

What is force?

Forces are influences that can change the movement of an object. A force can change the velocity of an object with mass, i.e. accelerate it. Forces can also be described intuitively by pushing or pulling. A force has both magnitude and direction and is a vector quantity.

Force exerted by the lion:

Normal force = mg

170 = m × 9.8

m = 17.34 kg

Forward force = ma

= 17.34 × 10.0

= 173.4 N

Total force = Normal force + Forward force

Total force = 170 + 173.4

= 343.4 N

Force exerted by the man:

Normal force = mg

75 = m × 9.8

m = 7.65 kg

Forward force = ma

= 7.65 × 10.0

= 76.5 N

Total force = Normal force + Forward force

Total force = 7.65 + 76.5

= 84.15 N

The difference in the forces exerted by these species is:

343.4 N - 76.5 N = 259.25 N

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Gabriel kicks a soccer ball so that it has an initial velocity 22 meters per second, at an angle of 16 above the ground. How much time does it take for the soccer ball to reach its maximum height?

0.62s
2.24s
0.77s
2.16s

WHICH ONE???

Answers

The time taken to reach the maximum height, given that the ball has an initial velocity of 22 m/s is 0.62 s

How do I determine the time taken to reach the maximum height?

The time taken to reach the maximum height can be obtained by using the following formula:

t = uSineθ / g

Where

t is the time taken to reach the maximumu is the initial velocityθ is the angle of projectiong is the acceleration due to gravity

Now, we shall determine the time taken to reach the maximum as follow:

Initial velocity (u) = 22 m/sAngle of projection (θ) = 16 °Acceleration due to gravity (g) = 9.8 m/s²Time taken to reach the maximum height (t) = ?

t = uSineθ / g

t = (22 × Sine 16) / 9.8

t = 0.62 s

Thus, the time taken is 0.62 s

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a dockworker loading crates on a ship finds that a 29-kg crate, initially at rest on a horizontal surface, requires a 71-n horizontal force to set it in motion. however, after the crate is in motion, a horizontal force of 50 n is required to keep it moving with a constant speed. find the coefficients of static and kinetic friction between crate and floor.

Answers

The coefficients of static and kinetic friction between crate and floor are

0.25 and 0.176 respectively.

When a body is at rest and if a force is applied to move it, then it would require the force which is equal to the static friction force, if

fs is the static frictional force and the us is the static friction coefficient and Fn is the normal force

[tex]f_{s}[/tex] = us*Fn

Fn = mg

putting the appropriate values, we get

=  71/(29*9.8) = 71/284.2

= 0.2498 = 0.25

Now, similarly when body is in motion, kinetic frictional force is applied, so we can write

[tex]f_{k}[/tex] = uk*Fn

so putting the appropriate values, we get

= 50/mg = 50/284.2 = 0.1759

= 0.176

Hence the value of coefficient of static friction is 0.25 and the value of coefficient of kinetic friction is 0.176.

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how would stellar parallax observed from saturn differ from the stellar parallax we observe from earth?

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Saturn is undergoing an apparent retrograde movement period as the Earth moves closer to Saturn in its orbit and then both planets are located on the side of the Sun. Stars that are nearer to us will exhibit higher parallax, similar to how it occurs on Earth.

The star parallax of the Earth is quite modest, barely 0.03 seconds of arc. It would be difficult to see against the backdrop of stars, even with a good telescope.

The angle between the Earth's place at a single time of year and the Earth 6 months later, as determined from a nearby star, is known as the parallax angle. This angle is used by astronomers to calculate how far away that star is from Earth.

We may calculate the distance to a nearby planet using the method described before, s. Now, measuring from an observation point O, we determine the angle the planet occupies, which is. Therefore, P1P2=d, where d is the planet's diameter. As a result, we may use the parallax method to calculate the radius of a neighboring planet.

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. an object is placed 53.0 cm in front of a diverging lens. what is the focal length if the distance between object and the image is 30.0 cm?

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If there is a distance between the object and the image, the focus length is -0.021cm.

How long is the focal point?

A lens's focal length is established when it is focused at infinity. We can determine the magnification—how large individual elements will be—and the angle of view—how much of the scene will be captured—by knowing the focal length of the lens. The narrower the field of view and higher the magnification, the longer the focal length.

Distance from object to picture d= 30 cm.

object distance = 53cm

We must determine the object's distance.

u - v =d

u = 30+53

u = 83cm

We must determine the focus length.

Using the lens

1/f = 1/v -1/u

in the formula, include the value

1/f = 1/-30 -1/83

1/f = -0.021cm

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a 1621 kg car is traveling down the road at 84.6 km/h. while traveling at this rate of speed, what is the kinetic energy of this vehicle in kilojoules?

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The kinetic energy of the car in kilojoules is 447 KJ.

The kinetic energy of the car is, E = 1/2 m[tex]v^{2}[/tex]

The velocity of the car is,  v = v (1000m/3600s)

V = 23.5 m/s

The kinetic energy of the car in joules is,

E = 1/2m[tex]v^{2}[/tex]

E = 1/2 (1621)(23.5)

E = 447KJ

An object's kinetic energy is the power it draws from movement. It is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity. The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed. When slowing down from its current pace to a condition of rest, the body expends the same amount of energy. Any term in a system's Lagrangiam that has a derivative with respect to time is formally referred to as having kinetic energy.

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you are designing a symmetric double convex lens that is made of glass with index of refraction equal to 1.33 and has a focal length of 0.165 m. what curvature radius of the lens surface should you use (in m; answer a positive number)?

Answers

The curvature radius of the lens surface is 0.1089 meters.

The convex lens is a lens that converges rays of light that convey parallel to its fundamental axis (i.e. converges the incident rays toward the main axis) which is highly thick throughout the middle and skinny at the decrease and higher edges. the edges are curved outward in preference to inward.

Calculation:-

Since the double convex is symmetric in nature,

R₁ = R

R₂ = - R

Given, Refractive index (n) = 1.33

The focal length of the double convex lens (l) = 0.156

Now,

1/f = (n-1) (1/R₁ - 1/R₂)

1/f = (n-1) (1/R + 1/R)

1/f = (n-1) × (2/R)

R = 2(n-1)f

   = 2 × (1.33 - 1) × 0.165 meter

   = 0.1089 meter

Hence, the radius of curvature of the lens surface is    = 0.1089 meter

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What is the density of a liquid if a volume of 0.025 L has a mass of 0.034 Kg? Express the result in g/cm3?

Answers

Answer: density = 1.36g/cm3

Explanation: 0.025L = 25cm3 and 0.034kg = 34 grams

  Density= mass/volume

           = 34/25

           = 1.36g/cm3

                   

Answer:

Explanation:

Given:

V = 0.025 l;   or V = 25 cm³

m = 0.034 kg = 34 g

______________

ρ - ?

ρ = m / V

ρ = 34 / 25 = 1.36 g/cm³

How much energy is stored in the 180-µF capacitor of a camera flash unit charged to 300.0 V?

Answers

Energy is stored in the 180-µF capacitor of a camera flash unit charged to 300.0 V is 8.10 J.

A capacitor is a tool that stores electrical electricity in an electric-powered field by way of the distinctive feature of accumulating electric expenses on two close surfaces insulated from each other. it's miles a passive digital component with terminals.

The impact of a capacitor is called capacitance. A capacitor is an electrical component that shops capacity power. Capacitors hold wonderful and bad electricity on separate plates separated by way of an insulator. A capacitor(s) is called cap(s) for brief.

Calculation:-

energy stored in capacitor = C V^2 /2  

= 180 x 10^-6  x 300^2  / 2   = 8.10 J

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Michael Hout of Ohio can run 110.0 meter hurdles in 18.9 s at an average speed of 5.82 m/s. What makes this interesting is that he juggles three balls as he runs the distance. Suppose Hout throws a ball up and forward at twice his running speed and just catches it at the same level. At what angle, θ, must the ball be thrown? (Hint: Consider horizontal displacements for Hout and the ball.)

Answers

Answer:

60 degrees

Explanation:

The ball must  be thrown at an angle 60°.

Given parameters:

Michael Hout of Ohio can run 110.0 meter hurdles in 18.9 s at an average speed of 5.82 m/s.

Hout throws a ball up and forward at twice his running speed and just catches it at the same level.

So, Speed of the ball = 2× 5.82 m/s. = 11.62 m/s.

The angle at which the ball thrown = θ.

According to the question,

Horizontal component of speed of the ball = Speed of  Hout

⇒  11.62 cosθ = 5.82

⇒ cosθ = 0.5

⇒ θ = 60°.

Hence,  the ball must be thrown at 60° angle.

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The xylem tube which transports sap to the top of a tree can be considered as uniform cylinders if the transport of sap is entirely due to capillarity determine the diameter of the tube which will move the sap up a tree which is 25m tall.take the surface tension of sap to be 5*10^-2 s.g is 1 g is 9.8 an

Answers

The wide wood pores that link to the tree's roots allow sap to be drawn up into the maple tree when it starts to freeze. The tree is really replenishing itself with fluids at this time from its roots.

As long as the temperature is below freezing and the sap is increasing, the process continues.

How does the xylem sap of tall trees go from the roots to the top?

Water is drawn up from the roots to the top of the plant according to the cohesion-tension hypothesis of sap ascent. Water and minerals travel upward from the roots through the xylem due to a negative water potential gradient created by the evaporation of mesophyll cells in the leaves.

The water potential gets increasingly negative as you climb the tree, and these variations provide a pull or tension that causes the water to ascend the tree. The loss of water from the leaves through a process called transpiration is a crucial element in the draw of water up the tree.

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if you had something the size of a sugar cube that was made of white dwarf matter, it would weigh about as much as

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If you had a sugar cube that was made of white dwarf matter, it would weigh about as much as an elephant.

White dwarfs are the smallest type of stars in the universe, and they have a density of around 100 million times greater than that of water. This means that if you took a sugar cube that was made entirely out of white dwarf matter and put it on your kitchen counter, it would weigh about as much as an elephant!

But don't worry—you're not going to find any white dwarfs at your local grocery store or restaurant. White dwarfs are formed when red giants collapse in on themselves after burning through their fuel. And if you did happen to find one, you'd need a really big countertop.

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consider a neutron star with a mass equal to the sun, a radius of 11 km , and a rotation period of 1.0 s . what is the speed of a point on the equator of the star?express your answer with the appropriate units.

Answers

At equator line the speed of the star is 69115 m/s

When a big star runs out of heat and collapses, neutron stars are created. Every proton and electron in the star's core, or most central region, fuse into neutrons as it falls. These freshly generated neutrons can stop the collapse, leaving a neutron star behind, if the core of the collapsing star is between one and three solar masses.

Radius is 11 km

Period of rotation is 1 second

Converting radius to meters:

11 km = 11 x 10^3 = 11000m

We know that the velocity relation is v = 2πr/T

v = 2 x π x r / 1

v = 2π x 11000

v = 69115 m/s

Hence the speed of the star at the equator is 69115 m/s

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looking at your spectroscope, you see several discrete, clearly defined lines. what is one possible source for this spectrum

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Looking at your spectroscope, you see several discrete, clearly defined lines. The one possible source for this spectrum is fluorescent lamp.

What is fluorescent lamp?

A  fluorescent lamp is a low pressure mercury lamp or discharge bulb. When the light spectrum emitting from the fluorescent bulb fall on the spectroscope, it releases several discrete lines.

In this lamp, fluorescence source is used which produces visible light when it lights up.

Moreover, a fluorescent lamp alters electrical energy into chemical energy or light more efficiently than the incandescent lamp.

Simply put, fluorescent lamps are more efficient than other lamps and are mostly used for commercial and outdoor application as they use 75% less electricity.

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a hybrid electric vehicle is submerged under water. a rescue squad member consults automotive technicians for information regarding safety precautions. technician a says that there is no danger of electrical shock from touching the body of the vehicle or the frame in or out of the water. technician b says that the vehicle will detect a ground fault and open the hv relays. which technician is correct?

Answers

All lines carrying current to and from a motor are passed through the window of a specialized current transformer known as a ground fault sensor in order to detect ground fault current.

Explain about the ground fault detected?

Ground fault relays (or sensors) are used to detect ground faults with low magnitude. The control system instructs the circuit disconnect to open when the G.F. relay pick up setting is reached by the ground fault current magnitude and time.

An overvoltage relay can therefore be fitted to either directly monitor the voltage at the wye point or to detect the secondary voltage of a transformer that has been installed between the wye point and ground in order to identify the fault

No appreciable current will be created in the sensor secondary if all of the current to the motor returns through the lines in the sensor window.

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a playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.600 rev/s. what is its angular velocity (in rev/s) after a 21.0 kg child gets onto it by grabbing its outer edge? the child is initially at rest.

Answers

The value of the final angular velocity = 0.44 rev/s

How to calculate the angular velocity?

Let Initial angular momentum = [tex]L_{i}[/tex]

Let Final angular momentum = [tex]L_{f}[/tex]

Here, mass of merry go round = [tex]m_{m}[/tex] = 120 kg

radius= r = 1.8 m

initial angular velocity = [tex]w_{i} = 1.2 \pi[/tex]rad/s

mass of the child = [tex]m_{c}[/tex] = 21kg

By law of conservation of angular momentum,

[tex]L_{i}=L_{f}\\\\I_{m}w_{i}=I_{m+c} w_{f}\\\\w _{f} =\frac{I_{m}w_{i}}{I_{m+c}}[/tex]

Here, substitute  [tex]I = \frac{mr^{2} }{2}[/tex]

[tex]w _{f} =\frac{I_{m}w_{i}}{I_{m+c}}\\\\w _{f} =\frac{\frac{m_{m}{r _{m}}^{2}}{2} w_{i}}{\frac{m_{m}{r _{m}}^{2}}{2}+{m_{c}r_{c}}^{2} }\\\\w _{f}= \frac{\frac{120(1.8)^{2} }{2} *1.2\pi}{\frac{120(1.8)^{2} }{2} +21(1.8)^{2}}\\\\w _{f} = 2.8 rad/s[/tex]

The value of the final angular velocity = 2.8 rad/s

                                                                =2.8/2 π

                                                                = 0.44rev/s

What is angular velocity?The rotation rate, which refers to how quickly an object rotates or revolves in relation to another point, is measured vectorially using angular velocity. The speed at which an object rotates or revolves around an axis is known as its angular velocity. Because a point on a rotating object constantly changes direction, it is challenging to determine the direction of the angular velocity. The rotating object only has a fixed direction at its axis.

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an object of mass 10.0 kg is initially at rest. a 100 n force causes it to movehorizontally through a distance of 6.00 m along a frictionless surface. what is the changein the kinetic energy of this object?

Answers

The change in the kinetic energy of this object is 600 J, when an object of mass 10 kg is initially at rest, and 100 N force cause it move horizontally at a distance of 6 m.

Mass of the object = 10kg

Force = 100N

Distance = 6m

Change in kinetic energy of this object =Δ KE

Expression for the change in the kinetic can be given as follows:

Δ Kinetic Energy = W

,W is the workdone on the object.

This is given by the formula below,

W= F *d

Hence,

Δ KE = F × d

Δ K.E= (100N × 6m)

Δ K.E. = 600Nm

Δ K.E. = 600 Joule

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A 2.5 newton weight falls freely from rest from the roof of a building. What is the total distance the weight falls in the first 4.0 seconds?

Answers

Answer:

Explanation:

L = g·t² / 2 = 9.8·4.0² / 2 = 78.4 m

A gas receives from an external thermal source an amount of heat equal to 1000 J. This energy, in addition to producing heating in the gas, causes its expansion, with the consequent performance of work equivalent to 600 J. What was the change in the internal energy of the gas? gas?

help someone help me​

Answers

Hello..!

Subject: Thermodynamics

The first law of thermodynamics relates work and transferred heat exchanged in a system through a new thermodynamic variable, internal energy. This energy is neither created nor destroyed, only transformed.

We can think of gas as a thermodynamic system, all because gases can work and absorb heat, and then they can turn all that into energy.

The formula for the change in energy is given by the first law of thermodynamics expressed as:

[tex] \: \: \: \: \: \: \: \: \: \: {\boxed{\boxed{ \sf\large \rm \Delta U = Q - W }}}[/tex]

Being:

ΔU = change in energyQ = added heatW = Work done

Problem:

A gas receives from an external thermal source an amount of heat equal to 1000 J. This energy, in addition to producing heating in the gas, causes its expansion, with consequent performance of work equivalent to 600 J. What was the change in the internal energy of the gas? gas?

Data:

ΔU = ¿? (Meet)Q = 1000 JW = 600 J

Now adding the data in the formula to find the energy change:

[tex] \sf\large \rm \Delta U = 1000J - 600J[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{\boxed{\boxed{\large \rm \Delta U = 400 J}}}[/tex]

[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

what kind of motion is a uniform circular motion? does the body have an acceleration in a uniform circular motion?

Answers

A uniform circular motion is one in which the velocity of the object remains constant. This means that the object is moving with a constant speed and in a circle, without acceleration.

In this type of motion, the acceleration is zero. Acceleration is defined as a vector quantity, which means that it has both magnitude and direction. In this case, both magnitude and direction are zero, so there is no acceleration—the body moves in a straight line at constant speed in a circle.

A body has an acceleration when it is changing its velocity, either increasing or decreasing it. An example would be stopping on a highway, where your foot would push down harder on the gas pedal to increase your speed while going around a curve, then slowing down as you straightened out again.

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A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.

Answers

40.47 m/s is the speed at which the arrow departs the bow.

Does velocity not depend on gravity?

An object's horizontal velocity is constant for small displacements and operates independently of the vertical force of gravity. The horizontal and vertical halves of an object that is projected at an angle to gravity can also be separated. The force of gravity has no impact on the horizontal velocity component either.

The arrow will start moving and accelerating as soon as it is let go from the bow. The arrow obeys the second law of motion, according to Newton. The method

m = mass of the arrow (kg) = 0.0850 kg

a = acceleration of the arrow (m/s²)

F = force (N) = 89.0 N

F=m*a

a = 1,047.059 m/s²

When an object accelerates, it will travel in a non-uniform manner. The method

[tex]v^{2} = v_{0} ^{2} +2*a*d[/tex]

= 40.47 m/s

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Where do you predict the energy that is not transferred into the electrical grid is lost as it moves from
system to system?

Answers

The energy that is not transferred into the electrical grid is lost as heat as it moves from system to system.

The electricity that is produced in power stations reach the consumers through a complex system of electric cables and grid. The grid usually means transformers which is used to step up and step down the voltage when necessary.

The first transformer from the power plant steps up the voltage of the current for the purpose of long distance transmissions. Before entering the household another transformer steps down the voltage to avoid short circuiting the electrical appliances. During all these processes the current is carried through electrical lines. Due to its contact with the atmosphere some energy is lost has heat in the air.

Therefore, the energy that is not transferred into the electrical grid is lost as heat as it moves from system to system.

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