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corresponding alternate angle for B is V
Related Questions
Calculate than round to the nearest 2 decimal places. Is it possible to get his GPA up to a 3.0 by graduation?
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The overall GPA is calculated by dividing the total grade points by the number of credit hours attended. Therefore, we need to calculate the total sum of the grade points by multiplying the GPA by the total number of credit hours:
For the 105 credit hours we have:
[tex]\begin{gathered} g_1=(2.78)(105) \\ g_1=291.9 \end{gathered}[/tex]Now we calculate the grade points for the last semester:
[tex]\begin{gathered} g_2=(4)(15) \\ g_2=60 \end{gathered}[/tex]Now we add both grades to get the total number of grade points:
[tex]\begin{gathered} g=291.9+60 \\ g=351.9 \end{gathered}[/tex]Now we divide the total grade points by the total number of credit hours:
[tex]\begin{gathered} \text{GPA}=\frac{351.9}{105+15} \\ \text{GPA}=\frac{351.9}{120} \\ \text{GPA}=2.9 \end{gathered}[/tex]Therefore, the overall GPA is 2.9.
It is impossible to get a 3.0 GPA because the maximum possible GPA is 4.0 and that is what we use in the calculation
Solve the right triangle.a=63.63 mi, b= 43.59 mi, C= 45.4 degrees
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To solve this question we will use the cosine rule
[tex]c=\sqrt{a^2+b^2-2abcosC}[/tex]Since a = 63.63 mi
Since b = 43.59 mi
Since C = 45.4 degrees
Substitute them in the rule above to find c
[tex]\begin{gathered} c=\sqrt{63.63^2+43.59^2-2(63.63)(43.59)cos(45.5^{\circ})} \\ c=45.54160285 \end{gathered}[/tex]Round it to 2 decimal places
c = 45.54 mi
The answer is A, c = 45.54 mi
A bee can pull 300 times its weight. If a person could pull a load in this same proportion, how many pounds could you pull? i weigh 120 pounds
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Each of the 7 cats in a pet store was weighed. Here are their weights (in pounds).13 , 15 , 9, 9, 9, 14, 10Find the mean and median weights of these cats.If necessary, round your answers to the nearest tenth.
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The median weight is the value that divide the sample of wights into a higer half and a lower half.
To find the median wight, first we must put the weights in crescent order:
9, 9, 9, 10, 13, 14, 15
Then, we can check that 10 pounds is the median weight, since there is three lower weights on its left {9,9,9} and three higer weights on its right {13, 14, 15}
Finally, the mean is caculated by the sum of the weights of each cat divided by the total number of cats:
[tex]\frac{13+15+9+9+9+14+10}{7}=\frac{79}{7}\approx11.3\text{ pounds}[/tex]Posted 11:55 AM Substitute and solve 3 for x and 7 for y 4y+ 2x - 7+14=?? Your answer
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Given:
4y + 2x - 7 + 14
To solve, substitute x for 3 and y for 7:
4(7) + 2(3) - 7 + 14
= 28 + 6 - 7 + 14
= 34 - 7 + 14
= 27 + 14
= 41
ANSWER:
41
I need help answering this questionThird part: What is the range of the function?
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From the graph we can see that the value of y when x is less than 0 is y = 0. Also we can see that the value of y when x is bigger than 0 is y = 2
The thing we need to look at now is the circles in x = 0. The filled circle is in y = 0, which implies y = 0 for x less or equal than 0.
Thus the answer is:
Option B:
[tex]f(x)=\begin{cases}0,\text{ if }x\le0 \\ 2,\text{ if }x>0\end{cases}[/tex]Please check the solution I gave in the Answer Tab. Do you understand what I did?
Second part of the question:
Since the function is defined for all values of x, the domain are all real numbers. In interval notation,
Option B:
[tex]\text{The domain is }(-\infty,\infty)\text{.}[/tex]Third part of the question:
The range are all the values of y that the function takes. Since the function has only 2 values of y: 0 and 2, the range is:
[tex]\text{The range is }\mleft\lbrace0,2\mright\rbrace[/tex]1. Carly interview students to ask favorite kind of television programs 12 students claimed they preferred comedies,18 liked drama, 13 enjoyed documentaries and 7 voted for news program What is the percentage of the student that selected comedies?2.Bob's Biker Shop is having a storewide sale and is offering 20% discount on all items! If the original price is in helmet for $75, how much will it cost after the discount?
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Given data:
The numbers of student like comedies are c=12.
The numbers of student like drama are d=18.
The numbers of student like documentaries are D=13.
The numbers of student like new program are n=7.
The expression for the perecentage of the students who like comedies is,
[tex]p=\frac{c}{c+d+D+n}\times100[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} p=\frac{12}{(12+18+13+7)}\times100 \\ =24\text{ percentage} \end{gathered}[/tex]Thus, the perecentage of the students who like comedies is 24%.
This one is different than the other one so I’m confused it’s geometry
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Solution:
According to the information given in the problem, we get the following equation:
[tex]\frac{ER}{30}=\frac{13}{65}[/tex]By cross-multiplication, we get:
[tex](ER)(65)=(13)(30)[/tex]this is equivalent to:
[tex](ER)(65)=390[/tex]solving for ER, we get:
[tex]ER\text{ =}\frac{390}{65}=6[/tex]so that, we can conclude that the correct answer is:
[tex]6[/tex]Ifarighttriangle hastwolegs oflength9and12,andahypotenuse oflength15,findthelength of the two legs of a similar triangle with hypotenuse 25
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Since we want to specify the length of the sides of a triangle from the known lengths of another triangle that is similar to the first one, we can express the ratios of their sides like this:
[tex]\frac{hypotenuse2}{hypotenuse1}=\frac{a2}{a1}=\frac{b2}{b1}[/tex]Where 1 means triangle 1, 2 means triangle 2, a is the first leg and b is the other leg.
Replacing the values that we know from the triangle one we get:
[tex]\begin{gathered} \frac{hypotenuse2}{hypotenuse1}=\frac{a2}{a1}=\frac{b2}{b1} \\ \frac{25}{15}=\frac{a2}{9}=\frac{b2}{12} \end{gathered}[/tex]Now, let's find the length of the second triangle with the first two ratios, like this:
[tex]\begin{gathered} \frac{25}{15}=\frac{a2}{9} \\ \frac{25}{15}\times9=\frac{a2}{9}\times9 \\ \frac{25}{15}\times9=a2 \\ a2=\frac{25}{15}\times9=\frac{5}{3}\times9=15 \end{gathered}[/tex]And for the second length of the second triangle we can use the first and the last ratio, like this:
[tex]\begin{gathered} \frac{25}{15}=\frac{b2}{12} \\ \frac{25}{15}\times12=\frac{b2}{12}\times12 \\ b2=\frac{25}{15}\times12=\frac{5}{3}\times12=20 \end{gathered}[/tex]Then the second triangle has two legs of length 15 and 20
This is a bit hard and I’ve tried multiple times and still don’t get itA. F(1)B. F(-4)
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Answer:
a) f(1) = 2
b) f(-4) = -13
Explanation:
Given the below function;
[tex]f(x)=-x^2_{}+3[/tex]a) To determine the value of f(1), we have to substitute x with 1 in the function and perform the indicated operations as seen below;
[tex]f(1)=-(1)^2+3=-1+3=2[/tex]b) To determine the value of f(-4), we have to substitute x with -4 in the function and perform the indicated operations as seen below;
[tex]f(-4)=-(-4)^2+3=-16+3=-13[/tex]Consider the equation: x2 + 10x + 9 = 0 = E and A) First, use the "completing the square" process to write this equation in the form (x + D)? enter your results below. x2 + 10x + 9 = 0 is equivalent to: Preview left side of eqn: B) Solve your equation and enter your answers below as a list of numbers, separated with a comma where necessary. Answer(s):
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Answer:
-1, -9
Explanation:
Given the expression;
[tex]x^2+10x+9=0[/tex]To apply the completing the square method;
First, subtract 9 from both sides
[tex]\begin{gathered} x^2+10x+9-9=0-9 \\ x^2+10x=-9 \end{gathered}[/tex]Complete the square by adding the half of the square of the coefficient of x to both sides of the expression as shown;
[tex]\begin{gathered} x^2+10x+(\frac{10}{2})^2=-9+(\frac{10}{2})^2 \\ x^2+10x+(5)^2=-9+(5)^2 \\ (x+5)^2=-9+25 \\ (x+5)^2=16 \end{gathered}[/tex]Next is to find the values of x by squaring both sides of the expression;
[tex]\begin{gathered} \sqrt[]{(x+5)^2}=\pm\sqrt[]{16} \\ x_{}+5=\pm4 \\ x+5\text{ = 4 and x+5=-4} \\ x\text{ = 4-5 and x = -4-5} \\ x\text{ = -1 and x =-9} \end{gathered}[/tex]Hence the values of x are -1 and -9
The graph shows the outside temperature over a 24-hour period.Which statement about the graph is the true?a. The temperature decreases at a slower rate during the first 6 hours after reaching its maximum than it does during the next 6 hours. b. The temperature increases at a constant rate from the beginning of the 24-hour period until it reaches its maximum. c. The temperature increases at varying rates form the beginning of the 24-hour period until it reaches its maximum
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By analyzing the graph, we can see that the line represents the relationship between temperature and time.
The red part represents the temperature increasing, note that since it is not a straight line, this means that the temperature is increasing at varying rates in this yellow part. Then it reaches its maximum at the red part. And in the green part of the line, the temperature decreases.
Thus, the statement that is true about the graph is C.
Enter the equation of the circle with the given center and radius. Center: (0,5); radius: 8 The equation of the circle is
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The general equation of a circle is
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{ Where} \\ (h,k)\text{ are the coordinates of the center and} \\ r\text{ is the radius of the circle} \end{gathered}[/tex]So, in this case, you have
[tex]\begin{gathered} (h,k)=(0,5) \\ \text{ Then} \\ h=0 \\ k=5 \\ \text{ and} \\ r=8 \end{gathered}[/tex]Then,
[tex](x-0)^2+(y-5)^2=8^2[/tex]Therefore, the equation of the circle is
[tex]x^2+\mleft(y-5\mright)^2=64[/tex]Using the given system of equations, what variable will you eliminate and why?3x + y = 43x + 4y = 6
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Given the system of equations,
[tex]\begin{cases}3x+y=4 \\ 3x+4y=6\end{cases}[/tex]To use the elimination method, the better option is to eliminate the x variable, since the coefficient that accompanies x in both equations is the same. Then, subtracting the first equation from the second one,
[tex]\begin{gathered} (3x+4y)-(3x+y)=6-4 \\ \Rightarrow4y-y=2 \\ \Rightarrow3y=2 \\ \Rightarrow y=\frac{2}{3} \end{gathered}[/tex]Then, we can use the value of y to find x, as shown below
[tex]\begin{gathered} y=\frac{2}{3} \\ \Rightarrow3x+\frac{2}{3}=4 \\ \Rightarrow3x=\frac{10}{3} \\ \Rightarrow x=\frac{10}{9} \end{gathered}[/tex]The better option is to eliminate x first because its coefficient is the same (3) in both equations.
Kirk had a goal of running three miles more than Laura. He ends up only running half of his goal Express the number of miles that Kirk ran in terms of m. PARTYTETTOYA
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1/2 (m + 3)
Explanation:
let the number of miles Laura ran = m
Kirk goal of running three miles more than Laura:
Kirk goal = m + 3
He ends up only running half of his goal:
half of his goal = 1/2 (m + 3)
The number of miles that Kirk ran in terms of m = 1/2 (m + 3)
Jeremiah has $1,000 in a savings account that earns 10% interest, compounded annually.To the nearest cent, how much will he have in 4 years?$
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Given data:
The given initial amount is P=$1,000.
The given rate of interest is r=10%.
The given time is t=4 years.
The expression for the final amount after 4 years is,
[tex]A=P(1+\frac{r}{100})^t[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} A=(1000)(1+\frac{10}{100})^4 \\ =1000(1.1)^4 \\ =1464.10 \end{gathered}[/tex]Thus, the final amount after 4 years is $1464.10.
kids can pat starfish at the starfish exhibit everyday at 11:00a.m in the morning. The patting session will last for one and a half past hours.when is the patting session done?
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The sesion start at 11:00 am and it last 1 and a halve hour so it ends at:
12:30 pm
Do (1,4) and (4,1) represent the same point on the coordinate plane? Explan.
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Given:
[tex]\begin{gathered} (1,4) \\ \text{and} \\ (4,1) \end{gathered}[/tex]For point (1,4) then value is x=1 and y=4
for second point is (4,1) so x= 4 and y=1
both point in coordinates is:
Find the area of the shaded portion. Show all work for full credit.6120
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thepriceof a microwaveoven was marked downfrom $187.50 to $150.00what was the percentdecrease in price.
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Let us get the difference in the price of the microwave oven
[tex]\begin{gathered} price\text{ difference=\$187.50-\$150.00} \\ \text{price difference=\$37.50} \end{gathered}[/tex]Let us get the percentage decrease in price
[tex]\begin{gathered} \frac{\text{price difference}}{Actual\text{ price}}\times100\text{ \%} \\ \\ \text{where Actual price=\$187.50} \end{gathered}[/tex][tex]\begin{gathered} \text{ }\frac{\text{\$37.50}}{\text{ \$187.50}}\times100\text{ \%} \\ =\frac{3750\text{ \%}}{187.50}=20\text{ \%} \end{gathered}[/tex]Hence, the percentage decrease is 20%.
Triangle ABC is shown:What statement must be true?cos(A) = sin(A)cos(A) = sin(B)cos(A) = cos(B)sin(A) = sin(B)
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The statement that must be true is;
[tex]\cos \text{ A = sin B}[/tex]Here, we want to select the correct option
The triangle we can see is a right-angled triangle
That means the two angles are complementary
When two angles are complementary, they add up to be 90
Thus, we have it that;
[tex]A\text{ + B = 90}[/tex]Now, let us consider the options.
a) The sine of an angle is not the same value as its cos, except if the angle is 45 degrees. Since we cannot ascertain that the angles are 45 degrees in value, then the statement must not be true
b) cos A = sin B
This is possible
This is because, the sine of an angle is equal to the cosine of its complement and also; the cosine of an angle is equal to the sine of its complement
We have this as;
[tex]\begin{gathered} A\text{ + B = 90} \\ A\text{ = 90-B} \\ \sin \text{ A = cos (90-A)} \\ 90-A\text{ = B} \\ \sin \text{ A = cos B} \end{gathered}[/tex]The last two cases are only true if A = B which means the angle is 45. Since we cannot confirm this, then we can say that only the second statement is a possibility
A car dealership requires an initial deposit of $1,000 and a monthly payment of around $600 for a new car purchase. This is represented by the equation C=600m+1000, where C represents the total cost and m represents the monthly payment. If the dealership runs a sale stating that you can purchase a new car with no money down, how should the linear equation be changed to represent the new monthly payment amount? Responses .
A .Change the slope to 0.
B. Change the y-intercept to zero.
C. Change the x-intercept to 0.
D. Change the cost to 0.
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The linear equation would change to represent the new monthly payment account, in such a way that you would: B. Change the y-intercept to zero.
What is the Linear Equation?The linear equation is usually used to represents scenarios using the initial value which is also called the y-intercept, and the unit rate which is also referred to as the slope of the line.
The linear equation is given and expressed as:
y = mx + b, here, b is the y-intercept or the initial value, while m is the slope of the line.
Given the equation, C = 600m + 1000, where:
C = total cost
m = number of months
600 = monthly payment
1,000 = initial deposit (this is the y-intercept)
Thus, if no money down is required anymore, it means the y-intercept, which is the initial deposit would be removed or be equal to 0. Thus, the linear equation would now be C = 600m + 0, which is C = 600m.
Therefore, the answer is, B. Change the y-intercept to zero.
Learn more about the linear equation on:
https://brainly.com/question/26260688
#SPJ1
laws of exponent - divisionsimplifyx³—x⁴
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Given the expression:
[tex]\frac{x^3}{x^4}[/tex]Applying the law in dividing exponents, we get:
[tex]\frac{x^3}{x^4}=x^{3-4}=x^{-1}[/tex][tex]x^{-1}\text{ = }\frac{1}{x}[/tex]Therefore, the expression, when simplified, is equal to 1/x.
At the local college, a study found that students earned an average of 14.4 credit hours per semester. A sample of 117 students was taken. What is the best point estimate for the average number of credit hours per semester for all students at the local college?
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By the Central Limit Theorem, the best point estimate for the average number of credit hours per semester for all students at the local college is 14.8.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of the sample:
14.8 credit hours per semester.
So
By the Central Limit Theorem, the best point estimate for the average number of credit hours per semester for all students at the local college is 14.8.
3x + y = 6i need a graph to the linear equation and labled points corresponding
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To make a graph of this linear equation, the best way to find the coordinates is when x = 0 and y = 0.
1st coordinates, when x = 0
[tex]3\text{x+ y =6}[/tex][tex]3(0)\text{ + y = 6}[/tex][tex]y\text{ = 6 }[/tex]1st coordinates: (0,6)
2nd coordinates, when y = 0
[tex]3\text{x + 0 = 6}[/tex][tex]3\text{x = 6}[/tex][tex]\text{ x = 2}[/tex]2nd coordinates: (2,0)
Let's now plot the graph using (0.6) and (2,0),
$8000 accumulating to $11672.12 compounded quarterly for 8 years
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The formula for compounded interest is;
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where;
A = Final amount
P = Principal
r = rate
n = number of times the interest is compounded per time
t = time
Making r the subject of formula we have;
[tex]undefined[/tex]the Diameter of the Circle measure: 28 ftwhat is the Circumference of the Circle?use 3.14 for pie do Not round
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Solution:
Given the circle with diameter AB as shown below
The circumference of the circle is expressed as
[tex]\begin{gathered} \text{Circumference = 2}\times\pi\times r\text{ ----- equation 1} \\ \text{where} \\ r\text{ is the radius of the circle.} \\ \text{The radius of the circle is } \\ r=\frac{\text{diameter of the circle}}{2} \\ \Rightarrow diameter\text{ =2r} \end{gathered}[/tex]Thus, equation 1 becomes
[tex]\begin{gathered} \text{Circumference = }\pi\times\text{ diameter of the circle ---- equation 2} \\ (\sin ce\text{ diameter = 2}\times r) \end{gathered}[/tex]Given that the diameter AB of the circle is 28 ft, the circumference of the circle will be evaluated as
[tex]\begin{gathered} \text{Circumference = }\pi\times\text{ diameter of the circle} \\ =3.14\times28 \\ \text{Circumference =}87.92\text{ ft} \end{gathered}[/tex]Hence, the circumference of the circle is 87.92 ft.
Select all the correct locations on the graph.Select the section(s) of the graph where the function is decreasing.
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A function is decreasing if its slope is negative or the curve/line is leaning to the left. Based on the graph of the piecewise function, the sections of the graph in which the function is decreasing are labeled below:
We have three sections that are decreasing. These are the blue, red, and green sections as pointed out in the picture above.
One woman won $1 million from the lottery. Years later she won $1million again. In the first game she beat the odds of 1 in 5.2 million to win. In the second she beat odds of 1 in 805,600.
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Given that:
Amount win from the scratch-off game = $1 million
The individual beat odds of 1 in 6.2 million to win in the first game and in the second game, the individual beat odds of 1 in 805600.
Let A and B denote the events "Won in first game" and "Won in the second game".
Then, find P(A) and P(B)5
[tex]\begin{gathered} P(A)=\frac{1}{5.2\text{ Million}} \\ =\frac{1}{5.2\times10^6} \\ =1.92\times10^{-7} \end{gathered}[/tex][tex]\begin{gathered} P(B)=\frac{1}{805600} \\ =1.24\times10^{-6} \end{gathered}[/tex](a) P(Indiviual win in both games)
[tex]\begin{gathered} =P(A)\times P(B) \\ =1.92\times10^{-7}\times1.24\times10^{-6} \\ =2.381\times10^{-13} \end{gathered}[/tex](b) P(Individual win twice in the second game)
[tex]\begin{gathered} =P(B)\times P(B) \\ =1.24\times10^{-6}\times1.24\times10^{-6} \\ =1.54\times10^{-12} \end{gathered}[/tex]6(5 – 8v) + 12 = -54V =
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The given formula is,
[tex]6(5-8v)+12=-54[/tex]Thus,
[tex]\begin{gathered} 6\times5-(6\times8v)+12=-54 \\ 30-48v+12=-54 \\ 30+12+54=48v \\ 96=48v \\ v=\frac{96}{48}=2 \end{gathered}[/tex]The answer is v=2.