Answer:
[tex]\displaystyle x = \frac{\pi}{3} +k\, \pi[/tex] or [tex]\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi[/tex], where [tex]k[/tex] is an integer.
There are three such angles between [tex]0[/tex] and [tex]2\pi[/tex]: [tex]\displaystyle \frac{\pi}{3}[/tex], [tex]\displaystyle \frac{2\, \pi}{3}[/tex], and [tex]\displaystyle \frac{4\,\pi}{3}[/tex].
Step-by-step explanation:
By the double angle identity of sines:
[tex]\sin(2\, x) = 2\, \sin x \cdot \cos x[/tex].
Rewrite the original equation with this identity:
[tex]2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0[/tex].
Note, that [tex]2\, (2\, \sin x \cdot \cos x)[/tex] and [tex](-2\, \sin x)[/tex] share the common factor [tex](2\, \sin x)[/tex]. On the other hand, [tex]2\sqrt{3}\, \cos x[/tex] and [tex](-\sqrt{3})[/tex] share the common factor [tex]\sqrt[3}[/tex]. Combine these terms pairwise using the two common factors:
[tex](2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0[/tex].
Note the new common factor [tex](2\, \cos x - 1)[/tex]. Therefore:
[tex]\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0[/tex].
This equation holds as long as either [tex]\left(2\, \sin x + \sqrt{3}\right)[/tex] or [tex](2\, \cos x - 1)[/tex] is zero. Let [tex]k[/tex] be an integer. Accordingly:
[tex]\displaystyle \sin x = -\frac{\sqrt{3}}{2}[/tex], which corresponds to [tex]\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi[/tex] and [tex]\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi[/tex].[tex]\displaystyle \cos x = \frac{1}{2}[/tex], which corresponds to [tex]\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi[/tex] and [tex]\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi[/tex].Any [tex]x[/tex] that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:
[tex]\displaystyle x = \frac{\pi}{3} + k \, \pi[/tex] (from [tex]\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi[/tex] and [tex]\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi[/tex], combined,) as well as[tex]\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi[/tex].Find the median, mean and mode of : 0,2,2,4,4,6,6,6,6 pls show working
Answer:
Step-by-step explanation:
The median is 4, which is the middle number. If there is no middle number, get the average of the two numbers closest to the median.
The mean is 4, which is the average of all the numbers. you add all of them up and divide by how many integers there are in the list.
The mode is 6, which is the integer that is shown the most.
Answer:
mean=4
median=4
mode=6
Step-by-step explanation:
Mean: add 0+2+2+4+4+6+6+6+6=36
36/ (the amount of numbers) 9= 4
Median: cross out the numbers left to right until you get to the middle which is 4.
Mode: 6 occurred four times, which is the most out of any of the other numbers in this sequence, so the answer is 6.
In how many ways can you arrange 4 different colored balls? 4,8,4!,3!,5!
Answer:
We can arrange 4 different colored balls in 24 ways.
Step-by-step explanation:
We have to find the number of ways in which we can arrange 4 different colored balls.
Firstly, we have to decide that either we use Permutation or we use Combination.
A Permutation is used when the order of arranging the numbers matters while on the other hand, a combination is used when the order of arranging the numbers doesn't matter.
So, in our question; the ordering matters to us as a ball which is placed in the first place can't be put again put in other places.
Number of ways of arranging 4 different colored balls = [tex]^{4}P_4[/tex]
= [tex]\frac{4!}{(4-4)!}[/tex] {[tex]\because ^{n} P_r = \frac{n!}{(n-r)!}[/tex] }
= 4! = [tex]4 \times 3 \times 2\times 1[/tex]
= 24 ways
Hence, we can arrange 4 different colored balls in 24 ways.
What is the midpoint of the segment shown below? (3, 7) (2, -1)
Answer:
( 2.5 , 3 )Step-by-step explanation:
Let the points be A and B
A ( 3 , 7 ) --------> (x1 , y1 )
B ( 2 , -1 ) --------> ( x2 , y2 )
Finding the midpoint:
[tex]( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )[/tex]
[tex] = ( \frac{3 + 2}{2} , \: \frac{7 + ( - 1)}{2} )[/tex]
[tex] = ( \frac{5}{2} , \: \frac{7 - 1}{2} )[/tex]
[tex] = ( \frac{5}{2} ,\: \frac{6}{2} )[/tex]
[tex] = (2.5 ,\: 3)[/tex]
Hope this helps...
Good luck on your assignment ....
Answer:
(2,-1)
Step-by-step explanation:
Welol to find the line of (3,7) and (2,-1) we need to use the following formula,
[tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
So -1 is y2 7 is y1 so -1 - 7 = -8
2-3 = -1
Hence, the slope of the line is 8.
And graphing more points on the graph using the slope we can see the y intercept is -17.
So the equation is y = 8x - 17
And the mid point is at (2, -1)
Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3 x = negative 1 x = 1 x = negative 1 and x = 1 x = 0, x = negative 1, and x = 1
Answer:
x = 1
Step-by-step explanation:
Using the rules of logarithms
log [tex]x^{n}[/tex] ⇔ n log x
[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
3[tex]log_{2}[/tex] (2x) = 3
[tex]log_{2}[/tex] (2x)³ = 3
(2x)³ = 2³
8x³ = 8 ( divide both sides by 8 )
x³ = 1 ( take the cube root of both sides )
x = 1
Answer:
x=1 is the correct answer
Step-by-step explanation:
got it right on edge!!!!
For each function, state the vertex and whether the function has a maximum or minimum value. Explain how you decided? f(x) = -(x + 1)^2 + 6
Answer:
maximum value at (- 1, 6 )
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
• If a > 0 then minimum value
• If a < 0 then maximum value
y = - (x + 1)² + 6
with (h, k) = (- 1, 6 ) and a = - 1
Thus vertex = (- 1, 6 ) and is a maximum
A climbing structure needs to be built in the shape of a square-based pyramid. Look at the diagram below. What is the perimeter of the flat, orange shape? PLEASE HELP A GIRL OUT
Answer:
40 m
Step-by-step explanation:
The perimeter of the flat, orange shape is the sum of all the sides that forms a boundary around the shape.
The shape is made up of 4 triangles having 2 equal side lengths each, which surrounds the center square.
Each side length of the triangle, that forms a boundary round the shape = 5 m.
There are 8 of this equal side length.
Perimeter = 8(5m) = 40 m
Determine the solution to the following set of linear equations by using the graph below
a) 2x + y = 5
2x - 2y = 2
Answer:
(2,1)
Step-by-step explanation:
Well first we single out y or x in one of the equations,
we’ll use 2x + y = 5 and single out y.
2x + y = 5
-2x to both sides
y = -2x + 5
So we can plug in -2x + 5 into y in 2x - 2y = 2.
2x - 2(-2x + 5) = 2
2x + 4x - 10 = 2
combine like terms,
6x - 10 = 2
Communicarice property
+10 to both sides
6x = 12
divide 6 to both sides
x = 2
If x is 2 we can plug 2 in for x in 2x + y = 5.
2(2) + y = 5
4 + y = 5
-4 to both sides
y = 1
(2,1)
Thus,
the solution is (2,1).
Hope this helps :)
29 point plus brainiest
The function f(x) = −x2 − 7x + 30 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in feet, and the horizontal distance x, in feet, of a diver from the diving board. What is a zero of f(x), and what does it represent?
x = 10; the diver hits the water 10 feet away horizontally from the board.
x = 3; the diver hits the water 3 feet away horizontally from the board. x = 10; the diver jumps in the pool at 10 feet per second.
x = 3; the diver jumps in the pool at 3 feet per second.
this is your answer..................
The length of time a full length movie runs from opening to credits is normally distributed with a mean of 1.9 hours and standard deviation of 0.3 hours. Calculate the following: A random movie is between 1.8 and 2.0 hours. A movie is longer than 2.3 hours. The length of movie that is shorter than 94% of the movies
Answer:
0.260.911.43Step-by-step explanation:
given data
mean = 1.9 hours
standard deviation = 0.3 hours
solution
we get here first random movie between 1.8 and 2.0 hours
so here
P(1.8 < z < 2 )
z = (1.8 - 1.9) ÷ 0.3
z = -0.33
and
z = (2.0 - 1.9) ÷ 0.3
z = 0.33
z = 0.6293
so
P(-0.333 < z < 0.333 )
= 0.26
so random movie is between 1.8 and 2.0 hours long is 0.26
and
A movie is longer than 2.3 hours.
P(x > 2.3)
P( [tex]\frac{x-\mu }{\sigma}[/tex] > [tex]\frac{2.3-\mu }{\sigma}[/tex] )
P (z > [tex]\frac{2.3-1.9 }{0.3}[/tex] )
P (z > 1.333 )
= 0.091
so chance a movie is longer than 2.3 hours is 0.091
and
length of movie that is shorter than 94% of the movies is
P(x > a ) = 0.94
P(x < a ) = 0.06
so
P( [tex]\frac{x-\mu }{\sigma }[/tex] < [tex]\frac{a-\mu }{\sigma }[/tex] )
[tex]\frac{a-1.9 }{0.3 } = -1.55[/tex]
a = 1.43
so length of the movie that is shorter than 94% of the movies about 1.4 hours.
11/12-1/6q+5/6q-1/3 it says its wrong
Answer:
2/3q + 7/12
Step-by-step explanation:
If you are trying to simplify your expression
4/6q + 7/12
2/3q + 7/12
calculate the area and leave your answer in term of pie
Answer: [tex]2.25\sqrt{3}[/tex]
Not sure what you mean by terms of pi, unless you want us to find the area of the sector, not the triangle.
Step-by-step explanation:
Assuming you mean the area of the triangle...
First draw an altitude from the 120 degree angle to the opposite base. You will find that the altitude will also be a median. This forms 2 30-60-90 right triangles. Thus, the height of the altitude is 1.5 and the base of the triangle is 1.5*root3. Thus, the base of the triangle is [tex]3\sqrt{3}[/tex] and the height is 1.5. Thus, the area of the triangle is [tex]2.25\sqrt{3}[/tex]
What is the product of 7/16 and -6/13 I will make you the brainlest
Answer:
[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex]
Step-by-step explanation:
[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex] . First multiply 7*-6=-42.
Then do 16*13=208.
Simplify by dividing both by 2.
You get [tex]\frac{-42}{208}=\frac{-21}{104}[/tex].
Your final simplified answer is [tex]\frac{-21}{104}[/tex]
I hope this helps!
Given the geometric sequence where a1 = −1 and the common ratio is 7, what is the domain for n? A. All integers B. All integers where n ≥ −1 C. All integers where n ≥ 0 D. All integers where n ≥ 1
Answer:
D
Step-by-step explanation:
Hello, This is a geometric sequence where the first term is [tex]a_1=-1[/tex].
It means that the sequence is [tex](a_n)_{n\geq 1}[/tex].
In other words, as the common ratio is 7 the sequence is defined by
[tex]a_1=-1[/tex]
[tex]a_{n+1}=a_n\cdot 7 \ \ \text{ for n }\geq 1[/tex]
For instance, we can estimate the first terms:
[tex]a_1=-1\\\\a_2=7a_1=-7\\\\a_3=7a_2=-49[/tex]
And we know that we can even find a formula for the [tex]n^{th}[/tex] term of the sequence by:
[tex]a_n=a_1\cdot 7^{n-1}=-7^{n-1}[/tex]
Now, to answer the question, the domain for n is all integers where [tex]n\geq 1[/tex].
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
A shipping container is in the shape of a cube and has a side length of 6ft. It can hold 4 smaller boxes of flour.
If the dimensions of the shipping container are tripled, what is the max number of smaller boxes of flour that the shipping box can hold
Answer:
c. 108
Step-by-step explanation:
Given
Shape of container: Cube
Initial dimension of the container = 6ft by 6ft by 6ft
Initial Number of boxes = 4
Required
Calculate the number of boxes when the dimension is tripled
The first step is to calculate the initial volume of the box;
[tex]Volume = Length * Length * Length[/tex]
[tex]Volume = 6ft * 6ft * 6ft[/tex]
[tex]Volume = 216ft^3[/tex]
This implies that the container can contain 4 small boxes when its volume is 216;
Represent this as a ratio;
[tex]4 : 216[/tex]
The next step is to calculate the volume when the dimension is tripled;
[tex]New\ Length = Old\ Length * 3[/tex]
[tex]New\ Length = 6ft* 3[/tex]
[tex]New\ Length = 18ft[/tex]
Hence;
[tex]Volume = 18ft * 18ft * 18ft[/tex]
[tex]Volume = 5832ft^3[/tex]
Let the number of boxes it can contain be represented with x
Similarly, represent this as a ratio
[tex]x : 5832[/tex]
Equate both ratios;
[tex]4 : 216 = x : 5832[/tex]
Convert ratios to fractions
[tex]\frac{4}{216} = \frac{x}{5832}[/tex]
Multiply both sides by 5832
[tex]5832 * \frac{4}{216} = \frac{x}{5832} * 5832[/tex]
[tex]5832 * \frac{4}{216} = x[/tex]
[tex]\frac{5832 *4}{216} = x[/tex]
[tex]\frac{23328}{216} = x[/tex]
[tex]108 = x[/tex]
[tex]x = 108[/tex]
Hence, the maximum number of boxes it can contain is 108
Determine the angles of rotation. Please answer!!!
Answer:
total rotation = 90 clockwise.
Step-by-step explanation:
Rotation from B to negative y-axis = 45 degrees because B(-3,-3)
Rotation from negative y-axis to B' = 45 degrees because B(-3,3)
Therefore total rotation = 45+45 = 90 clockwise.
La suma de dos números es 50 y la diferencia es 22. ¿Cuáles son los números?
Answer:
(3,2)
Step-by-step explanation:
Just took the test
Use the drawing tool(s) to form the correct answer on the provided number line. Consider the functions below. Represent the interval where both functions are increasing on the number line provided.
In order to solve this problem, we will need a little more information, for example, we need to know what the functions are. Let's say the problem looks like this:
Use the drawing tool(s) to form the correct answer on the provided number line. Consider the functions below.
[tex]f(x)=|3x|-3[/tex]
and
[tex]g(x)=-x^{2}+8x-5[/tex]
Represent the interval where both functions are increasing on the number line provided.
Answer:
See attached picture
Step-by-step explanation:
Since this problem is posted on the algebra section of Brainly, I assume we will need to make use of an algebraic approach to solve this. Basically, the idea is to graph the functions and find the x-values for which both functions increas. In order to graph the functions, we will need to build a table with points for each of the functions. In order to graph the functions you need to pick the x-values you wish and evaluate them in the given functions. (See attached pictures)
Once you got the desired points, you can plot them in the coordinate axis and find the x-values for which both graphs will be increasing. If we take a close look at the graphs we can see the f(x) graph increases in the interval:
(0,∞)
and the g(x) graph increases in the interval:
(-∞,4)
so the interval in which both graphs are increasing will be the region where both intervals cross each other, which will be (0,4)
so that's the interval we draw on our number line. (see attached picture.
Answer:
see photos
Step-by-step explanation:
Plato/Edmentum
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music, if the total of 55 students got medals and only 6 students got medals in the three categories ,how many students get medals in exactly two of these categories?
Answer:
210
Step-by-step explanation:
Given:
Medals in sports = 40
Medals in dance = 25
Medals in music = 212
Total students that received medals = 55
Total students that received medals in all three categories = 6
Required:
How many students get medals in exactly two of these categories?
Take the following:
A = set of persons who got medals in sports.
B = set of persons who got medals in dance
C = set of persons who got medals in music.
Therefore,
n(A) = 40
n(B) = 25
n(C) = 212
n(A∪B∪C)= 55
n(A∩B∩C)= 6
To find how many students get medals in exactly two of these categories, we have:
n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)
=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)
n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)
Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)
Using equation 1:
=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18
Substitute values in the equation:
= 40 + 25 + 212 + 6 − 55 − 18
= 283 - 73
= 210
Number of students that get medals in exactly two of these categories are 210
1. Following is the Receipt and Payment A/c. of a club for the year ended 31-03-2014.
Receipt ₹ Payment ₹
To Balance b/d 75,000 By Salaries 22,000
To Subscription By office expenses 8,000
2012-13 35,000 By Sports equipment
2013-14 9,50,000 (Purchased on 1-10-2013) 6,00,000
2014-15 55,000 10,40,000 By Telephone charges 12,000
To Donation 90,000 By Electricity charges 18,000
To Entrance Fees 60,000 By Travelling Expenses 6,000
To Locker rent 20,000 By 10% Fixed Deposit
To Donation for Building 1,50,000 (made on 1-07-2013) 7,00,000
By balance c/d. 69,000
14,35,000 14,35,000
Additional information:
a) Outstanding subscription for 2013-14 ₹80,000. Outstanding salaries as on 1-04-2013 were ₹2,000 and as on 31-03-2014 were ₹4,000.
b) One third of Entrance fee to be treated as General income.
c) Locker rent rate is ₹2,000 per month.
d) Depreciation on sports equipment 10% p.a.
Prepare Income and Expenditure A/c. for the year ending 31-03-2014.
Answer:
Excess of income over expenditure is ₹1,185,500.
Step-by-step explanation:
Note: The data in this question are merged together. They are therefore sorted before answering this question. See the attached pdf file for the sorted question.
The question is now answered as follows:
Question: Prepare Income and Expenditure A/c. for the year ending 31-03-2014.
Answer and explanation:
Note: See the attached excel file for the Income and Expenditure A/c. for the year ending 31-03-2014.
Both receipts and payments account and income and expenditure account are prepared by not-for-profit organizations such as charity organizations, human right campaign, clubs, etc.
Receipts and payments account is an account gives a summary of all the cash transitions, cash received and paid, that the organization engaged in during a particular period. It is similar to the cash book prepared by profit making organizations. The receipts and payments account is prepared in or to determine the balance of cash in hand or at bank or bank overdraft at the end of the period.
Income and expenditure account is an account gives a summary of all incomes and expenses of an organization during a particular period. It is similar to the trading and profit and loss account prepared by profit making organizations. The income and expenditure account is prepared in order to determine whether there is a surplus or a deficit balance during the period.
Dos conductores A y B llenan un estanqe en 20 horas .Si el conductor B fuera un desague el estanq se llenaria en 52 horas ¿En q tiempo se llenara el estanque estando solo abierto el conducto A?
Answer:
Con el conducto A abierto, el estanque se llenará en 32.5 horas.
Step-by-step explanation:
Deje que el volumen de agua presente en el estanque sea x litros
La tasa conjunta sería x / 20 litros por hora.
Para el conducto A, no sabemos la hora, llamemos a esto y así que la tasa aquí será x / y
Para el conducto B tomará 52 horas y su tasa es x / 52
Matemáticamente, cuando sumamos ambas tasas juntas, obtendremos la tasa conjunta; Así; x / y + x / 52 = x / 20
Saca x en ambos lados 1 / y+ 1/52 = 1/20
(52 + y) / 52y = 1/20
20 (52 + y) = 52y
1040 + 20y= 52y
1040 = 52y -20y
32y = 1040 y = 1040/32
y = 32.5 horas
Con el conducto A abierto, el estanque se llenará en 32.5 horas.
Simplify: 34w-(-8w)
Answer: 42w
Step-by-step explanation:
Subtracting a negative is like adding.
Please answer this in two minutes
Answer:
R = 21.8° to the nearest tenth
Step-by-step explanation:
To find Angle R we use tan
tan ∅ = opposite / adjacent
From the question
The opposite is 2
The adjacent is 5
So we have
tan R = 2/5
R = tan-¹ 2/5
R = 21.8° to the nearest tenthHope this helps you
Please help!! I need to get this! Brainliest For Right Anwser!
Answer:
Data set A best fit by the regression line.
Answer:
Data Set C.
Step-by-step explanation:
Well just even by common sense, the line for "data set A" is not good for the points on the graph
BOTS
TINSS
Self Mastery
1. Pak Kamil is a food committee member for a programme. He buys 10 kg of fish and 6 kg of vegetables for RM136 to
make a feast for the programme. He then adds 4 kg fish and 2 kg of vegetables for RM54. After experiencing some
technical problems, the programme had to be cancelled. If Pak Kamil sells all the fish and vegetables for RM8 and
RM0.50 per kilogram, respectively, what is the total loss experienced by Pak Kamil? Show your calculations.
TP 6
Answer:
The total loss experienced by Pak kamil is RM74
Step-by-step explanation:
The cost of 10 kg and 6 kg of vegetables = RM 136
The cost of 4 kg fish and 2 kg of vegetables = RM 54
Amount for which the fish was sold = RM8 per kilogram
Amount for which the vegetables was sold = RM0.50 per kilogram
The total mass of the fish = 10 kg + 4 kg = 14 kg
The total mass of the vegetables = 6 kg + 2 kg = 8 kg
The amount for which the meat was sold = 14 kg × RM8/kg = RM112
The amount for which the fish was sold = 8 kg × RM0.50/kg = RM4
RM112 + RM4 = RM116
The total amount for which the fish and vegetable was sold = RM136 + RM54 = RM190
Therefore, the total loss experienced by Pak kamil = RM190 - RM116 = RM74.
22. “n is less than 15 and greater than or equal to 3”
Complete the following steps to receive full credit for this question:
• The inequality translated in numerical form
• The solution graphed on a number line
• The solution in interval form
Answer:
3 ≤ n < 15
not nnot nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nnot n1-2. not n
3-4. yes n
5-6. yes n
7-8. yes n
9-10. yes n
11-12. yes n
13-14. yes n
15-16. not n
Step-by-step explanation:
Everything on this side is less than, < but everything on this side is greater.
Everything on this side could be equal or less, ≤ but everything on this side is
not.
I'm had a hard time with the number line, but imagine a line going through the periods and there being a dot where the yes ns end, and start.
Intervals has each point represent more than one number making the line shorter.
Question 5 of 10
Which of the following is the converse of the statement "If it is summer, then
it is warm outside"?
A. If it is warm outside, then it is summer.
B. If it is not warm outside, then it is summer.
O
C. If it is warm outside, then it is not summer.
D. If it is not warm outside, then it is not summer.
hs
Answer:
If it is warm outside, then it is summer
Step-by-step explanation:
To find the converse, interchange the hypothesis and the conclusion
"If it is summer, then it is warm outside"
If it is warm outside, then it is summer
Answer:
A. If it is warm outside, then it is summer
Step-by-step explanation:
statement "If it is summer, then it is warm outside" : warm=summer
A. If it is warm outside, then it is summer. : warm = summer ✓
B. If it is not warm outside, then it is summer. : not warm = summer x
C. If it is warm outside, then it is not summer. : warm =not summer x
D. If it is not warm outside, then it is not summer. : not warm = not summer x
Solve the equation for all exact solutions where appropriate. Round approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures. sine theta cosine theta minus sine theta equals 0
A. {270 degree - 360 degree n, where n is any integer}
B. {270 degree + 180 degree n, where n is any integer}
C. {270 degree + 180 degree n, 315 degree + 180 degree n, where n is any integer}
D. {270 degree + 360 degree n, 315 degree + 360 degree n, where n is any integer}
Step-by-step explanation:
The equation is sinθ * cosθ - sinθ = 0
sinθ * cosθ -sinθ = 0sinθ * cosθ = sinθcosθ = sinθ/sinθcosθ = 1θ = 0 + 2kπ
θ = 2kπ where k is any integer
The solutions to the equation are: {0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}
Hence, the correct option is C.
The given equation is:
sin theta × cos theta - sin theta = 0
We can factor out the sine theta:
sin theta (cos theta - 1) = 0
This means that either sin theta = 0 or cos theta - 1 = 0.
If sin theta = 0, then theta = 0, 180 degrees, 360 degrees, etc.
If cos theta - 1 = 0, then cos theta = 1, which means that theta = 0 degrees and 360 degrees.
Therefore, the solutions to the equation are:
{0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}
So the answer is C.
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Which two features of igneous rocks are determined by their cooling rate?
color and shininess
shininess and hardness
hardness and crystal size
crystal size and rock texture
Answer:
crystal size and rock texture D
Step-by-step explanation:
:)
Hence, the option (D) is the correct answer i.e., crystal size and rock texture.
What is the texture?
The texture is defined as a tactile quality of an object's surface. It appeals to our sense of touch, which can evoke feelings of pleasure, discomfort, or familiarity.
The texture of an igneous rock is dependent on the rate of cooling of the melt slow cooling allows large crystals to form, fast coolng yields small crystals.
Hence, the option (D) is the correct answer i.e., crystal size and rock texture.
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Suppose a geyser has a mean time between eruptions of 72 minutes. Let the interval of time between the eruptions be normally distributed with standard deviation 23 minutes. Complete parts (a) through (e) below.
(a) What is the probability that a randomly selected time interval between eruptions is longer than 82minutes? The probability that a randomly selected time interval is longer than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(b) What is the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes? The probability that the mean of a random sample of 13 time intervals is more than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(c) What is the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes? The probability that the mean of a random sample of 34 time intervals is more than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(d) What effect does increasing the sample size have on the probability? Provide an explanation for this result. Fill in the blanks below. If the population mean is less than 82 minutes, then the probability that the sample mean of the time between eruptions is greater than 82 minutes ▼ increases decreases because the variability in the sample mean ▼ decreases increases as the sample size ▼ decreases. increases.
(e) What might you conclude if a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes? Select all that apply.
A. The population mean may be less than 72.
B. The population mean must be more than 72, since the probability is so low.
C. The population mean cannot be 72, since the probability is so low.
D. The population mean is 72, and this is just a rare sampling.
E. The population mean may be greater than 72.
F. The population mean is 72, and this is an example of a typical sampling result.
G. The population mean must be less than 72, since the probability is so low.
Answer:
(a) The probability that a randomly selected time interval between eruptions is longer than 82 minutes is 0.3336.
(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 minutes is 0.0582.
(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is 0.0055.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) The population mean must be more than 72, since the probability is so low.
Step-by-step explanation:
We are given that a geyser has a mean time between eruptions of 72 minutes.
Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.
(a) Let X = the interval of time between the eruptions
So, X ~ N([tex]\mu=72, \sigma^{2} =23^{2}[/tex])
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
Now, the probability that a randomly selected time interval between eruptions is longer than 82 minutes is given by = P(X > 82 min)
P(X > 82 min) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{82-72}{23}[/tex] ) = P(Z > 0.43) = 1 - P(Z [tex]\leq[/tex] 0.43)
= 1 - 0.6664 = 0.3336
The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.
(b) Let [tex]\bar X[/tex] = sample mean time between the eruptions
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
n = sample of time intervals = 13
Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes is given by = P([tex]\bar X[/tex] > 82 min)
P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{13} } }[/tex] ) = P(Z > 1.57) = 1 - P(Z [tex]\leq[/tex] 1.57)
= 1 - 0.9418 = 0.0582
The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.
(c) Let [tex]\bar X[/tex] = sample mean time between the eruptions
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
n = sample of time intervals = 34
Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is given by = P([tex]\bar X[/tex] > 82 min)
P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{34} } }[/tex] ) = P(Z > 2.54) = 1 - P(Z [tex]\leq[/tex] 2.54)
= 1 - 0.9945 = 0.0055
The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 minutes, then we conclude that the population mean must be more than 72, since the probability is so low.
Answer:
The probability that a randomly selected time interval between eruptions is longer than 82minutes = [tex]0.3336[/tex]The probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes = [tex]0.0594[/tex]The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes = [tex]0.0057[/tex]Step-by-step explanation:
From the given data
mean, u = 72
Standard deviation [tex]\rho[/tex] = 23
A) Probability that a randomly selected time interval between eruptions is longer than 82minutes
[tex]P (x > 82) = P[\frac{x-u}{\rho} > \frac{82-72}{23}]\\\\P (x > 82) = P[z > 0.43]\\\\P (x > 82) = 0.3336[/tex]
B)
[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{13}}}]\\\\P (x > 82) = P[z > 1.5676]\\\\P (x > 82) = 0.0594[/tex]
C)
[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{34}}}]\\\\P (x > 82) = P[z > 2.5351]\\\\P (x > 82) = 0.0057\\\\[/tex]
D) If the mean is less than 82minutes, then the probability that the sample mean of the time between eruptions is greater than 83 minutes decrease because the variability in the sample mean decrease as the sample size increases
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points Q and R are midpoints of the sides of triangle ABC. Triangle A B C is cut by line segment Q R. Point Q is the midpoint of side A B and point R is the midpoint of side A C. The lengths of A Q and Q B are 4 p, the length of Q R is 2 p + 3, and the length of C B is 6 p minus 4. The lengths of A R and R C are congruent. What is AQ? 10 units 14 units 20 units 32 units
Answer:
AQ = 20 units
Step-by-step explanation:
I tried figuring in the pic below..
Similar triangles are triangles whose corresponding measures are proportional. All of their corresponding angles are also congruent. There are theorems and postulates that prove triangle similarity. Usually they requrie at least three parts of each triangle. The symbol for similarity is ~.
We have two triangles in the figure. ΔAQR and ΔABC. We will prove first that they are similar.
Answer:
20
Step-by-step explanation:
RQ is 1/2 of CB, so 2(2p+3)=6p-4. This would make p=5. Then, 5*4=20.
(also it is right on edgenuity)