How do our attitudes help us organize our reality?

Answer:

the speed of the textbook just before it hits the floor is 2.4 m/s

Explanation:

  Given the data in the question;

mass of pulley = 1.50 kg

radius of pulley = 0.240 m

mass of text book = 2.0 kg

height from which text book was released = 0.9 m

angular speed of the pulley = 10.0 rad/s

the speed of the textbook just before it hits the floor = ?

the speed of the textbook v = angular speed of the pulley × radius of pulley

we substitute

v = 10.0 rad/s × 0.240 m

v = 2.4 m/s

Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s

Answer:

w = w₀ / 2    the angular velocity is half the initial value.

Explanation:

We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved

initial instant.

          L₀ = I₀ w₀

final moment

          L_f = I w

the moment is preserved

          L₀ = L_f

          I₀ w₀ = I w

the moment of inertia of a disk is

         I = ½ m R²

we substitute

          ½ m R² w₀ = ½ (2m) R² w

          w = w₀ / 2

for the case of a disk with twice the mass, the angular velocity is half the initial value.

Answer:

he maximum frequency occurs when the denominator is minimum

 f’= f₀  [tex]\frac{343}{343 + v_s}[/tex]

Explanation:

This is a doppler effect exercise, where the sound source is moving

           f = fo [tex]\frac{v}{v-v)s}[/tex]      when the source moves towards the observer

           f ’=f_o  [tex]\frac{v}{v+v_{sy}}[/tex]  Alexandrian source of the observer

the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects

          f’= f₀  [tex]\frac{343}{343 + v_s}[/tex]

Answer:

sudden cardiac arrest

Explanation:

Answer:

The answer is B

Explanation:

Answer:

λ = a

Explanation:

This is a diffraction exercise that is described by the expression

          a sin θ = m λ

         sin θ  = m λ/ a

the first zero of the diffraction occurs for m = 1

        sin θ  = λ / a

angles are generally very small and are measured in radians

         sin θ  = θ  = y / x

we substitute

         [tex]\frac{y}{x} = \frac{\lambda}{a}[/tex]

the width of the central maximum is twice the distance to zero

         w = 2y

in the exercise indicate that this width is equal to twice the distance to the screen (2x)

          W = 2x

           2y = 2x

we substitute

          1 = λ/ a

          λ = a

we see that the width of the slit is equal to the wavelength used.

Answer:

FORCE as for my answer....

Answer: 5.08 L.

Explation down below

Answer:

B

Explanation:

Answer:

ozone, letter b

ozone is basically an allotrope of oxygen having three atoms instead of two.

Answer:

a) ferromagnetic type,  b) superconductor or ferromagnetic

Explanation:

In substances, magnetism is the result of the magnetic moments of the electrons in their orbits and of the spin.

These two let us take interacting magnetic between them, if the sum of these magnetic moments is maximum we have a material of the ferromagnetic type, which is represented in figure a, where all the magnetic moments are aligned in one direction and this type of material is a magnet permanent.

Figure b shows a material where the magnetic moments have a circular shape, so the total moment is zero.The type of substrate material can have several possibilities

* The most test is that the substrate material is a superconductor where the marked areas are the superconducting magnetic areas and the areas without spine are the normal areas

* Another possibility is that the material is ferromagnetic, that is, there are several magnetic sub-networks in different orientation, resulting in a random field, the material is not a permanent magnet

Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

For car A:

Speed = 40 km/h

Time = 3 hours

Distance =?

Speed = distance / time

40 = distance / 3

Cross multiply

Distance = 40 × 3

Distance = 120 Km

For car B:

Speed = 50 km/h

Time = 3 hours

Distance =?

Speed = distance / time

50 = distance / 3

Cross multiply

Distance = 50 × 3

Distance = 150 Km

Finally, we shall determine the distance between car B an car A. This can be obtained as follow:

Distance travelled by car B (D₆) = 150 Km

Distance travelled by car A (Dₐ) = 120 Km

Distance apart =?

Distance apart = D₆ – Dₐ

Distance apart = 150 – 120

Distance apart = 30 Km

Therefore, car B will be 30 Km ahead of car A.

Answer:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your own

Explanation:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your ownWhich sentence uses a superlative adjective correctly?

Anthony is running more quickly than anyone else on the field.

Shalon is a very talented pianist.

That is the best chocolate cake I have ever tasted.

Ani is the better gymnast of the two.

Which statement best compares and contrasts the purpose of "PROSERPINE" to that of "How Old Man Winter Was Driven Back"?

The Greek myth explains the creation of the earth, while the Iroquois myth also explains why there is evil in the world.

The Greek myth explains the creation of the earth, while the Iroquois myth also explains the creation of the moon.

The Greek myth explains the changing of the seasons as well as the existence of the underworld, while the Iroquois myth also explains the changing of the seasons.

The Greek myth explains the creation of the moon, while the Iroquois myth explains the creation of the sun.

Read the passages:

from "How Old Man Winter Was Driven Back"

"I, too, am powerful, and I am young! I do not fear you. When I touch the earth, it grows soft and warm. Every living thing stirs in its sleep,—birds and bees, flowers and trees, animals and men. When I speak, the sleeping sun awakes. See! Already he begins to send down his arrows. Hasten! that they may not find you, on the trail to the North Sky."

from "How the World Was Made"

Even some of the trees went to sleep. Only the cedar, the pine, the spruce, the holly, and the laurel were awake all seven nights. Therefore they are always green. They are also sacred trees. But to the other trees it was said, “Because you did not stay awake, therefore you shall lose your hair every winter.”

Which best uses textual evidence to compare and contrast these two myths?

Both myths show the change in seasons as a violent battle.

In "How Old Man Winter Was Driven Back," the change in

Answer:

Both sound and waves

Explanation:

Thank me later

Answer:

B = 1.37 mT

Explanation:

Given that,

The magnitude of the electric field, E = 480 N/C

The speed of the proton, [tex]v=3.50 \times 10^5\ m/s[/tex]

We need to find the magnitude of the magnetic field. In a velocity selector, the electric field is balanced by the magnetic field. So,

[tex]qE=qvB[/tex]

Where

B is the magnetic field

[tex]B=\dfrac{E}{v}\\\\B=\dfrac{480}{3.5\times 10^5}\\\\B=1.37\times 10^{-3}\ T\\\\or\\\\B =1.37\ mT[/tex]

So, the magnetic field is equal to 1.37 mT.

If everything else remains constant, then the received signal power is simply an inverse-square function of its distance from the transmitter.

That is, down 6dB when distance is doubled etc.

If distance increases from 16 to 20, then received power decreases by the factor of (16/20)^2.

That's (0.8)^2 = 0.64

New receive power is 5x0.64 = 3.2 nW

=. ===== ==========

Here's how I do it at my job:

Initial RSL = 5nW ~ - 53 dBm

loss = 20log(20/16)= 20log(1.25)~1.94dB

New RSL = - 54.94 dBm or ~ 3.2 nW .

Answer:

8.33 meters/sec.

time = 30 sec. 30 sec. = 8.33 meters/sec.

Answer:

[tex]4.61\times 10^{-5}\ \text{T}[/tex]

[tex]1.05\times 10^{-6}\ \text{Nm}[/tex]

Explanation:

[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi10^{-7}\ \text{H/m}[/tex]

[tex]r_l[/tex] = Radius of loop = 15 cm

[tex]I_l[/tex] = Current in loop = 11 A

[tex]r_c[/tex] = Radius of coil = 0.76 cm

N = Number of turns of coil = 66

[tex]I_c[/tex] = Current in coil = 1.9 A

Magnetic field is given by

[tex]B=\dfrac{\mu_0I_l}{2r_l}\\\Rightarrow B=\dfrac{4\pi\times 10^{-7}\times 11}{2\times 0.15}\\\Rightarrow B=4.61\times 10^{-5}\ \text{T}[/tex]

Magnitude of magnetic field produced by the loop at its center is [tex]4.61\times 10^{-5}\ \text{T}[/tex].

Torque is given by

[tex]\tau=BI_c\pi r_c^2N\sin90^{\circ}\\\Rightarrow \tau=4.61\times 10^{-5}\times 1.9\times \pi\times (0.76\times 10^{-2})^2\times 66\sin90^{\circ}\\\Rightarrow \tau=1.05\times 10^{-6}\ \text{Nm}[/tex]

Magnitude of torque on the coil due to the loop is [tex]1.05\times 10^{-6}\ \text{Nm}[/tex]

Answer:

B. Refraction

Explanation:

Jope this helps

Answer:

The basic properties (parts) of a wave include: frequency, amplitude, wavelength and speed. Frequency is a measure of how many waves pass a point in a certain amount of time.

Answer:

2.75 N

Explanation:

Given that,

Box A has a mass 21.0 kg and box B has a mass 8.0 kg.

A horizontal force of 100N is exerted on box A.

Let a be the acceleration of the system. Using second law of motion,

[tex]F=(m_A+m_B)a\\\\a=\dfrac{F}{(m_A+m_B)}\\\\a=\dfrac{10}{(21+8)}\\\\a=0.344\ m/s^2[/tex]

Now applying Newton's second law to box B. So,

[tex]F_A=m_Ba\\\\=8\times 0.344\\\\=2.75\ N[/tex]

So, 2.75 N is the force that box A exerts on box B.

The key concept here is that when two objects interact, the forces they exert on each other are equal in magnitude but opposite in direction. The magnitude of the force that box A exerts on box B is also 100N.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. It is one of the three fundamental principles described by Sir Isaac Newton in his Laws of Motion.

According to Newton's third law, when an object exerts a force on another object, the second object simultaneously exerts a force of equal magnitude but in the opposite direction on the first object. In simpler terms, if object A applies a force on object B, then object B applies an equal force in the opposite direction on object A.

Since boxes A and B are in contact on a frictionless surface, the force exerted on box A will be transmitted to box B. According to Newton's third law of motion, the magnitude of the force that box A exerts on box B will be equal in magnitude but opposite in direction to the force exerted on box A.

Therefore, the magnitude of the force that box A exerts on box B is also 100N.

For more details regarding Newton's third law of motion, visit:

https://brainly.com/question/29768600

#SPJ6

Answer:

636.6 W/m²

Explanation:

From the given information:

The area of the circular spot can be calculated as:

A = πr²

A = π(0.5 × 10⁻³ m)²

A = 7.85 × 10⁻⁷ m²

The intensity can be determined by using the formula:

[tex]I = \dfrac{P}{A}[/tex]

[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]

[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]

I = 636.6 W/m²

Answer:

A. harmful substances in the air, water, or soil

hope my ans helps

be sure to follow me

stay safe

have a good day

Answer:

Answer:

Table A

Measuring Current as a Function of Voltage with a 20 Ω Resistor

Voltage

(V)

Current: Calculated

(A)

Current: Experimental

(A)

1 0.05 0.05

5 0.25 0.25

10 0.50 0.50

20 1.00 1.00

50 2.50 2.50

Table B

Measuring Current as a Function of Resistance at 25 V

Resistance

(Ω)

Current: Calculated

(A)

Current: Experimental

(A)

10 2.50 2.50

20 1.25 1.25

100 0.25 0.25

200 0.12 0.12

Table C

Measuring Current in a Parallel Circuit

Resistor Set

(Ω)

Total  

Resistance

(Ω)

Calculated

Current

(A)

Observed  

Current

(A)

Observed Current  

through Each Resistor

(A)

20, 20, 20 6.67 3.75 3.74 1.25, 1.25, 1.25

20, 20, 200 9.52 2.63 2.62 1.25, 1.25, 0.12

Voltage needed to raise current to 3.75 A (20, 20, 200 resistor set):

Calculated: 35.7

Observed: 36

Table D

Calculating Power of Circuit ComponentsTeacher Guide (continued)

Observed Total Current

(A)

Current through Each Bulb

(A)

Power Usage per Bulb

(W)

2.00 0.67 6.7

Explanation:

got this from the teachers guide