Explanation:
For the calibration process, use a weight that is 50% of the scale's capacity for accurate calibration. Weights less than 10% can result in inaccuracy. Make sure that the scale doesn't have any weights placed on it and nothing is rubbing against the scale or the platform.
When 1 mol of a nonvolatile, nondissociating solute is dissolved in 3 mol of volatile solvent, the ratio of vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately:________
Answer:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Explanation:
Hello there!
In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:
[tex]P_{solution}=x_{solvent}P_{solvent}^{vap}[/tex]
Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:
[tex]x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}[/tex]
Thus, we plug in the moles of solvent and solute to obtain:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Regards!
determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount
Answer:
9 moles of NaNO3 is obtained
Explanation:
The balanced chemical reaction equation for the reaction is;
Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3
Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.
1 mole of Al(NO3)3 yields 3 moles of NaNO3
4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3
Also,
3 moles of NaCl yields 3 moles of NaNO3
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3
Hence, NaCl is the limiting reactant and 9 moles of NaNO3 is obtained.
9 moles of NaNO₃ is obtained.
Balanced chemical reaction:
[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]
From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.
1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃
4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃
Also,
3 moles of NaCl yields 3 moles of NaNO₃
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃
Hence, NaCl is the limiting reactant and 9 moles of NaNO₃ is obtained.
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a solar eclipse only happens during a Moon
A. New
B. Crescent
C. Gibbous
D. Full
Answer:
A. New
Explanation:
PLEASEEE HELPPP WILL MARK BRAINLIEST FOR RIGHT ANSWER!!!
You have an unknown concentration of 0.035 L of HCl acid and added 0.033 L of 0.3 M NaOH before the equivalence point was reached. What is the concentration of the HCl?
HCl + NaOH -> H2O + NaCl
A) 0.28 M HCl
B) 0.11 M HCl
C) 0.035 M HCl
D) 3.14 M HCl
Answer:
A
Explanation:
Answer:
C
Explanation:
Pretty sure!
Please help will give brainliest to right answer!!
You add 1.5 moles of HF to 6 liters of water. The concentration is at equilibrium when [H+] is at 0.10 M. What is the Ka of HF? HF -> H+ + F-.
A) 0.067
B) 0.10
C) 0.25
D) 1.5
Answer:
C
Explanation:
NP
Calculate the specific heat of a substance given that 49 joules of heat is required to raise the temperature of 25.0 g of the substance from 92.6 ºC to 99.4 ºC.
Answer:
0.29 J/g.°C
Explanation:
Step 1: Given data
Added heat (Q): 49 JMass of the substance (m): 25.0 gInitial temperature: 92.6 °CFinal temperature: 99.4 °CStep 2: Calculate the temperature change (ΔT)
ΔT = 99.4 °C - 92.6 °C = 6.8 °C
Step 3: Calculate the specific heat of the substance (c)
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C
How many L of 3.0M solution
can be made with 78g of
NaCl?
Answer:
Need to find moles NaCl.
526 grams NaCl (1 mole NaCl/58.44 grams)
= 9.0 moles NaCl
----------------------------------------------------
now,
Molarity = moles of solute/Liters of solution
or, for our purposes
Liters of solution = moles of solute/Molarity
Liters of solution = 9.0 moles NaCl/3.0 M
= 3.0 liters in volume
A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?
Answer:
What is
the volume of the balloon when the temperature is 310K?
At which temperature is water in its gas phase (water vapor)?
Group of answer choices
-40
40
140
When calcium forms an ion that has the same number of outer electrons as which noble gas?
1. neon
2. helium
3. argon
4. krypton
BRAINLIEST FOR HELP ASAP!!!!
Many scientists are studying tiny particles called nanoparticles, Which best
describes how the scientists are probably trying to learn about these
particles?
Answer:
By experimenting
Explanation:
1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -CH3
b) -CH2OH
c) -CH2NH2
d) -CH2BR2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -F
b) -CH2OH
c) -CHO
d) -CH3
Answer:
1. CH₂Br > CH₂OH > CH₂NH₂ > CH₃
2. -F > -CHO > - CH₂OH > CH₃
Explanation:
The arrangement of the above atom is due to their atomicity and electronegativity of the given compounds.
From (1) we will realize that Bromine (Br) possesses the greatest priority because its atomic number is the highest. This is followed by oxygen (O) in CH₂OH since atomic no 8 is higher than that of Nitrogen N(7). Lastly, CH₃ has the only hydrogen attached to it with the atomic no of (1)
In the second part of the question>
The electronegativity of an element increases across the period and down the group. Fluorine is highly electronegative and contains the highest atomic number of oxygen in -CHO. The oxygen (O) in -CHO has a double bond which gives an edge over the (O) in CH₂OH. Lastly, CH₃ contains a substituted hydrogen atom
12 moles of sodium into grams
Answer:
12 moles sodium= 275.87724000000003 grams
Explanation:
1 moles sodium = 0.043497607849056.
A sample of dry gas is found to occupy 3.650 L at 22.0°C and 740.0 mmHg. How many moles of gas are present?
will mark brainliest
Answer:
0.147
Explanation
PV/RT
Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4
Answer:
2.35x10²³ molecules of C2Cl4 are present
Explanation:
To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:
Moles C2Cl4:
73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4
Molecules:
0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =
2.35x10²³ molecules of C2Cl4 are presentHow many moles of Oxygen atoms are contained in 45.9 mol CO2?
Answer:
Explanation:
10 moles of oxygen atoms.\ \textbf{b)} 91.8 moles of oxygen at
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
Answer:
The answer is "2%"
Explanation:
Equation:
[tex]HNO_2\ (aq) \leftrightharpoons H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\ K_a = 4.0\times \ 10^{-4}[/tex]
[tex]H^{+}=?[/tex]
Formula:
[tex]Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}[/tex]
Let
[tex][H^{+}] = [NO_2^{-}] = x[/tex] at equilibrium
[tex]x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \ M\\\\[/tex]
therefore,
[tex][H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M[/tex]
Calculating the % ionization:
[tex]= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\[/tex]
The approximate percent ionization of HNO₂ in a 1.0 M HNO₂ (aq) solution is 2%.
How we calculate the % ionization?% ionization of any compound will be calculated as follow:
% ionization = ([ion]/[acid or base]) ₓ 100
Given chemical reaction with ICE table will be represented as:
HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)
initial 1 0 0
change -x +x +x
equilibrium 1-x x x
Equilibrium constant will be represented as:
Ka = [H⁺][NO₂⁻] / [HNO₂]
Acid dissociation constant for HNO₂ = 4×10⁻⁴
Putting all values in the above equation, we get
4×10⁻⁴ = x² / 1-x
Value of changeable quantity is very less, so we neglect from the concentration of HNO₂.
4×10⁻⁴ = x²
x = 2 × 10⁻²
So, the concentration of H⁺ ion = 2 × 10⁻²M
Now we put all these values in the % ionization equation, we get
% ionization = (0.02/1) × 100 = 2%
Hence , % ionization is 2%.
To know more about % ionization, visit the below link:
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If an alkene is protonated and the solvent is an alcohol rather than water, a reaction takes place that is very similar to acid-catalyzed hydration, but in the second step of the mechanism the alcohol functions as a nucleophile instead of water. Draw a plausible mechanism for the following process: What is the most likely sequence of steps in the mechanism
Answer:
Please find the structure of the mechanism in the attached file.
Explanation:
To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.20 g Pb
They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
Write the structure of all possible peptides containing these amino acids: Asp, Glu, Gln Use single letter abbreviations and capital letters only; i.e. GYR, not Gly-Tyr-Arg. If there are fewer than 6 peptides, leave an appropriate number of answer boxes empty. fill in the blank 1 , fill in the blank 2 , fill in the blank 3 , fill in the blank 4 , fill in the blank 5 , fill in the blank 6
Answer:
QED, EDQ, DQE, EQD, DEQ, QDE
Explanation:
The structure of all possible peptides that contain the given amino acids are :
QED, EDQ, DQE, EQD, DEQ, QDE
where : Asp is represented by the letter code D
Glu is represented by the letter code E
Gln is represented by the letter code Q
Note : when three amino acids combine they form what is known as tripeptide ( i.e. contains two peptide linkages ) while a peptide linkage is been formed by the combination of a carboxyl group of an amino acid and the amino group of different amino acid
What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?
What answer is it and how ? please help !!!!!! ill mark brainlyest if right
Answer:
The answer is B
Brainliest please!
What is the IUPAC name for the following compound?
a. benzenecarbonitrile
b. benzenecyanide
c. phenylcyanide
d. cyanophenyl
Answer:
Option a. Benzenecarbonitrile
Explanation:
You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.
As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.
This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.
phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.
Hope this helps
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L flask with 4.5 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 1.1 atm. Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
Kp = 7.4727
Explanation:
Let's write the balanced equilibrium reaction:
2NH₃ <-------> N₂ + 3H₂ Kp = ??
Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:
2NH₃ <-------> N₂ + 3H₂
I. 4,5 0 0
C. -2x +x +3x
E. 4,5-2x x 3x
According to this chart, the Kp expression should be:
Kp = (PH₂)³ * (PN₂) / (PNH₃)² (1)
The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:
Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²
Kp = 39.5307 / 5.29
Kp = 7.4727Hope this helps
What is the pH of a house cleaning solution with molar hydrogen ion concentration [H+] of 1.0 x 10-8? please explain. Thank you so much!
[tex]pH = - log({H}^{ + } ) \\ pH = - log(1.0 \times {10}^{ - 8} ) \\ pH = 8[/tex]
pH is the measure of acidity and alkalinity of a solution. A pH value less than 7 means the solution is acidic. A pH value greater than 7 means the solution is basic. A pH value of 7 means the solutions is neutral.
concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature (a) what volume (mL) of this solution is needed to make a 1.00L solution of 1.00M phosphoric acid?
Answer:
82.0 mL
Explanation:
Step 1: Given data
Concentration of concentrated acid (C₁): 12.2 MVolume of concentrated acid (V₁): ?Concentration of dilute acid (C₂): 1.00 MVolume of dilute acid (V₂): 1.00 LStep 2: Calculate the required volume of the concentrated acid
We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL
What is the hydrogen ion concentration of a solution with pH=7.75 ?
Answer:
[tex][H^+]=1.78x10^{-8}M[/tex]
Explanation:
Hello there!
In this case, according to the given information about the pH, it is firstly necessary for us to remember that the pH is defined as the potential of the hydrogen ions in the solution and the concentration of those ions represents how many of them are present in the solution; in such a way, it is possible for us use:
[tex]pH=-log([H^+])[/tex]
Whereas the concentration of hydrogen ions can be calculated as follows:
[tex][H^+]=10^{-pH}[/tex]
So we plug in the given pH to obtain:
[tex][H^+]=10^{-7.75}=1.78x10^{-8}M[/tex]
Regards!
What is the ph of a HCl solution with a concentration of 2.51x10^-5M
Answer:
pH = 4.6
Explanation:
As hydrochloric acid (HCl) is a strong acid, the molar concentration of H⁺ species is the same as the molar concentration of the HCl solution. In other words:
[H⁺] = 2.51x10⁻⁵ MWith the information above in mind we can calculate the pH:
pH = -log[H⁺]pH = -log(2.51x10⁻⁵ M)pH = 4.6According to the kinetic molecular theory which substances are made of particles ?
Answer:
The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.
Explanation:
Kinetic molecular theory explains the properties of solids, liquids and gases. As per this theory, matter is made of particles.
What is kinetic theory?
Kinetic molecular theory explains the properties of different states of matter. According to this theory matter is made up of particles. But the theory is mostly applies for gases.
According to kinetic theory of gases, gaseous substances consists of tiny spherical particles which are located apart from each other and hence no intermolecular force acts between them. They are in random motion and gains kinetic energy.
The kinetic energy of particles are temperature dependant and it increase as temperature rises. The collision between the particles and the particle and wall of the container in which they are will be elastic collision.
These concepts are applicable only for ideal gases. An less applicable for other states of matter.
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What is the percent yield of a reaction producing 26g Iridium V Sulfate from 30g Lithium Sulfate and 30g Iridium V Carbonate?