Answer:
It makes it lighter when its closer and heavier when its farther way.
Explanation:
A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed into elastic potential energy of the bending board; if the board bends far enough, it breaks. Applying a force to the center of a particular pine board deflects the center of the board by a distance that increases in proportion to the force. Ultimately the board breaks at an applied force of 870 N and a deflection of 1.3 cm .
Required:
To break the board with a blow from the hand, how fast must the hand be moving? Use 0.50kg for the mass of the hand.
Answer:
6.726 m/s
Explanation:
Given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
W = fd.
W = 870 * 0.013
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
K.E = 1/2mv²
Where K.E = 11.31
11.31 = 1/2 * 0.5 * v²
22.62 = 0.5v²
v² = 45.24
v = √45.24
v = 6.726 m/s
To break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
What is speed?
Speed is defined as the distance traveled by any object with respect to the time.
Now it is given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
[tex]W=F\times d[/tex]
[tex]W=870\times 0.013[/tex]
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
[tex]KE=\dfrac{1}{2}mv^2[/tex]
Where K.E = 11.31
[tex]11.31=\frac{1}2}\times 0.5\times v^2[/tex]
[tex]0.5v^2=22.62[/tex]
[tex]v^2=45.24[/tex]
[tex]v=6.726\ \ \frac{m}{s}[/tex]
Hence to break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
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Someone who snorts and stop breathing during sleep may be suffering from: a. Catoplexy b. Narcolepsy c. Sleep Apnea d. Insomnia
Answer:
C. Sleep Apnea
Explanation:
Sleep Apnea is when someone who snores and stops breathing while sleeping
Someone who snorts and stop breathing during sleep may be suffering from Sleep Apnea. Hence, option (c) is correct.
What is Sleep Apnea?Breathing repeatedly stops and begins while you sleep, which is a frequent symptom of sleep apnea. Your body may not receive enough oxygen as a result.
There are two different forms of sleep apnea.
When your upper airway is repeatedly closed while you sleep, airflow is reduced or entirely stopped, which is known as obstructive sleep apnea. This kind of sleep apnea is the most prevalent.When your brain fails to deliver the necessary signals for breathing, central sleep apnea develops. Central sleep apnea can be brought on by medical problems that alter how your brain regulates the muscles in your chest and airway.Learn more about sleep apnea here:
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A car of weight (80 N) been revoked by other car . Find the tnsion force
exerted on that car when it is accelerated by (0.5 m/s2
) .
Answer:
T = 4 N
Explanation:
Given that,
Weight of a car, W = 80 N
We know that,
Weight = mg
80 = 10m
m = 8 kg
If the acceleration of the car is 0.5 m/s², then force becomes,
F = 8 × 0.5
F= 4 N
So, the required tension force is 4 N.
How could you prove that
through
rock layers in one area match rock layers
found in another area?
Answer:
An unconformity shows where some rock layers have been lost because of erosion. To date rock layers, geologists first give a relative age to a layer of rock at one location and then give the same age to matching layers at other locations. Certain fossils, called index fossils, help geologists match rock layers.
Explanation:
really simple science packet, i just need help it’s due tomorrow. thank y’all :)
Answer:
13: (Im not sure sorry)
14: C
15: B
16: B
17: B
18: B
A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder, causing the piston to slowly move upward. For the gas inside the cylinder, what kind of process is this?
Answer:
isobaric
Explanation:
According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure
The ideal gas law derives
PV = nRT
As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric
PLEASE HELP MEE PLEASE!
Answer;
gram
Explanation
16. Using the formula P = V x I, find the amount of power flowing through a circuit carrying a current of 20 amperes at a potential difference of 120 volts.
O A 2400 Watts
B. 6 Watts
C. 1200 Watts
D. 24 Watts
PLEASE HELP! I'LL GIVE BRAINLEST
the answer is the first one
A rock falls from a cliff and hits the ground at a velocity of 28m/s. How long did it take to fall?
Answer:
2.8s
Explanation:
=>a = v-u/t
=> t = v - u / t
= 28-0 / 10
= 2.8 s
A 25 MGD surface water drinking plant has four circular clarifiers (aka sedimentation basin), operated in parallel with each basin receiving equal flow, that all have a diameter of 16 meters and are 3 m deep. Assume that all particles entering the clarifiers have the same particle density of 1.2 mg/mL and the average water temperature is 20 oC with an average viscosity of 1 g/(m*s) and an average density of 998.2 kg/m3.
1. What is the diameter of the smallest particles (in mm) that can be removed by these clarifiers?
2. If the each of the four clarifiers is to be rectangular in shape with a length to width ratio of 5:1, what is the minimum width that each clarifier can be (in meters)?
Answer:
can y
Explanation:
jj
The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
What is the equation for the settling velocity of a particle?The equation for the settling velocity of a particle:
V_s = (2/9) * (ρ_p - ρ_w) * g * r^2 / η
where V_s is the settling velocity, ρ_p is the particle density, ρ_w is the water density, g is the acceleration due to gravity, r is the particle radius, and η is the water viscosity.
1. We can rearrange the equation to solve for the particle radius:
r = [9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
We want to find the particle diameter, which is twice the radius, so we can substitute 2r for d in the following equation:
d = 2r = 2[9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
To remove the smallest particles, we want to use the smallest settling velocity possible, which corresponds to a particle just barely settling to the bottom of the clarifier. Therefore, we can set V_s equal to the minimum settling velocity required for particles to be removed:
V_s = Q / (A * X)
where Q is the flow rate (25 MGD), A is the surface area of one clarifier (πr^2), and X is the overflow rate, which is the flow rate per unit area of the clarifier. A typical overflow rate for a sedimentation basin is 600-1200 gallons per day per square foot (gpd/ft^2), or 2.5-5 m^3/day/m^2. We will use the lower end of this range, 2.5 m^3/day/m^2.
Substituting in the values for Q, A, and X, we get:
V_s = (25 MGD) / (π(8 m)^2 * 2.5 m^3/day/m^2) = 0.00159 m/s
Now we can substitute the values for η, ρ_p, ρ_w, g, and V_s into the equation for the particle diameter:
d = 2[9(1 g/(m*s))(0.00159 m/s) / (2(1200 kg/m^3 - 998.2 kg/m^3)(9.81 m/s^2))]^(1/2) = 0.0257 mm
So, the smallest particles that can be removed by these clarifiers have a diameter of approximately 0.0257 mm.
2. To find the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1, we can use the same overflow rate and flow rate as before, and we can assume a depth of 3 m. The surface area of one clarifier must still be the same as before, so we can use the equation for the surface area of a rectangle:
A = L * W
where L is the length and W is the width.
Substituting in the values for Q, X, and A, we get:
W = (25 MGD) / (5 * 24 hr/day * 60 min/hr * 60 s/min * 2.5 m^3/day/m^2 * 5 * L)
Simplifying, we get:
W = 0.023 L
So, the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
Therefore, The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and a rectangular clarifier's minimum width is 0.023 times the length when the length-to-width ratio is 5:1.
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Which statement is true of a catalyst in a reaction?
A. It acts as a reactant, in place of the original reactant.
B. It gets used up in the reaction.
C. It changes the activation energy required for the reaction.
D. It makes a reaction faster by adding energy.
Answer:
Hello There!!
Explanation:
The answer is=>C. It changes the activation energy required for the reaction.
hope this helps,have a great day!!
~Pinky~
The true statement for a catalyst used in a reaction is that it makes a reaction faster by adding energy. The correct option is D.
What is a catalyst?A catalyst is a substance that increases the chemical reaction rate without undergoing any permanent chemical change in itself. It makes the reaction faster.
The correct option is D.
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What is the name of the scientist and science fiction writer: *
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
A child with a mass of 12.32kg weight how much? Show all work including a equation
Answer:
123.2newtons
Explanation:
weight =mass × gravity
w= m×g
gravitational pull is approximately 10N/Kg
w= 12.32kg×10n/kg
=123.2newtons or 12.3N
What are the limitations of sending information using electronic waves
Answer:
The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.
A Boulder drops in the water and creates a wave with a period of 2s/cycle and a wavelength of .75 m/cycle. How fast is the wave moving ?
Answer:
v = 0.375 m/s
Explanation:
Given that,
The wavelength of a wave is 0.75 m/cycle
The period of a wave is 2s/cycle
We need to find the speed of the wave. We know that,
[tex]v=\dfrac{d}{t}[/tex]
Substitute all the values,
[tex]v=\dfrac{0.75}{2}\\\\v=0.375\ m/s[/tex]
So, the speed of the wave is equal to 0.375 m/s.
A 2kg mass moving at a speed of 3 m/s is stopped by a constant force of 15N. How many seconds must the force act on the mass to stop it.
Answer:
t = 0.4 seconds
Explanation:
Given that,
Mass of the object, m = 2 kg
Initial speed of the object, u = 3 m/s
Finally, it stops, v = 0
Constant force applied to the object, F = 15 N
We know that,
Force, F = ma
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s[/tex]
So, it will take 0.4 seconds to stop the mass.
provides some pertinent background for this problem. A pendulum is constructed from a thin, rigid, and uniform rod with a small sphere attached to the end opposite the pivot. This arrangement is a good approximation to a simple pendulum (period = 0.61 s), because the mass of the sphere (lead) is much greater than the mass of the rod (aluminum). When the sphere is removed, the pendulum no longer is a simple pendulum, but is then a physical pendulum. What is the period of the physical pendulum?
Answer:
the period of the physical pendulum is 0.498 s
Explanation:
Given the data in the question;
[tex]T_{simple[/tex] = 0.61 s
we know that, the relationship between T and angular frequency is;
T = 2π/ω ---------- let this be equation 1
Also, the angular frequency of physical pendulum is;
ω = √(mgL / [tex]I[/tex] ) ------ let this equation 2
where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and [tex]I[/tex] is moment of inertia of rod.
Now, moment of inertia of thin uniform rod D is;
[tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD²
since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.
we substitute equation 2 into equation 1
we have;
T = 2π/ω OR T = 2π/√(mgL/[tex]I[/tex]) OR T = 2π√([tex]I[/tex]/mgL)
so we can use [tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD² for moment of inertia of the rod
Since center of gravity of the uniform rod lies at the center of rod
so that L = [tex]\frac{1}{2}[/tex]D.
now, substituting these equations, the period becomes;
T = 2π/√([tex]I[/tex]/mgL) OR T = [tex]2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } }[/tex] OR T = 2π√(2D/3g ) ----- equation 3
length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),
we have;
ω[tex]_{simple[/tex] = 2π/[tex]T_{simple[/tex] OR ω[tex]_{simple[/tex] = √(g/D) OR ω[tex]_{simple[/tex] = 2π√( D/g )
so we simple solve for D/g and insert into equation 3
so we have;
T = √(2/3) × [tex]T_{simple[/tex]
we substitute in value of [tex]T_{simple[/tex]
T = √(2/3) × 0.61 s
T = 0.498 s
Therefore, the period of the physical pendulum is 0.498 s
1: Which person is not doing work?
O A. A person climbing a hill
O B. Someone climbing stairs
O C. A person lifting a bag of sand
O D. A person holding a baby
Answer:
D
Explanation:
The speed of light is 3 x 10 m/s.
Calculate the frequency of light that is absorbed the most by the 100m length of fibre.
Give your answer in standard form.
Answer:
[tex]3 \times 10 {}^6[/tex]
Newton's law of universal gravitation is represented by
GMm
where F is the magnitude of the gravitational force
exerted by one small object on another, M and mare
the masses of the objects, and ris a distance. Force has
the SI units kg m/s. What are the SI units of the pro-
portionality constant GP
Answer:
i҈ d҈o҈n҈t҈ k҈n҈o҈w҈ w҈h҈a҈t҈ y҈o҈u҈r҈ s҈a҈y҈i҈n҈v҈ b҈c҈h҈
Answer:
[tex]m^{3}kg^{-1} s^{-2}[/tex]
Explanation:
Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the string. In the questions below, assume you only change one aspect of the system at a time.
1. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the speed of the wave?
2. If you double the tension in the string, what will happen to the speed of the wave?
3. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the wavelength of the propagating wave?
4. If you double the tension in the string, without changing the rate at which you're shaking it, what will happen to the wavelength of the wave?
For each question, choose from the following choices:
a. It will double.
b. It will remain unchanged.
c. It will increase by a factor of √ 2.
d. It will increase by a factor of 4.
e. It will be half as fast/long.
Answer:
Part 1:
Option B is correct (It will remain unchanged).
Part 2:
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Option E is correct (It will be half as fast/long.)
Part 4:
Option C is correct (It will increase by a factor of √ 2.)
Explanation:
Formula we are going to use:
V=f*λ
Where:
V is the speed of Sound
f is the frequency of wave
λ is the wavelength.
The speed of wave , tension and linear density have following relation:
[tex]V=\sqrt{F/\rho}[/tex]
Where:
V is the speed of Sound (Initial)
F is the tension in string (Initial)
[tex]\rho[/tex] is the linear density of string (Constant)
Terms:
V' is the new speed
f' is the new frequency
λ' is the wavelength
Solution:
Part 1:
From [tex]V=\sqrt{F/\rho}[/tex]:
Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.
Option B is correct (It will remain unchanged)
Part 2:
If F'=2F then
[tex]V=\sqrt{F/\rho}[/tex]
[tex]V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V[/tex]
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Formula we are going to use:
V=f*λ
Given f'=2f,
Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.
V'=f'*λ'
f*λ=f'*λ'
f*λ=2f*λ'
Solving above Equation:
λ'=λ/2
Option E is correct (It will be half as fast/long.)
Part 4:
T'=2T means [tex]V'=\sqrt{2}V[/tex] (From Part 1)
f'=f
Now:
V'=f'*λ'
[tex]\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda[/tex]
Option C is correct (It will increase by a factor of √ 2.)
In an electrical circuit, electrons move from the __________.
A. Negative pole to negative pole B. Negative pole to positive pole
C. Positive pole to positive pole
Answer:
the answer is B from negative pole to positive pole
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 95.0 cm and diameter 2.00 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g
Answer:
[tex]22.84\ \text{N}[/tex]
Explanation:
[tex]\rho[/tex] = Density = [tex]7800\ \text{kg/m}^3[/tex]
h = Length of rod = 95 cm
d = Diameter of rod = 2 cm
r = Radius = [tex]\dfrac{d}{2}=1\ \text{cm}[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
V = Volume of rod = [tex]\pi r^2h[/tex]
Mass is given by
[tex]m=V\rho[/tex]
Weight is given by
[tex]w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi\times (1\times 10^{-2})^2\times (95\times 10^{-2})\times 7800\times 9.81\\\Rightarrow w=22.84\ \text{N}[/tex]
The weight of the rod is [tex]22.84\ \text{N}[/tex].
What are fossil fuels composed of
Oxygen and carbon
Rocks under extreme pressure
Remains of living things
Answer:
C. Remains of living things
Explanation:
They are made up of dead animals or plants. Coal, Oil, and Natural Gas are the three types of fossil fuels and all of them come from dead organisms. Even the name Fossil Fuels, sounds like a name for something like this.
Hope this Helps ʕ•ᴥ•ʔ
Answer:
C
Explanation:
took the test
A current of 8 A is used to operate a Nespresso coffee machine. Choose the most suitable fuse size from the following
- 3 A
- 5 A
- 13A
-10 A
It needs fuse of size 3A to be operated
Answer: 10 A
Explanation: The 3a and 5 a will blow immediately which would not allow you to use the coffee machine
The 13 a is too high and might lead to damage to the coffee machine or a fire being started
10 A is perfect because its low enough that if their was a power surge it would be blown without damaging anything else and it is high enough to let the coffee machine work without any trouble
From Coulomb's Law:
Electric force is:
A. directly proportional to distance.
B. inversely proportional to distance.
C. directly proportional to the square of the distance.
D. inversely proportional to the square of the distance.
Answer:
D
Explanation:
Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carrying three blocks instead of one, with the
fan still blowing the same direction, what could the x vs t graph look like?
A Graph A
B. Graph B
OC. Graph C
O D. Graph D
Answer:
Graph C
Explanation:
With the same force and more mass, the position in time will still be parabolic
i.e. x = ½at², but the rate of acceleration will be lower so the position curve will be broader.
In a city with an air-pollution problem, a bus has no combustion engine. It runs on energy drawn from a large, rapidly rotating flywheel under the floor of the bus. The flywheel is spun up to its maximum rotation rate of 4000 rev/min by an electric motor at the bus terminal. Every time the bus speeds up, the flywheel slows down slightly. The bus is equipped with regenerative braking so that the flywheel can speed up when the bus slows down. The flywheel is a uniform solid cylinder with mass 1600 kg and radius 0.650 m. The bus body does work against air resistance and rolling resistance at the average rate of 18.0 hp as it travels with an average speed of 40 km/h. How far can the bus travel before the flywheel has to be spun up to speed again
Answer:
the bus can travel 24.54 km before the flywheel has to be spun up to speed again
Explanation:
Given the data in the question;
mass of wheel m = 1600 kg
radius of the fly wheel r = 0.650 m
angular speed of the wheel ω = 4000 rev/min = 418.879 rad/s
Average speed of the bus v = 40 km/h = 11.1111 m/s
Power p = 18 hp = 13428 watt
So moment of inertia of the fly wheel is;
[tex]I[/tex] = [tex]\frac{1}{2}[/tex]mr²
we substitute
[tex]I[/tex] = [tex]\frac{1}{2}[/tex] × 1600 kg × (0.650 m)²
[tex]I[/tex] = 338 kgm²
So, the rotational energy of the bus will be;
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex][tex]I[/tex]ω²
we substitute
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex] × 338 kgm² × ( 418.879 rad/s )
[tex]E_r[/tex] = 29652675.212329 J
relation of power to energy
P = E / t
but we know that time t = distance / velocity
t = d/v
∴
P = E / ( d/v)
we solve for distance (d)
P = Ev / d
Pd = Ev
d = Ev / P
so we substitute
d = [( 29652675.212329 J )( 11.1111 m/s )] / [ 13428 W ]
d = 24536.33 m
d = 24.54 km
Therefore, the bus can travel 24.54 km before the flywheel has to be spun up to speed again