how does the resting energy expenditure change as a person ages

Answers

Answer 1

Answer:

Resting energy expenditure (REE) decreases from young to old age by 1% to 2% per decade [1]. This is partly explained by age-related decreases in fat free mass (FFM) [2]. FFM accounts for 50%–70% of the variance in REE [3,4,5].Explanation:


Related Questions

A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe very large accelerations.
Part A) What is the acceleration at the end of a test tubethat is 10 cm from the axis of rotation?
Part B) For comparison, what is the magnitude of theacceleration a test tube would experience if dropped from a heightof 1.0 m and stopped in a 1.0-ms-long encounter with a hardfloor?

Answers

Answer:

A)  a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²

Explanation:

Part A) The relation of the test tube is centripetal

               a_c = v² / r

the angular and linear variables are related

              v = w r

we substitute

               a_c = w² r

let's reduce the magnitudes to the SI system

              w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s

               r = 1 cm (1 m / 100 cm) = 0.10 m

let's calculate

              a_c = 418.88² 0.1

               a_c = 1.75 10⁴ m / s²

part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor

as part of rest the initial velocity is zero and on the floor the height is zero

                v² = v₀² - 2g (y- y₀)

                v² = 0 - 2 9.8 (0 + 1)

                v =√19.6

                v = -4.427 m / s

now let's look for the applied steel to stop the test tube

                v_f = v + a t

                0 = v + at

                a = -v / t

                a = 4.427 / 0.001

                a = 4.43 10³ m / s²

A block starting from rest slides down the length of an 18 plank with an acceleration of 4.0 meters per second. How long does the block take to reach the bottom?

Answers

Answer:

[tex]\boxed{\text{\sf \Large 3.0 s}}[/tex]

Explanation:

Use distance formula

[tex]\displaystyle d=ut+\frac{1}{2} at^2[/tex]

[tex]u= \text{\sf initial velocity}\\d= \text{\sf distance}\\a= \text{\sf acceleration}\\t= \text{\sf time taken}[/tex]

[tex]\displaystyle 18=0 \times t+\frac{1}{2} \times 4 \times t^2[/tex]

[tex]t=3[/tex]

A block starting from rest slides down the length of an 18 m plank with an acceleration of 4.0 meters per second square. Time taken by the block  to reach at the bottom is 3 sec.

What is acceleration?

The rate at which an object changes its velocity is known as acceleration. Acceleration is a vector quantity. If an object's velocity is changing then it is accelerating and an object with a constant velocity is not accelerating.

The speed at which something moves in a specific direction is known as its velocity. As an illustration, think of the speed of a car travelling north on a highway or the speed at which a rocket takes off.

Given that in the question block slides down an 18 m plank length with an acceleration of 4.0 meters per second square when it begins at rest.

Using equation of motion,

S = ut + (1/2)at²

s is distance, s = 18 m

u is initial velocity, u = 0

a is acceleration, a = 4 m/sec²

t is time

18 = 0*t + (1/2)*4*t

solving we get t = 3 sec.

Time taken by the block  to reach at the bottom is 3 sec.

To learn more about acceleration refer to the link:

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1. Is it possible for the ball to move so quickly that the angle between the cable and vertical post stays at ninety degrees?
2. When the ball is moving in a horizontal circle, what vertical force (or component) balances gravity?
3. What happens to the centripetal force as the length of the cord increases?

Answers

Answer:

Tetherball is an interesting game in which two players tries to hit the ball hard so that it goes around the

pole.Each time the player hits the ball, it's orbit rises higher off the ground.Let's understand the physics

behind this.The motion of a tetherball is governed by two forces.These two forces combine to generate a

net force, i.e. centripetal force.If the ball is moving more quickly, it requires a greater centripetal force,

which in turn requires a greater tension force.Since the ball's weight hasn't changed, the angle of the

tension force changes until the ball is in vertical equilibrium.

To access this physics simulation visit: http://goo.gl/xVdwgO Page 02Exploration Series www.ck12.org

Ball Mass : This slider controls the mass of the ball. A ball with more mass will have more inertia, requiring

a greater net force to accelerate it. A ball with more mass will ALSO have a greater gravitational force

acting on it. Watch both of these effects occur when you manipulate this slider.

Cable Length : This slider controls the length of the cable. A longer cable is capable of allowing a greater

circular radius of motion for the ball. It is important to remember that the radius of the circular motion is

NOT equal to the length of the cable. Instead, if you want to understand the size of the circle of the ball's

motion, ignore the cable and just imagine the path of the ball.

Ball Speed : This slider controls the speed of the ball - imagine a kid just hit the ball and it sped up. A ball

moving more quickly is also accelerating more quickly because its velocity is changing as it moves in a

circle (remember that changes in DIRECTION of velocity 'count' as changes to velocity).

Force Diagram : This allows you to turn on or off the diagram of the forces acting on the ball. Look for the

ball to be in vertical force balance, which means the vertical component of tension is canceled by the

gravitational force. The ball should NOT be in horizontal force balance - it is accelerating towards the center

of the circle! It is important to note that this free body diagram should really be moving with the ball so that

To access this physics simulation visit: http://goo.gl/xVdwgO Page 03Exploration Series www.ck12.org

the tension force always points along the cord - we are just showing the forces at the moment the ball is at

the furthest-right on this screen.

Centripetal force vs Tetherball speed : This is a plot of centripetal force required to keep the ball in

circular orbit about the pole as a function of its speed. As expected, a more quickly-moving ball is changing

in velocity more often in a given amount of time, and so is accelerating more. This greater (centripetal, or

center-pointing) acceleration requires a greater net force.

Explanation:

a. If half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve on dry concrete where the coefficient of kinetic friction is 0.7 and the coefficient of static friction is 1m/s^2.
b. Will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at this rate where the coefficient of kinetic friction is 0.3 and the coefficient of static friction is 0.55?
c. Answer both of these questions for the case that the truck has four-wheel drive, and the cabinet is wooden.

Answers

Answer:

A) a_max = 4.9 m/s²

B) the metal cabinet will not slip.

C) a_max = 9.8 m/s². The cabinet will slip.

Explanation:

A) We are given;

Coefficient of static friction; μ_s = 1

Coefficient of kinetic friction; μ_k = 0.7

Formula for maximum static friction;

F_s = μ_s•N

We are dealing with half of the weight of a flatbed truck. Thus;

N = mg/2

Thus;

F_s(max) = ½μ_s•mg

Now, the maximum acceleration it can achieve on dry concrete will be when the Maximum static friction is reached.

Because after maximum static friction, the cabinet will slip.

Thus; F_s(max) = ma

Therefore,

ma = ½μ_s•mg

m will cancel out to give;

a = ½μ_s•g

a = ½ × 1 × 9.8

a_max = 4.9 m/s²

B) we are told that the coefficient of static friction is now 0.55

Thus, the friction between the metal and the wood is;

F = μ_s•g = 0.55 × 9.8

F = 5.39 N

The acceleration gotten in the first part is less than μ_s•g = 5.39 N, then the metal cabinet will not slip.

C) Now, if we are considering a 4 wheel drive, then we will not divide the mass by 2 and so; N = mg

Like we did in A above;

ma = μ_s•mg

a = μ_s•g

a = 1 × 9.8

a = 9.8 m/s²

Now, this value of a_max is greater than μ_s•g in answer A above.

Thus, a_max > μ_s•g and thus, the cabinet will slip.

What are Heredity and Punnett Squares?

Answers

Answer: A Punnett square can be used to predict genotype and phenotypes of offspring from genetic crosses. ... In the P generation, one parent has a dominant yellow phenotype and the genotype YY, and the other parent has the recessive green phenotype and the genotype yy.

Explanation:

A system consists of a copper tank whose mass is 13 kg, 4 kg of liquid water, and an electrical resistor of negligible mass. The system is insulated on its outer surface. Initially, the temperature of the copper is 27oC and the temperature of the water is 50oC. The electrical resistor transfers 120 kJ of energy to the system. Eventually the system comes to equilibrium. Determine the final equilibrium temperature (in oC).

Answers

Answer:

T =  30.42°C

Explanation:

According to the conservation of energy principle:

[tex]Energy\ Given\ by\ Resistor = Heat\ Gain\ by\ Copper + Heat\ Gain\ by\ Water\\E = m_{c}C_{c}(T_{2c} - T_{1c}) + m_{w}C_{w}(T_{2w} - T_{1w})[/tex]

E = 120 KJ

mc = mass of copper = 13 kg

Cc = specific heat capacity of copper = 0.385 KJ/kg.°C

T2c = T2w = Final Equilibrium Temperature = T = ?

T1c = Initial Temperature of Copper = 27°C

T1w = Initial Temperature of Water = 50°C

mw = mass of water = 4 kg

Cw = specific heat capacity of water = 4.2 KJ/kg.°C

Therefore,

[tex]120\ KJ = (13\ kg)(0.385\ KJ/kg^oC)(T-27^oC) + (4\ kg)(4.2\ KJ/kg^oC)(T-50^oC)\\120\ KJ - 135.135\ KJ - 840\ KJ = (- 5.005T - 16.8 T)\ KJ/^oC\\T = \frac{-855.135\ KJ}{-28.105\ KJ/^oC}\\[/tex]

T =  30.42°C

he inductance of a tuning circuit of an AM radio is 4 mH. Find the capacitance of the circuit required for reception at 1200 kHz.

Answers

Answer:

4.4pF

Explanation:

the capacitance of the circuit required for reception is given:

wL =  [tex]\frac{1}{wC}[/tex]

w = 2π [tex]f[/tex]

Using both equation

Capacitance is given

C =   1 - 4π2  f2 L

1- 4×9.8969×144×10 10 ×0.004

​=4.4pF

A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot

Answers

The answer is Copper

On half of the moon appears to be lit (Light is on the RIGHT side of the moon)

this is science btw!!

Answers

Answer:

Moon appears lit on the right half of the Moon during the First Quarter. The Moon appears lit on the left side during the Third Quarter because the Moon is on the other side of Earth. Again, if you think of the baseball analogy, and you’re standing at home plate, the first base or First Quarter is on your right side.

Explanation:

i hope is help

Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the drive force is shut off, the snowmobile coasts to a halt. The snowmobile and its rider have a mass of 128 kg. Under the influence of a drive force of 195 N, it is moving at a constant velocity whose magnitude is 5.90 m/s. The drive force is then shut off. Find (a) the distance in which the snowmobile coasts to a halt and (b) the time required to do so.

Answers

Answer:

a) Δx = 11.6 m

b) t = 3.9 s

Explanation:

a)

Since the snowmobile is moving at constant speed, and the drive force is 195 N, this means that thereis another force equal and opposite acting on it, according to Newton's 2nd Law, due to there is no acceleration present in the horizontal direction .This force is just the force of kinetic friction, and is equal to -195 N (assuming the positive direction as the direction of the movement).Once the drive force is shut off, the only force acting on the snowmobile remains the friction force.According Newton's 2nd Law, this force is causing a negative acceleration (actually slowing down the snowmobile) that can be found as follows:

       [tex]a = \frac{F_{fr} }{m} = \frac{-195N}{128kg} = -1.5 m/s2 (1)[/tex]

Assuming the friction force keeps constant, we can use the following kinematic equation in order to find the distance traveled under this acceleration before coming to an stop, as follows:

       [tex]v_{f} ^{2} -v_{o} ^{2} = 2* a* \Delta x (2)[/tex]

Taking into account that vf=0, replacing by the given (v₀) and a from (1), we can solve for Δx, as follows:

       [tex]\Delta x =- \frac{v_{o}^{2}}{2*a} =- \frac{(5.90m/s)^{2}}{2*(-1.5m/s2)} = 11.6 m (3)[/tex]

b)

We can find the time needed to come to an stop, applying the definition of acceleration, as follows:

       [tex]v_{f} = v_{o} + a*\Delta t (4)[/tex]

Since we have already said that the snowmobile comes to an stop, this means that vf = 0.Replacing a and v₀ as we did in (3), we can solve for Δt as follows:

       [tex]\Delta t = \frac{-v_{o} }{a} = \frac{-5.9m/s}{-1.5m/s2} = 3.9 s (5)[/tex]

You dip your finger into a pan of water twice each second, producing waves with crests that are separated by 0.19 m. (a) Determine the frequency of the water waves. Hz (b) Determine the period of the water waves. s (c) Determine the speed of the water waves.

Answers

Answer:

a) The frequency of the waves are = 2 Hz (since you are making two pulses every second)

b)The period of the waves is 0.19 m (as the consecutive crests are separated by 0.19 m)

c) V = L x f

v = 0.19 m x 2 S-1 (Hz is actually per second)

v = 0.38 ms-1

pe nis

9. Name the two different symbols used to store all digital data on microchips in binary code. Explain how only two options can store such a great variety of data, such as a digital picture of a kitten. (1 point)​

Answers

Answer:

x and y, or 0 and 1. These two symbols form hundreds of patterns that represent data like numbers, letters, even pictures, and videos. Digital images are made up of pixels, and each pixel contains binary code. When all that code comes together and the pixels are formed we can see things like family photo albums or we can watch a movie on our phones. We can even see a digital picture of a kitten I guess. k, bye.

Explanation:

6) The acceleration due to gravity on Mars surface is 37.9% of that on Earth. An
astronaut's life support backpack weighs 300 lb on Earth. What does it weigh on the
Red Planet?

Answers

Weight  is directly proportional to the acceleration of gravity wherever you happen to be at the moment.

If the backpack weighs 300 lb on Earth, and you take it to a place where gravity is 37.9% of Earth's gravity, then the backpack will weigh

(37.9%) x (300 lb)

(0.379) x (300 lb)

That's 113.7 lb.

The parallel plates in a capacitor, with a plate area of 6.70 cm2 and an air-filled separation of 2.50 mm, are charged by a 8.70 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 9.90 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

Answers

Answer:

a. 34.45 V

b. 89.80  pJ

c. 355.57  pJ

d. -265.67 pJ

Explanation:

(a) the potential difference between the plates

Since charge is conserved, charge before separation, Q = charge after separation, Q'

Q = C₁V₁ and C₁ = capacitance before separation = ε₀A/d₁ where A = area of plates = 6.70 cm² = 6.70 × 10⁻⁴ m²and d₁ = initial separation of plates = 2.50 mm = 2.50 × 10⁻³ m, V₁ = initial potential difference across plates = 8.70 V

Q' = C₂V₂ and C₂ = capacitance before separation = ε₀A/d₂ where A = area of plates = 6.70 cm² = 6.70 × 10⁻⁴ m² and d₁ = final separation of plates = 9.90 mm = 9.90 × 10⁻³ m. V₂ = final potential difference across plates = unknown

So, Q = Q'

C₁V₁ = C₂V₂

ε₀AV₁/d₁ = ε₀AV₂/d₂

So, V₁/d₁ = V₂/d₂

V₂ = V₁d₂/d₁

Substituting the values of the variables into the equation, we have

V₂ = 8.70 V × 9.90 mm/2.50 mm

V₂ =  8.70 V × 3.96

V₂ = 34.452 V

V₂ ≅ 34.45 V

(b) the initial stored energy

The energy stored in a capacitor U = 1/2CV².

So, the initial energy stored U₁ = 1/2C₁V₁² = ε₀AV₁²/2d₁

Substituting the values of the variables into the equation, we have

U₁ = ε₀AV₁²/2d₁

U₁ = 8.854 × 10⁻¹² F/m × 6.70 × 10⁻⁴ m² × (8.70V)²/(2 × 2.50 × 10⁻³ m)

U₁ = 4490.07 × 10⁻¹⁶ FmV²/5 × 10⁻³ m

U₁ = 898.01 × 10⁻¹³ J

U₁ = 89.801 × 10⁻¹² J

U₁ = 89.801  pJ

U₁ ≅ 89.80  pJ

(c) the final stored energy

The energy stored in a capacitor U = 1/2CV².

So, the initial energy stored U₂ = 1/2C₂V₂² = ε₀AV₂²/2d₂

Substituting the values of the variables into the equation, we have

U₂ = ε₀AV₂²/2d₂

U₂ = 8.854 × 10⁻¹² F/m × 6.70 × 10⁻⁴ m² × (34.45 V)²/(2 × 9.90 × 10⁻³ m)

U₂ = 70403.26 × 10⁻¹⁶ FmV²/19.8 × 10⁻³ m

U₂ = 3555.72 × 10⁻¹³ J

U₂ = 355.572 × 10⁻¹² J

U₂ = 355.572  pJ

U₂ ≅ 355.57  pJ

(d) the work required to separate the plates.

The work required to separate the plates W = -ΔU is the difference between the energy stored at the separation of 9.90 mm and 2.50 mm.

So, W = -(U₂ - U₁) = -(355.57  pJ - 89.80  pJ) = -265.67 pJ.

how were the outer planets formed?

Answers

Answer:

All planets including the outer larger planets were formed at the same time somewhere around 4.5 Billion years ago.

Explanation:

the young sun drove away most of the gas from the inner solar system, leaving behind the rocky cores also known as the terrestrial planets.

What is one disadvantage of sending information over long distances
wirelessly using digital signals?
O A. The signals become weaker the farther the receiver is from the
source.
B. The farther the signals travel, the more slowly they move.
C. The signals become stronger the farther the receiver is from the
source.
O D. The farther the signals travel, the easier they are to detect.

Answers

The disadvantage of sending information over long distances wirelessly using digital signals is "the signals become weaker the farther the receiver is from the source."

Since most of the signal which we use for communication are radio signal Radio signal are basically electromagnetic waves.As the wave moves forward it looses its amplitude.So basically radio signal becomes weaker for long distance.

What are radio signals?Radio signals or radio waves are a form of electromagnetic wave. Although this may sound complicated, it is possibly sufficient to say that these waves have both electric and magnetic components. They are the same as light rays, ultra-violet and infra-red. The only difference is in the wavelength of the waves.

Thus , The disadvantage of sending information over long distances wirelessly using digital signals is "the signals become weaker the farther the receiver is from the source."

Learn more about Radio waves here -

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PLEASE HELP!

what would the answer be?

Answers

Answer:

Tie aluminium foil on each end of the battery using rubber band, then use copper wire to attach the led to the aluminium foil...... probably would work

What are some ways the government can help reduce greenhouse gases?

Answers

Answer:

Switching power plants, for example, from coal-burning to gas-burning can significantly reduce emissions. Equip fossil fuel plants with carbon capture and storage technology. ... Although it doesn't exactly reduce emissions, carbon capture technology does prevent emissions from reaching the atmosphere.

Which has the greater kinetic energy–a 1-ton car moving at 30 m/s or a half-ton car
moving at 60 m/s?
A) Both have the same kinetic energy
B) The half-ton car
C) The 1-ton car
D) It cannot be determined because the mass of the cars can't be found

Answers

Answer:

B). half-ton car

Explanation:

We can find Kinectic using below expresion.

m= mass of the object

v= velocity

mass (1) 1 ton= 1000kg

Mass(2)0.5= 500kg

K.E= 1/2 mv^2

For 1 ton car

Substitute the values

Kinectic energy= 1/2( 1000) 30^2

= 450,000J

For 0.5 ton car

Kinectic energy= 1/2(500)60^2

= 900,000J

Hence, half-ton car has greater Kinectic energy

Describe what happens to the magnitude of the net electrostatic force on the electron as the electron
is moved toward the positive plate. [1]

Answers

When the electron is moved toward the positive plate, the electrostatic force increases causing the electron to be attracted to the positive plate.

What is the electrostatic force?

The electrostatic force is the force tat acts between two charges. The nature of this force is described by the Coulumb law.

When the electron is moved toward the positive plate, the electrostatic force increases causing the electron to be attracted to the positive plate.

Learn more about electrostatic force:https://brainly.com/question/1851822

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why do the stars rotate​

Answers

Answer:

Angular momentum

Explanation:

Stars are formed as a result of a collapse of a low-temperature cloud of gas and dust. During the colapse conservation of angular momentum causes any small net rotation of the cloud to increase thus forcing the material into rotating

Can atoms go bad?, not in the reversible way like ionization and isotopes but really malfunction our die.​

Answers

Answer:

atoms cannot go bad

Explanation:

Because they stay alive and get good nutriants

The magnetic field of a magnet is strongest
a. at its north pole.
b. at its south pole.
c. in the middle.
d. at both of its poles.

Answers

The answer is C !!!!

A child falls sideways off the sled while sledding on frictionless ice. What happens to the velocity of the sled

Answers

Answer:

Same as before.

Explanation:

we can use momentum conservation to solve the problem.

Let mass of child be m and of the sled be M. Also let both have initial velocity u.

since, child fells off on the sled it will still have same velocity of ''u''.

By momentum conservation we have,

(M + m) x u = m x u + M x v

⇒ Mu=Mv

⇒ u=v

Hence, velocity of the sled remains the same.

If I jump 4.8m/s South onto a sitting boat, what velocity do the boat and I travel at
when I land if I am 140kg and the boat is 160kg?

Answers

Answer:

An 85.0 kg fishermen jumps from a dock into an135 kg boat at rest. If the velocity of the fisherman as he leaves the dock is 4.30 m/s west, what is the final velocity of the boat and fisherman together?

)) What do these two changes have in common?
mixing chocolate syrup into milk
rain forming in a cloud
) Select all that apply.
Both involve chemical bonds breaking.
Both are changes of state.
Both are only physical changes.
Both are chemical changes.

Answers

Answer:

Both are only physical changes

Explanation:

A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.

According to this question, two processes were given as follows:

1. mixing chocolate syrup into milk

2. rain forming in a cloud

These two processes are similar in the sense that they are both examples of physical changes.

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.310 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. m/s (b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2 (c) Calculate the force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Answers

Answer:A)u =4.295m/s  , B)a = 29.746m/s²   C) F=3,153N

Explanation:

Using the kinematic expression  

v² = u² - 2as

where

u = initial velocity

v = final velocity

s = distance

g = acceleration due to gravity .

Given that he reaches a height of 0.940 m above the floor,

the final velocity  = 0

Here, acceleration due to gravity is acting in  opposite the initial direction of motion. So, a=-9.81 m/s.

v² = u² + 2as

0² - u² = 2 (- 9.81) × 0.940

- u² = 2 × - 9.81 × 0.920

- u² = -18.4428

cancelling the minus in both sides , we have that  

u² = 18.4428

u = √18.4428

u =4.295m/s

(b) His acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2

Using v² = u² + 2as

where u = initial speed of basketball player before lengthening = 0 m/s,

v = final speed of basketball player after lengthening =  4.295m/s,

a = acceleration while  straightening his legs

s = distance moved during lengthening = 0.310m

v² = u² + 2as  

 a = (v² - u²)/2s

a = (4.29m/s)² - (0 m/s)²)/(2 × 0.310m)

a = (18.4428 m²/s² - 0 m²/s²)/(0.62 m)

a = (18.4428 m²/s²/(0.62 m)

a = 29.746m/s²

c) The force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Force= mass x acceleration.

F = 106 kg X 29.746m/s²

 F = 3,153.076 rounded to  3,153N

What is the tension on a rope holding up a 7.50 kg box?
A) 7.50N
B) 73.5N1
C) 7.3N
D) 0.765N

Answers

Answer:

B

Explanation:

F=m×g

=7.50×9.8 (standard gravitational force of earth)

=73.5N

The correct option is (b) 73.5N.

Tension is the force produced by pulling something tightly, a strain in a relationship, or physical or mental strain. The feeling of trying to reach a deadline is an illustration of tension. For example -Pulling the rubber band's two ends apart further and further is an illustration of tension.

Is tension force?The force transferred through a rope, string, or wire when two opposing forces pull on it is known as the tension force. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.

F= 7.50 kg is given in this question .

So, we apply formula

                            F=m×g

                           =7.50×9.8          (g= 9.8standard gravitational force of earth)

                            =73.5N

Therefore, The tension on a rope holding up is 73.5N .

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The acceleration used for the height is 9.81 m/s2 because it is the acceleration due to gravity. (true or false)

Answers

Answer:

true

Explanation:

Gravity (or the acceleration due to gravity) is 9.81 meters per second squared, on the surface of Earth, because of the size of Earth and the distance we are on its surface from its center.

The new roller coaster at Carowinds flies along at 80 m/s. How long does it take to
travel 16000 meters of track?

Answers

It takes about a really long time
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