how is the process of finding the mass of a gas different from that of finding the mass of a liquid why is the difference necessary​

Answer:

The acceleration is 4

Explanation:

use the formula v= change in position/change in time for vecter quantity's which will be in word problems that say acceleration or velocity.

Answer:

  6.23 mm

Explanation:

The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...

  a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²

Then the force on the car (in addition to that required to counter gravity) is ...

  F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N

The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...

  ((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm

The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.

_____

We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).

Answer:

Explanation:

Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,

its centrifugal acceleration = speed^2 / radius

= 23^2 / 600

= 0.8817 m/s^2

The centrifugal force in turn = mass * acceleration

= 1300 * 0.8817

= 1146.17 N

This force is absorbed by suspension springs of the four wheels.

Given spring constant of 4.6 x 10^4 N/m and 4 springs total,

the extra compression = Force / number of springs / spring constant

= 1146.17 / 4 / 4.6 x 10^4

= 0.006229 m

= 6.23 mm

Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.

Answer:

200000 joules or 200 kilojoules

Explanation:

Kinetic energy = 1/2m(v^v)

Kinetic energy = 1/2*1000* 20^20

Kinetic energy = 500*400

Kinetic energy = 200000 joules or 200 kilojoules

Answer:

It would take 16 hours

Explanation:

800 divided by 50 = 16

Brainly pls

Answer: [tex]t[/tex] = 16

Explanation:

Hey there! I will give the following reason, if you have any questions feel free to ask me in the comments below.

Because a train is traveling at a speed of 50 km/hr and a train needs to travel 800 km, you would need to divide the distance by the speed to find the hours.

Formula: [tex]t[/tex] = [tex]\frac{distance}{speed}[/tex]

The distance would be 800, and the speed would be 50.

[tex]t = \frac{800}{50}[/tex]

Simplify.

[tex]t = 16[/tex]

~I hope this helps you! :)~

Complete Question

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string,  If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?

Answer:

The value is [tex]\theta = 4.41^o[/tex]      

Explanation:

From the question we are told that

  The mass of the rock is  [tex]m_r = 940 \ g = 0.94 \ kg[/tex]

   The length of the string is [tex]l = 1.30 \ m[/tex]

    The breaking strength(i.e the maximum tension) on the string is [tex]T = 120 \ N[/tex]

Gnerally the vertical component of the tension experienced by the string is mathematically represented as

     [tex]T_v = T sin(\theta)[/tex]

Generally this vertical component  of tension is equivalent to the weight of the rock

So

     [tex]Tsin (\theta) = mg[/tex]

=>  [tex]\theta = sin^{-1} [\frac{mg}{ T} ][/tex]

=>    [tex]\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ][/tex]

=>    [tex]\theta = 4.41^o[/tex]      

Answer:

acceleration

Explanation: how fast something can get to a certain speed

Answer: Safety symbols have a triangle shape, usually the colors are red, orange, and yellow. On the symbol of an element there can be a line going across diagonal They can have symbols that have a person slipping to let you know if someones mopping you may slip. Others may have one that has fire that lets you know fire may happen. And last but not least others can have deers on them to let you deers are on the street/road. Hope this helps.

Explanation:

Answer: 16.44 kg

Explanation:

Answer:

I think its B. wait...U love ME?????

Answer:

Yes, the velocity would also be zero.

Explanation:

Acceleration is the change in velocity over time, therefore, there has to be a change in velocity for something to accelerate. which means without acceleration, the object has no velocity.

Answer:

If the force is higher then the resitance o fht eobject then force will make object accelerate.

Explanation:

Does that make sense. If you need something else as an answer tell me in the comments and please mark with a heart and brainliest. If you don't mind

We know:

Force =Mass×Accerlation

[tex]∴Accerlation = \dfrac{force}{mass} [/tex]

So by seeing this formula we came to know that accerlation is directly proportional to force and inversely proportional to mass.

So by increase of force acceleration also increases.

Answer:

The resistance force that the soil exerts on the plough is 160 Newtons.

Explanation:

Fr = m.a

Fr = 80. 0,5

Fr = 40 N

Ft - F = Fr

200 - F = 40

F = 200 - 40

F = 160 Newtons

Answer:

☝ Some of the properties of sedimentary rocks

Answer:

a) a= 19 m/s2, b ) F = F = 38 N

c)  the correct one is B

Explanation:

1) To solve this exercise, let's use the concept of torque, let's start by looking for the mass of the mass of the head, which is 65 of 65 kg

         m= 0.06  65 = 3.9 kg

torque is defined

        τ = F x R

the bold indicate vectors

        τ = F R sin θ

the force is the weight of the head and the distance R = 0.20 m

        τ = mg R sin θ

        τ = 3.9 9.8 0.2 sin 50

        τ = 5.86 N m

Newton's second law expression for rotational motion is

         τ = I α

In general, the head is approximated by a sphere, so the moment of foolishness with respect to the base of the neck (turning point) using the parallel axis theorem is

         I = I_sphere + m d²

Neck height data is not indicated, so we will assume that it is zero (d = 0)

         I = 2/5 m R²

angular and linear acceleration are related

        a = α R

        α = a / R

let's replace

         τ = 2/5 mR²  (a / R)

        a = 5/2 τ / mR

let's calculate

         a = 5/2 5.86 / (3.9 0.2)

         a = 18.8 m / s²

         a= 19 m/s²

2) as the neck and the head are related, the forces are action and reaction, therefore the neck force is

         F = m g

         F = 3.9 9.8 = 38.2 N

          F = 38 N

3) He asks us about the efficiency of the headrest, after reviewing the different alternatives, the correct one is B

Yes. A headrest ensures that both the head and the body experience the same forward force at approximately the same time.

Answer:

Yes

Explanation:

The star would have died over thousands of years ago but the light takes a long time for it to reach us on Earth.

Answer:

The new freezing point of water is -0.476°C.

Explanation:

Given that,

Mass of water = 4.62 kg

Mass of CaBr₂ = 236.5 g

We need to calculate the molality of solution

Using formula of molality

[tex]m=\dfrac{mass\ of\ CaBr_{2}}{molar\ mass\ of\ CaBr_{2}\times mass\ of\ water}[/tex]

Put the value into the formula

[tex]m=\dfrac{236.5}{200\times4.62}[/tex]

[tex]m=0.256\ mol/kg[/tex]

[tex]m=0.256\ m[/tex]

We need to calculate the depression in freezing point of water

Using formula of freezing point

[tex]\Delta T=m\times k[/tex]

Where, k = depression constant

m = molality of solution

Put the value into the formula

[tex]\Delta T=0.256\times1.86[/tex]

[tex]\Delta T=0.476^{\circ}C[/tex]

We know that,

The standard freezing point of water is 0°C

We need to find the new freezing point of water

Using formula for freezing point of water

Freezing point of 4.62 kg of water = freezing point of water-depression in freezing point of water

[tex]\Delta T'=0-\Delta T[/tex]

Put the value into the formula

[tex]\Delta T'=0-0.476[/tex]

Hence, The new freezing point of water is -0.476°C.

Answer:

The answer is 198.23 kg

Explanation:

To find the mass of an object given it's mass and acceleration we use the formula

where

m is the mass

F is the force

a is the acceleration

From the question

a = 92.54 m/s²

F = 18,344 N

We have

We have the final answer as

198.23 kg

Answer:

198.22

Explanation:

using m=f/a you divide the force by the acceleration to get the mass (18344 / 92.54) = 198.22

Answer:

The size will increase.

Explanation:

When you bend a plastic ruler, it's size will increase because it is elastic and will exhibit elastic deformation. When it is been bent, it will continue to stretch until it get to a point where it will not be able to regain it formal shape, it size wound of increase. Therefore when the ruler get to elastic limit and you have bend it to the point it cannot regain it's formal shape back, it will remain bent and if further force is apply on it,it will break.

Answer:

4.12 m/s^2

Explanation:

unbalanced force means the presence of resultant force (net force)

[tex]net \: force \: = mass \times accleration[/tex]

f = 28N

m = 6.8kg

a = ?

? = 28/6.8

= 4.1176...

approximately = 4.12 m/s^2

Answer:

ratio between m/v

or d= m/v

m= mass

v= volume

¡Hola!

For this problem, first, lets recabe information:

v = 0 m/s

t = 3 s

g = 9,82 m/s²

v' = ?

d = ?

First, for calculate the final velocity:

v' = v + g * t

v' = 0 m/s + 9,82 m/s² * 3 s

v' = 29,46 m/s [tex]\leftarrow \boxed{\text{Velocity} }[/tex]

Now, for calculate how far did it fall:

d = v * t + g * t^2 / 2

Like v = 0 m/s, we can simplificate equation:

d = g * t^2 / 2

d = 9,82 m/s² * (3 s)^2 / 2

d = 9,82 m/s² * 9 s² / 2

d = 88,38 m / 2

d = 44.19  m [tex]\leftarrow \boxed{\text{Distance} }[/tex]

¡Buena suerte!

Answer:

The angular speed   [tex]w = 0.5813 \ rad/s[/tex]

Explanation:

From the question we are told that

  The diameter is  d =  58.0 m    

Generally for the occupants feel that they have the same weight as they do on Earth then the centripetal acceleration of the circular ring must be  equal to the acceleration due to gravity this can be mathematically represented as

      [tex]a_c = g[/tex]

Here [tex]a_c[/tex] is the centripetal acceleration which is mathematically represented as

       [tex]a_c = w^2 * r[/tex]

Here r is the radius of the circular ring

=>    [tex]w^2 * r = g[/tex]

=>    [tex]w = \sqrt{\frac{g}{r} }[/tex]

=>   [tex]w = \sqrt{\frac{9.8}{ \frac{d}{2} } }[/tex]

=>   [tex]w = \sqrt{\frac{9.8}{ \frac{58.0 }{2} } }[/tex]

=>   [tex]w = 0.5813 \ rad/s[/tex]

Answer:

The size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

Explanation:

To determine the size of the magnetic force on the wire due to the Earth's magnetic field,

The magnetic force is given by the formula

F = ILB sinθ

Where F is the magnetic force on the wire

I is the electric current in Amperes (A)

L is is the length of wire in meters (m)

B is the magnetic field in Tesla (T)

and θ is the angle between current and magnetic field

From the question,

L = 0.30 m

I = 0.50 A

B = 0.50 gauss = 0.5 × 10⁻⁴ T (NOTE: 1 Gauss = 10⁻⁴ Tesla)

θ = 38°

Now, putting the values into the equation

F = ILB sinθ

F = 0.50 × 0.30 × 0.5 × 10⁻⁴ sin38°

F = 7.5 × 10⁻⁶ (0.61566)

F = 4.62 × 10⁻⁶ N

Hence, the size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

Okay, hun. Velocity is a vector quantity that measures displacement over a period of time. Velocity = Speed/Time (v=s/t). Hope this helped you. I took physics over 4 years ago. I'm more of a biology/chemistry person. (I major in those)