How many 3-digits numbers which are greater than 300 can be formed from 6
digits (1,2,3,4,5,6)? while
i. Repetition not allowed
ii. Repetition allowed

Answers

Answer 1

Explanation:

111 even numbers greater than 300 can be formed with the digits 1,2,3,4,5 if repetition of digits in a number is not allowed.


Related Questions

When you measure
with a multimeter, you must break open the circuit and connect the meter's test leads in series with other circuits components
A. voltage
B. power
C. current
D. resistance

Answers

Answer:

resistance

Explanation:

so as to determine the reading

which of the following is not arithmetic operations​

Answers

Explanation:

The basic arithmetic operations are addition, subtraction, multiplication, and division. There are more arithmetic operators like exponentiation, modulus operations, increment, decrement, etc. * - Multiplication operator. So, And operator is not an arithmetic operator.

Explain the importance of water quality in aquaculture business.

Answers

Answer:

this is very important the agricultural because there can be a risk of hight salt concentrations that can limit the amount of water plants can take

Answer:

Mantain the image of the business

Explanation:

Good water quality gives good images to others and furthers business

..................................................

Answers

..................................................

Answer: yayyyy free sh.it

Explanation:

Q.14
What is the most common way to isolate the CPU from the external circuit?
Select one:
A. OPTICAL ISOLATION
B. SMALL RELAYS
C. BRIDGE RECTIFIERS
D. RHEOSTATS

Answers

Answer:

A. optical isolation

Explanation:

well I can't really give a good explanation because I also saw the same question in my exams and option A was the correct answer

8. Which of these plastics is a themoplastic - melts or softens with heat.
Acrylic
Bakelite
Polyester resin
Melamine
Epoxy Resin

Could someone please help me, this is very urgent, I will pay an extra bonus if done correct.

Answers

Answer:

Acryclic

Explanation:

Hope it helps you!

explain the working and performance of a centrifugal clutch with a sketch​

Answers

Answer:

A centrifugal clutch works, as the name suggests, through centrifugal force.

One of the most common methods is by mounting the clutch onto the parallel or taper crank shaft of the engine.

When the crank shaft rotates the shaft of the clutch rotates at the same speed as the engine

How would I get this python code to run correctly? it's not working.​

Answers

Answer:

See Explanation

Explanation:

This question requires more information because you didn't state what the program is expected to do.

Reading through the program, I can assume that you want to first print all movie titles then prompt the user for a number and then print the move title in that location.

So, the correction is as follows:

Rewrite the first line of the program i.e. movie_titles = ["The grinch......."]

for each_movie_titles in movie_titles:

   print(each_movie_titles)

   

usernum = int(input("Number between 0 and 9 [inclusive]: "))

if usernum<10 and usernum>=0:

   print(movie_titles[usernum])

Line by line explanation

This iterates through the movie_titles list

for each_movie_titles in movie_titles:

This prints each movie title

   print(each_movie_titles)

This prompts the user for a number between 0 and 9    

usernum = int(input("Number between 0 and 9 [inclusive]: "))

This checks for valid range

if usernum<10 and usernum>=0:

If number is valid, this prints the movie title in that location

   print(movie_titles[usernum])

The hot-wire anemometer.' A hot-wire anemome ter is essentially a fine wire, usually made of platinum,which is heated electrically and inserted into a flowingfluid. The wire temperature, which is a function of the fluidtemperature, fluid velocity, and the rate of heating, may bedetermined by measuring its electrical resistance. It is used for measuring velocities and velocity fluctuations in flow systems. In this problem we analyze the temperature distribution in the wire element. We consider a wire of diameter D and length 2L supported at its ends (z = -L and z =+L) and mounted perpendicular to an air stream. An electric current of density I amp/cm^2 flows through the wire, and the heat thus generated is partially lost by convection to the air stream and partially by conduction toward the ends of the wire. Because of their size and their high electrical and thermal conductivity, the supports are not appreciably heated by the current, but remain at the temperature TL, which is the same as that of the approaching air stream. Heat loss by radiation is to be neglected.

Required:
Derive an equation for the steady-state temperature distribution in the wire, assuming that T depends on z alone.

Answers

Answer:

attached below

Explanation:

To derive the equation we have to make some assumptions

assumptions:

Assume T depends on Z alone

Assume uniform thermal and electrical conductivities (k and ke) in the wire, Assume  a uniform heat

transfer coefficient h from the wire to the air stream.

attached below is the required derivation of the equation

Hot engine oil with heat capacity rate of 4440 w/k (product of mass flow rate and specific heat) and an inlet temperature of 150°c flows through a double pipe heat exchanger. the double pipe heat exchanger is constructed of a 1.5-m-long copper pipe (k = 250 w/m·k) with an inner tube of inside diameter 2 cm and outside tube diameter of 2.25 cm. the inner diameter of the outer tube of the double pipe heat exchanger is 6 cm. oil flowing at a rate of 2 kg/s through inner tube exits the heat exchanger at a temperature of 50°c. the cold fluid, i. e., water enters the heat exchanger at 20°c and exits at 70°c. assuming the fouling factor on the oil side and water side to be 0.00015 m2 ·k/w and 0.0001 m2 ·k/w, respectively, determine the overall heat transfer coefficient on inner and outer surface of the copper tube.

Answers

Explanation:

fluid, i. e., water enters the heat exchanger at 20°c and exits at 70°c. assuming the fouling factor on the oil side and water side to be 0.00015 m2 ·k/w and 0.0001 m2 ·k/w, respectively, determine the overall heat transfer coefficient on inner and outer surface of the copper tube.xgjicbb .follow me

A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from the wall outlet. The number of turns in the primary is 300, and it delivers 500 mA (the secondary current) at an output voltage of 6.4 V (rms). (a) Should the transformer have more turns in the secondary compared to the primary, or fewer turns

Answers

Answer:

The secondary coil should have fewer turns compared to the primary coil.

Explanation:

[tex]N_p[/tex] = Number of turns in primary coil = 300

[tex]N_s[/tex] = Number of turns in secondary

[tex]V_p[/tex] = Voltage in primary coil = 120 V

[tex]V_s[/tex] = Voltage in secondary coil = 6.4 V

We have the relation

[tex]\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}\\\Rightarrow N_s=\dfrac{N_p}{V_p}\times V_s\\\Rightarrow N_s=\dfrac{300}{120}\times 6.4\\\Rightarrow N_s=16[/tex]

The secondary coil has 16 turns which is less than the turns in the primary coil.

write three ways of soil investigation of a site​

Answers

Methods of Soil Exploration
Open excavation.
Borings.
Subsurface soundings.
Geographical methods.

How to report the analysis and calorific values of fuel​

Answers

Answer: Shawty my lil baddie

Explanation:

Technician A says that ultra-high-strength steels (UHSS) are generally defined as those steels with tensile strengths greater than 700 MPa.
Technician B says that advanced high-strength steels (AHSS) are generally defined as those steels with tensile strengths from 375 MPa up to 1700
Who is right?
O A only
OB only
O Both A and B
O Neither A norb
Table of Contents

Answers

b only i think i’m not fully sure.

Designing is a way to generate solutions to a real-world problem experienced by humans.
True

False

Answers

True,My good sir/maam

The IRT has a vital responsibility in gathering forensic evidence, which is defined as collecting and preserving the information that can be used to reconstruct events.

a. True
b. False

Answers

The answer would be true

Two kilograms of air in a piston-cylinder assembly undergoes an isothermal
process from an initial state of 200 K, 300 kPa to 600 kPa.
How much work is done during the process, in kj?​

Answers

Answer:

a) 0.39795 kJ/K

b) 79.589.37 kJ

Explanation:

m = Mass of air = 2 kg

Temperature = 200 K

P₁ = Initial pressure = 300 kPa

P₂ = Final pressure = 600 kPa

R = mass-specific gas constant for air = 287.058 J/kgK

a) For isentropic process

∴ Entropy is generated in the process is 0.39795 kJ/K

b)

∴ Amount of lost work is 79.589.37 kJ

The inverted U-tube is used to measure the pressure difference between two points A and B in an inclined pipeline through which water flows. The differenceof level h=0.4m ; X=0.2; and Y=0.3m. Calculate the pressure difference between point B and A if the top of the manometer is filled with:
i) Air
ii) paraffin of relative density of 0.75

Answers

Answer:

i) 0.610 m or 610 mm

ii) 0.4 m or 400 mm

Explanation:

The pressure difference between the pipes is

a) Air

Pa + πha +Ha = Pb + πhb +Hb

Pa - Pb = π(hb-ha) + Hb-Ha

Relative density of air = 1.2754 kg /m3

Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm

b) paraffin of relative density of 0.75

Pa - Pb = π(hb-ha) + Hb-Ha

Pa - Pb = 0.75 * 0.4 + (0.3-0.2) = 0.4 m or 400 mm

Consider a fuel cell vehicle. The vehicle draws 30 kW of power at 60 mph and is 40% efficient at rated power. (It converts 40% of the energy stored in the hydrogen fuel to electric power.) You are asked to size the fuel cell system so that a driver can go at least 300 miles at 60 mph before refueling. Specify the minimum volume and weight requirements for the fuel cell system (fuel cell + fuel tank) given the following information:

• Fuel cell power density: 1 kW/L
• Fuel tank energy density (compressed hydrogen): 4 MJ/L

Answers

Answer:

minimum volume = 367.5 lit

minimum weight = 228.75 kg

The tensile strength of brittle materials may be determined using a variation of Equation 8.1. Compute the critical crack tip radius for an Al2O3 specimen that experiences tensile fracture at an applied stress of 275 MPa (40,000 psi). Assume a critical surface crack length of 2 × 10−3 mm and a theoretical fracture strength of E/10, where E is the modulus of elasticity.

Answers

Answer:

0.39 nM

Explanation:

The critical crack tip radius from the equation

attached below

for fracture to occur the бm will have to reach the fracture strength of material

i.e.  бm =  E/10

from equation 2 attached below

St = ( 400 * a * бo^2 ) / E^2 ------ 3

Given : a = 2*10^-3 mm , бo = 275 MPa, E = 393 * 10^3 MPa ( gotten from table)

Input given values into equation 3

St = 3.9 * 10^-7 ≈ 0.39 nM

A baker deck decorates 42 cupcakes and 30 minute she decorated cupcakes at a constant rate how many cups cage the baker decorate pre-minute

Answers

Answer: 1.4 cupcakes per minute.

Explanation:

Here's the correct question:

A baker decorates 42 cupcakes in 30 minutes. How many cupcakes can the baker decorate per minute?

Since the baker decorates 42 cupcakes in 30 minutes, the number of cupcakes that the baker decorates for each minutes since it's at a constant rate will be the total number of cupcakes made divided by the number of minutes. This will be:

= 42cupcakes / 30minutes

= 1.4 cupcakes per minute.

Therefore, the number of cupcakes that the baker can decorate per minute is 1.4cupcakes/minute

A hydraulic jump is formed in a 4m wide outlet just downstream of a control gate, which is located at the upstream end of the outlet. The flow depth upstream of the gate is 20 m. Assume there are no losses in the flow through the gate. If the outlet discharge is 40 m3/s, determine (6 points)a. Flow depth downstream of the jump (y1)b. Energy losses in the jump (between y1 and y2).

Answers

Answer:

Width w = 4m

Glow depth = y1 = 20m

Outlet discharge = 40m

V1= velocity of flow = 40/20*4 = 1/2 = 0.5m/s

Froud number = v1/√gy1

= 0.5/√9.81x20 = 0.0356

1. Y2/20 = 1/2[-1+√1+8*(0.0356)²]

Y2 = 0.05

2. Energy loss in the jump = (20-0.05)²/4x20x0.05

= 1985m

Jerry wants to manufacture flat metal sheets. Which process will he use?
A. Turning
B. Reaming
C. Blow molding
D. Cold rolling
E. Milling

Answers

Option choice d is the correct answer

Answer:

c) blow molding

Explanation: when making bottles, you have hot plastic and use a blowing technique to shape it

How to report the analysis and calorific values of fuel​

Answers

Answer: heat value of a fuel is the amount of heat released during its combustion. Also referred to as energy or calorific value, heat value is a measure of a fuel's energy density, and is expressed in energy (joules) per specified amount (e.g. kilograms

Explanation:

Define Ancestor, Descendant, Siblings, Height, Depth, Root and Leaf for the
above tree. Keep in mind that you can take any nodes of your choice to explain
your answer.

Answers

Answer:

Ancestor are our great grandparents

two ways in accepting responsibility can help teenagers to maintain coach relations with parents​

Answers

Answer:

1. It will help the teenagers gain the trust of their parents

2. It will help the teenagers obtain more privileges from their parents.

Explanation:

Responsibility is the state of accepting blame for a particular thing. A teenager who accepts responsibilities owns up to his mistakes and takes control over situations he is assigned to.

When teenagers accept responsibility for their actions, it helps the speaker to gain the trust of his parents who coach him in life. This trust will enable the parents to assign greater privileges to the teenagers because they believe they can handle them. Responsible teenagers do not engage in reckless activities.

Which part of a machine control unit interacts with the machine tools through electric signals?=]

A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.

Answers

Answer:

control loop unit

Explanation:

Edmentum/Plato

Stefan Lano needs displays that will show the musical instrument inventory in his chain of music stores that caters to musicians playing in world-class symphony orchestras in Basel, Switzerland; Buenos Aires, Argentina; and Philadelphia and New York in the United States. Design a form-fill interface for the inventory control of musical instruments in all four stores that could be used on a computer display screen. Assume that English will be the interface language.

Answers

Answer:

attached below is an example of  the form

Explanation:

This type of form-fill can be described/developed based on the requirements or information needed by the organization in order to perfectly fulfill an order  and also to retain customers by making the form very easy and interactive attached below is an example of such form fill  interface

A current value of 0.000005 A is equal to
Α. 50 μΑ. .
B. 5 mA.
C.5 HA.
D. 50 mA.

Answers

The correct answer is letter C

A current value of 0.000005 A is equal to 5 HA.

What is Current?

Current is a measure of rate. In physics, there are various rate quantities. For instance, velocity, which measures how quickly an item changes position, is a rate quantity.

Velocity is defined mathematically as the position change to time ratio. The rate at which an object changes its velocity is called acceleration, which is a rate quantity.

Acceleration is defined mathematically as the ratio of velocity change to time. Power, which measures the rate at which work is done on an object, is a rate quantity.

A current value of 0.000005 A is equal to 5 HA.

To learn more about current, refer to the link:

https://brainly.com/question/13076734

#SPJ2

A composite shaft with length L = 46 in is made by fitting an aluminum sleeve (Ga = 5 x 10^3 ksi) over a
steel core (Gs = 11 x10^3 ksi). The composite shaft is fixed against rotation at the wall A and has outside diameter da = 5 in. The steel core has diameter ds = 4 in. A torque TB = 3 kip. in is applied at B. % Matlab input: L = 46 Ga = 5 * 10^3 Gs = 11 * 10^3; da = 5; ds = 4; Tb = 3;
Determine the magnitude of the angle of twist at end B.

Answers

Answer:

Explanation:

Given the data in the question;

L = 46 in

Ga = 5 × 10³ ksi

Gs = 11 × 10³ ksi

Outside diameter da = 5 in

ds = 4 in

Tb = 3 kip.in

Now,

Ja = polar moment of Inertia of Aluminum;

Ja ⇒ π/32( 5⁴ - 4⁴ ) = π/32( 625 - 256 ) = π/32( 369 ) [tex]in^u[/tex]

Js = polar moment of inertia of steel

Js ⇒ π/32 ds⁴ = π/32( 4⁴ ) = π/32( 256 )

Ta is torque transmitted by Aluminum  

Ts is torque transmitted by steel  

{composite member }

T = Ta + Ts ------ let this be equation m1

Now, we use the relation;

T/J = G∅/L

JG∅ = TL

∅ = TL/GJ

so, for aluminum rod ∅[tex]_{alu[/tex] = TaLa/GaJa

for steel rod ∅[tex]_{steel[/tex] = TsLs/GsJs

but we know that, ∅a = ∅s = ∅[tex]_B[/tex]

so

[TaLa/GaJa]  =  [TsLs/GsJs]

also, we know that, La = Ls = L

∴ [Ta/GaJa]  =  [Ts/GsJs]

we solve for Ta

TaGsJs = TsGaJa  

Ta = TsGaJa / GsJs

we substitute

Ta = [Ts(5 × 10³)( π/32( 369) )] / [ (11 × 10³)( π/32( 256 ) ) ]

Ta = 0.66Ts

now, we substitute 0.66Ts for Ta and 3 for T in equation 1

T = Ta + Ts

3 = 0.66Ts + Ts

3 = 1.66Ts

Ts = 3 / 1.66

Ts = 1.8072 ≈ 1.81 kip-in

so

∅[tex]_{steel[/tex] = TsLs / GsJs

we substitute

∅[tex]_{steel[/tex] = (1.81 × 46 ) / ( 11 × 10³ × π/32( 256 ) )

∅[tex]_{steel[/tex] = 83.26 / 276460.1535

∅[tex]_{steel[/tex]  = 0.000301

∅[tex]_{steel[/tex] = 3.01 × 10⁻⁴ rad

so

[tex]_{steel[/tex] = ∅[tex]_B[/tex] = 3.01 × 10⁻⁴ rad

Therefore, the magnitude of the angle of twist at end B is 3.01 × 10⁻⁴  rad

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