Answer:
4
Step-by-step explanation:
Answer:16
Step-by-step explanation:4^2
Liam, Sarah and Emily shared some money in the ratio 3:6:8
Emily got £80 more than Liam.
How much money did Sarah get?
inverse operation needed
Answer:
it is C.
Step-by-step explanation:
we know,
14+17= 31
so if we subtarct 17 from 31 we get 14
and if we subtract 14 from 31 we get 17
Examine the expanded form.
a. a. a. a. a. a. a
which is the expression in exponential from?
O 7a
O 7a
O a7 <-------
O a + 7
need help fast pls!
Answer:
c
Step-by-step explanation:
Lucy invested $19,000 in an account paying an interest rate of 3% compounded annually. Assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 8 years?
Answer:
Step-by-step explanation:
A=19000( 1 + 0.03)^8
A=24068.6315464
A≈24100
Round to the nearest hundred dollars
What is the solution to the following system?
x+2y+z=9
x-y+3z=13
2z=10
Answer:
x=0 y=2 z=5
Step-by-step explanation:
so for z
2z=10
divid both side by 2
z=5
equation one
x+2y+5=9
x+2y=4 ------eqn1
equation two
x-y+ 3(5)=13
x-y+15=13
x-y=-2-----eqn2
now you solve it by elimination
eqn1-eqn2
3y=6
y=2
put y=2 into eqn2
x-2=-2
x=0
Using the method of proof by contradiction, prove that if a product of two positive real numbers is greater than 1,000,000, then at least one of the numbers is greater than 1000.
Step-by-step explanation:
To prove - Using the method of proof by contradiction, prove that if
a product of two positive real numbers is greater than
1,000,000, then at least one of the numbers is greater
than 1000.
Proof -
For a proof of contradiction , firstly we have to assume that the statement is not true.
Here given statement is - A product of two positive real numbers is greater than 1,000,000.
Let if possible, there does not exist 2 +ve integer real number such that at least one of the numbers is greater than 1000.
⇒both the number are in between 0 to 1000
Let a and b are 2 +ve real numbers.
⇒ab < 1000×1000
⇒ab < 1000000
As given,
ab > 1000000
Contradiction.
Hence proved.
If a product of two positive real numbers is greater than 1,000,000, then at least one of the numbers is greater than 1000.
Plz help thanks
Plz help.
Plz help ASAP thanks
Answer:
C) 1 3/8
I hope this helped :)
explanation:
I used the process of elimination. The other answers didn't make sense.
A teacher buys a binder for $1.75 and a monthly planner for $9.50 for each student in their classroom. The teacher spends a total of $562.50 for all of the binders and monthly planners.
How many students are in the teacher's class?
Please help I need the answer ASAP
Answer:
for 1 student it would equal 11.25
11.25 x 50 = 562.50
ur answer is 50 students hope this helps :)
Answer:
the teacher has 50 students
Step-by-step explanation:
1.75+9.50=11.25
562.50/11.25=50
Help plz plz plz plz plz plz
What is the area of this figure?
Enter your answer in the box.
Answer:
20
Step-by-step explanation:
add 3ft+3ft+11ft+3ft and that's your answer
Dave sold 60 general and reserved tickets for a concert. He sold general tickets for $10 each and reserved tickets for $15 each collecting a total of $725. Write a system of equations to determine the number of tickets he sold at each price and solve your system of equations?
Answer:
The system is of equations is:
[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]
Where g is the amount of general tickets and r is the amount of reserve tickets.
35 general tickets and 25 reserve tickets were sold.
Step-by-step explanation:
Let general tickets be represented by g and reserved tickets be represented by r.
Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:
[tex]10g+15r=725[/tex]
And a total of 60 tickets were sold. Hence:
[tex]g+r=60[/tex]
Our system of equations is:
[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]
We can solve by substitution. First, divide both sides of the first equation by 5:
[tex]2g+3r=145[/tex]
Next, we can subtract a variable (r in this case) from the second equation:
[tex]g=60-r[/tex]
Substitute:
[tex]2(60-r)+3r=145[/tex]
Distribute:
[tex]120-2r+3r=145[/tex]
Simplify:
[tex]120+r=145[/tex]
Subtract:
[tex]r=25[/tex]
Using the previous equation:
[tex]g=60-r[/tex]
Substitute and evaluate:
[tex]g=60-(25)=35[/tex]
So, 35 general tickets and 25 reserve tickets were sold.
Cylinders a and b each stated with different amounts of water. The graphs shows how the height of the water changed as the volume of the water increased in each cylinder. Which cylinder has the larger radius? a or b
Which expression is equivalent to 4(m+2)?
Answer:
=4m+8
Step-by-step explanation:
=(4)(m+2)
=(4)(m)+(4)(2)
=4m+8
Answer:
4m +8
Step-by-step explanation:
Take out the parenthesis
HELP ME.,,,,,,,,,,,,,,,,,,,
Answer:
Step-by-step explanation:
Use pythagorean theorem
9^2 +40^2=x^2
81+1600=x^2
1681=x^2
now find the square root of each side
[tex]\sqrt{1681} =\sqrt{x}[/tex]
x=41
Brianna has six bags of soil filling one flower pot requires 1/3 of a bag of soil how many flower pots can be filled with the six flags
Answer:
18
Step-by-step explanation:
[tex]\frac{6}{1}[/tex] ÷ [tex]\frac{1}{3}[/tex]
Keep Change Flip
[tex]\frac{6}{1}[/tex] × [tex]\frac{3}{1}[/tex] = [tex]\frac{18}{1}[/tex]
The perimeter of a rectangle is 72 meters. The width of the rectangle is 4 meters less than the
length. Find the length and width of the rectangle. (Use I for the length)
e meters
le - 4) meters
Answer:
Step-by-step explanation:
Perimeter = 2l + 2w
With the given statement, the width of the rectangle is 4 meters less than the
length,
w = l - 4
sub that in the first equation,
Perimeter = 2l + 2(l - 4)
Perimeter = 2l + 2l - 8
Perimeter = 4l - 8
Since perimeter is 72m,
72 = 4l - 8
4l = 80
l = 20m
Lara made some chocolate tarts. For every 5 cups of chocolate chips, she added 3 cups of sugar. The ratio of chocolate chips to sugar in Lara's chocolate tarts is ____. (5 points)
Answer:
5:3
Step-by-step explanation:
) Find the area of the shape. *
Answer:
20 + 75 = 95
Step-by-step explanation:
10 - 5 = 5 x 4 = 20
5 x 15 = 75
Add them together,
75 + 20 = 95
72 - 4
f(x) = 3x3 + 8x2
= 2x
6
Find (f - g)(x).
5x + 2
9x + 2
O A. (f - g)(x) = 3x3 + 822
O B. (f - g)(x) = 3x3 + 8x2
O c. (f - g)(x) = 323 + 8x2
O D. (f - g)(x) = 3x3 + 8x2
9x
10
53
-
10
Answer:
B.
Step-by-step explanation:
(f-g)(x) = f(x) - g(x) =
= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =
= 3x³ + 8x² - 9x + 2
A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t. Find the rate at which the number of grams of salt in the tank is changing at time t.
Answer:
[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]
A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]
Step-by-step explanation:
Given - A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t.
To find - Find the rate at which the number of grams of salt in the tank is changing at time t.
Find the number A(t) of grams of salt in the tank at time t.
Proof -
Given that,
Total fluid in the tank = 350 litres
Total salt = 40 grams
Rate in flow = 5 L/min
Rate out flow = 5 L/min
Concentration in = 0
Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)
Now,
Total solution in the tank at time t = Total fluid in the tank + (Rate in flow - Rate out flow )t
= 350 + (5 - 5)t
= 350
⇒Solution in the tank at time t = 350
⇒Concentration out = [tex]\frac{A(t)}{350}[/tex]
Now,
Rate of change in the tank at time t = [tex]\frac{dA}{dt}[/tex]
= (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)
= 5(0) - 5([tex]\frac{A(t)}{350}[/tex])
= 0 - [tex]\frac{A(t)}{70}[/tex]
= [tex]-\frac{A(t)}{70}[/tex]
⇒[tex]\frac{dA}{dt}[/tex] = [tex]-\frac{A(t)}{70}[/tex]
⇒[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]
Integrate both sides , we get
ln(A) = [tex]-\frac{1}{70}t + C[/tex]
⇒A(t) = [tex]e^{-\frac{t}{70}+ C}[/tex]
= [tex]e^{-\frac{t}{70}}*e^{C}[/tex]
= [tex]C_{1} e^{-\frac{t}{70}}[/tex]
⇒A(t) = [tex]C_{1} e^{-\frac{t}{70}}[/tex]
Now,
Given that,
Initially, the tank has 40 grams of salt
⇒A(0) = 40
⇒C₁ = 40
⇒A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]
how many rhombuses in a trapezoid?
plz help asap (make sure to put a real explanation)
Answer:
w= 1 29/45
isolate the variable by dividing each side by the numbers that don't contain the variable.
What's the slope and y-intercept of the graph of 7x + y = 8? Question 4 options: A) Slope = –7, y-intercept = 8 B) Slope = –7, y-intercept = –8 C) Slope = –8, y-intercept = 7 D) Slope = 7, y-intercept = 8
Answer:
Slope is -7 and the y-intercept is 8
Step-by-step explanation:
Your options :
9,2
10,4
11,5
10,6
Answer:
i would say (10,6)
Step-by-step explanation:
The dot plot below shows the number of concerts students at Albus Middle School have attended.
What is the interquartile range of the data set shown?
A. 2
B. 6
C. 3
D. 1
Answer:
2
Step-by-step explanation:
The interquartile range of the given data set is 2.
We need to find the interquartile range of the data set given.
How to find the interquartile range?To find the interquartile range (IQR), first, find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
The given set of data is
0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6
To find Q1:
The lower half of the numbers are
That is 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2,
So the median of the lower half (Q1)=1
To find Q3:
The upper half of the numbers are 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6
So the median of the upper half (Q3)=3
Then, IQR=Q3-Q1=3-1=2
Therefore, the interquartile range of the given data set is 2.
To learn more about the interquartile range visit:
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victor is selling lemonade to raise money for his school the amount of money he collected from his sales each day is summarized on the box plot below
The interquartile range of Victor's lemonade sale is A = 7
What in Interquartile Range ( IQR )?The distance between the upper and lower quartiles is known as the interquartile range. Half of the interquartile range corresponds to the semi-interquartile range. Finding the values of the quartiles in a small data set is straightforward.
The spread of the data, or statistical dispersion, is measured by the interquartile range. The middle 50%, fourth spread, or H-spread are further names for the IQR. It is described as the spread between the data's 75th and 25th percentiles.
Given data ,
Let the interquartile range of sales of Victor's lemonade be A
Now , the equation will be
Let the 75th percentile data = 29
Let the 25th percentile data be = 22
Now , the IQR is calculated by spread between the data's 75th and 25th percentiles
On simplifying , we get
The IQR = 29 - 22 = 7
Hence , the interquartile range is 7
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The complete question is :
Victor is selling lemonade to raise money for his school the amount of money he collected from his sales each day is summarized on the box plot below.
What is the interquartile range of the data?
The first Portuguese explorer to lay claim to Brazil was
Question 3 options:
Getulio Vargas
a Jesuit priest
Pedro Cabral
Ferdinand Magellan
Answer:
Cabral is right
Step-by-step explanation:
Mark me brainleyest plz
Helpppp hurry and no links please
Answer:
8.3
Step-by-step explanation:
Marge wants to buy a CD player. The CD player costs $300. Marge gets 30% off. How much did Marge pay?
Answer:
300-(300*0.3) = 210
Step-by-step explanation:
Answer:
$210
Step-by-step explanation:
300*30%=90
300-90=210
Write a ratio for each phrase :
5 cupcakes for every 2 children