how many grams of Na2co3 will be produced from the thermal decomposition of 250.0 g of nahco3?. 157.7 g​

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

For a gas at 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.

How much gas, in grams, is mathematically given as

s2=8.3782grams

Generally, the equation for the   is mathematically given as

Si /S2 √P1/√P2

Therefore

[tex]s2=9.5*\sqrt{3.5}/\sqrt{4.5}[/tex]

s2=8.3782g

In conclusion. The solubility is

s2=8.3782g

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Answer:

erosion, weathering, dissolution, precipitation, and lithification So,D.weathering and erosion followed by compaction

Explanation:

mark me brainliest!!

Answer:

They are all vascular plants.

Explanation:

Vascular plants, also known as tracheophytes, are highly advanced plant creatures with leaves, stems, and roots, as well as a vascular system made up of conducting vessels. Ferns are herbaceous, pteridophytic vascular plants that do not produce flowers or seeds. Gymnosperms are vascular plants that produce seeds but do not produce blooms. Because the seeds aren't covered or protected by an ovary, they can be seen on the plant's leaves or other components. Angiosperms are flowering plants containing seeds that develop inside the ovary, which develops and produces fruit.

Answer:

They all produce seeds

Explanation:

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

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Answer:

Absolute zero is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvin.

Answer: To melt 500 g of ice, 4000 joule of heat is required.

Explanation:

I love the helps

The energy required to melt one gram of ice is 334 J. Then the heat energy required to melt 500 g of ice into water is 1.6 × 10⁵ J.

The change in energy associated with a phase change or any chemical reaction is called enthalpy change. Then, heat energy required to melt or freeze the substance.

The heat of fusion of ice is 334 J/g. Therefore, the heat energy required to melt the 1 g of ice is 334 J. Now the equation being used to  find the energy for m g of ice to melt is:

q = mHf.

Hf = 334J/g

m = 500 g

q = 500 × 334 J/g = 1.6 × 10⁵ J

Therefore, the heat energy needed to melt 500 g of ice to water is 1.6× 10⁵ J.

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The volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

The volume of a substance can be calculated using the following expression:

Molarity = number of moles ÷ volume

The number of moles of NaOH can be calculated by dividing the mass of NaOH by its molar mass.

Molar mass of NaOH = 40g/mol

n = 5/40

n = 0.125moles

Volume of NaOH = 0.125mol ÷ 0.15M

Volume = 0.83L

Therefore, the volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

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An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

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Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

Answer:

S orbital

Explanation:

no explanation, just a name you memorize

Between a water molecule and an anion, like Cl-, a hydrogen bon occurs between hydrogen atom of the water molecule and the anion.

Hydrogen bond is a weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in the other. Hydrogen atom in water molecule attract anion due to presence of hydrogen bond.

So we can conclude that hydrogen bond occurs between hydrogen atom of the water molecule and the anion.

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Answer:

Explanation:88766

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According to the given equation, 2C4H10 + 1302 — 8CO2 + 10H, 2 moles of O are required to react with 4.71 moles of C4H10.

The number of moles of a compound can be calculated stoichiometrically as follows:

The balanced chemical equation is given as follows:

2C4H10 + 1302 — 8CO2 + 10H

Based on the above equation, 2 moles of C4H10 reacts with 13 moles of O

Therefore; 4.71 moles of C4H10 will react with 4.71 × 6.5 = 30.62 moles of O

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Answer: 30.6

Explanation:

to generate steam which act on copper

Answer:

More common near convergent boundaries

Explosive Eruptions

Low Viscosity Magma

Explanation:

Hot spots like hawaii are better known for shield volcanoes. The magma is high viscosity which causes them to build pressure before erupting, leading to explosive eruptions.

Answer:

Explanation:

1 mole of nickel contains 6.02 * 10^23 atoms

3.63 mols of nickel contain x atoms.

What you have is a proportion. A proportion consists of 2 ratios or 4 parts.

Of the 4 parts, you know three of them. The problem is to solve for the 4th.

1/3.63 = 6.02*10^23 / x               Cross multiply

x = 3.63 * 6.02* 10^23                Combine the right.

Answer: x = 2.19*10^24 atoms

Answer:

chemical composition and physical properties of packaging materials determine their ability to fulfill the various functions expected from the package. 

There are eight lone pairs and four bond pairs of electrons in the SO3 molecule. The valence electrons are found on the valence shell of the molecule.

The molecule SO3 is represented by the Lewis structure shown in the image attached to this answer. The central atom in the molecule is sulfur.

There are sixteen non bonding electrons in the molecule and eight bonding electrons in the molecule Hence, we have eight lone pairs and four bond pairs of electrons in the molecule as shown in the Lewis structure.

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The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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The emission wavelength of the atoms excited above the ground state is 599.8 nm.

The emission wavelength of the atom is determined by using the following formulas as shown below;

E = hf

E = hc/λ

where;

λ = hc/E

λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / (3.314 x 10⁻¹⁹)

λ = 5.998 x 10⁻⁷ m

λ = 599.8 x 10⁻⁹ m

λ = 599.8 nm

Thus, the emission wavelength of the atoms is 599.8 nm.

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The dental assistant should respond to this patient’s concerns by telling him that the amount of x-ray is very minimal and can't cause any negative effect.

This is a penetrating form of electromagnetic radiation which produces images of the structures inside your body.

Exposure to large amounts of radiation could increase risk of cancer which is why minimal amounts which is safe is adopted.

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Weak base: [OH⁻] = √Kb.C

pKb = 4.2

[tex]\tt Kb=10^{-4.2}[/tex]

c = concentration

MM Amphetamine (C9H13N) = 135.21 g/mol

c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59  x 10⁻³ mol/L

[tex]\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}[/tex]

pOH = 4 - log 3.17

pH = 14 - (4 - log 3.17)

pH = 10 + log 3.17 = 10.50

Answer:

0.1 M Calcium phosphate

Explanation:

Which is also

0.1mCal2

Answer:

Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.

Explanation:

Not sure what you meant exactly, but this is my best guess.

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

1 mole of substance = 6.02×10²³ molecules

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

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The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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The lead acid battery produces energy by oxidation of lead. The amount of lead oxidized in this case is 1.47 g.

The lead acid battery is the common accumulator that we have in use. It is made up of a cell that contains lead electrodes in an acid.

The oxidation of lead occurs according to thr equation;

Pb(s) ----> Pb^2+(aq) + 2e

If 207 g of Pb is oxidized by 2(96500)C

x g of lead is oxidized by (221 * 6.20) C

x = 207 g * (221 * 6.20) C/2(96500)C

x = 1.47 g

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Answer:

D beacuse I think that's Force

Answer:

Balanced equation: Zn (NO 3) 2 + 2 NH 4 OH = 2 NH 4 NO 3 + Zn (OH) 2 Reaction type: double replacement

Explanation:

Explanation:

0.9 grams of oxygen gas we need.