How many liters of chlorine gas at 25°C and 0.950 atm can be produced by the reaction of 12.0 g of MnO2 with excess HCl(aq) according to the following chemical equation?
MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g)

Answer:

a) common ion effect

b) solubility

c) saturated solution

d) solubility product constant

e) molar solubility

Explanation:

When a substance, say BA2 is dissolved in a solution and another substance CA2 is dissolved in the same solution. The solubility of BA2 is decreased due to the addition of CA2. This is known as common ion effect.

The mass of a substance that will dissolve in a given Volume of solvent is known as it's solubility.

The molar solubility is the amount of moles of solvent that dissolves in 1 dm^3 of solvent.

A solution that contains just as much solute as it can normally hold at a given temperature is known as a saturated solution.

Lastly, the product of molar solubilites raised to the power of the molar coefficient is know as the solubility product constant.

The correct matches and their explanation are:

a) A decrease in the solubility of an ionic compound as a result of the addition of a common ion: Option 4. common ion effect

b) The mass of salt in grams that will dissolve in 100 mL of water: Option 1. solubility

c) A solution that has dissolved the maximum amount of a compound at a given temperature. Any further addition of salt will remain undissolved: Option 5. saturated solution

d)  The product of the molarities of the dissolved ions, raised to a power equal to the ion's coefficient in the balanced chemical equation: Option 3. solubility product constant

e) The maximum number of moles of a salt that will dissolve in 1 L of solution: Option 2. molar solubility

To learn more about molar solubility and common ion effect follow the link:

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Your radio picks up those radio waves and channels them into electric circuits in your radio that convert them into sounds you can hear.

Answer: here u go

Explanation:

A. 3.7 x 10^4

B. 4.56 × 10^-8

C. 8.01 × 10^6

Work for A:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 37,000

New Number: 3.7000

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number: 3 . 7 0 0 0

Decimal Count:   1 2 3 4

There are 4 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 3.7 (Please notice any zeroes on the end have been removed)

b = 4

Now the whole thing:

3.7 x 104

Step 4

Check your work:

104 = 10,000 x 3.7 = 37,000

Work for B:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 456

New Number: 0.0000000456

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number: 0 . 0 0 0 0 0 0 0 4 5 6

Decimal Count:   1 2 3 4 5 6 7 8 9 10

There are 2 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 4.56

b = 2

Now the whole thing:

4.56 x 102

Step 4

Check your work:

102 = 100 x 4.56 = 456

Work for C:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 8,010,000

New Number: 8.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number: 8 . 0 1 0 0 0 0

Decimal Count:   1 2 3 4 5 6

There are 6 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 8.01 (Please notice any zeroes on the end have been removed)

b = 6

Now the whole thing:

8.01 x 106

Step 4

Check your work:

106 = 1,000,000 x 8.01 = 8,010,000

Hope this helps!

Answer:

The disruption of the bonds or attractions occurs during protein hydrolysis which results in the loss for the primacy structure. The peptide bonds is the bond affected in this scenario.

The disruption of the bonds however only exist in the process of denaturation and this results in a change in the confirmation which could be secondary, tertiary, and quaternary structural related. And example of the bonds affected include salt bridges, disulfide bridges, hydrogen bonds etc.

Answer:

this

Explanation:

What is the unit rate of the better deal? (Number answers only.)

LaTeX: \frac{160\:miles}{5\:gallons}\:or\:\frac{315\:miles}{9\:gallons}160 m i l e s 5 g a l l o n s o r 315 m i l e s 9 g a l l o n s

The better deal has a unit rate of [m] miles per gallon.

Answer:

See explanation

Explanation:

A popular experiment that describes the effect of heat on the position of equilibrum is the change of colour when copper II chloride is heated.

As the solution is heated, it's colour changes from blue to green, this implies the the colour change (blue to green) is an endothermic process (equilibrum position shifts to the right with increase in temperature)

The equilibrum is represented by the equation;

[Cu(H2O)6]^2+(aq) + 4Cl^-(aq)<------>[CuCl4]^2-(aq) + 6H2O(l) ∆H=positive

The equilibrium mixture undergoing cooling or heating have colour changes. The temperature affects the colour of the products formed and the forward reaction is endothermic.

In the reaction copper (II) chloride or [tex]\rm CuCl_{4}[/tex] is the main species. The heat or the temperature affects the colour formation of copper (II) chloride as the equilibrium change affects the colouration of the product.

The heating of the solution affects the colour change from blue to the green of the reactant to products and the forward reaction shifts the equilibrium towards the right when the temperature is increased and is an endothermic reaction.

The reaction at the equilibrium can be shown as,

[tex]\rm [Cu(H_{2}O)_{6}]^{2+} (aq) + 4Cl^{-} (aq) \Leftrightarrow [CuCl_{4}]^{2-}(aq) + 6H_{2}O(l), \Delta H=positive[/tex]

Therefore, temperature changes the colouration and the forward reaction is an endothermic reaction.

Learn more about temperature and equilibrium here:

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And we can see that the potassium ion, K+, has the same electronic configuration as the chloride ion, Cl-, and the same electronic configuration as an atom of argon, Ar. Therefore, Ar, Cl-, and K+ are said to be isoelectronic species.

Answer:

[tex]\rm Sn[/tex], [tex]\rm Se[/tex], [tex]\rm S[/tex], [tex]\rm Si[/tex].

Explanation:

The relative atomic mass of an element is numerically equal to the mass (in grams) of one mole of its atoms. This quantity can help estimate the number of moles of atoms in each of these four [tex]10.0\; \rm g[/tex] samples.  

Look up the relative atomic mass for each of these four elements (on a modern periodic table.)

The relative atomic mass of [tex]\rm Si[/tex] is (approximately) [tex]28.085[/tex]. Therefore, the each mole of silicon atoms would have a mass of approximately [tex]28.085\; \rm g[/tex]. How many moles of silicon atoms would there be in a [tex]10.0\; \rm g[/tex] sample?

Given:

Number of mole of silicon atoms in the sample: [tex]\displaystyle n(\mathrm{Si}) = \frac{m(\mathrm{Si})}{M(\mathrm{Si})} = \frac{10.0\; \rm g}{28.085\; \rm g \cdot mol^{-1}}\approx 0.356\; \rm mol[/tex].

Similarly:

[tex]\displaystyle n(\mathrm{S}) = \frac{m(\mathrm{S})}{M(\mathrm{S})} = \frac{10.0\; \rm g}{32.06\; \rm g \cdot mol^{-1}}\approx 0.312\; \rm mol[/tex].

[tex]\displaystyle n(\mathrm{Se}) = \frac{m(\mathrm{Se})}{M(\mathrm{Se})} = \frac{10.0\; \rm g}{78.971\; \rm g \cdot mol^{-1}}\approx 0.127\; \rm mol[/tex].

[tex]\displaystyle n(\mathrm{Sn}) = \frac{m(\mathrm{Sn})}{M(\mathrm{Sn})} = \frac{10.0\; \rm g}{118.710\; \rm g \cdot mol^{-1}}\approx 0.0842\; \rm mol[/tex].

Therefore, among these [tex]10.0\; \rm g[/tex] samples:

[tex]n(\mathrm{Sn}) < n(\mathrm{Se}) < n(\mathrm{S}) < n(\mathrm{Si})[/tex].

It is not a coincidence that among these four samples, the one with the fewest number of atoms corresponds to the element with the largest relative atomic mass.

Consider two elements, with molar mass [tex]M_1[/tex] and [tex]M_2[/tex] each. Assume that [tex]n_1[/tex] moles and [tex]n_2[/tex] moles of atoms of each element were selected, such that the mass of both samples is [tex]m[/tex]. That is:

[tex]m = n_1\cdot M_1[/tex].

[tex]m = n_2\cdot M_2[/tex].

Equate the right-hand side of these two equations:

[tex]n_1 \cdot M_1 = n_2\cdot M_2[/tex].

[tex]\displaystyle \frac{n_1}{n_2} = \frac{M_2}{M_1} = \frac{1/M_1}{1/M_2}[/tex].

In other words, the number of moles atoms in two equal-mass samples of two elements is inversely proportional to the molar mass of the two elements (and hence inversely proportional to the formula mass of the two elements.) That explains why in this question, the sample containing the smallest number of atoms corresponds to element with the largest relative atomic mass among those four elements.

Answer: Membrane Protiens

Explanation:

In facilitated diffusion, molecules diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers. A concentration gradient exists for these molecules, so they have the potential to diffuse into (or out of) the cell by moving down it.

Answer:

Be

Explanation:

The atomic radius decreases as you go from left to right in a period. Be has the largest radius out of those given elements.

Answer:

10.)Weight and mass are different because only weight describes the force of gravity on an object.

11.)On a planet with more mass than earth your weight would be higher because greater gravitational pull.

On a planet with less mass than earth your weight would be less because of the lower gravitational pull.

Explanation:

Answer:

A=element

B=compond

C=solution

Answer:

a

Explanation:

because the sytem it si locate at the bothe side

Answer:

6.7

⋅

10

23

atoms of H

Explanation:

Answer:

[tex]Kc=\frac{[SF_6]^8}{[F_2]^2^4}[/tex]

Explanation:

Hello.

In this case, for the undergoing chemical reaction:

[tex]S_8(s) + 24F_2(g) \rightleftharpoons 8SF_6(g)[/tex]

We consider the law of mass action in order to write the equilibrium expression yet we do not include S8 as it is solid and make sure we power each gaseous species to its corresponding stoichiometric coeffient (24 for F2 and 8 for SF6), thus we obtain:

[tex]Kc=\frac{[SF_6]^8}{[F_2]^2^4}[/tex]

Best regards!

Answer : The correct match is:

1 positive charge = 1 negative charge

2 positive charges = 2 negative charges

3 positive charges = 3 negative charges

Explanation :

As we now that there are three subatomic particles which are protons, electrons and neutrons.

The protons and neutrons are located inside the nucleus and electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and neutrons are neutral.

As we know that all the things are made up of charges and opposite charges attract to each other.

In a neutral atom, the positive charges and negative charges are balanced in an object. That means, in neutral atom the number of positive charges are equal to the negative charges.

So we can say that:

1 positive charge = 1 negative charge

2 positive charges = 2 negative charges

3 positive charges = 3 negative charges

Answer:

1 positive---- 1 negative

2 positive---- 2 negative

3 positive---- 3 negative

Explanation:

edge 2023

Answer:

A graph can be very handy in collecting data and storing it in one place. A graph can be a very effective tool in presenting visual information rather swiftly. Hope this helps! I am learning about graphs in my course!

Explanation:

Answer:

graph) a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.

Explanation:

Graphing is used daily. From stockbrokers to performance evaluation in companies. All use them to boost sales and meet deadlines. Even simple calculations can be assessed better by using a graph.

(let me know if this helps?)

Answer:

9000 pounds

Explanation:

9000 pounds

Answer: 9000 lbs.

Explanation: 4.5 tons = 9000 pounds.

Answer:

the ball will move towards the big bully

Finally, someone gave a clear photo.

Answer:

10

Explanation:

Answer:

[tex]Cu_2O[/tex]

Explanation:

Hello.

In this case, since the reaction obeys the law of conservation of mass, since the initial oxide had a mass of 0.500 g and yielded 0.444 g of copper, the mass of oxygen in the oxide is:

[tex]m_O=0.500g-0.444g=0.056g[/tex]

In such a way, we next compute the moles of copper and oxygen by using their atomic masses:

[tex]n_{Cu}=0.444g*\frac{1mol}{63.546 g} =0.00699mol\\\\n_O=0.056g*\frac{1mol}{16.00g}=0.0035mol[/tex]

Next, in order to compute the subscripts of Cu and O on the empirical formula we divide the moles by the fewest moles, in this 0.0035 mol as shown below:

[tex]Cu:\frac{0.00699}{0.0035} =2\\\\O:\frac{0.0035}{0.0035} =1[/tex]

It means that the empirical formula turns out:

[tex]Cu_2O[/tex]

Best regards!

Answer:

look at the explanation

Explanation:

The air that you breathe is a homogeneous mixture of oxygen, nitrogen, argon, and carbon dioxide, along with other elements in smaller amounts. Because each layer of the Earth's atmosphere has a different density, each layer of air is its own homogeneous mixture.

Hope this helps. :)

Answer:

Both ionic bonds and covalent bonds (coordinate and non-coordinate) are present in crystalline [tex]\rm CuSO_4\cdot 5\, H_2O[/tex].

Explanation:

[tex]\rm CuSO_4\cdot 5\, H_2O[/tex] can be formed by adding water to the anhydrous salt [tex]\rm CuSO_4[/tex].

[tex]\rm CuSO_4[/tex] itself is an ionic compound consisting of [tex]\rm Cu^{2+}[/tex] ions and [tex]\rm {SO_4}^{2-}[/tex] ions. Ionic bonds are present between these ions. However, within each sulfate [tex]\rm {SO_4}^{2-}[/tex] ion, covalent bonds connect the central sulfur atom to each of the oxygen atoms.

Water molecules [tex]\rm H_2O[/tex] are highly polar. Partial negative charges surround the oxygen atom in each water molecule.

When water is added to anhydrous [tex]\rm CuSO_4[/tex], the negatively-charged portion of these [tex]\rm H_2O\![/tex] molecules would be attracted to the positively-charged [tex]\rm Cu^{2+}[/tex] ions in [tex]\rm CuSO_4\![/tex].

Lone pairs on oxygen atoms in [tex]\rm H_2O\!\![/tex] would form coordinate covalent bonds with [tex]\rm Cu^{2+}\![/tex] ions. (These bonds are considered "coordinate" because both electrons in each of these bonds come from the oxygen atom, not the [tex]\rm Cu^{2+}[/tex] ion.) That would produce coordination complexes with one [tex]\rm Cu^{2+}\!\![/tex] ion and five [tex]\rm H_2O\!\!\![/tex] "ligands" each.

Because the [tex]\rm H_2O[/tex] ligands carry no electric charge, each of these complexes would also carry a charge of [tex](+2)[/tex] (same as the charge on one [tex]\rm Cu^{2+}\!\![/tex] ion.) Ionic bonds would be present between the positively-charged coordination complexes and the negatively-charged [tex]\rm {SO_4}^{2-}[/tex] ions.

Summary: