Answer:
26.9L of SO2
Explanation:
The reaction between Sulphur and oxygen is as follows:
[tex]S_2 + 2O_2 \to 2SO_2[/tex]
This implies that:
2 moles of oxygen reacts with 1 mole of sulphur to produce 2 moles of SO₂
2 moles of oxygen also yields 2 moles of SO₂
The number of moles of oxygen given is determined as:
[tex]= 26.9 \ L \ of \ O _2 \times (\dfrac{1 \ mol \ of O_2 }{22.4 \ L}) \\\\ = 1.20 \ mol \ of \ O_2[/tex]
The number of moles of SO₂ by using the ratio is:
[tex]= 1.20 \ mol \ of \ O_2 \times (\dfrac{1 \ mol \ of \ SO_2 }{1 \ mol \ O_2}) \\ \\ = 1.20 \ mol \ of SO_2[/tex]
Finally, the volume by applying the new moles is computed as:
[tex]= 1.20 \ moles \ of \ O_2 \times ( \dfrac{1 \ mo \ of \ SO_2}{1 \ mol \ of O_2}) \times ( \dfrac{22.4 }{1 \ mol }) \\ \\ = 26.9 \ L \ of \ SO_2[/tex]
A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145
Answer:
a
Explanation:
Which statement describes the best way to determine how different levels of light affect the growth of seedling plants?
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Choose five different light levels, and place one identical plant under each of the light levels for exactly one week.
Choose four different light levels, and place eight different plant types under the light levels, two under each one, and observe them every day.
Choose one type of light and one type of plant, and then observe the plant for at least four weeks, measuring it each day.
Answer:
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Explanation:
How will an increase in wind speed affect soil erosion?
O A Soil erosion will increase.
O B. Soil erosion will decrease.
O C. Soil erosion will completely stop.
OD Soil erosion will remain the same.
Answer:
A. Soil erosion will increase.
Option A is correct. Increase in wind speed will increase the rate of erosion.
The process of eroding, transferring, and depositing tiny particles as well as nutrients from the top layer of soil is known as soil erosion by wind.
In arid and semiarid regions, wind-driven soil erosion is a serious issue that impedes the environmental sustainability of animal husbandry and agriculture and threatens ecological security.
A wind that is blowing at 30 mph will erode at a rate that is more than 3 times faster than a wind that is blowing at 20 mph. As soil moisture rises, wind erosion declines. For instance, dry soil erodes approximately 1.3 times more quickly than soil with just enough moisture to support plant life.
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When 16.35 moles of SI reacts with 11.26 moles of N2, how many moles of SI3N4 are formed
Answer:
5.450 mol Si₃N₄
Explanation:
Step 1: Write the balanced equation
3 Si + 2 N₂ ⇒ Si₃N₄
Step 2: Establish the theoretical molar ratio between the reactants
The theoretical molar ratio of Si to N₂ is 3:2 = 1.5:1.
Step 3: Establish the experimental molar ratio between the reactants
The experimental molar ratio of Si to N₂ is 16.35:11.26 = 1.45:1. Comparing both molar ratios, we can see that Si is the limiting reactant.
Step 4: Calculate the moles of Si₃N₄ produced from 16.35 moles of Si
The molar ratio of Si to Si₃N₄ is 3:1.
16.35 mol Si × 1 mol Si₃N₄/3 mol Si = 5.450 mol Si₃N₄
What happens to the entropy when a solution is made?
A. The entropy increases.
B. The entropy decreases.
C. The entropy goes to zero.
D. The entropy is unaffected.
Answer:
The entropy increases
Explanation:
Just took the quiz
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Answer:
90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you.
If 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of NaOH in the resulting solution
Answer:
Molarity of NaOH = 1.8 M.
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Volume = 500 mL
Molarity of NaOH =?
Next, we shall determine the number of mole in 36 g of NaOH. This can be obtained as follow:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 36 / 40
Mole of NaOH = 0.9 mole
Next, we shall convert 500 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
500 mL = 500 mL × 1 L / 1000 mL
500 mL = 0.5 L
Finally, we shall determine the molarity of NaOH. This can be obtained as follow:
Mole of NaOH = 0.9 mole
Volume = 0.5 L
Molarity of NaOH =?
Molarity = mole / Volume
Molarity of NaOH = 0.9 / 0.5
Molarity of NaOH = 1.8 M
Consider pure water separated from an aqueous sugar solution by a semipermeable membrane, which allows water to pass freely but not sugar. After some time has passed, the concentration of sugar solution: a. will have decreased b. will be the same on both sides of the membrane c. might have increased or decreased depending on other factors d. will not have changed e. will have increased
Answer:
it will be the same on both sides of the membrane
When the pure water is separated from the aqueous sugar solution when the sugar cannot pass through the semipermeable membrane. So the water moves through the membrane to the sugar solution. Therefore, the concentration of sugar solution will be decreased.
What is osmosis?Osmosis can be described as the spontaneous net movement or diffusion of solvent molecules through a permeable membrane from a region of lower solute concentration to a higher solute concentration in a direction that tends to balance the solute concentrations on both sides.
A physical process in which any solvent moves across a selectively permeable membrane separating two solutions of different concentrations.
Osmotic pressure can be described as the external pressure needed to be applied so that there is no net movement of a solvent across the membrane. Osmotic pressure can be defined as a colligative property because it depends on the molar concentration of the solute but not on its identity.
Therefore, option (A) is correct.
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3. How many times does earth rotate on its axis in one year?
Answer:
There are approximately 366.25 sidereal days in a year so that the Earth spins 366.25 times with respect to distant stars in a year
hope this helps
have a good day :)
Explanation:
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Answer:
sdfhioupsdfiuhikdfjsdfhsdksdflk";d089sdfojskdfk
pls give brainlyest
Explanation:
200 IQ intellectual right here ^^
How many liters of 3.6 M solution can be made using 110 grams of
lithium bromide (LiBr)?
Answer:
0.2878 liters
Explanation:
It is possible to make 0.2878 liters of 4 M solution of lithium bromide using 100 grams of the compound.
of the two Lewis/electron dot
structure representations, which is
the correct one for oxygen gas?
The electron dot diagram for an element shows the valence electrons for the element. Oxygen is in group 16/VIA, so it has six valence electrons. Draw the symbol for oxygen. Then place one dot at each side of the symbol.
I need help to get the correct answers for this task.
Answer:
*Numbering from left to right.
Synthesis: 1,2,9
Decomposition: 4,7,11
Single Replacement: 3,6
Double Replacement: 5,8,10, 12
Explanation:
Synthesis=A+B->AB; 2 separate elements getting together
Decomposition=AB->A+B; 2 Elements that are bonded separating
Single Replacement=A+BC->AX+B; a single swap
Double replacement=AX+BY-> AY+BX; a double swap
How do children use food molecules to grow taller?
Options
A - Children grow taller when they use food molecules they eat to build large molecules that make up new cells.
B - Children grow taller when they use the food molecules they eat to make up new cells without changing the food molecules.
C - Children grow taller when they use the energy from the food molecules, but all of the molecules leave the body as waste.
D- Children grow taller when they store food molecules as fat.
A or B or C Or D ?
Answer:
C) Children grow taller when they use the energy from the food molecule, but all of the molecules leave the body as waste.
hope it helps.
Answer:
C - Children grow taller when they use the energy from the food molecules, but all of the molecules leave the body as waste.
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How do I turn on a Girl???
Answer:
7 Ways to turn a woman on. ...
Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same. ...
Know her body. ...
Help her feel comfortable receiving oral sex. ...
Play with lube or toys. ...
Remember that great sex won't happen overnight.
Explanation:
Answer: Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same.
Hope this helps
What's you're favorite year?
Answer:
2020 cause of the lockdown
Explanation:
1. A bird perching in the tree hears the chirping of another bird. A whale hears
the songlike sound made by another whale swimming pcar it. Which sound
travels faster, the bird's chirping or the whale's singing? Explain your answer.
Answer:
The sound from the whales singing is faster than that from the birds chirping.
Explanation:
The sound from the whales singing will travel faster than the sound from the birds chirping because sound travels faster through a medium than through air.
In this case the whales are in water which is a medium while the birds are in the air and thus, the sound from the water will travel faster.
What is one benefit that nuclear power plants currently provide for our environment?
O A. They provide energy without increasing carbon dioxide emissions.
O B. They provide energy without increasing nuclear waste.
C. They provide energy while increasing natural gas pollution.
O D. They provide energy while increasing biomass by-products.
Explanation:
Nuclear power plants deliver electricity 24 hours a day, 7 days a week, irrespective of weather and seasons. As well as reducing greenhouse gas emissions, nuclear generation helps reduce air pollution
Answer:
D
Explanation:
Just did the test
What does putting on the sweater, even though it isn’t hers, reveal about Rachel?
She sticks up for herself when she knows she is right.
She will do what she is told, especially when facing conflict.
She can be talked into liking something that she does not like.
Answer:
B: She will do what she is told, especially when facing conflict
Explanation:
I know it cause I'm doing it rn and I got it right
When a certain nuclide undergoes alpha emission, astatine-217 is produced. What is the identity of the nuclide that underwent decay?
a. actinium-219
b. francium-217
c. francium-221
d. astatine-221
e. actinium-221
Please explain the answer
Answer:
C: francium-221
Explanation:
First of all to get a broader perspective, every isotope of francium usually undergoes decay to form astatine, radium, or radon.
Now, Francium-223 and francium-221 are it's only isotopes that occur in nature.
However, francium-221 is the one that undergoes alpha decay to produce astatine-217.
If the mass defect for a radionuclide is –8.7839×10-30 kg, what's the binding energy per atom?
Question 7 options:
A)
–7.8944×10-13 J/atom
B)
–4.76×1011 J/atom
C)
–7.8944×10-13 kJ/atom
D)
7.8944×10-13 J/atom
Answer:
A) –7.8944×10-13 J/atom
Explanation:
Mass defect of a radionuclide (m)
[tex]=-8.7839[/tex]×[tex]10^{-30} kg[/tex]
Formula for binding energy
[tex]E=mc^{2}[/tex]
[tex]=(-8.7839x10^{-30} kg)(3x10^{8} m/s)^{2}[/tex]
[tex]E=-7.8944x10^{-13} J/atom[/tex]
If the mass defect for a radionuclide is – 8.7839 × 10⁻³° kg, the binding energy per atom will be –7.8944 × 10⁻¹³ J/atom. The correct option is A.
What is radionuclide?A radionuclide is an unstable nuclide because it contains so much charge. The excess energy is used by the gamma radiation by the nucleus, the electron uses energy to move to another orbital.
Radionuclides are particles that are used to scanning or monitor the radioactive chemicals that are in the body due to swallowing or inhaling.
The binding energy per atom can be calculated by the formula
The mass of defect of a radionuclide (m) is – 8.7839 × 10⁻³° kg
E = mc²
E = – 8.7839 × 10⁻³° x 3 x 10⁸ m/s
E = –7.8944 × 10⁻¹³ J/atom.
Thus, the correct option is A. –7.8944×10-13 J/atom.
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Laughing gas can decompose into nitrogen and oxygen
Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.
A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the equivalence point. In a separate titration, a 10.0 mL H3PO4 solution was titrated with the same NaOH solution. This time, 34.9 mL NaOH was required to reach the equivalence point. What is the concentration of the H3PO4 solution
Answer:
0.172 M
Explanation:
The reaction for the first titration is:
HCl + NaOH → NaCl + H₂OFirst we calculate how many HCl moles reacted, using the given concentration and volume:
19.6 mL * 0.189 M = 3.704 mmol HClAs one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:
3.704 mmol / 25.0 mL = 0.148 MAs for the second titration:
H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂OWe determine how many NaOH moles reacted:
34.9 mL * 0.148 M = 5.165 mmol NaOHThen we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:
5.165 mmol NaOH * [tex]\frac{1mmolH_3PO_4}{3mmolNaOH}[/tex] = 1.722 mmol H₃PO₄Finally we determine the H₃PO₄ solution concentration:
1.722 mmol / 10.0 mL = 0.172 MBears stop coming to a river ecosystem where they have been eating many fish each day. The fish the bears eat normally eat smaller fish, which eat plants along the river bottom.
What happens to the ecosystem?
Both the larger and the smaller fish populations grow quickly but then die out because the plant life is insufficient for them all to eat.
The larger fish population will drop first, and the smaller fish population will grow quickly. The plants will die off because too many of the smaller fish are eating them.
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
The smaller fish population begins to eat more plants and to grow. The larger fish have more food to eat so their population is able to grow, too.
Answer:
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
Explanation:
How many moles are in 9.83 x 1021 atoms of Na
Answer:
0.016 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
[tex]n = \frac{9.83 \times {10}^{21} }{6.02 \times {10}^{23} } \\ = 0.01632...[/tex]
We have the final answer as
0.016 molesHope this helps you
A mixture of He, Ar, and Xe has a total pressure of 2.40 atm. The partial pressure of He is 0.300 atm, and the partial pressure of Ar is 0.250 atm. What is the partial pressure of Xe?
Express your answer to three significant figures and include the appropriate units.
The partial pressure of Xe in the mixture is 1.850 atm. (partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar = 1.850 atm).
To find the partial pressure of Xe, we need to subtract the partial pressures of He and Ar from the total pressure.
Total pressure = partial pressure of He + partial pressure of Ar + partial pressure of Xe
Given:
Total pressure = 2.40 atm
Partial pressure of He = 0.300 atm
Partial pressure of Ar = 0.250 atm
Let's solve for the partial pressure of Xe:
Partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar
Partial pressure of Xe = 2.40 atm - 0.300 atm - 0.250 atm
Partial pressure of Xe = 1.850 atm
Therefore, the partial pressure of Xe in the mixture is 1.850 atm.
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Which is a LIMIT that authors telling stories using aural media, such as radio plays, must deal with?
A. listeners can hear how each actor says lines of dialogue
B. sound effects can enhance the story's action
C. music can reinforce the story's emotional moments
D. characters thoughts and feelings must be spoken aloud
Please help me on 6 and 8 thanks
Answer:
6.) 3, 12, 1, and 4 8.) 4, 1, and 3
Explanation:
By multiplying subscripts inside and outside of the parentheses you can count the number of atoms that are present. I recently answered a question for you and I did the math wrong I am going to go back and comment so you know which one and I will correct my errors. Sorry for the inconvenience!
the number of atoms in number 6:
N: 3
H: 12
P: 1
O: 4
the number of atoms for number 8:
Ca: 4
C: 1
O: 3
hope I clarified my mistake and helped you! :)
You are managing a city that needs to upgrade its disinfection basin at your 40 MGD surface water drinking water treatment plant. You would like to use chlorine (Cl2) as your disinfectant and you need to achieve a 4-log removal of E. coli. You are deciding between a traditional 750,000 gallon PFR contact basin (serpentine flow) and a newer system which contains three 150,000 gallon CSTRs in series, each receiving an equal injection of Cl2. Your final decision is going to be based on which system requires the least amount of Cl2 to achieve a 4-log removal of E. coli.
Required:
What is the amount of Cl2 required to operate each system (please answer in units of kg Cl/day)?
Solution :
According to Chick's law
[tex]$\frac{N_t}{N_0}=e^{-k'C^n t}$[/tex]
where, t = contact time
c = concentration of disinfectant
k' = lethality coefficient = 4.71
n = dilution coefficient = 1
4 log removal = % removal = 99.99
[tex]$\frac{N_t}{N_0}=\frac{\text{bacteria remaining}}{\text{bacteria initailly present}}$[/tex]
= 1 - R
= 1 - 0.9999
Now for plug flow reactor contact time,
[tex]$\tau =\frac{V}{Q} =\frac{75000}{40 \times 10^6}$[/tex]
= 0.01875 days
= 27 minutes
For CSTR, [tex]$\tau =\frac{V}{Q} =\frac{150000}{40 \times 10^6}$[/tex]
[tex]$=3.75 \times 10^{-3}$[/tex] days
= 5.4 minute
There are 3 reactors, hence total contact time = 3 x 5.4
= 16.2 minute
Or [tex]$\frac{N_t}{N_0}=e^{-k'C^n t}$[/tex]
or [tex]$(1-0.9999)=e^{-4.71 \times C \times t}$[/tex]
∴ C x t = 1.955
For PFR, [tex]$t_1 = 27 $[/tex] min
∴ C [tex]$=\frac{1.955}{27}$[/tex] = 0.072 mg/L
For CSIR, [tex]$t_2=16.2$[/tex] min
[tex]$C=\frac{1.955}{16.2} = 0.1206$[/tex] mg/L
∴ Chlorine required for PFR in kg/day
[tex]$=\frac{0.072 \times 40 \times 10^6 \times 3.785}{10^6}$[/tex] (1 gallon = 3.785 L)
= 18.25 kg/day
Therefore we should go for PFR system.
Is water an acid, base, or neutral?