How many liters of water are produced from the combustion of 2.5 moles of methane gas?

Answer:

Make Li-Ion batteries.

Produce commercial electric vehicles.

Create underwater subsea electrification.

Power telecommunication devices.

Explanation:

Minerals are essential raw materials in our daily lives, and are vital for economic, social and technological development. For example, in the following:

Agriculture: Phosphate rock, potash and lime are used in agricultural fertilisers and other mineral products are used to improve soil. The water you drink uses minerals to make it clean.

Construction: About 60 tonnes of aggregate are used to build an average house in the UK. If we include the associated infrastructure, this can be as high as 400 tonnes.

Minerals are used in building houses, schools, libraries, hospitals, offices and shops. Buildings use a wide range of minerals:

iron (as steel) in the framework of large building,

clay in bricks and roofing tiles,

slate for roofing tiles,

limestone, clay, shale and gypsum in cement,

gypsum in plaster,

silica sand in window glass,

sand and gravel and crushed rock as aggregates for fill and in concrete,

copper for plumbing and wiring,

clays for bathroom fixtures and fittings and tiles,

paint may include pigments, extenders and fillers from mineral sources.

Answer: toothpaste

Explanation:

The initial temperature of copper is 89.41°C.

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

According to this question, a 98.3 g piece of copper with specific heat of 0.380 J/g･°C is heated and then placed into 400.0 g of water initially at 20.7°C. The water increases in temperature to 22.2°C. The initial temperature can be calculated as follows;

Q = mc∆T

Where;

Q(water) = -Q(metal)

400 × 4.184 × 1.5 = -(98.3 × 0.38 × {22.2 - x})

2510.4 = - (829.26 - 37.354x)

2510.4 = -829.26 + 37.354x

3339.659 = 37.354x

X = 89.41°C

Therefore, 89.41°C is the initial temperature of the copper metal.

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The initial temperature of the copper piece is approximately 0.72°C.

To find the initial temperature of the copper piece, we can use the equation Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

First, let's calculate the heat energy gained by the water. The mass of the water is 400.0 g, and the change in temperature is 22.2°C - 20.7°C = 1.5°C.

Using the equation Q = mcΔT, we have:

Q_water = (400.0 g)(4.18 J/g • °C)(1.5°C) = 2490 J

Next, let's calculate the heat energy lost by the copper piece. The mass of the copper is 90.7 g, and the change in temperature is the same as the water, 1.5°C.

Using the equation Q = mcΔT, we have:

Q_copper = (90.7 g)(0.380 J/g • °C)(1.5°C) = 51.8 J

Since energy is conserved, the heat energy gained by the water is equal to the heat energy lost by the copper piece:

Q_water = Q_copper

2490 J = 51.8 J

Now, let's solve for the initial temperature of the copper piece. Rearranging the equation Q = mcΔT to solve for the initial temperature, we have:

T_initial = (Q_copper) / (m_copper * c_copper)

Substituting the values, we get:

T_initial = (51.8 J) / (90.7 g * 0.380 J/g • °C) ≈ 0.72°C

Therefore, the initial temperature of the copper piece is approximately 0.72°C.

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The mass of the solute required is 250.25 g.

We know that the number of moles of the solute can be used to obtain the mass of the solute that is  required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M *  6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles  * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

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Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

Answer:

18g

Explanation:

1g H + 8g O = 9g H2O since H is limiting factor

Decantation is widely used to purify a liquid by separating it from an insoluble particle suspension (e.g. in red wine, where the wine is decanted from the potassium bitartrate crystals to avoid unsavory taste).

Decantation is a process of separating solid-liquid mixtures or two or more immiscible liquids. Allowing the mixture to settle into various layers, the lightest/heaviest liquid layers are drained out.

This approach is used in the following ways:

1. Mud-water mixture separation (solid-liquid mixture)

2. Oil and water separation (immiscible liquid mixture)

3. Kerosene and water separation

Decantation is the process of separating liquid from solid and other immiscible (non-mixing) liquids by eliminating the liquid layer on top from the solid or liquid layer underneath.

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The simplest form of calcium carbonate is CaCO3.

What is the use of Calcium carbonate?

Calcium carbonate can be used as a dietary supplement when the amount of calcium in a person's body is less. Calcium is used even as an antacid. Calcium is necessary by the body for bones, heart and muscles.

In this, we are not provided the direct masses, so we will use this percentage composition.

The number of moles of each element are:

Ca-40/40= 1

C- 20/12 = (1.6 considered to be 1)

O- 48/16 = 3

Now all the three will be divided with the lowest value and that is 1, so the ratio of Ca: C: O= 1:1:3

Therefore, the simplest formula is CaCO3.

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Triple beam balance is not used to measure the weight of water because it is used to  measure mass.

The triple beam balance is an instrument used to measure mass very precisely. Such devices typically have a reading error of ±0.05 grams. Its name refers to its three beams, where the middle beam is the largest, the far beam of medium size, and the front beam the smallest.

Spring balance is used to measure the weight of the body whereas beam balance is used to measure the mass of the body. Since the mass of the body remains the same on earth as well as on moon but the acceleration due to gravity differs.

Therefore Triple beam balance is not used to measure the weight of the water.

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The energy from the photons in the FM station is greater than that from the AM station.

We have to recall that the radio waves are also a part of the electromagnetic spectrum and that the speed that is possessed by all of the waves waves that are in the electromagnetic spectrum is the speed of light (3 * 10^8 m/s).

We have;

E = hf

E = energy

h = Plank's constant

f = frequency

For the AM station;

E = 6.6 * 10^-34 Js * 1030 * 10^3 Hz

E = 6.798 * 10^-28 J

For the FM station;

E = 6.6 * 10^-34 Js * 98.4 * 10^6 Hz

= 6.494 * 10^-25 J

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Missing parts;

An AM radio station broadcasts at 1030 kHz , and its FM partner broadcasts at 98.5 MHz .

partA;Calculate the energy of the photons emitted by the AM radio station.

partB;Calculate the energy of the photons emitted by the FM radio station.

partC;Compare the energy of the photons emitted by the AM radio station with the energy of the photons emitted by the FM radio station.

A = 2.86 x [tex]10^{23[/tex] molecules of  [tex]KMnO_4[/tex]

B = 323.76 grams of Al

C = 1.53 moles of Au

D = 7.71 x [tex]10^{23[/tex] molecules of [tex]H_3PO_4[/tex]

E = 4.52 x [tex]10^{23[/tex] total atoms

According to Avogadro, a single mole of any substance contains 6.022 x [tex]10^{23[/tex] molecules or atoms of the substance.

Also, the mole of a substance is the ratio of the mass of the substance and the molar mass of the substance. In other words;

mole = mass/molar mass

These theories are what we need to solve the outlined problems.

       Mole of 75 g of [tex]KMnO_4[/tex]:

       mass/molar mass = 75/158

                                     = 0.4747 mol

        Since 1 mole = 6.022 x [tex]10^{23[/tex] molecules

         0.4747 mole = 0.4747 x 6.022 x [tex]10^{23[/tex]

                                = 2.86 x [tex]10^{23[/tex] molecules

       Since 1 mole =  6.022 x [tex]10^{23[/tex] molecules or atoms

        7.23 x [tex]10^{24[/tex] atoms = 7.23 x [tex]10^{24[/tex] / 6.022 x [tex]10^{23[/tex]

                                     = 12 moles

        Mass of 12 moles Al = 12 x 26.98

                                          =  323.76 grams    

                                    = 1.53 moles

                                   = 1.28 moles

         1.28 moles = 1.28 x 6.022 x [tex]10^{23[/tex]

                            = 7.71 x [tex]10^{23[/tex] molecules

                                        = 4.52 x [tex]10^{23[/tex] atoms

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The intermolecular forces between the oxygen molecules are very weak because of which a very less amount of energy is required for the oxygen to evaporate into a gas. There is no H-bonding or dipole movement present in oxygen molecules because of which the forces binding the molecules are absent in oxygen.

hence your correct option should be D

The molarity of the stock Mn²⁺ ions is 0.0288 M

Based on the dilution formula;

The molarity of a solution is the number of moles of a solute dissolved in a given volume of solution in liters.

The molarity of the stock solution is:

moles of Mn²⁺ ions = mass / molar mass

molar mass of  Mn²⁺ ions = 55.0 g/mol

moles of Mn²⁺ ions = 1.584 / 55

moles of Mn²⁺ ions = 0.0288 moles

molarity of Mn²⁺ ions = 0.0288 / 1

molarity of Mn²⁺ ions = 0.0288 M

The dilution formula is used to determine the molarities of A, B, and C.

C₁V₁ = C₂V₂

C₂ = C₁V₁ / V₂

Where;

Molarity of A = 50 * 0.0288 / 1000

Molarity of A = 0.00144 M

Molarity of B = 10 * 0.00144 / 250

Molarity of B = 0.0000576 M

Molarity of C = 10 * 0.0000576 / 500

Molarity of C = 0.000001152 M

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Answer:

Hope It Helps You

Explanation:

The molar solubility of the barium salt is obtained as  1.29 * 10^-19 M.

We know that the solubility has to do with the amount of the solute that is able to dissolve in a solvent at a particular temperature. As such, it is clear that the solubility depends on the temperature of the solution.

We know that the Ksp can be gotten from the expression of the Ksp as follows;

Ksp = [3x]^3 [2x]^2

Ksp = 9x^3 * 4x^2

Ksp = 36 * x^5

Ksp = 36x^5

x =[tex]\sqrt[5]{\frac{KSP}{36} }[/tex]

x = [tex]\sqrt[5]{6.00x10^-37} /36[/tex]

x = 1.29 * 10^-19 M

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Early "chemists" focused on practical problems - the production of dyes and perfumes, the production of soap, the use of metals, the production of glass, etc. The goal was not to make sense of the physical world.

Tapputi (also known as Tapputi-Belatekallim, referring to the female attendants of the palace), believed to be the world's first recorded chemist and perfume maker, mentioned in a cuneiform tablet from Babylonian Mesopotamia, circa 1200 BC It is BC is mentioned.

Along with Lavoisier, Boyle, and Dalton, Berzelius is considered the father of modern chemistry. In 1828, using oxygen as a standard and fixing its weight at 100, he produced a table of relative atomic weights containing all the elements known at the time.

Very early chemists were often motivated primarily by achieving a particular goal or product. It didn't take a lot of theory to make perfume or soap, just a good recipe, and attention to detail. There was no standard way to name substances (and no periodic table we could all agree on).

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The specific heat capacity of the metal can be calculated using the calorimeter equation. The specific heat capacity of the metal is obtained as 0.406 J/(°C g).

The specific heat capacity of a substance is the heat energy required to raise its temperature by one degree celsius per one gram of that substance.

The calorimeter equation relating heat energy q, mass m and temperature difference ΔT and specific heat capacity c is written as:

q = mcΔT.

In the given system the heat energy is transferred from the metal to water thus the final temperature of both will be 25 °C. Thus, at thermal equilibrium we can write it as:

25 g × c (95 -25 °C) = 25 × 4.18  × (25 - 18.2 °C )

Where, mass of water can be taken as 25 g since its density is 1 g/ml. From this specific heat capacity of the metal c is calculated as follows:

c =  [ 25 × 4.18  × (25 - 18.2 °C ) ] / 25 g ×  (95 -25 °C)

  = 0.406 J/(°C g).

Therefore, the specific heat capacity of the metal is  0.406 J/(°C g).

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The molarity of the 724.4g of ammonium phosphate in 4500 mL of alcohol is 1.0804m.

Ammonium  phosphate [tex]$\Rightarrow\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$[/tex]

GMM of Ammonium Phosphate [tex]$\Rightarrow 109 \mathrm{~g}+40 \mathrm{~g}$[/tex] [tex]$\Rightarrow 149 \mathrm{~g}$[/tex]

No. of moles of Ammonium Phosphate [tex]$\Rightarrow\left\{\frac{724.4}{149}\right\} \Rightarrow 4.8$[/tex]

Molarity = 4.86/4.5 = 1.0804m.

Phosphates are low in toxicity, however they create nutrient contamination and nourish algae. Eutrophication and hazardous algal blooms result as a result of this. Many countries, notably the European Union and the United States, have outlawed the use of phosphates in detergent.

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A chemist must take 6.053 mL of 3.6 M NaOH in water to form 16.61 mL of 1.312 M NaOH solution.

In the laboratory, high-concentration solutions are prepared for using a longer duration. This solution is known as a stock solution. These solutions are diluted based on chemical needs.                                               We need 6.61 mL of 1.312 M NaOH solution                                                                                The stock concentration of NaOH solution = 3.6 M                                                  We have to find the volume of this stock solution that should be taken Given M₁ = 3.6 M M₂ = 1.312 M V₂ = 16.61 mL V₁ =?

M₁V₁ =M₂V₂

3.6 × V₁ = 1.312 × 16.61

V₁ = 1.312 × 16.61 ÷ 3.6

V₁ = 6.053 mL

Hence, 6.053 mL of 3.6 M NaOH is needed to form 16.61 mL of 1.312 M NaOH solution

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hope this helps you out I would have typed an answer using my notes but that was taking to long anyways have a nice day

The molecules in which the central atom has an expanded octet is BrF₃ ans SF₆.

Hypervalent compound is the compound in which central atom contains more than 8 electrons or expanded octet.  Hypovalent is the compound in which atom posses less than eighth electron in the valence shell. in  In  BrF₃ , Bromine has 7 valence electron and fluorine seven electrons . the three F atom complete their octet after the bonding with Br but In Br there are 10 electrons in valence shell . so,  BrF₃ has expanded octet. SF₆, the sulfur , sulfur has 6 valence electron and Fluorine has 7 valence electron F atom complete there octet with sulphur but S atom has 12 valence electrons that is expanded octet.

Thus, The molecules in which the central atom has an expanded octet is BrF₃ ans SF₆.

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o.703..litter

Explanation:

M=n/v(l)solution

so v=n/M..... =8.48/12.05=0.703...

Examples of buffer solutions include:

Some applications of buffer solutions in Pharmaceutical Sciences include:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.

Buffers are broadly divided into two types

1. acidic buffer solutions and

2. alkaline buffer solutions.

Acidic buffers are solutions that have a pH below 7 and contain a weak acid.

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Different types of matter have different requirements because the pressure and temperature of a substance's environment dictate its phase.

Matter is anything that occupies space and has mass. The states or phases of matter include solids, liquids, gases, and plasma. Any material in a form that has a distinct shape and volume is referred to as a solid. Phase change refers to a shift in the condition of matter. Phase shifts can be carried out by people and occur frequently in nature.

A set of molecules will experience various movements, such as vibrations, rotations, and translations, depending on the average temperature in their vicinity.

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Acetic anhydride is a colorless liquid with a characteristic pungent odor. It is used in the manufacture of plastics, drugs, dyes, perfumes, explosives, and aspirin.

This chemical compound has a colorless liquid appearance, also called anhydride, acetic, smells like vinegar.

Chlorine gas is bubbled through a calcium bromide solution is a single displacement reaction.

Chlorine (in the form of a gas or dissolved in water) replaces bromine when added to calcium bromide solution. Chlorine replaces bromine in calcium bromide because it is more reactive than bromine. The solution darkens. The displaced bromine is responsible for this brown color. calcium chloride is the product of the chlorine.

A single replacement reaction, also known as a single displacement reaction, occurs when one element in a molecule is swapped out for another. Starting ingredients are always pure elements combined with an aqueous compound, such as pure hydrogen gas or zinc metal. A new aqueous compound and a different pure element will be produced as products when a replacement reaction takes place.

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Mass of 7.64 x 10^25 molecules of l₂ is 3.04 grams

Calculation of mass here we are doing from the number of molecules given. To do so we use the Avogadro's number. Avogadro's number is one of the most  fundamental constants of chemistry. It helps us to compare the different atoms or molecules of given substances where the same number of atoms or molecules are being compared.

Along with that we will also be using the number mole as well here. number of moles is nothing but the given mass divided by the molecular mass of the compound.

To solve the above given question we use the below given formulas;

number of molecules = Number of moles × Avogadro number

Number of moles = Number of molecules

                                  Avogadro number

⇒ 7.64×[tex]10^{25}[/tex]    = 0.012 moles

   6.023×[tex]10^{23}[/tex]

Mass = Number of moles × Molecular mass

⇒ 0.012 × 253.80 = 3.045 grams

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The IUPAC name and molecular formula for the following are,

a) prop-1-yne, C3H4

b) non-4-yne, C9H16

c) hex-3-yne, C6H10

What is IUPAC name?

International Unit for Pure and Applied Chemistry (IUPAC) is the method of naming the organic compounds in chemistry. It creates a standardized naming for the chemical compounds. There are prefixes, suffixes and parent chain considered while naming a compound.

The IUPAC name can be written by counting the parent chain carbons and considering the functional group present which is a triple bond in the given compounds. The molecular formula can be written by counting the number of different atoms present in the compound.

Therefore, the IUPAC name and molecular formula of the given compounds can be written as,

a) prop-1-yne, C3H4

b) non-4-yne, C9H16

c) hex-3-yne, C6H10

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The number of moles in 0.620 L of a 2.6M KCl solution is 1.61 moles.

Molarity is the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.

The molarity of a solution can be calculated by dividing the number of moles of the substance by its volume as follows:

no of moles = molarity × volume

According to this question, 0.620 L of a KCl solution has a molarity of 2.6 M. The number of moles of the substance is as follows:

no of moles = 2.6M × 0.620L = 1.612moles

Therefore, 1.61 moles is the number of moles in the pottasium chloride solution.

The incomplete question is as follows:

Determine the number of moles contained in 0.620L of a 2.6 M KCl solution.

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The mole is an SI unit that links the microscopic and macroscopic world that is why yes, mole is the base of SI unit.

What is a mole?

A mole is a popular scientific measurement unit for large quantities of very small items like atoms, molecules, or other specified particles in chemistry. It can also be spelt mol.

A extremely big amount, 6.02214076 1023 units, are designated by the mole. As of May 20, 2019, the General Conference on Weights and Measures defined the mole as this quantity for the International System of Units (SI). The mole was traditionally defined as the number of atoms found by experimentation to be present in 12 grammes of carbon-12.

The quantity of units in a mole is also referred to as Avogadro's number or Avogadro's constant in honour of the Italian physicist Amedeo Avogadro. Equal volumes of gases under the same conditions, according to Avogadro.

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5.57  is the pH of the buffer .

What is buffer ?

Buffer, in chemistry, usually a solution containing acids and bases or salts that tends to maintain a constant concentration of hydrogen ions. An ion is an atom or molecule that has lost or gained one or more electrons. A common buffer is a solution of acetic acid (CH3COOH) and sodium acetate. In aqueous solution, sodium acetate completely dissociates into sodium (Na+) and acetate (CH3COO-) ions. Buffer solutions with different hydrogen ion concentrations can be prepared by varying the buffer ratio and choosing acids of appropriate intrinsic strength. Commonly used buffers include phosphate, citrate, or borate and their salts

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