how many liters of water would it require to 36 grams of the substance?

Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.

Moles are the ratio of mass and the molar mass of the compound or the molecule.

Moles of oxygen are calculated as:

[tex]\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}[/tex]

The balanced chemical reaction can be shown as,

[tex]\rm 2HgO \rightarrow 2Hg + O_{2}[/tex]

From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.

Moles of mercury oxide are calculated as:

[tex]\begin{aligned} \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\; HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}[/tex]

Therefore, option C. 15.63 moles of mercury (II) oxide is needed.

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Answer:

The aspirin is more soluble in ethanol than water - the water helps the crystals separate from solution.

Explanation:

Hope this helps!

Answer:

dam aye someone give this person a medal

Explanation:

The molar mass of Oz is 48 g/mol is true.

Molar mass of a substance is the mass of 1 mole of that substance or it is the number of grams per mole of a substance. The units for molar mass is grams/mole.

Therefore,The molar mass of Oz is 48 g/mol is correct because ozone have three oxygen and the molar mass of one oxygen is 16g/mol.

Ozone= 16×3

Ozone=48g/mol.

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Answer:

Ginger ale is a strong acid

Explanation:

This is because of the high amounts of carbonic acid that it contains, putting it below the 4.6 Ph threshold.

Answer:

H3CS06

Explanation:

A chemical supply company sells sulfuric acid (H3CS06) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 s…

Molarity is the ratio of a mole of the solute of the substance to the liter of solution. The volume of solution required to make 12.0 ml of 0.50 M solution is 1.5 mL.

Molar dilution is the calculation of the molarity or the volume of the unknown value from the known value. It is given as,

[tex]\rm M_{1}V_{1}= \rm M_{2}V_{2}[/tex]

Given,

Initial molarity = 4.00 M

Initial volume =?

Final molarity = 0.50 M

Final volume = 12.0 mL

Substituting values in the equation:

[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{\rm M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.50 \times 12.0 }{4.00}\\\\&= 1.5 \;\rm ml\end{aligned}[/tex]

Therefore, 1.5 ml of 4.00 M sulfuric acid must be used to make 12 ml of 0.50 M solution.

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Option C) 19.3L is the correct answer.

Hence, the final volume of the gas at the standard atmospheres and temperature is 19.3L.

Given the data in the question;

At Standard temperature and pressure( STP)

Then

Final Volume; [tex]V_2 = \ ?[/tex]

Combined gas law combines both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

To determine the new volume of the gas, we substitute our values into the expression above.

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\P_1V_1T_2 = P_2V_2T_1\\\\1.00atm * 29.3L * 250.15K = 1.39atm * V_2 * 273.15K\\\\7329.395atm.L.K = 379.6785atm.K * V_2\\\\V_2 = \frac{7329.395atm.L.K}{379.6785atm.K} \\\\V_2 = 19.3L[/tex]

Option C) 19.3L is the correct answer.

Hence, the final volume of the gas at the standard atmospheres and temperature is

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Answer:

25% is left   15 gm

Explanation:

(1/2)^2 = 25%

Answer:

b. 25% unchanged and 75% stable

Explanation:

got it right on edge

When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

In solution

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)

The reaction proceeds as follow

MgCl₂(aq) + AgNO₃(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

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When a solution of MgCl₂ and one of AgNO₃ are mixed, the net ionic equation is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

Net ionic reactions are those reactions in which each species are written in their respective ions form except the spectator ions.

Given chemical reaction is:

MgCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Mg(NO₃)₂(aq)

Ionic form of the given reaction will be written as

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) → 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Spectator ions are those which are commonly present on both side of the reaction and for this reaction they are Mg²⁺ and NO₃¯. So the net ionic reaction will be:

2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s)

Hence required net ionic reaction is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

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From the available options with respect to Taylor's experiment, none of the data is qualitative.

These are data that cannot be measured using any instrument or assigned a numerical value.

Qualitative data are observable data based on perception.

This is unlike quantitative data that can be measured using relevant instruments and assigned numeric figures.

Mass can be measured in grams using a weighing balance, angle of inclination can be measured using relevant instruments, and time can be measured using a stopwatch.

Thus, none of the options is qualitative.

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Answer:

None are Qualitative

Explanation: I took the test and got a 100%

Answer:

(CH₃COO)₂Ca(aq) + Na₂CO₃(aq) = 2CH₃COONa(aq) + CaCO₃(s)

2CH₃COO⁻ + Ca²⁺ + 2Na⁺ + CO₃²⁻ = 2CH₃COO⁻ + 2Na⁺ + CaCO₃

Ca²⁺ + CO₃²⁻ = CaCO₃

Answer:

formula of concentration ion.

Answer:

an energy level represents the three dimensional space surrounding nucleus where electrons are most likely to be.

Explanation:

The Change in Gibb's free energy, ΔG for the reaction at 298K is; -56.92KJ.

It follows from the Gibb's free energy formula as expressed in terms of Enthalpy and Entropy that;

On this note, it follows that;

Hence, the Gibb's free energy for the reaction is;

Remarks: The question requires that we determine the Gibb's free energy for the reaction at 298K.

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The Gibbs free energy for the reaction Br²(g) Cl²(g)⇌2BrCl(g) is -56.92 KJ.

It's the total work done in a closed thermodynamic system.

By the formula of Gibbs free energy

[tex]\rm \Delta G = \Delta H - T \Delta S[/tex]

The H is 14.6 KJ/mol

The change in temperature is 0.24

Putting the values in the equation

[tex]\Delta G = 14.6 - (298 \times 0.24)\\\\ \Delta G = 14.6 - 71.52\\\\ \Delta G = -56.92KJ[/tex]

Thus, the Gibbs free energy for the reaction is -56.92 KJ

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Answer:

0.14 liters nitric acid

Explanation:

Molarity = moles / liter

7.0 M = x / 0.03 L

= 0.21 moles NaOH

0.21 moles NaOH x ( 1 mole HNO3 / 1 mole NaOH) = 0.21 moles HNO3

Molarity = moles / liter

1.5 M  = 0.21 moles / x

x = 0.21 moles / 1.5 M

x = 0.14 Liters HNO3

Answer:

[tex]140mL[/tex]

Explanation:

[tex]M_1V_1=M_2V_2[/tex]

[tex]M_1=1.5M[/tex] molarity of nitric acid

[tex]V_1=?[/tex]  volume of nitric acid

[tex]M_2=7.0M[/tex] molarity of sodium hydroxide

[tex]V_2=30.0mL[/tex] volume of sodium hydroxide

[tex](1.5M)(V_1)=(7.0M)(30.0mL)[/tex]

[tex]V_1 =\frac{(7.0M)(30.0mL)}{1.5M}=140mL[/tex]

Hope this helps whoever needs it :)

Have a good day!!!

If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

The molarity of a solution can be calculated using the following expression:

M1V1 = M2V2

Where;

25 × 0.80 = 40 × M2

20 = 40M2

M2 = 20/40

M2 = 0.5M

Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

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Explanation:

Big C carbon surrounded by He helium

The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

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The grams of NiCl₂.6H₂O will be used to prepare a 0.0350M, 500ml of NiCl₂ solution is 2.268 grams.

Mass in grams of any substance will be calculated by using moles as:

n = W/M, where

W = given mass

M = molar mass

Moles from molarity will be calculated by using the below formula:

M = n/V, where

M = molarity of NiCl₂ solution = 0.0350M

V = volume of solution = 500mL = 0.5L

On putting values, we get

n = (0.035)(0.5) = 0.0175 mol

Now we convert these moles into grams by using the first formula as:
W = (0.0175mol)(129.6g/mol) = 2.268g

Hence required mass of NiCl₂.6H₂O is 2.268g.

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The valur of energy of formation ΔGf of H₂O is -228.6 kJ/mol.

ΔG of any reaction will be calculated as:

ΔG = Sum of ΔG of products - Sum of ΔG of reactants

Given chemical reaction is:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)

For this reaction, ΔG will be calculated as:

ΔG = [ΔGf 4(NO) + ΔGf 6(H₂O)] - [ΔGf 4(NH₃) + ΔGf 5(O₂)]

Given that:

ΔG = -957.9 kJ

ΔGf of NH₃ = -16.66 kJ/mol

ΔGf of NO = 86.71 kJ/mol

ΔGf of O₂ = 0 (because it is present in elemental form)

ΔGf of H₂O = let x (to find)

On putting all these values on the above equation, we get

-957.9 = [4(86.71) + 6(x)] - [4(-16.66) + 5(0)]

-957.9 = 346.84 + 6x + 66.64

6x = -957.9 - 346.84 - 66.64

6x = -1,371.38

x = -228.56 = -228.6 kJ/mol

Hence, correct option is (1) i.e. -228.6 kJ/mol.

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Answer:

A) -228.6 kJ/mol

Explanation:

EDGE 2022

In Ferromagnetism, materials are changed into permanent magnets.

Ferromagnetism is a process in which specific materials are turned into permanent magnets. The spins of electrons are shifted and electrons become more aligned and sequence with the direction of the field.

So we can conclude that in Ferromagnetism, materials are changed into permanent magnets.

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Answer:

Bison were saved through the combined efforts of conservationists, scientists, ranchers and ultimately the general public. As their comeback continues, I believe that they can teach us how to be better stewards of the land and provide a future for the Plains where ecosystems and human cultures thrive.

Explanation:

[tex]watch.some.anime[/tex]

Answer:

Molybdenum is M, Einsteinium is E, and N is Nitrogen. Lastly, S is sulfur.

The concentration of the final solution after mixing water into the H₂SO₄ is 0.375 M.

Concentration in terms of molarity will be calculated by using the below formula as:

M₁V₁ = M₂V₂, where

M₁ = molarity of H₂SO₄ = 1.50 M

V₁ = volume of H₂SO₄ = 50 mL

M₂ = molarity of water = ?

V₂ = volume of water = 200 mL

On putting all values on the above equation, we get

M₂ = (1.50)(50) / (200) = 0.375 M

Hence option (2) is correct.

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a leguminous plant, Phaseolus aureus, whose seeds are used as food in India.

Answer:

Green Gram is a small round edible green bean which is also known as moong ki daal in the subcontinent.

Explanation:

The green gram bean which is also known as the mung, maash or moong, is a plant species in the legume family. The green gram bean is mainly cultivated in East, Southeast and South Asia. It is used as an ingredient in both savoury and sweet dishes.

The equation that shows conservation of both mass and charge is:

(4) Ni + Pb²⁺ → Ni²⁺ + Pb

Which equation shows conservation of both mass and charge?

(1) Cl₂ + Br → Cl⁻ + Br

No, the equation does not show conservation of mass nor charge.

(2) Cu + 2 Ag⁺ → Cu²⁺ + Ag

No, the equation does not show conservation of mass.

(3) Zn + Cr³⁺ → Zn²⁺ + Cr

No, the equation does not show conservation of charge.

(4) Ni + Pb²⁺ → Ni²⁺ + Pb

Yes, the equation show conservation of mass and charge.

The equation that shows conservation of both mass and charge is:

(4) Ni + Pb²⁺ → Ni²⁺ + Pb

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Answer: Evaporation Condensation is used to seperate the parts of a mixture

Explanation: This is because it is the first order of the distilation process

The use of evaporation and condensation to separate the parts of a mixture is called distillation.

What is distillation?

Separating salt water to produce pure water and salt is an example of a simple distillation mixture.

The water begins to evaporate during the distillation process, and the vapor cools down to form pure water.

A second container is used to collect the pure water.

Thus, the use of evaporation and condensation to separate the parts of a mixture is called distillation.

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Answer:

Explanation:

The elements in Group I of the periodic table are called alkali metals. They are called alkali metals because they react with water to form alkali solutions. These metals are very reactive; hence they have to be stored under oil to protect them from corrosion by air and waterwaterwater

The group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.

They are the metals that are soft, lustrous, and have a low melting point. Air and moisture react readily with alkali metals.

Special precautions must be taken when using and storing these metals due to their reactivity.

The seven alkali metals are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

Thus, the group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.

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